I'm relatively new to the programming scene (my only experience was C++ in first year engineering) and I'm trying to teach myself Swift language. I have the Swift Programming Language e-book from the App Store and came across the Function and Closure section regarding Tuples and am currently confused. The code they provide as an example is:
func calculateStatistics(scores:[Int]) -> (min:Int, max:Int, sum:Int) {
var min = scores[0]
var max = scores[0]
var sum = 0
for score in scores {
if score > max {
max = score
} else if score < min {
min = score
}
sum += score
}
return (min, max, sum)
}
let calculateStatistics([5, 3, 100, 3, 9])
and it'll output (3, 100, 120).
I'm just not sure about the process of how they get those values via the For-Loop and if-statement.
If any one of you can kindly walk me through whats exactly is happening in this if-statement that would be greatly appreciated!! My thinking is obviously wrong but the way I viewed it was that the min and max value is "5" by the initial variable declaration. But what is the initial value of "score" and how do you determine if score is > or < the max and min?
Tuples are just a group of values. The function is declared to return a tuple of three ints. At the end of the function there's a return statements where the resulting tuple is created from existing variables.
As for the loops and ifs, they just go through the list given as the parameter to the function, and find the highest and lowest values in the list, like this:
max is initialized to be the first value in the list. (It has to have an initial values so that it can be compared against other values with < and >.)
Go through every int in the list with for score in scores (score is initialized to be the next value in the list with each iteration: first it's 5, then 3, then 100, etc.).
If an int is found to be greater than max, max is updated to that value.
After going through every int in the list, max will have the value of the greatest int in that list.
And same for min.
Edit: In the Swift Programming Language e-book, a few pages before Functions and Closures, there's an explanation on the for-in loop structure. Check it out.
Related
I have an array of 1 x 400, where all element values are above 1500. However, I have some elements that have values<50 which are wrong measures and I would like to have the mean of the elements before and after the wrong measured data points and replace it in the main array.
For instance, element number 17 is below 50 so I want to take the mean of elements 16 and 18 and replace element 17 with the new mean.
Can someone help me, please? many thanks in advance.
No language is specified in the question, but for Python you could work with List Comprehension:
# array with 400 values, some of which are incorrect
arr = [...]
arr = [arr[i] if arr[i] >= 50 else (arr[i-1]+arr[i+1])/2 for i in range(len(arr))]
That is, if arr[i] is less than 50, it'll be replaced by the average value of the element before and after it. There are two issues with this approach.
If i is the first or last element, then one of the two values will be undefined, and no mean can be obtained. This can be fixed by just using the value of the available neighbour, as specified below
If two values in a row are very low, the leftmost one will use the rightmost one to calculate its value, which will result in a very low value. This is a problem that may not occur for you in practice, but it is an inherent result of the way you wish to recalculate values, and you might want to keep it in mind.
Improved version, keeping in mind the edge cases:
# don't alter the first and last item, even if they're low
arr = [arr[i] if arr[i] >= 50 or i == 0 or i+1 == len(arr) else (arr[i-1]+arr[i+1])/2 for i in range(len(arr))]
# replace the first and last element if needed
if arr[0] < 50:
arr[0] = arr[1]
if arr[len(arr)-1] < 50:
arr[len(arr)-1] = arr[len(arr)-2]
I hope this answer was useful for you, even if you intend to use another language or framework than python.
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Hope you are doing well. Would anyone please explain this code to me? I am still not getting how we got 120 here. When the parameters were passed to the function, where was it saved? How did it determine max and min before calculating?
Would be really appreciated if anyone could explain it for me please..
You're getting 120 because you're asking the tuple for the sum value twice. The tuple passed back is (min: Int, max: Int, sum: Int). In this case, sum is also index number 2 (min is index zero, max is index one). So in this case statistics.sum == statistics.2
If you want to access min or max you can access them using statistics.min or statistics.max respectively. You can also use statistics.0 or statistics.1 if you prefer (I recommend using the labels though).
Final thought: I would change your initial assignment of max and min inside the function to read as follows:
guard var max = scores.first, var min = scores.first else {
return (0, 0, 0)
}
This will protect against the user accidentally passing an empty array.
You could have also set min and max to 0 ,not to scores[0].
This func is very simple, I think you should read somewhere How functions are working.
For loop is used to go through every element, in your case every element in array scores. In every iteration, variable sum is increased by current element in array. So:
At the beginning of the function : sum = 0
1. iteration: sum = 0 + 5
2. iteration: sum = 5 + 3
3. iteration: sum = 8 + 100
4. iteration: sum = 108 + 3
5. iteration: sum = 111 + 9
For loop ends. Sum = 120.
Score in Scores means like every single element in score. So name Score can be whatever you want to name it. You could have also name it element , x, a or whatever you like.
The function returns a tuple of type (min: Int, max: Int, sum: Int).
max and min are not determined before being calculated. When they're first assigned at the top of the function, they just contain the first element of the passed in scores array. But by the time the loop below finishes, they indeed have the correct minimum and maximum values. Those values are then returned in a tuple matching the return type.
Let's say I want to generate a random number between 1 and 100, but I don't want to include 42. How would I do this without repeating the random method until it is not 42.
Updated for Swift 5.1
Excluding 1 value
var nums = [Int](1...100)
nums.remove(at: 42)
let random = Int(arc4random_uniform(UInt32(nums.count)))
print(nums[random])
Excluding multiple values
This extension of Range does provide a solution when you want to exclude more than 1 value.
extension ClosedRange where Element: Hashable {
func random(without excluded:[Element]) -> Element {
let valid = Set(self).subtracting(Set(excluded))
let random = Int(arc4random_uniform(UInt32(valid.count)))
return Array(valid)[random]
}
}
Example
(1...100).random(without: [40,50,60])
I believe the computation complexity of this second solution is O(n) where n is the number of elements included in the range.
The assumption here is the no more than n excluded values are provided by the caller.
appzYourLife has some great general purpose solutions, but I want to tackle the specific problem in a lightweight way.
Both of these approaches work roughly the same way: Narrow the range to the random number generator to remove the impossible answer (99 answers instead of 100), then map the result so it isn't the illegal value.
Neither approach increases the probability of an outcome relative to another outcome. That is, assuming your random number function is perfectly random the result will still be random (and no 2x chance of 43 relative to 5, for instance).
Approach 1: Addition.
Get a random number from 1 to 99. If it's greater than or equal to the number you want to avoid, add one to it.
func approach1()->Int {
var number = Int(arc4random_uniform(99)+1)
if number >= 42 {
number = number + 1
}
return number
}
As an example, trying to generate a random number from 1-5 that's not 3, take a random number from 1 to 4 and add one if it's greater than or equal to 3.
rand(1..4) produces 1, +0, = 1
rand(1..4) produces 2, +0, = 2
rand(1..4) produces 3, +1, = 4
rand(1..4) produces 4, +1, = 5
Approach 2: Avoidance.
Another simple way would be to get a number from 1 to 99. If it's exactly equal to the number you're trying to avoid, make it 100 instead.
func approach2()->Int {
var number = Int(arc4random_uniform(99)+1)
if number == 42 {
number = 100
}
return number
}
Using this algorithm and narrowing the range to 1-5 (while avoiding 3) again, we get these possible outcomes:
rand(1..4) produces 1; allowed, so Result = 1
rand(1..4) produces 2, allowed, so Result = 2
rand(1..4) produces 3; not allowed, so Result = 5
rand(1..4) produces 4, allowed, so Result = 4
I’m a beginner in programming and playing around with the arc4random_uniform() function in Swift. The program I’m making so far generates a random number from 1-10 regenerated by a UIButton. However, I want the variable ’highest' that gets initialised to the random number to update if the next generated number is larger than the one currently held in it. For example the random number is 6 which is stored in highest and if the next number is 8 highest becomes 8. I don't know how to go about this. I have connected the UIButton to an IBAction function and have the following code:
var randomValue = arc4random_uniform(11) + 1
highest = Int(randomValue)
if (Int(randomValue) < highest) {
// Don’t know what to do
}
Initialise highest to 0
Every time you generate a new random number, replace the value of highest with the higher of the two numbers
highest = max(highest, randomValue)
The max() function is part of the Swift standard library and returns the larger of the two passed in vales.
edited to add
Here's a playground showing this with a bit more detail, including casting of types:
var highest: Int = 0
func random() -> Int {
let r = arc4random_uniform(10) + 1
return Int(r)
}
var randomValue = random()
highest = max(highest, randomValue)
You can see that multiple calls persist the highest value.
I'm in the process of getting comfortable passing unnamed functions as arguments and I am using this to practice with, based off of the examples in the Swift Programming Guide.
So we have an array of Ints:
var numbers: Int[] = [1, 2, 3, 4, 5, 6, 7]
And I apply a transform like so: (7)
func transformNumber(number: Int) -> Int {
let result = number * 3
return result
}
numbers = numbers.map(transformNumber)
Which is equal to: (7)
numbers = numbers.map({(number: Int) -> Int in
let result = number * 3
return result;
})
Which is equal to: (8)
numbers = numbers.map({number in number * 3})
Which is equal to: (8)
numbers = numbers.map({$0 * 3})
Which is equal to: (8)
numbers = numbers.map() {$0 * 3}
As you can see in the following graphic, the iteration count in the playground sidebar shows that in the furthest abstraction of a function declaration, it has an 8 count.
Question
Why is it showing as 8 iterations for the last two examples?
It's not showing 8 iterations, really. It's showing that 8 things executed on that line. There were 7 executions as part of the map function, and an 8th to do the assignment back into the numbers variable.
It looks like this could probably provide more helpful diagnostics. I would highly encourage you to provide feedback via https://bugreport.apple.com.
Slightly rewriting your experiment to use only closures, the call counts still differ by one:
Case 1: Explicitly specifying argument types (visit count is 7)
var f1 = {(number: Int) -> Int in
let result = number * 3
return result
}
numbers.map(f1)
Case 2: Implicit argument types (visit count is 8)
var f2 = {$0 * 3}
numbers.map(f2)
If the (x times) count reported by the REPL does indeed represent a count of visits to that code location, and noting that the count is greater by one in cases where the closure type arguments are not explicitly specified (e.g. f2), my guess is that at least in the playground REPL, the extra visit is to establish actual parameter types and fill that gap in the underlying AST.