This is very similar to Cognos Calculate Variance Crosstab (Relational), but my data source is dimensional.
I have a simple crosstab such as this:
| 04-13-2013 | 04-13-2014
---------------------------------------
Sold | 75 | 50
Purchased | 10 | 15
Repaired | 33 | 44
Filter: The user selects 1 date and then we include that date plus 1 year ago.
Dimension: The date is the day level in a YQMD Hierarchy.
Measures: We are showing various measures from a Measure Dimension.
Sold
Purchased
Repaired
Here is what is looks like in report studio:
| <#Day#> | <#Day#>
---------------------------------------
<#Sold#> | <#1234#> | <#1234#>
<#Purchased#> | <#1234#> | <#1234#>
<#Repaired#> | <#1234#> | <#1234#>
I want to be able to calculate the variance as a percentage between the two time periods for each measure like this.
| 04-13-2013 | 04-13-2014 | Var. %
-----------------------------------------------
Sold | 75 | 50 | -33%
Purchased | 10 | 15 | 50%
Repaired | 33 | 44 | 33%
I added a Query Expression to the right of the <#Day#> as shown below, but I cannot get the variance calculation to work.
| <#Day#> | <#Variance#>
---------------------------------------
<#Sold#> | <#1234#> | <#1234#>
<#Purchased#> | <#1234#> | <#1234#>
<#Repaired#> | <#1234#> | <#1234#>
These are the expressions I've tried and the results that I get:
An expression that is hard coded works, but only for that 1 measure:
total(case when [date] = 2014-04-13 then [Sold] end)
/
total(case when [date] = 2013-04-13 then [Sold] end)
-1
I thought CurrentMember and PrevMember might work, but it produces blank cells:
CurrentMember( [YQMD Hierarchy] )
/
prevMember(CurrentMember([YQMD Hierarchy]))
-1
I think it is because prevMember produces blank.
prevMember(CurrentMember([YQMD Hierarchy]))
Using only CurrentMember gives a total of both columns:
CurrentMember([YQMD Hierarchy])
What expression can I use to take advantage of my dimensional model and add a column with % variance?
These are the pages I used for research:
Variance reporting in Report Studio on Cognos 8.4?
Calculations that span dimensions - PDF
IBM Cognos 10 Report Studio: Creating Consumer-Friendly Reports
I hope there is a better way to do this. I finally found a resource that describes one approach to this problem. Using the tail and head functions, we can get to the first and last periods, and thereby calculate the % variance.
item(tail(members([Day])),0)
/
item(head(members([Day])),0)
-1
This idea came from IBM Cognos BI – Using Dimensional Functions to Determine Current Period.
Example 2 – Find Current Period by Filtering on Measure Data
If the OLAP or DMR data source has been populated with time periods into the future (e.g. end of year or future years), then the calculation of current period is more complicated. However, it can still be determined by finding the latest period that has data for a given measure.
item(tail(filter(members([sales_and_marketing].[Time].[Time].[Month]),
tuple([Revenue], currentMember([sales_and_marketing].[Time].[Time]))
is not null), 1), 0)
Related
I have this table inside my postgresql database,
item_code | date | price
==============================
aaaaaa.1 |2019/12/08 | 3.04
bbbbbb.b |2019/12/08 | 19.48
261893.c |2019/12/08 | 7.15
aaaaaa.1 |2019/12/17 | 4.15
bbbbbb.2 |2019/12/17 | 20
xxxxxx.5 |2019/03/12 | 3
xxxxxx.5 |2019/03/18 | 4.5
how can i calculate the average per item, per month over the year. so i get the result something like:
item_code | month | price
==============================
aaaaaa.1 | 2019/12 | 3.59
bbbbbb.2 | 2019/12 | 19.74
261893.c | 2019/12 | 7.15
xxxxxx.5 | 2019/03 | 3.75
I have tried to look and apply many alternatives but i am still not get the point, would really appreciate your help because i am new to postgresql.
I don't see how the question relates to a moving average. It seems you just want group by:
select item_code, date_trunc('month', date) as date_month, avg(price) as price
from mytable
group by item_code, date_month
This gives date_month as a date, truncated to the first day of the month - which I find more useful that the format you suggested. But it you do want that:
to_char(date, 'YYYY/MM') as date_month
I will be very grateful for your advice regarding the following issue.
Given:
PostgreSQL database
Initial (basic) query
select day, Value_1, Value_2, Value_3
from table
where day=current_date
which returns a row with following columns
Day | Value_1(int) | Value_2(int) | Value 3 (int)
2019-11-14 | 10 | 10 | 14
It is needed to create a view with this starting information and add a new row every day based on the outcome of initial query executed at 22:00.
The expected outcome tomorrow at 22:01 will be
Day | Value_1 | Value_2 | Value_3
2019-11-14 | 10 | 10 | 14
2019-11-15 | N | M | P
Many thanks in advance for your time and support.
I have a Tableau workbook which has 3 measures m1,m2 and m3.
Those are aggregated by year and summed, so I end up with a table like this:
| | 2017 | 2018 |
----------------------------------------
| m1 | 10 | 20 |
----------------------------------------
----------------------------------------
| m2 | 10 | 20 |
----------------------------------------
----------------------------------------
| m3 | 10 | 20 |
----------------------------------------
However, I have to apply a date filter to variable m3 so that the resulting table will look exactly like the one above, but in the background m3 data is filtered.
I would like to be able to do something like:
if metric == m3 then filter(year)
Does anyone know how to achieve this in Tableau?
Thanks
Use Level of Detail Expressions.
Create a calculated field for m1 and m2 measures, as follows:
{FIXED [Year]: SUM(m1)}
This will make all filters other than Year don't have any effect on this measure.
try this:
if metric == m3 and year=2017
then sales
end
Given a table that has a column of time ranges e.g.:
| <2015-10-02>--<2015-10-24> |
| <2015-10-05>--<2015-10-20> |
....
how can I create a column showing the results of org-evalute-time-range?
If I attempt something like:
#+TBLFM: $2='(org-evaluate-time-range $1)
the 2nd column is populated with
Time difference inserted
in every row.
It would also be nice to generate the same result from two different columns with, say, start date and end date instead of creating one column of time ranges out of those two.
If you have your date range split into 2 columns, a simple subtraction works and returns number of days:
| <2015-10-05> | <2015-10-20> | 15 |
| <2013-10-02 08:30> | <2015-10-24> | 751.64583 |
#+TBLFM: $3=$2-$1
Using org-evaluate-time-range is also possible, and you get a nice formatted output:
| <2015-10-02>--<2015-10-24> | 22 days |
| <2015-10-05>--<2015-10-20> | 15 days |
| <2015-10-22 Thu 21:08>--<2015-08-01> | 82 days 21 hours 8 minutes |
#+TBLFM: $2='(org-evaluate-time-range)
Note that the only optional argument that org-evaluate-time-range accepts is a flag to indicate insertion of the result in the current buffer, which you don't want.
Now, how does this function (without arguments) get the correct time range when evaluated is a complete mystery to me; pure magic(!)
I have several spreadsheets for a SUS-Score usability test.
They have this form:
| Strongly disagree | | | | Strongly agree |
I think, that I would use this system often | x | | | | |
I found the system too complex | |x| | | |
(..) | | | | | x |
(...) | x | | | | |
To calculate the SUS-Score you have 3 rules:
Odd item: Pos - 1
Even item: 5 - Pos
Add Score, multiply by 2.5
So for the first entry (odd item) you have: Pos - 1 = 1 - 1 = 0
Second item (even): 5 - Pos = 5 - 2 = 3
Now I have several of those spreadsheets and want to calculate the SUS-Score automatically. I've changed the x to a 1 and tried to use IF(F5=1,5-1). But I would need an IF-condition for every column: =IF(F5=1;5-1;IF(E5=1;4-1;IF(D5=1;3-1;IF(C5=1;2-1;IF(B5=1;1-1))))), so is there an easier way to calculate the score, based on the position in the table?
I would use a helper table and then SUM() all the cells of the helper table and multiply by 2.5. This formula (modified as needed, see notes below) can start your helper table and be copy-pasted to fill out the entire table:
=IF(D2="x";IF(MOD(ROW();2)=1;5-D$1;D$1-1);"")
Here D is an answer column
Depending on what row (odd/even) your answers start you may need to change the =1 after the MOD function to =0
This assumes the position number is in row 1; if position numbers are in a different row change the number after the $ appropriately