Powershell question.
I need a command that will do a find and replace for ^ ^ (2 spaces between the hats) and replace it with ^^ (no space between the hats).
Sample data:
123456^100.00^10/14/2013^ ^^Columbus^
Want the result to be:
123456^100.00^10/14/2013^^^Columbus^
I would also like this command to perform this find and replace across all files in a given directory, say C:\SampleDirectory*.*
Any help you guys can provide would be greatly appreciated.
$string = "12456^100.00^10142013^ ^^Columbus"
$string -replace "\^\s\s\^\^","^^^"
To do it across all files just do a get-childitem and a foreach loop... Although I can't figure out how you would get a file name with slashes in it.
http://blogs.technet.com/b/heyscriptingguy/archive/2011/03/21/use-powershell-to-replace-text-in-strings.aspx
Related
Question about running a custom function in Powershell.
I'm on Windows 10 and I'd like to somehow print my monorepository's directory tree structure excluding node_modules. This is not supported out of the box but requires a custom function to be defined. I found one solution on StackOverflow (https://stackoverflow.com/a/43810460/9654273), which would enable using a command like:
tree -Exclude node_modules -Ascii > tree.txt
The problem is I don't know what to do with the provided source code :D The answer says "add to your $PROFILE, for instance", so I ran notepad $PROFILE in PowerShell, pasted the code snippet there, saved it and tried running the command. It didn't work because I did something wrong. According to the StackOverflow post's comments from anand_v.singh and mklement0 I was still running some other tree command, not the one I just attempted to define.
So how do I use a custom function in PowerShell? Starting point is that source code is on StackOverflow and I don't know where to paste it. Or do you know some other, easier way to print a directory tree on Windows 10 excluding node_modules?
I had the same problem with that function. The issue is the special characters in the hashtable at line 106:
$chars = #{
interior = ('├', '+')[$ndx]
last = ('└', '\')[$ndx] #'
hline = ('─', '-')[$ndx]
vline = ('│', '|')[$ndx]
space = ' '
}
I changed the special characters to ascii as follows:
$chars = #{
interior = ('+', '+')[$ndx]
last = ('\', '\')[$ndx] #'
hline = ('-', '-')[$ndx]
vline = ('|', '|')[$ndx]
space = ' '
}
The only downside is that you do not now have the option of using special graphics characters (the Ascii switch is still there, but does nothing). Maybe someone could tell us how to embed them properly.
I have a file that needs to have the first two characters of each line replaced. It seems easy but those same first two characters "|0" showup elsewhere in the file. So I've ended up having the replacement strings "$bp" all over the place. Any way to just replace the first instance of "|0" for each line only? Here is the sample data:
0|Corrupt Record|0|0|0|0|0|0|0|0|0
Your question is unclear (|0 vs 0|).
You can use this snippet to replace the 2 first characters of each line if they are 0|:
$oldContent = Get-Content "my/file"
$newContent = $OldContent | ForEach-Object { $_ -replace "^0\|","newstring" }
# simpler
#$newContent = $OldContent -replace "^0\|","newstring"
$newContent | Set-Content "my/file"
I'm sure there are other ways to do this, but here is how my approach would be.
To replace just the first occurrence of "0|" and have the remaining stay you can replace it like so.
$CorruptString = "0|Corrupt Record|0|0|0|0|0|0|0|0|0"
[regex]$ToReplace = "0\|"
$ToReplace.replace($CorruptString, "", 1)
This will Output:
Corrupt Record|0|0|0|0|0|0|0|0|0
Just a simple regex to replace the corrupt string and replace it with either nothing or whatever you wanted to replace it with. Naturally the 1 is so it only does it one time.
I believe that is what you were looking for. If not try to explain more.
EDIT: because there was some confusion with the post. To replace the first two characters in a string you can just do substring to remove the first two.
"0|Corrupt Record|0|0|0|0|0|0|0|0|0".Substring(2)
I've got a bunch of directory names and file names, some are absolute path, some are relative path. I just wish to get the 2 leading parts of each path. Input:
D:\a\b\c\d.txt\
c:\a
\my\desk\n.txt
you\their\mine
I expect to get:
D:\a
c:\a
\my\desk
you\their
Is there a convenient way in PowerShell to achieve this?
You can sometimes get your hand slapped for suggesting string manipulation as it can sometimes be "unreliable". However your test data contains 3 different possibilities. Also, never seen someone looking for the first parts from a path.
I present a simple solution the nets your desired output as you have it in your question
"D:\a\b\c\d.txt\","c:\a","\my\desk\n.txt","you\their\mine" | ForEach-Object{
($_ -split "(?<=\S)\\")[0..1] -join "\"
}
I needed to use a lookbehind since your sample output contains a leading a leading slash that you wanted to retain. It splits every string on slashes that have a non white-space character in front of them.
This would not return the correct path for UNC's. Split-Path would be the obvious choice if you only wanted a single portion of the path. I suppose you could nest the call to get 2 but at this time I am unable to find a simple way to account for all of your examples with the same logic.
I am using PowerShell and I need replace a line in a .txt file.
The .txt file always has different number at the end of the line.
For example:
...............................txt (first)....................................
appversion= 10.10.1
............................txt (a second time)................................
appversion= 10.10.2
...............................txt (third)...................................
appversion= 10.10.5
I need to replace appversion + number behind it (the number is always different). I have set the required value in variable.
How do I do this?
Part of this issue you are getting, which I see from your comments, is that you are trying to replace text in a file and saved it back to the same file while you are still reading it.
I will try to show a similar solution while addressing this. Again we are going to use -replaces functionality as an array operator.
$NewVersion = "Awesome"
$filecontent = Get-Content C:\temp\file.txt
$filecontent -replace '(^appversion=.*\.).*',"`$1$NewVersion" | Set-Content C:\temp\file.txt
This regex will match lines starting with "appversion=" and everything up until the last period. Since we are storing the text in memory we can write it back to the same file. Change $NewVersion to a number ... unless that is your versioning structure.
Not sure about what numbers you are keeping
About which part of the numbers, if any, you are trying to preserve. If you intend to change the whole number then you can just .*\. to a space. That way you ignore everything after the equal sign.
Yes, you can with regex.
Let call $myString and $verNumber the variables with text and version number
$myString = "appversion= 10.10.1";
$verNumber = 7;
You can use -replace operator to get the version part and replace only last subversion number this way
$mystring -replace 'appversion= (\d+).(\d+).(\d+)', "appversion= `$1.`$2.$verNumber";
I am parsing a JBOSS log file using powershell.
A typical line would being like this :
2011-12-08 09:01:07,636 ERROR [org.apache.catalina.core.ContainerBase.[jboss.web].etc..
I want to remove all the characters from character 1 until the word ERROR. So I want to remove the date and time, the coma and the number right after it. I want my lines to begin with the word ERROR and delete everything before that.
I looked on google and tried different things I have found but I struggle and can't make it work. I tried with substring and replace but can't find how to delete all characters until the word ERROR.
Any help would be greatly appreciated,
Thanks a lot!
This one-liner will read the contents of your file (in the example jboss.txt) and replace every line containing ERROR by ERROR + whatever follows on that line. Finally it will save the result in processed_jboss.txt
get-content jboss.txt | foreach-object {$_ -replace "^.*?(ERROR.*)",'$1'} | out-file processed_jboss.txt
Assuming the log line is in a variable of type string this should do it:
$line = "2011-12-08 09:01:07,636 ERROR [org.apache.catalina.core.ContainerBase.[jboss.web].etc.."
$ErrorIndex = $line.indexof("Error",0)
$CleanLogLine = $Line.Substring($ErrorIndex, $line.length)
Reference:
http://msdn.microsoft.com/en-us/library/system.string.aspx