Given a table that has a column of time ranges e.g.:
| <2015-10-02>--<2015-10-24> |
| <2015-10-05>--<2015-10-20> |
....
how can I create a column showing the results of org-evalute-time-range?
If I attempt something like:
#+TBLFM: $2='(org-evaluate-time-range $1)
the 2nd column is populated with
Time difference inserted
in every row.
It would also be nice to generate the same result from two different columns with, say, start date and end date instead of creating one column of time ranges out of those two.
If you have your date range split into 2 columns, a simple subtraction works and returns number of days:
| <2015-10-05> | <2015-10-20> | 15 |
| <2013-10-02 08:30> | <2015-10-24> | 751.64583 |
#+TBLFM: $3=$2-$1
Using org-evaluate-time-range is also possible, and you get a nice formatted output:
| <2015-10-02>--<2015-10-24> | 22 days |
| <2015-10-05>--<2015-10-20> | 15 days |
| <2015-10-22 Thu 21:08>--<2015-08-01> | 82 days 21 hours 8 minutes |
#+TBLFM: $2='(org-evaluate-time-range)
Note that the only optional argument that org-evaluate-time-range accepts is a flag to indicate insertion of the result in the current buffer, which you don't want.
Now, how does this function (without arguments) get the correct time range when evaluated is a complete mystery to me; pure magic(!)
Related
I'm trying to create a google form in which i have to ask consumption data for each month in a certain period. So I'd like to format the output file like so: the rows will be 12 (Jan, Feb, Mar, Apr, etc...) and the columns 3 (F1, F2, F3). And I want to populate these 12x3 fields for every submission.
Now, Google form saves each submission in one row: I'd have 12x3 columns this way. I'd like to know if there's a way to arrange the entry data in a table (12x3) instead of 12x3 columns.
So the result would be:
| name | months | F1 | F2 | F3 |
|:---- |:------:| -----:|-----: |-----: |
|example|Jan|50|50|20|
| example | Feb | 60 |30|10|
| example | Mar | 50 |90|70|
| ... | ... | ... |...|...|
And the last row would be: example; Dec; number1, number2, number3
Thanks in advance
I have a column that contains a Month-Year string that I would like to convert to an actual date representing the first day of the Month and Year combination. For example
+----------+------------+
| Original | Desired |
+----------+------------+
| Aug-19 | 08/01/2019 |
+----------+------------+
| Sep-20 | 09/01/2020 |
+----------+------------+
| May-22 | 05/01/2022 |
+----------+------------+
I have tried breaking apart the Month-Year string using split_part but when I try and pass Month as a parameter into date_parse it throws an error with the input (INVALID_FUNCTION_ARGUMENT). I could break apart the Month-Year into strings and then recombine, hard-coding the 01 however the problem seems that three letter month cannot be parsed into an actual month by Presto. I also want to avoid a 12 line CASE WHEN statement to parse the month if possible.
I'm not sure where the year comes from, but the query will be like this:
select date_format(date_parse('May-22', '%b-%d'), '%m/%d/%Y')
https://trino.io/docs/current/functions/datetime.html?mysql-date-functions
I will be very grateful for your advice regarding the following issue.
Given:
PostgreSQL database
Initial (basic) query
select day, Value_1, Value_2, Value_3
from table
where day=current_date
which returns a row with following columns
Day | Value_1(int) | Value_2(int) | Value 3 (int)
2019-11-14 | 10 | 10 | 14
It is needed to create a view with this starting information and add a new row every day based on the outcome of initial query executed at 22:00.
The expected outcome tomorrow at 22:01 will be
Day | Value_1 | Value_2 | Value_3
2019-11-14 | 10 | 10 | 14
2019-11-15 | N | M | P
Many thanks in advance for your time and support.
I have strings that look like this:
schedulestart | event_labels
2018-04-04 | 9=TTR&11=DNV&14=SWW&26=DNV&2=QQQ&43=FTW
When I look at it in the database. I have code that relies in this string in this format to display a schedule with events with those labels on those days.
Now I find myself needing to break down the string in postgres for reporting/analysis, and I can't really pull out the string and parse it in another language, so I have to stick to postgres.
I've figured out a way to unpack the string so my results look like this:
User ID | Schedule Start | Unpacked String
2 | 2018-04-04 | TTR
2 | 2018-04-04 | 9
2 | 2018-04-04 | DNV
2 | 2018-04-04 | 11
2 | 2018-04-04 | SWW
2 | 2018-04-04 | 14
2 | 2018-04-04 | DNV
2 | 2018-04-04 | 26
select schedulestart, unnest(string_to_array(unnest(string_to_array(event_labels, '&')), '=')) from table;
Now what I need is a way to actually perform an interval calculation (so 2018-04-04+11 days::interval), and I can if I only get a numbers list, but I need to also bind that result to each string. So the goal is an output like this:
eventdate | event_label
2018-04-12 | TTR
2018-04-20 | DNV
Where eventdate is the schedule start + which day of the schedule the event is on. I'm not sure how to take the unpacked string I created and use it to perform date calculations, and tie it to the string.
I've considered doing only one unnest, so that it's 11=TTR and 14=DNV, but I'm not sure how to take that to my desired result either. Is there a way to read a string until you reach a certain character, and then use that in calculations, and then read every character past a certain character in a string into a new column?
I'm aware completely rewriting how this is handled would be ideal, but I did not initially write it, and I don't have the time or means to rewrite the ~20 locations this is used.
Here is your table (I added userid column):
CREATE TABLE test(userid INTEGER, schedulestart DATE, event_labels VARCHAR);
And input data:
INSERT INTO test(userid,schedulestart , event_labels) VALUES
(2,DATE '2018-04-04', '9=TTR&11=DNV&14=SWW&26=DNV&2=QQQ&43=FTW');
And finally the solution:
SELECT
userid,
(schedulestart + (SPLIT_PART(kv,'=',1)||' days')::INTERVAL)::DATE AS eventdate,
SPLIT_PART(kv,'=',2) AS event_label
FROM (
SELECT
userid,schedulestart,
REGEXP_SPLIT_TO_TABLE(event_labels, '&') AS kv
FROM test
WHERE userid = 2
) a
This is very similar to Cognos Calculate Variance Crosstab (Relational), but my data source is dimensional.
I have a simple crosstab such as this:
| 04-13-2013 | 04-13-2014
---------------------------------------
Sold | 75 | 50
Purchased | 10 | 15
Repaired | 33 | 44
Filter: The user selects 1 date and then we include that date plus 1 year ago.
Dimension: The date is the day level in a YQMD Hierarchy.
Measures: We are showing various measures from a Measure Dimension.
Sold
Purchased
Repaired
Here is what is looks like in report studio:
| <#Day#> | <#Day#>
---------------------------------------
<#Sold#> | <#1234#> | <#1234#>
<#Purchased#> | <#1234#> | <#1234#>
<#Repaired#> | <#1234#> | <#1234#>
I want to be able to calculate the variance as a percentage between the two time periods for each measure like this.
| 04-13-2013 | 04-13-2014 | Var. %
-----------------------------------------------
Sold | 75 | 50 | -33%
Purchased | 10 | 15 | 50%
Repaired | 33 | 44 | 33%
I added a Query Expression to the right of the <#Day#> as shown below, but I cannot get the variance calculation to work.
| <#Day#> | <#Variance#>
---------------------------------------
<#Sold#> | <#1234#> | <#1234#>
<#Purchased#> | <#1234#> | <#1234#>
<#Repaired#> | <#1234#> | <#1234#>
These are the expressions I've tried and the results that I get:
An expression that is hard coded works, but only for that 1 measure:
total(case when [date] = 2014-04-13 then [Sold] end)
/
total(case when [date] = 2013-04-13 then [Sold] end)
-1
I thought CurrentMember and PrevMember might work, but it produces blank cells:
CurrentMember( [YQMD Hierarchy] )
/
prevMember(CurrentMember([YQMD Hierarchy]))
-1
I think it is because prevMember produces blank.
prevMember(CurrentMember([YQMD Hierarchy]))
Using only CurrentMember gives a total of both columns:
CurrentMember([YQMD Hierarchy])
What expression can I use to take advantage of my dimensional model and add a column with % variance?
These are the pages I used for research:
Variance reporting in Report Studio on Cognos 8.4?
Calculations that span dimensions - PDF
IBM Cognos 10 Report Studio: Creating Consumer-Friendly Reports
I hope there is a better way to do this. I finally found a resource that describes one approach to this problem. Using the tail and head functions, we can get to the first and last periods, and thereby calculate the % variance.
item(tail(members([Day])),0)
/
item(head(members([Day])),0)
-1
This idea came from IBM Cognos BI – Using Dimensional Functions to Determine Current Period.
Example 2 – Find Current Period by Filtering on Measure Data
If the OLAP or DMR data source has been populated with time periods into the future (e.g. end of year or future years), then the calculation of current period is more complicated. However, it can still be determined by finding the latest period that has data for a given measure.
item(tail(filter(members([sales_and_marketing].[Time].[Time].[Month]),
tuple([Revenue], currentMember([sales_and_marketing].[Time].[Time]))
is not null), 1), 0)