i18n, Messages object in every template necessary? Play Scala - scala

I am new to Play and Scala as well. And I meet a problem with i18n while reading book "Play with Scala". The problem was the Messages object, which has to be obtained in every template to let application work properly.
What bothers me is that even if I don't use the Messages object in one of my Scala template files, but I inherit/call another template in it, I still have to add
(implicit messages: Messages) at the top of the file.
Can somebody explain me why is that? Is it necessary to add the Messages object in every template? Its quite problematic and I am sure it can be solved somehow.

This is not a Play Framework specific problem, it is just how implicit parameters work in Scala (see Understanding implicit in Scala).
Take the following function which "magically" adds a number to a list of numbers.
def addMagic[A](numbers: List[Int])(implicit add: Int) = numbers.map(_ + add)
We can use addMagic as follows :
{
implicit val magicNumber = 42
addMagic(List(1, 2, 3))
// List[Int] = List(43, 44, 45)
}
If we use addMagic in another function without passing an implicit Int :
def printMagicNumbers(numbers: List[Int]) = println(addMagic(numbers))
we get the following error:
error: could not find implicit value for parameter add: Int
So we also need to add an implicit parameter to printMagicNumbers :
def printMagicNumbers(numbers: List[Int])(implicit add: Int) =
println(addMagic(numbers))
In the same manner your template function needs an implicit Messages object if it calls a template function which needs the Messages object.

Related

How can I provide a custom header to a ZIO during tests

I have service that returns a ZIO[Has[MyCustomHeader]], and I'm having trouble testing it.
Other services in our organisation are tested by converting ZIO to Twitterfuture using runtime.unsafeRunToFuture (where runtime is a Runtime[ZEnv] ) and then awaiting the future, thus running the tests in blocking mode.
However this service has a Has[] requirement and runtime.unsafeRunToFuture doesnt handle those. So far my approach has been to try to convert my ZIO[Has[MyCustomHeader]] to a ZIO[ZEnv], but I've yet to succeed at this.
from what I gather I need to provide a ZLayer via ZIO.provideSomeLayer() but I'm simply too stupid to understand how to construct a ZLayer properly?
Am I even on the right path here? and if so, How do I construct a ZLayer with a static value for MyCustomHeader to use in my tests?
This is how far along I am at trying to add a header for testing purposes: it doesn't work, but might illustrate what I'm trying to achieve..maybe... I'm pretty confused myself:
object effectAwait {
implicit class ZioEffect[A](private val value: ZIO[Has[EnvironmentHeader], RequestFailure, A]) extends AnyVal {
final def await(implicit runtime: Runtime[ZEnv] = Runtime.default): A = {
val zmanaged = ZManaged.fromEffect(value).provide(Has(EnvironmentHeader("test")))
val layered = value.provideSomeLayer(zmanaged.toLayer)
val sf = runtime.unsafeRunToFuture(layered)
Await.result(sf, 10.seconds)
}
}
}
this however gives me the error:
could not find implicit value for izumi.reflect.Tag[A]. Did you
forget to put on a Tag, TagK or TagKK context bound on one of the
parameters in A? e.g. def x[T: Tag, F[_]: TagK] = ...
<trace>:
deriving Tag for A, dealiased: A:
could not find implicit value for Tag[A]: A is a type parameter without an implicit Tag!
val layered = value.provideSomeLayer(zmanaged.toLayer)
I think you can just use ZIO.provideLayer (instead of provideSomeLayer) here :)
Also, there's a runtime.unsafeRun that will wait for the result as well, so you don't necessarily have to convert it to a Future. Also, also, instead of relying on an implicit runtime, there's always zio.Runtime.default that you can use anywhere (it's a Runtime[ZEnv] so it should work just as well, unless you've otherwise customized the runtime's behavior)

Map an instance using function in Scala

Say I have a local method/function
def withExclamation(string: String) = string + "!"
Is there a way in Scala to transform an instance by supplying this method? Say I want to append an exclamation mark to a string. Something like:
val greeting = "Hello"
val loudGreeting = greeting.applyFunction(withExclamation) //result: "Hello!"
I would like to be able to invoke (local) functions when writing a chain transformation on an instance.
EDIT: Multiple answers show how to program this possibility, so it seems that this feature is not present on an arbitraty class. To me this feature seems incredibly powerful. Consider where in Java I want to execute a number of operations on a String:
appendExclamationMark(" Hello! ".trim().toUpperCase()); //"HELLO!"
The order of operations is not the same as how they read. The last operation, appendExclamationMark is the first word that appears. Currently in Java I would sometimes do:
Function.<String>identity()
.andThen(String::trim)
.andThen(String::toUpperCase)
.andThen(this::appendExclamationMark)
.apply(" Hello "); //"HELLO!"
Which reads better in terms of expressing a chain of operations on an instance, but also contains a lot of noise, and it is not intuitive to have the String instance at the last line. I would want to write:
" Hello "
.applyFunction(String::trim)
.applyFunction(String::toUpperCase)
.applyFunction(this::withExclamation); //"HELLO!"
Obviously the name of the applyFunction function can be anything (shorter please). I thought backwards compatibility was the sole reason Java's Object does not have this.
Is there any technical reason why this was not added on, say, the Any or AnyRef classes?
You can do this with an implicit class which provides a way to extend an existing type with your own methods:
object StringOps {
implicit class RichString(val s: String) extends AnyVal {
def withExclamation: String = s"$s!"
}
def main(args: Array[String]): Unit = {
val m = "hello"
println(m.withExclamation)
}
}
Yields:
hello!
If you want to apply any functions (anonymous, converted from methods, etc.) in this way, you can use a variation on Yuval Itzchakov's answer:
object Combinators {
implicit class Combinators[A](val x: A) {
def applyFunction[B](f: A => B) = f(x)
}
}
A while after asking this question, I noticed that Kotlin has this built in:
inline fun <T, R> T.let(block: (T) -> R): R
Calls the specified function block with this value as its argument and returns
its result.
A lot more, quite useful variations of the above function are provided on all types, like with, also, apply, etc.

Possible to find parameter type methods return type in Scala where parameter is a primitive type?

Suppose I have:
class X
{
val listPrimitive: List[Int] = null
val listX: List[X] = null
}
and I print out the return types of each method in Scala as follows:
classOf[ComplexType].getMethods().foreach { m => println(s"${m.getName}: ${m.getGenericReturnType()}") }
listPrimitive: scala.collection.immutable.List<Object>
listX: scala.collection.immutable.List<X>
So... I can determine that the listX's element type is X, but is there any way to determine via reflection that listPrimitive's element type is actually java.lang.Integer? ...
val list:List[Int] = List[Int](123);
val listErased:List[_] = list;
println(s"${listErased(0).getClass()}") // java.lang.Integer
NB. This seems not to be an issue due to JVM type erasure since I can find the types parameter of List. It looks like the scala compiler throws away this type information IFF the parameter type is java.lang.[numbers] .
UPDATE:
I suspect this type information is available, due to the following experiment. Suppose I define:
class TestX{
def f(x:X):Unit = {
val floats:List[Float] = x.listPrimitive() // type mismatch error
}
}
and X.class is imported via a jar. The full type information must be available in X.class in order that this case correctly fails to compile.
UPDATE2:
Imagine you're writing a scala extension to a Java serialization library. You need to implement a:
def getSerializer(clz:Class[_]):Serializer
function that needs to do different things depending on whether:
clz==List[Int] (or equivalently: List[java.lang.Integer])
clz==List[Float] (or equivalently: List[java.lang.Float])
clz==List[MyClass]
My problem is that I will only ever see:
clz==List[Object]
clz==List[Object]
clz==List[MyClass]
because clz is provided to this function as clz.getMethods()(i).getGenericReturnType().
Starting with clz:Class[_] how can I recover the element type information that was lost?
Its not clear to me that TypeToken will help me because its usages:
typeTag[T]
requires that I provide T (ie. at compile time).
So, one path to a solution... Given some clz:Class[_], can I determine the TypeTokens of its method's return types? Clearly this is possible as this information must be contained (somewhere) in a .class file for a scala compiler to correctly generate type mismatch errors (see above).
At the java bytecode level Ints have to be represented as something else (apparently Object) because a List can only contain objects, not primitives. So that's what java-level reflection can tell you. But the scala type information is, as you infer, present (at the bytecode level it's in an annotation, IIRC), so you should be able to inspect it with scala reflection:
import scala.reflect.runtime.universe._
val list:List[Int] = List[Int](123)
def printTypeOf[A: TypeTag](a: A) = println(typeOf[A])
printTypeOf(list)
Response to update2: you should use scala reflection to obtain a mirror, not the Class[_] object. You can go via the class name if need be:
import scala.reflect.runtime.universe._
val rm = runtimeMirror(getClass.getClassLoader)
val someClass: Class[_] = ...
val scalaMirrorOfClass = rm.staticClass(someClass.getName)
// or possibly rm.reflectClass(someClass) ?
val someObject: Any = ...
val scalaMirrorOfObject = rm.reflectClass(someObject)
I guess if you really only have the class, you could create a classloader that only loads that class? I can't imagine a use case where you wouldn't have the class, or even a value, though.

Using overloaded constructors from the superclass

I'm writing a message parser. Suppose I have a superclass Message with two auxiliary constructors, one that accepts String raw messages and one that accepts a Map with datafields mapped out in key-value pairs.
class Message {
def this(s: String)
def this(m: Map[String, String])
def toRaw = { ... } # call third party lib to return the generated msg
def map # call third party lib to return the parsed message
def something1 # something common for all messages which would be overriden in child classes
def something2 # something common for all messages which would be overriden in child classes
...
}
There's good reason to do this as the library that does parsing/generating is kind of awkward and removing the complexity of interfacing with it into a separate class makes sense, the child class would look something like this:
class SomeMessage extends Message {
def something1 # ...
def something2 # ...
}
and the idea is to use the overloaded constructors in the child class, for example:
val msg = new SomeMessage(rawMessage) # or
val msg = new SomeMessage("fld1" -> ".....", "fld2" -> "....")
# and then be able to call
msg.something1
msg.something2 # ...
However, the way auxiliary constructors and inheritance seem to behave in Scala this pattern has proven to be pretty challenging, and the simplest solution I found so far is to create a method called constructMe, which does the work of the constructors in the above case:
val msg = new SomeMessage
msg.constructMe(rawMessage) # or
msg.constructMe("fld1" -> ".....", "fld2" -> "....")
which seems crazy to need a method called constructMe.
So, the question:
is there a way to structure the code so to simply use the overloaded constructors from the superclass? For example:
val msg = new SomeMessage(rawMessage) # or
val msg = new SomeMessage("fld1" -> ".....", "fld2" -> "....")
or am I simply approaching the problem the wrong way?
Unless I'm missing something, you are calling the constructor like this:
val msg = new SomeMessage(rawMessage)
But the Message class doesn't not take a parameter, your class should be defined so:
class Message(val message: String) {
def this(m: Map[String, String]) = this("some value from mapping")
}
Also note that the constructor in scala must call the primary constructor as first action, see this question for more info.
And then the class extending the Message class should be like this:
class SomeMessage(val someString: String) extends Message(someString) {
def this(m: Map[String, String]) = this("this is a SomeMessage")
}
Note that the constructor needs a code block otherwise your code won't compile, you can't have a definition like def this(someString: String) without providing the implementation.
Edit:
To be honest I don't quite get why you want to use Maps in your architecture, your class main point it to contain a String, having to do with complex types in constructors can lead to problems. Let's say you have some class which can take a Map[String, String] as a constructor parameter, what will you do with it? As I said a constructor must call himself as first instruction, what you could is something like this:
class A(someString: String) = {
def this(map: Map[String, String]) = this(map.toString)
}
And that's it, the restrictions in scala don't allow you to do anything more, you would want to do some validation, for example let's say you want to take always the second element in the map, this could throw exceptions since the user is not forced to provide a map with more than one value, he's not even forced to provide a filled map unless you start filling your class with requires.
In your case I probably would leave String as class parameter or maybe a List[String] where you can call mkString or toString.
Anyway if you are satisfied calling map.toString you have to give both constructor implementation to parent and child class, this is one of scala constructor restrictions (in Java you could approach the problem in a different way), I hope somebody will prove me wrong, but as far as I know there's no other way to do it.
As a side note, I personally find this kind of restriction to be correct (most of the time) since the force you to structure your code to be more rigorous and have a better architecture, think about the fact that allowing people to do whatever they want in a constructor (like in java) obfuscate their true purpose, that is return a new instance of a class.

Scala: Why use implicit on function argument?

I have a following function:
def getIntValue(x: Int)(implicit y: Int ) : Int = {x + y}
I see above declaration everywhere. I understand what above function is doing. It is a currying function which takes two arguments. If you omit the second argument, it will invoke implicit definition which returns int instead. So I think it is something very similar to defining a default value for the argument.
implicit val temp = 3
scala> getIntValue(3)
res8: Int = 6
I was wondering what are the benefits of above declaration?
Here's my "pragmatic" answer: you typically use currying as more of a "convention" than anything else meaningful. It comes in really handy when your last parameter happens to be a "call by name" parameter (for example: : => Boolean):
def transaction(conn: Connection)(codeToExecuteInTransaction : => Boolean) = {
conn.startTransaction // start transaction
val booleanResult = codeToExecuteInTransaction //invoke the code block they passed in
//deal with errors and rollback if necessary, or commit
//return connection to connection pool
}
What this is saying is "I have a function called transaction, its first parameter is a Connection and its second parameter will be a code-block".
This allows us to use this method like so (using the "I can use curly brace instead of parenthesis rule"):
transaction(myConn) {
//code to execute in a transaction
//the code block's last executable statement must be a Boolean as per the second
//parameter of the transaction method
}
If you didn't curry that transaction method, it would look pretty unnatural doing this:
transaction(myConn, {
//code block
})
How about implicit? Yes it can seem like a very ambiguous construct, but you get used to it after a while, and the nice thing about implicit functions is they have scoping rules. So this means for production, you might define an implicit function for getting that database connection from the PROD database, but in your integration test you'll define an implicit function that will superscede the PROD version, and it will be used to get a connection from a DEV database instead for use in your test.
As an example, how about we add an implicit parameter to the transaction method?
def transaction(implicit conn: Connection)(codeToExecuteInTransaction : => Boolean) = {
}
Now, assuming I have an implicit function somewhere in my code base that returns a Connection, like so:
def implicit getConnectionFromPool() : Connection = { ...}
I can execute the transaction method like so:
transaction {
//code to execute in transaction
}
and Scala will translate that to:
transaction(getConnectionFromPool) {
//code to execute in transaction
}
In summary, Implicits are a pretty nice way to not have to make the developer provide a value for a required parameter when that parameter is 99% of the time going to be the same everywhere you use the function. In that 1% of the time you need a different Connection, you can provide your own connection by passing in a value instead of letting Scala figure out which implicit function provides the value.
In your specific example there are no practical benefits. In fact using implicits for this task will only obfuscate your code.
The standard use case of implicits is the Type Class Pattern. I'd say that it is the only use case that is practically useful. In all other cases it's better to have things explicit.
Here is an example of a typeclass:
// A typeclass
trait Show[a] {
def show(a: a): String
}
// Some data type
case class Artist(name: String)
// An instance of the `Show` typeclass for that data type
implicit val artistShowInstance =
new Show[Artist] {
def show(a: Artist) = a.name
}
// A function that works for any type `a`, which has an instance of a class `Show`
def showAListOfShowables[a](list: List[a])(implicit showInstance: Show[a]): String =
list.view.map(showInstance.show).mkString(", ")
// The following code outputs `Beatles, Michael Jackson, Rolling Stones`
val list = List(Artist("Beatles"), Artist("Michael Jackson"), Artist("Rolling Stones"))
println(showAListOfShowables(list))
This pattern originates from a functional programming language named Haskell and turned out to be more practical than the standard OO practices for writing a modular and decoupled software. The main benefit of it is it allows you to extend the already existing types with new functionality without changing them.
There's plenty of details unmentioned, like syntactic sugar, def instances and etc. It is a huge subject and fortunately it has a great coverage throughout the web. Just google for "scala type class".
There are many benefits, outside of your example.
I'll give just one; at the same time, this is also a trick that you can use on certain occasions.
Imagine you create a trait that is a generic container for other values, like a list, a set, a tree or something like that.
trait MyContainer[A] {
def containedValue:A
}
Now, at some point, you find it useful to iterate over all elements of the contained value.
Of course, this only makes sense if the contained value is of an iterable type.
But because you want your class to be useful for all types, you don't want to restrict A to be of a Seq type, or Traversable, or anything like that.
Basically, you want a method that says: "I can only be called if A is of a Seq type."
And if someone calls it on, say, MyContainer[Int], that should result in a compile error.
That's possible.
What you need is some evidence that A is of a sequence type.
And you can do that with Scala and implicit arguments:
trait MyContainer[A] {
def containedValue:A
def aggregate[B](f:B=>B)(implicit ev:A=>Seq[B]):B =
ev(containedValue) reduce f
}
So, if you call this method on a MyContainer[Seq[Int]], the compiler will look for an implicit Seq[Int]=>Seq[B].
That's really simple to resolve for the compiler.
Because there is a global implicit function that's called identity, and it is always in scope.
Its type signature is something like: A=>A
It simply returns whatever argument is passed to it.
I don't know how this pattern is called. (Can anyone help out?)
But I think it's a neat trick that comes in handy sometimes.
You can see a good example of that in the Scala library if you look at the method signature of Seq.sum.
In the case of sum, another implicit parameter type is used; in that case, the implicit parameter is evidence that the contained type is numeric, and therefore, a sum can be built out of all contained values.
That's not the only use of implicits, and certainly not the most prominent, but I'd say it's an honorable mention. :-)