I'm typing up a table with org mode, where the equal sign(=) if the first character in the cell and it want to start a formula. how do I get it to display the symbol without it being a formula, of a way to use formulas to display it. I get errors when I use single quotes, and I see the Unicode decimal value when using double quotes.
I have tried the following
='=+'
="=+"
they give
#ERROR
[61, 43]
Use an escaped entity, \equal{} and it should display as you wish. See the variable org-entities for others you can use.
I'm a bit late :D
There may be a better way, but you can try with :='(format "=+")
Source: https://emacs.stackexchange.com/questions/19183/can-i-use-formula-to-manipulate-text-in-org-mode-table
When I ran into this problem just now, I found that I was able to get around it by replacing the equals sign with some other similar-looking character. Two which come to mind are ꞊ ‘U+A78A MODIFIER LETTER SHORT EQUALS SIGN’ and ⹀ ‘U+2E40 DOUBLE HYPHEN’.
Related
As stated in the title, I have two tables I'm attempting to link. Both Strings appear to be a match, however Crystal Reports is not picking it up. The only thing I can think is that that length of the field is different, even though the strings are the same. could that cause a discrepancy? If so how can I correct for it? Thank you
Length of the string will prevent a match. If you are using the Trim(string) function, that only removes spaces found at the beginning or end of your string, so the two strings could still be of different lengths after using this function. You will need to use another function to capture a substring of the original string. To do this you can use the Left(string, length) function to ensure both strings are the same length.
If they still do not match then you may have non-printable characters in one or both of your strings. Carriage Return and Line Feed tend to be the most commonly found non-printable characters. A Carriage Return is represented as Chr(10), while a Line Feed is represented as Chr(13). These are Built In Constants similar to those found in VBA and Visual Basic.
You can use a find and replace to remove them with the following formula. Its not a bad idea to also include the trim and left functions in this as well to ensure you get the best match possible.
Replace(Replace(Left(Trim({YourStringField}), 10),Chr(10), ""),Chr(13), "")
There are a few additional Built In Constants you may need to check for if this doesn't work. A Tab is represented as Chr(9) for example. Its very rare for strings to contain the other Built In Constants though. In most cases Carriage Return and Line Feed are the only ones that are typically found in Plain Text. Tabs and the other constants should only be found in Rich Text and are very rare in string data.
Is there an unicode symbol for "n/a"? There are some fractions like ½, but a n/a symbol seems to be missing.
If there is none, what would be the most appropriate unicode symbol to use for n/a in a website (which should be contained in common fonts, to avoid needing a webfont)?
Looking at the Unicode code charts, I do not see a single N/A symbol. I do, however, see ⁿ (U+207F) and ₐ (U+2090), which you could separate with / (U+002F) eg: ⁿ/ₐ, or ̷ (U+0337), eg: ⁿ̷ₐ, or ̸ (U+0338), eg: ⁿ̸ₐ. Probably not what you are hoping for, though. And I don't know if "common" fonts implement them, either.
For future reference, the fastest way I know to answer questions like the OP's when I have them myself is to go to unicodelookup.com, because of the way it works: there's a search bar at the top, and you just type a string and it will return any and all unicode characters containing that string (this is also a great way to discover new and useful symbols). So in the OP's case, he could proceed like this:
first try entering "not" (without the quotes) in the search field
visually scan through the results... doing so would not reveal a "not
applicable" character in this case
try again but this time entering "applic" in the search field
again, doing so would not turn up anything along the lines of what he's
looking for
At that point he would be reasonably confident the current Unicode standard does not have a "n/a" symbol.
If you use Firefox you can define a keyword like "uni" to search that site from the URL bar, meaning any time the browser is open and regardless of what page or site is currently showing, you could do this:
hit [F6]... this moves the cursor to the URL bar at the top
type something like "uni applic" and hit [Enter]... this brings up the
unicodelookup.com website with the search results for "applic" already
showing
For the above to work you would need to define your keyword ("uni" or wtv you prefer) to point to location http://unicodelookup.com/#%s.
There's a Negative Acknowlege icon...
␕ symbol for negative acknowledge 022025 9237 0x2415 ␕
Found by searching negative on the Unicode Lookup site.
I'm not a fan, and for my purposes have just gone with __N/A__ (Markdown..)
I see lots of answers going head-on at the "Not Applicable" abbreviation, without exploring what a symbol is. A quick search for the equivalent phrase "out of scope" brings up a couple of variations on the No symbol: ⃠ – this seems to fit the bill (and since I was looking for a way to represent inapplicability, I'll be using it in my technical document).
Per the Wikipedia article, the Unicode codepoint U+20E0 is a combining character, so it is superimposed on the preceding character; e.g. ! ⃠ overlays an exclamation point. To get it to appear isolated, use a non-breaking space
If you don't want to bother with the combining symbol, the article mentions there's also an emoji U+1F6AB 🚫 but it's typically going to be colored red, or won't render!
There's actually a single character that could be repurposed for this: the "Square Na" character ㎁ (U+3381), which is used to represent the nanoampere in fullwidth (CJK) scripts.
What about the "SYMBOL FOR NULL" ␀ (U+2400)?
I really need help with coming up with the pattern matching solution...
If the string is <6>[ 84.982642] Killing the process
How can I extract them into three separate strings...
I need one for 6, 84.982642, and Killing the process..
I've tried many things but these brackets and blank spaces are really confusing me and I keep getting the error message
"WARNING: Use of uninitialized value $bracket in pattern match..."
Is there anyway I can somehow write in this way
($num_1, $num_2, $name_process) = split(/[\-,. :;!?()[\]{}]+/);
Not sure how to extract these..
Help Please?
Thank you so much
Assuming the input is in $_
($num_1, $num_2, $name_process) = /^<(\d+)>\[([^\]]+)\]\s+(.*)$/;
This assumes the first token in the angle brackets is always a number. For a little more generality use
($num_1, $num_2, $name_process) = /^<([^>]+)>\[([^\]]+)\]\s+(.*)$/;
Explanation:
<([^>]+)> - a left-angle-bracket followed one or more characters that are not a right angle-bracket, followed by a right-angle bracket.
\[([^\]]+)\] - a left-bracket followed by one or more characters that are not a right bracket, followed by a right bracket
\s+(.*) - one or more spaces, then capture everything starting with the first non-blank after that.
I have an NSArray of lines (objective-c iphone), and I'm trying to find the line which starts with a number, followed by a dot and a space, but can have any number of spaces (including none) before it, and have any text following it eg:
1. random text
2. text random
3.
what regular expression would I use to get this? (I'm trying to learn it, and I needed the above expression anyway, so I thought I'd use it as an example)
With C#:
#"^ *[0-9]+\. "
It doesn't check for the presence of something after the ., so this is legal:
1.(space)
If you delete the # and escape the \ it should work with other languages (it is pretty "down-to-earth" as RegExpes go)
I may suggest (Perl-compatible regexp):
^\s*\d+\.\s
At the beginning of a line:
Any number (0-n) of spaces
One or more digits
A dot
A space
Something like
^\s*\d+\.
But it depends on the language.
/^\s*[0-9]+\.\s+/
would be my guess providing you don't have any space before the number
I've developed a workaround since crystal reports doesn't seem to have a substring function with the following formula:
right({_v_hardware.groupname},
truncate(instr(replace({_v_hardware.groupname},".",
","), ","))
What I'm trying to do is search for the period (".") in a string and replace it with a comma. Then find the comma position in the string and print all characters following after the comma. This is assuming the string will only have 1 period in the entire string.
Now when I attempt to do this, I get some weird characters which look like wingdings. Any ideas?
thanks in advance.
I don't know the entire issue that you are attempting to accomplish, but for this question alone, the step of replacing the period with a comma seems to be unnecessary. If you know that there is only one period in the string and you only want the characters right of the period then you should be able to do something like the following (this is #first_formula):
right({_v_hardware.groupname}, len({_v_hardware.groupname}) - instr({_v_hardware.groupname},"."))
If for some reason you want to show the comma then I'd do that in a separate formula. If you need the entire screen with the comma replaced then just do:
replace({_v_hardware.groupname},".",",")
And if you need the comma plus included in the string then it might just be easier to do something like:
"," + {#first_formula}
Hope this helps.