I'm working on a table which has more than 10 columns. One of the column name is ASAT which is of type DATE(Format is yyyy-mm-dd HH:MM:SS:mmm).
I'm looking for a sql query which returns all records of max date. Trying to use that query in java for JDBC call.
I tried this:
Select * from tablename where ASAT in (select MAX(ASAT) from tablename).
But it is not returning any records.
Any help is really appreciated.Thanks
How about:
SELECT MAX(Asat) FROM TableA;
SELECT MAX(Asat) FROM TableA GROUP BY Asat;
When you self join, I suggest aliasing each copy of the table. Personally I use the table letter with a number afterwards in case I need to track it for larger queries.
Select *
from tablename t1
where t1.ASAT = (
select MAX(t2.ASAT)
from tablename t2
)
I believe you are looking for something like this if I'm understanding you. First build a CTE containing the primary key and the MAX(ASAT). Then join to it, selecting where the primary key matches the primary key of the row with the MAX(ASAT). Note your "ID" may have to be more than one column.
with tbl_max_asat(id, max_asat) as (
select id, max(asat) max_asat
from tablename
group by id
)
select *
from tablename t
join tbl_max_asat tma
on t.id = tma.id;
This old post just popped up because it was edited today. Maybe my answer will still help someone. :-)
Related
I need the below results ..
Table :
Order postcode qnty
123 2234 1
Expected result:
Order 123
Postcode 2234
Qnty 1
SQL server:
Select pvt.element_name
,pvt.element_value(select order.postcode
from table name)up
unpivot (element_value for element_name in(order,postcode) as Pvt
How to achieve this in db2?
Db2 for IBM i doesn't have a built-in unpviot function.. AFAIK, it's not available on any Db2 platofrm...unless it's been added recently.
The straight forward method
select 'ORDER' as key, order as value
from mytable
UNION ALL
select 'POSTCODE', postcode
from mytable
UNION ALL
select 'QNTY', char(qnty)
from mytable;
A better performing method is to do a cross join between the source table and a correlated VALUES of as many rows as columns that need to be unpivoted.
select
Key, value
from mytable T,
lateral (values ('ORDER', t.order)
, ('POSTCODE', t.postcode)
, ('QNQTY', varchar(t.qnty))
) as unpivot(key, value);
However, you'll need to know ahead of time what the values you're unpivoting on.
If you don't know the values, there are some ways to unpivot with the XMLTABLE (possibly JSON_TABLE) that might work. I've never used them, and I'm out of time to spend answering this question. You can find some examples via google.
I have created a stored procedure for LUW that rotate a table:
https://github.com/angoca/db2tools/blob/master/pivot.sql
You just need to call the stored procedure by passing the tablename as parameter, and it will return a cursor with the headers of the column in the first column.
I have a rather large table of 50000 records, and I want to cut this down to 5000. How would I write an SQL query to delete the other 45000 records. The basic table structure contains the column of a datetime.
A rough idea of the query I want is the following
DELETE FROM mytable WHERE countexceeded(5000) ORDER BY filedate DESC;
I could write this in C# somehow grabbing the row index number and doing some work around that, however is there a tidy way to do this?
The answer you have accepted is not valid syntax as DELETE does not allow an ORDER BY clause. You can use
;WITH T AS
(
SELECT TOP 45000 *
FROM mytable
ORDER BY filedate
)
DELETE FROM T
DELETE TOP(45000) FROM mytable ORDER BY filedate ASC;
Change the order by to ascending to get the rows in reverse order and then delete the top 45000.
Hope this helps.
Edit:-
I apologize for the invalid syntax. Here is my second attempt.
DELETE FROM myTable a INNER JOIN
(SELECT TOP(45000) * FROM myTable ORDER BY fileDate ASC) b ON a.id = b.id
If you do not have a unique column then please use Martin Smith's CTE answer.
if the table is correctly ordered:
DELETE FROM mytable LIMIT 5000
if not and the table has correctly ordered auto_increment index:
get the row
SELECT id, filedate FROM mytable LIMIT 1, 50000;
save the id and then delete
DELETE FROM mytable WHERE id >= #id;
if not ordered correctly, you could use filedate instead of id, but if it's a date without time, you could get undesired rows deleted from the same date, so be carefull with filedate deletion solution
I have the need to look at two tables that share two variables and get a list of the data from one table that does not have matching data in the other table. Example:
Table A
xName
Date
Place
xAmount
Table B
yName
Date
Place
yAmount
I need to be able to write a query that will check Table A and find entries that have no corresponding entry in Table B. If it was a one variable issue I could use not in statement but I can't think of a way to do that with two variables. A left join also does not appear like you could do it. Since looking at it by a specific date or place name would not work since we are talking about thousands of dates and hundreds of place names.
Thanks in advance to anyone who can help out.
SELECT TableA.Date,
TableA.Place,
TableA.xName,
TableA.xAmount,
TableB.yName,
TableB.yAmount
FROM TableA
LEFT OUTER JOIN TableB
ON TableA.Date = TableB.Date
AND TableA.Place = TableB.Place
WHERE TableB.yName IS NULL
OR TableB.yAmount IS NULL
SELECT * FROM A WHERE NOT EXISTS
(SELECT 1 FROM B
WHERE A.xName = B.yName AND A.Date = B.Date AND A.Place = B.Place AND A.xAmount = B.yAmount)
in ORACLE:
select xName , xAmount from tableA
MINUS
select yName , yAmount from tableB
I've got two SQL2008 tables, one is a "Import" table containing new data and the other a "Destination" table with the live data. Both tables are similar but not identical (there's more columns in the Destination table updated by a CRM system), but both tables have three "phone number" fields - Tel1, Tel2 and Tel3. I need to remove all records from the Import table where any of the phone numbers already exist in the destination table.
I've tried knocking together a simple query (just a SELECT to test with just now):
select t2.account_id
from ImportData t2, Destination t1
where
(t2.Tel1!='' AND (t2.Tel1 IN (t1.Tel1,t1.Tel2,t1.Tel3)))
or
(t2.Tel2!='' AND (t2.Tel2 IN (t1.Tel1,t1.Tel2,t1.Tel3)))
or
(t2.Tel3!='' AND (t2.Tel3 IN (t1.Tel1,t1.Tel2,t1.Tel3)))
... but I'm aware this is almost certainly Not The Way To Do Things, especially as it's very slow. Can anyone point me in the right direction?
this query requires a little more that this information. If You want to write it in the efficient way we need to know whether there is more duplicates each load or more new records. I assume that account_id is the primary key and has a clustered index.
I would use the temporary table approach that is create a normalized table #r with an index on phone_no and account_id like
SELECT Phone, Account into #tmp
FROM
(SELECT account_id, tel1, tel2, tel3
FROM destination) p
UNPIVOT
(Phone FOR Account IN
(Tel1, tel2, tel3)
)AS unpvt;
create unclustered index on this table with the first column on the phone number and the second part the account number. You can't escape one full table scan so I assume You can scan the import(probably smaller). then just join with this table and use the not exists qualifier as explained. Then of course drop the table after the processing
luke
I am not sure on the perforamance of this query, but since I made the effort of writing it I will post it anyway...
;with aaa(tel)
as
(
select Tel1
from Destination
union
select Tel2
from Destination
union
select Tel3
from Destination
)
,bbb(tel, id)
as
(
select Tel1, account_id
from ImportData
union
select Tel2, account_id
from ImportData
union
select Tel3, account_id
from ImportData
)
select distinct b.id
from bbb b
where b.tel in
(
select a.tel
from aaa a
intersect
select b2.tel
from bbb b2
)
Exists will short-circuit the query and not do a full traversal of the table like a join. You could refactor the where clause as well, if this still doesn't perform the way you want.
SELECT *
FROM ImportData t2
WHERE NOT EXISTS (
select 1
from Destination t1
where (t2.Tel1!='' AND (t2.Tel1 IN (t1.Tel1,t1.Tel2,t1.Tel3)))
or
(t2.Tel2!='' AND (t2.Tel2 IN (t1.Tel1,t1.Tel2,t1.Tel3)))
or
(t2.Tel3!='' AND (t2.Tel3 IN (t1.Tel1,t1.Tel2,t1.Tel3)))
)
I'm working with a Sybase 12.5 server and I have a table defined as such:
CREATE TABLE SomeTable(
[GroupID] [int] NOT NULL,
[DateStamp] [datetime] NOT NULL,
[SomeName] varchar(100),
PRIMARY KEY CLUSTERED (GroupID,DateStamp)
)
I want to be able to list, per [GroupID], only the latest X records by [DateStamp]. The kicker is X > 1, so plain old MAX() won't cut it. I'm assuming there's a wonderfully nasty way to do this with cursors and what-not, but I'm wondering if there is a simpler way without that stuff.
I know I'm missing something blatantly obvious and I'm gonna kick myself for not getting it, but .... I'm not getting it. Please help.
Is there a way to find TOP X records, but with grouped data?
According to the online manual, Sybase 12.5 supports WINDOW functions and ROW_NUMBER(), though their syntax differs from standard SQL slightly.
Try something like this:
SELECT SP.*
FROM (
SELECT *, ROW_NUMBER() OVER (windowA ORDER BY [DateStamp] DESC) AS RowNum
FROM SomeTable
WINDOW windowA AS (PARTITION BY [GroupID])
) AS SP
WHERE SP.RowNum <= 3
ORDER BY RowNum DESC;
I don't have an instance of Sybase, so I haven't tested this. I'm just synthesizing this example from the doc.
I made a mistake. The doc I was looking at was Sybase SQL Anywhere 11. It seems that Sybase ASA does not support the WINDOW clause at all, even in the most recent version.
Here's another query that could accomplish the same thing. You can use a self-join to match each row of SomeTable to all rows with the same GroupID and a later DateStamp. If there are three or fewer later rows, then we've got one of the top three.
SELECT s1.[GroupID], s1.[Foo], s1.[Bar], s1.[Baz]
FROM SomeTable s1
LEFT OUTER JOIN SomeTable s2
ON s1.[GroupID] = s2.[GroupID] AND s1.[DateStamp] < s2.[DateStamp]
GROUP BY s1.[GroupID], s1.[Foo], s1.[Bar], s1.[Baz]
HAVING COUNT(*) < 3
ORDER BY s1.[DateStamp] DESC;
Note that you must list the same columns in the SELECT list as you list in the GROUP BY clause. Basically, all columns from s1 that you want this query to return.
Here's quite an unscalable way!
SELECT GroupID, DateStamp, SomeName
FROM SomeTable ST1
WHERE X <
(SELECT COUNT(*)
FROM SomeTable ST2
WHERE ST1.GroupID=ST2.GroupID AND ST2.DateStamp > ST1.DateStamp)
Edit Bill's solution is vastly preferable though.