Using SQL Server 2008 R2 I am trying to compare year values in a where clause like so:
AND year(convert(date, (LEFT(formAuditLog, 10)), 104 )) = year(GETDATE())
But I get this error:
Conversion failed when converting date and/or time from character string
I have also tried this but get that same result:
AND cast(year(convert(date, (LEFT(formAuditLog, 10)), 104 )) as int) = cast(year(GETDATE()) AS INT)
Note - formAuditLog is a string. I am getting the first 10 chars which is always mm/dd/yyyy (I have triple checked this) so I convert as a date and then get the year of this. Based on this info, should I not be able to do this comparison?
Thanks in advance
Added :
Note - When I put this in a select it works. I get the year part of the date I am expecting:
select top 10 year(convert(date, (LEFT(formAuditLog, 10)), 104 )) , * from myTableName
So why would this be allowed in a select but fail in a where clause?
Added : For completeness, there is actually nothing wrong with either of the two SQL bits at the top of this post. As mentioned in the accepted post comment below, it was a leading quote in one formAuditLog records that cause it to fall over
If your formAuditLog column is a string like you suggest and the left 10 characters is equivalent to a date format MM/DD/YYYY. This should have worked for you:
create table mytableName (id int, formAuditLog varchar(50));
insert into mytableName values
(1,'01/02/20141203'),
(2,'01/03/20151203'),
(3,'05/01/20151203');
select
id,
formAuditLog,
cast(left(formAuditLog,10) as date) as DateField,
year(cast(left(formAuditLog,10) as date)) as yearfield
from mytableName
where year(cast(left(formAuditLog,10) as date)) = year(cast(getdate() as date));
Code Demo
for sql server 2008, this should be your where condition
and year(GETDATE()) = case when isdate(LEFT(formAuditLog, 10))=1 then year(convert(date, (LEFT(formAuditLog, 10)))) else 99999 end
For sql server 2012..
AND year( try_parse(LEFT(formAuditLog, 10) as date) ) = year(GETDATE())
Related
Below is a script i am trying to run in Presto; Subtracting today's date from an integer field I am attempting to convert to date. To get the exacts days between. Unfortunately, it seems the highlighted block does not always convert the date correctly and my final answer is not correct. Please does anyone know another way around this or a standard method on presto of converting integer values to date.
Interger value in the column is in the format '20191123' for year-month-date
select ms, activ_dt, current_date, date_diff('day',act_dt,current_date) from
(
select ms,activ_dt, **CAST(parse_datetime(CAST(activ_dt AS varchar), 'YYYYMMDD') AS date) as act_dt**, nov19
from h.A_Subs_1 where msisdn_key=23480320012
) limit 19
You can convert "date as a number" (eg. 20180527 for May 27, 2018) using the following:
cast to varchar
parse_datetime with appropriate format
cast to date (since parse_datetime returns a timestamp)
Example:
presto> SELECT CAST(parse_datetime(CAST(20180527 AS varchar), 'yyyyMMdd') AS date);
_col0
------------
2018-05-27
You can use below sample query for your requirement:
select date_diff('day', date_parse('20191209', '%Y%m%d'), current_timestamp);
I'm trying to select records from a DB2 Iseries system where the date field is greater than the first of this year.
However, the date fields I'm selecting from are actually PACKED fields, not true dates.
I'm trying to convert them to YYYY-MM-DD format and get everything greater than '2018-01-01' but no matter what I try it says it's invalid.
Currently trying this:
SELECT *
FROM table1
WHERE val = 145
AND to_date(char(dateShp), 'YYYY-MM-DD') >= '2018-01-01';
it says expression not valid using format string specified.
Any ideas?
char(dateshp) is going to return a string like '20180319'
So your format string should not include the dashes.. 'YYYYMMDD'
example:
select to_date(char(20180101), 'YYYYMMDD')
from sysibm.sysdummy1;
So your code should be
SELECT *
FROM table1
WHERE val = 145
AND to_date(char(dateShp), 'YYYYMMDD') >= '2018-01-01';
Charles gave you a solution that converts the Packed date to a date field, and if you are comparing to another date field, this is a good solution. But if you are comparing to a constant value or another numeric field, you could just use something like this:
select *
from table1
where val = 145
and dateShp >= 20180101;
I'm new to crystal report. I have a date in string format like 2015-03-25 (Wed) and I want to convert it to date format like 03/25/2015. I tried with CDate and DateValue but it returned bad date string format. Any suggestions to convert such date string to proper date format?
If you have a DateTime field in Crystal Reports, you will see Date and Time tab option on the Format Editor when you right click on the field and select Format Field menu item. From the Date and Time tab, you may select the desired format and select OK.
It would be recommended to use the formats you want to use.
For eg : if you are giving string format for money or decimal you may not be able to use it at its full,like you may not be able to auto sum and other properties related to the datatype you intend to use
Not to do any thing in the code, Crystal Report have facility to this type of simple format.
#utility, you are near to answer.
As above image, in last Custom Format option, where you just go in Date tab and give format as
http://www.c-sharpcorner.com/UploadFile/mahesh/DateFormatInCR06132007092248AM/DateFormatInCR.aspx
Updated : sorry for above answer, that will work if you have valid date string.
In your case, where any arbitrary string need to convert into other date format. There is 2 option. In both case you have to extract the date and then format as you need and again combined with other sub-string.
Second you already done ie. crsytal report side, grab the date , format it and concatenate. this will slow down as need to process for each row.
SqlServer side - This option is faster from first option.
declare #t nvarchar(16) = '2015-03-25 (Wed)'
--get the acual date select SUBSTRING ( #t, 1, charindex('(' , #t ) -1 )
--above result give the charter datatype, so you first convert into date and then convert into other format select cast( SUBSTRING ( #t,
1, charindex('(' , #t ) -1 ) as date) --convert into date select
convert (varchar(15) , cast( SUBSTRING ( #t, 1, charindex('(' , #t )
-1 ) as date) , 103) --convert into dd/mm/yyyy format
--Above is for your understand, this is the actual execution of your code (Only write the below line) select convert (varchar(15) , cast(
SUBSTRING ( #t, 1, charindex('(' , #t ) -1 ) as date) , 103) + ' ' +
datename(dw, getdate() )
I suggest, go with Sqlserver side.
Let's say that I have a range of SQL tables that are named name_YYYY_WW where YYYY = year and WW = week number. If I call upon a function that guides a user defined date to the right table.
If the date entered is "20110101":
SELECT EXTRACT (WEEK FROM DATE '20110101') returns 52 and
SELECT EXTRACT (YEAR FROM DATE '20110101') returns 2011.
While is nothing wrong with these results I want "20110101" to either point to table name_2010_52 or name_2011_01, not name_2011_52 as it does now when I concanate the results to form the query for the table.
Any elegant solutions to this problem?
The function to_char() will allow you to format a date or timestamp to output correct the iso week and iso year.
SELECT to_char('2011-01-01'::date, 'IYYY_IW') as iso_year_week;
will produce:
iso_year_week
---------------
2010_52
(1 row)
You could use a CASE:
WITH sub(field) AS (
SELECT CAST('20110101' AS date) -- just to test
)
SELECT
CASE
WHEN EXTRACT (WEEK FROM field ) > 1 AND EXTRACT (MONTH FROM field) = 1 AND EXTRACT (DAY FROM field) < 3 THEN 1
ELSE
EXTRACT (WEEK FROM field)
END
FROM
sub;
CREATE PROCEDURE sp_ME
#ID int,
#ThisDate datetime = null
AS
SET NOCOUNT ON
IF #ThisDate IS NULL
BEGIN
SET #ThisDate = CURRENT_TIMESTAMP
END
DECLARE #intErrorCode int,
#QBegin datetime,
#QEnd datetime
SELECT #intErrorCode = ##ERROR
IF #ThisDate BETWEEN '01/01/' + CONVERT(VARCHAR(4), YEAR(#ThisDate))
AND '03/31/' + CONVERT(VARCHAR(4), YEAR(#ThisDate))
BEGIN
Select #QBegin = DATEADD(s,0,CAST ('10/01/' AS varchar(6) ) +
CONVERT(VARCHAR(4),DATEPART (year,#ThisDate)-1))
Select #QEnd = DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,#QBegin)+3,0))
SELECT * FROM QUERY
WHERE MEID = #ID
AND mydate >= #QBegin
AND mydate <= #QEnd)
END
SELECT #intErrorCode = ##ERROR
IF (#intErrorCode <> 0) GOTO ErrHandler
ErrHandler:
RETURN #intErrorCode
GO
It returns a dataset when you leave it blank and it assumes and fills in the date, however when you plug in a date it just states "The command completed successfully."
Any help would be more than appreciated.
At a guess, you need to query the previous quarter's results, which would just be this query:
SELECT * FROM QUERY
WHERE MEID = #ID
AND mydate >= DATEADD(quarter,DATEDIFF(quarter,'20010101',#ThisDate),'20001001'),
AND mydate < DATEADD(quarter,DATEDIFF(quarter,'20010101',#ThisDate),'20010101'))
And get rid of that big if condition, etc.
You could also get rid of the first if, if you put COALESCE(#ThisDate,CURRENT_TIMESTAMP) in the above, where I currently have #ThisDate.
I use the DATEADD(quarter,DATEDIFF(quarter,'20010101',#ThisDate),'20001001') pattern for a lot of datetime manipulation. It let's you achieve a lot in a few operations. In this case, it's the difference between the two dates ('20010101','20001001') which is giving us the previous quarter.
You'll frequently encounter the DATEADD/DATEDIFF pattern in questions involving removing the time portion from a datetime value. The canonical version of this is DATEADD(day,DATEDIFF(day,0,#Date),0). But the pattern can be generally extended to work with any of the datetime components. If you choose month rather than day, you'll get midnight at the start of the first of the month (of the day you've supplied)
Where it gets tricky is when you use dates (instead of 0), and especially if you don't use the same date for both calculations. This allows you to apply an additional offset that seems almost "free" - you're already using this construct to remove the time component, the fact that you can compute e.g. the last date in a quarter/month/etc is a bonus.