How do I use an SQLCMD variable to define a table name? - tsql

Question

So, using SSDT on Visual Studio 2013, I can specify a Database name...
create view vSample1 as
select * from [$(RandomDatabase)].dbo.TableName
I can also do this with a four part name
create view vSample2 as
select * from [$(RandomServer)].[$(RandomDatabase)].dbo.TableName
But when I try to do this with the TableName, I get errors...
create view vSample3
select * from [$(RandomServer)].[$(RandomDatabase)].dbo.[$(RandomTable)]
It gives me an error similiar to
Error: SQL71561: View: [vSample3] has an unresolved reference to object [$(RandomServer)].[$(RandomDatabase)].dbo.[$(RandomTable)].
I've been looking at the SQLCMD variables window in the project settings and have verified that the $(RandomTable) variable is defined as TableName, but it still gives me build errors.
Why is this, and how do I fix it?
Thanks

Answer 1

I would use pre/post deployment script to create such view using sp_executesql and dynamic query.
exec sp_executesql N'create view vSample3 as
select * from [$(RandomServer)].[$(RandomDatabase)].dbo.[$(RandomTable)]'

Answer 2

I would use synonyms - create a table which matches the actual table and create a synonym that points to that, then reference the synonym in the view or just reference instead of the view. You need this so you get it to compile and you get the good stuff like references etc.
Then when you deploy to each server just deploy the correct synonym to the correct server.
(Then kick your vendor in the b&DD$ for such an annoying system)