For use in SSRS multi-select dropdowns, I need to generate multiple DISTINCT lists of values.
This is easily done. Select DISTINCT Department from DimEmployee
In order to set an SSRS default value, you must have an ID field also in your data set.. this is not achieved by the above query
I need to assign an arbitrary uniqueID to each of these records from my distinct list
Any advice appreciated.
Final output would be:
Select * From dsDeptList
Results...
ID | DeptName
1 | DeptName1
2 | DeptName2
etc.....
Just include the EmployeeID column twice (with column aliases). Use it as the ID and the value. The DISTINCT guarantees it's unique in the resultset.
Please try below code:
CREATE TABLE #Test(EmpName VARCHAR(10));
INSERT #Test VALUES('A'),('A'),('B'),('C'),('C');
SELECT DISTINCT DENSE_RANK() OVER (ORDER BY EmpName) ID,EmpName
FROM #Test;
DROP TABLE #Test;
I hope this will help.
I think GROUP BY should solve your problem
SELECT EmployeeID,EmpName FROM YourTable
GROUP BY EmployeeID,EmpName
You'll definitely avoid dublications
Related
I have some issues while trying to get only one record per matching condition..
Let's suppose I have Certifications table with the following columns:
Id, EmployeeId, DepartmentId, CertificationTitle, PassedDate
An employee can have more then one record in this table but I need to get only one record per employee (based on latest PassedDate)
SELECT Id, EmployeeId, CertificationTitle
FROM certifications c
ORDER BY EmployeeId, PassedDate DESC
From this select I need somehow to get only the first record for each EmployeeId.
Does anyone have any ideas how I can achieve this, Is it possible?
The Id is the Primary Key on the table, so it is different on each record.
I need to keep all this columns specified in the Select query.
The Group By didn't worked for me, or maybe I did it wrong...
Use DISTINCT ON. This returns exactly the first ordered record of the group. You ordered correctly by PassedData DESC to get the most recent record first. The group for DISTINCT ON, naturally, is EmployeeID:
SELECT DISTINCT ON (EmployeeId),
Id,
EmployeeId,
CertificationTitle
FROM certifications c
ORDER BY EmployeeId, PassedDate DESC
I am not able to select distinct store_id from the table in postgres..
Your syntax is wrong - try using DISTINCT ON (more info here)
If you want to maintain the column order you can do a nested select
I'm working on a table which has more than 10 columns. One of the column name is ASAT which is of type DATE(Format is yyyy-mm-dd HH:MM:SS:mmm).
I'm looking for a sql query which returns all records of max date. Trying to use that query in java for JDBC call.
I tried this:
Select * from tablename where ASAT in (select MAX(ASAT) from tablename).
But it is not returning any records.
Any help is really appreciated.Thanks
How about:
SELECT MAX(Asat) FROM TableA;
SELECT MAX(Asat) FROM TableA GROUP BY Asat;
When you self join, I suggest aliasing each copy of the table. Personally I use the table letter with a number afterwards in case I need to track it for larger queries.
Select *
from tablename t1
where t1.ASAT = (
select MAX(t2.ASAT)
from tablename t2
)
I believe you are looking for something like this if I'm understanding you. First build a CTE containing the primary key and the MAX(ASAT). Then join to it, selecting where the primary key matches the primary key of the row with the MAX(ASAT). Note your "ID" may have to be more than one column.
with tbl_max_asat(id, max_asat) as (
select id, max(asat) max_asat
from tablename
group by id
)
select *
from tablename t
join tbl_max_asat tma
on t.id = tma.id;
This old post just popped up because it was edited today. Maybe my answer will still help someone. :-)
I have a table on pgsql with names (having more than 1 mio. rows), but I have also many duplicates. I select 3 fields: id, name, metadata.
I want to select them randomly with ORDER BY RANDOM() and LIMIT 1000, so I do this is many steps to save some memory in my PHP script.
But how can I do that so it only gives me a list having no duplicates in names.
For example [1,"Michael Fox","2003-03-03,34,M,4545"] will be returned but not [2,"Michael Fox","1989-02-23,M,5633"]. The name field is the most important and must be unique in the list everytime I do the select and it must be random.
I tried with GROUP BY name, bu then it expects me to have id and metadata in the GROUP BY as well or in a aggragate function, but I dont want to have them somehow filtered.
Anyone knows how to fetch many columns but do only a distinct on one column?
To do a distinct on only one (or n) column(s):
select distinct on (name)
name, col1, col2
from names
This will return any of the rows containing the name. If you want to control which of the rows will be returned you need to order:
select distinct on (name)
name, col1, col2
from names
order by name, col1
Will return the first row when ordered by col1.
distinct on:
SELECT DISTINCT ON ( expression [, ...] ) keeps only the first row of each set of rows where the given expressions evaluate to equal. The DISTINCT ON expressions are interpreted using the same rules as for ORDER BY (see above). Note that the “first row” of each set is unpredictable unless ORDER BY is used to ensure that the desired row appears first.
The DISTINCT ON expression(s) must match the leftmost ORDER BY expression(s). The ORDER BY clause will normally contain additional expression(s) that determine the desired precedence of rows within each DISTINCT ON group.
Anyone knows how to fetch many columns but do only a distinct on one column?
You want the DISTINCT ON clause.
You didn't provide sample data or a complete query so I don't have anything to show you. You want to write something like:
SELECT DISTINCT ON (name) fields, id, name, metadata FROM the_table;
This will return an unpredictable (but not "random") set of rows. If you want to make it predictable add an ORDER BY per Clodaldo's answer. If you want to make it truly random, you'll want to ORDER BY random().
To do a distinct on n columns:
select distinct on (col1, col2) col1, col2, col3, col4 from names
SELECT NAME,MAX(ID) as ID,MAX(METADATA) as METADATA
from SOMETABLE
GROUP BY NAME
I have a SQL query, like so:
SELECT DISTINCT ID, Name FROM Table
This brings up all the distinct IDs (1...13), but in the 13 IDs, it repeats the name (as it comes up twice). The order of the query (ID, Name) has to be kept the same as the app using this query is coded with this assumption.
Is there a way to ensure there are no duplicates?
Thanks
You can try :
select id, name from table group by id,name
But it seems like distinct should work. Perhaps there are trailing spaces at the end of your name fields?
Instead of using DISTINCT, use GROUP BY
SELECT ID, Name FROM Table GROUP BY ID, Name