I am on OS/X yosemite. I have performed similar searches like the following many times: uncertain why it would not work here.
The search is:
$find . -name \*assembly\*.jar
It returns nothing.
Now, what should it return? Well let us remove the extension and re-run the search:
$find . -name \*assembly\*
Well that returns a number of items - including the first one .. ends with .jar !
./mllib-tests/target/mllib-perf-tests-assembly.jar
./mllib-tests/target/streams/$global/assembly
./mllib-tests/target/streams/$global/assembly/$global/streams/assembly-inputs
./mllib-tests/target/streams/$global/assembly/$global/streams/assembly-outputs
./mllib-tests/target/streams/$global/assemblyOption
./mllib-tests/target/streams/$global/assemblyOption/$global/streams/assembly
./spark-tests/target/spark-perf-tests-assembly.jar
./spark-tests/target/streams/$global/assembly
./spark-tests/target/streams/$global/assembly/$global/streams/assembly-inputs
./spark-tests/target/streams/$global/assembly/$global/streams/assembly-outputs
./spark-tests/target/streams/$global/assemblyOption
./spark-tests/target/streams/$global/assemblyOption/$global/streams/assembly
So .. why is the first search failing?
OK discovered the answer. The
\*
wildcard is not a zero or more characters match. It is apparently a one or more characters match.
The following does work
$find . -name \*assembl\*.jar
./mllib-tests/target/mllib-perf-tests-assembly.jar
./spark-tests/target/spark-perf-tests-assembly.jar
Related
I am confused regarding variables.
I have code, where I have the following line:
$search = $Name.SelectedItem.Split('-')[$($Name.SelectedItem.Split('-').Count-1)]+'*'
This line does nothing else, as split up a selected item (I am working with a Dropdownbox) and transfers it to $search.
The funny thing is, it does exactly that, what I want it to do.
When I type $search, the result can be for example:
Rue de Rivoli*
When I continue in the code and use $search through several arrays, for some reason, it does not function, because it does not find anything in a foreach loop. I have no error message and even the Rue de Rivoli* existing in one of the arrays, it does not find anything.
When I replace the above code and give directly the name to the variable $search, as seen below
$search = 'Rue de Rivoli*'
my search in the array works.
What am I missing here? I am doing something wrong, but I do not know what it is, can someone help me please to understand?
Thank you very much,
Mike
As requested, here more of the code. It is a lot to deal with, that is why I shorten it.
Clear-Host
$search = $CreateNewUserFormDropDownBoxLocation.SelectedItem.Split('-')[$($CreateNewUserFormDropDownBoxLocation.SelectedItem.Split('-').Count-1)]+'*'
#$search = 'Rue de Rivoli*'
$AllLocations = (get-variable -Include USPennsylvaniaAve, USSixthStreet, USRodeoDrive, USOneMicrosoftWay,`
USNorthTantauAvenue, USMarketStreet, USMainStreet, USEmilyDrive,`
USCalle8, USBroadway, US18thStreetNW, UKOxfordStreet, UKDowningStreet,`
UKBondStreet, FRRuedeRivoli, FRChampsElysees, CHBahnhofstrasse,`
CA17thAvenue) | ? {$_.value -is [array]}
Foreach ($Array in $AllLocations)
{
if ($array.value -like $search)
{break}
}
$result = "`$$($array.name)"
$result
This is about to become a function and does nothing else, as from the selecteditem, it takes it apart and add's the * behind it, so I can search
for a name with a wildcard.
I have several arrays and therefore I included only the necessary ones. Next step is to loop through the arrays and as soon as it found the item, it stops and gives the result to result.
This is my test code and it runs and does what I want, besides the line after Clear-Host. The code is correctly resolved and added to $search but does not work.
Below that code of line, I have my cheat line, where I add directly the correct result to the variable and it works fine.
As commented, this should solve the problem.
(I'm adding this as answer too, so the OP can accept it. Otherwise this question will remain seemingly unsolved)
When hardcoding the search string $search = 'Rue de Rivoli*' works, but using a Split() to get the search string does not, then usually the string you obtain using the split is surrounded by whitespace characters. If you leave these in, the string will appear to look just fine, but when using as comparison it won't work.
If for instance the complete $CreateNewUserFormDropDownBoxLocation.SelectedItem string is:
"François Exemple - Rue de Rivoli"
Then, using $CreateNewUserFormDropDownBoxLocation.SelectedItem.Split("-")[-1] will return:
" Rue de Rivoli"
Note the space in front.
By simply performing a Trim() you will get rid of that space.
The line therefore should be:
$search = ($CreateNewUserFormDropDownBoxLocation.SelectedItem.Split('-')[-1]).Trim() + '*'
I have tried lots of variants of find and I can't seem to figure out which one to use to find files with names like
product (1).php
Parentheses have no special meaning in the filename matching pattern used by find, so you can just use:
find name_of_folder -type f -name '*(1)*'
Use quotes as usual to protect the asterisks from being expanded by the shell.
How do I take a substring where I don't know the length of the thing I want, but I know that the end of it is a CR/LF?
I'm communicating with a server trying to extract some information. The start point of the substring is well defined, but the end point can be variable. In other scripting languages, I'd expect there to be a find() command, but I haven't found one in PowerShell yet. Most articles and SE questions refer to Get-Content, substring, and Select-String, with the intent to replace a CRLF rather than just find it.
The device I am communicating with has a telnet-like command structure. It starts out with it's model as a prompt. You can give it commands and it responds. I'm trying to grab the hostname from it. This is what a prompt, command, and response look like in a terminal:
TSS-752>hostname
Host Name: ThisIsMyHostname
TSS-752>
I want to extract the hostname. I came across IndexOf(), which seems to work like the find command I am looking for. ":" is a good start point, and then I want to truncate it to the next CRLF.
NOTE: I have made my code work to my satisfaction, but in the interest of not receiving anymore downvotes (3 at the time of this writing) or getting banned again, I will not post the solution, nor delete the question. Those are taboo here. Taking into account the requests for more info from the comments has only earned me downvotes, so I think I'm just stuck in the SO-Catch-22.
You could probably have found the first 20 examples in c# outlining this exact same approach, but here goes with PowerShell examples
If you want to find the index at which CR/LF occurs, use String.IndexOf():
PS C:\> " `r`n".IndexOf("`r`n")
2
Use it to calculate the length parameter argument for String.Substring():
$String = " This phrase starts at index 4 ends at some point`r`nand then there's more"
# Define the start index
$Offset = 4
# Find the index of the end marker
$CRLFIndex = $string.IndexOf("`r`n")
# Check that the end marker was actually found
if($CRLFIndex -eq -1){
throw "CRLF not found in string"
}
# Calculate length based on end marker index - start index
$Length = $CRLFIndex - $Offset
# Generate substring
$Substring = $String.Substring($Offset,$Length)
I have this path ../../Capture.jpg. So far I've figured out this incomplete regex: '[../]+'. I want to check if user puts in the right path like ../../image file name. The file extensions can be jpg, png, ..
your [../]+ is not sufficient or correct for the job at hand, if you REALLY want to match a bunch of ../ at the start of a filename.
It's not completely clear what you want to do exactly, but the following will match one or more ../ at the start of a string:
/^((?:\.\.\/)+)/
basically:
^ to anchor to the start of the string being tested - will not match any ../ INSIDE the string
( and the balancing ) at the end: capture the contents within. All your ../../ will be available in a variable called $1
then I'm using (?: ) to wrap the next content. This groups the bit inside, but does NOT save the value inside a $1, $2, etc. More information soon...
The REAL pattern of interest is
\.\.\/
Since . and / are magic characters, they need 'escaping' with backslash. This tells Perl that the . and / do NOT have a special meaning at this point.
I've used the (?: ) wrapper to group them together, so that the + operates on all 3 characters of interest. The + operator means "one or more repetitions".
So, my pattern will match one or more repetitions of ../ which are anchored to the start of the string. Furthermore, the exact contents matched will be available in $1 if you are interested in doing something with that (eg count how many ../ you have)
Please ask if you have further questions, or I have misunderstood your goals.
EDIT: to suit your new requirements, and add a bit of bonus:
m!^\.\./\.\./(([^/]+)\.([^.]+))$!
Note first that I've used m!pattern! instead of /pattern/. Firstly, if Perl sees /pattern/ it assumes it's m/pattern/ but you can use an alternative character to wrap the patterns. This is useful if you actually want to use / in your pattern without having to go nuts with backslashes.
so:
^ exactly match only from the start
followed by exactly ../../
next I've used ( ) wrappers to capture the bits following. Explanation after...
ignoring the ( and ) now:
[^/]+ one or more repetitions (+) of any character that isn't /
. literally a dot - the one before the extension
[^./]+ one or more repetitions of any character that isn't . or /
Notice how the [^/]+ allows for any character including . but prevents another directory part from sneaking in. Thus, the filename could be foo.bar.jpg and it will be collected properly.
Notice how [^./]+ allows for any character in the extension except a dot - and also excluding / to prevent another directory segment from sneaking in.
Finally, $ is used to ensure we've reached the end of the pattern.
as for the captures:
$1 will contain all of foo.bar.jpg
$2 will contain foo.bar
$3 will contain jpg (not .jpg) but I'll leave it up to you to figure out what to change if you wish to capture the dot as well.
FINALLY - in a typical script, you might do something like:
if($filename =~ m!^\.\./\.\./(([^/]+)\.([^./]+))$!) {
print "You correctly entered ../../$1 giving basename=$2 and extension=$3 - Bravo!\n";
}
else {
print "you've failed to read the instructions properly\n";
}
As a bonus, I even tested that, and found 2 spolling mistaiks you'll never have to see
cheers.
# convert relative file paths to md links ...
# file paths and names with letters , nums - and _ s supported
$str =~ s! (\.\.\/([a-zA-Z0-9_\-\/\\]*)[\/\\]([a-zA-Z0-9_\-]*)\.([a-zA-Z0-9]*)) ! [$3]($1) !gm
If you don't care the path prefix, use:
$path =~ /\.(jpg|png)$/
or
substr($path, -4) ~~ ['.jpg', '.png']
With exactly '../../', use:
$path =~ m!^\.\./\.\./[^/]*\.(jpg|png)$!
With any number of '../'s, use:
$path =~ m!^(\.\./)*[^/]*\.(jpg|png)$!
Powershell question.
I need a command that will do a find and replace for ^ ^ (2 spaces between the hats) and replace it with ^^ (no space between the hats).
Sample data:
123456^100.00^10/14/2013^ ^^Columbus^
Want the result to be:
123456^100.00^10/14/2013^^^Columbus^
I would also like this command to perform this find and replace across all files in a given directory, say C:\SampleDirectory*.*
Any help you guys can provide would be greatly appreciated.
$string = "12456^100.00^10142013^ ^^Columbus"
$string -replace "\^\s\s\^\^","^^^"
To do it across all files just do a get-childitem and a foreach loop... Although I can't figure out how you would get a file name with slashes in it.
http://blogs.technet.com/b/heyscriptingguy/archive/2011/03/21/use-powershell-to-replace-text-in-strings.aspx