I am trying to use command line to zip a .bak file then cut the zip file to another location or copy/paste and delete the original once the copy is complete.
Right now my script is
copy "\\a\*.bak" "\\b"
I would like to compress the .bak file (in folder a) as it is a huge file, and then CUT the zip file into folder b.
Windows has a built-in functionality for this.
tar.exe -a -c -f file_Output.zip your_file.bak
file_Output.zip will be the file you will get as your zipped file, your_file.bak will be the file you are trying to compress.
Related
Using 7zip, I want to give a location of a folder of files something like...
D:\Home\files Then I want it to zip all the files in that folder and leave them there. So for example zipme.txt become zipme.zip, so all files would keep their name but just become a zip file. I have tried to use
FOR %i IN (D:\Home\files) DO 7z.exe a "%~ni.zip"
But when I do it it adds a zip file for the directory so my output would be in the correct folder but would contain
D:\Home\files\file.zip
D:\Home\files\zipme.zip
zipped files also all items in directory like..
zipme.txt
zipme2.txt
D:\Home\files/zipme2.zip
So how can I zip each file individual in a folder and have the new zipped name be the individual files name
Was able to get this to work.
FOR %i IN (D:\Home\files\*) DO 7z.exe a "%~ni.zip" "%i"
Suppose I have a directory structure like
C:\Users\Desktop\abc\d
I want to rar archive the abc folder so that the structure of rar is:
abc\d
When I try using powershell to archive, winrar replicates the full path inside the archive, like:
\Users\Desktop\abc\d
I dont want the full path to be created inside the archive
Here's the script:
https://gist.github.com/saurabhwahile/50f1091fb29c2bb327b7
What am I doing wrong?
Use the command line:
Rar.exe a -r -ep1 Test.rar "C:\Users\Desktop\abc"
Rar.exe is the console version of WinRAR stored in same directory as WinRAR.exe. You can use this command line also with WinRAR.exe if you want to see the compression process in a graphic window.
a is the command and means add files to archive.
-r is a switch to recursively add all files and subdirectories including empty subdirectories to the archive.
-ep1 is another switch which results in execluding base directory.
For this command line the base directory is "C:\Users\Desktop\" and therefore the created archive Test.rar contains only abc and all files and subdirectories in directory abc which is what you want.
One more hint: Using the command line
Rar.exe a -r -ep1 Test.rar "C:\Users\Desktop\abc\"
results in adding all files and subdirectories of directory abc to the archive, but without directory name abc being also stored in the archive. The backslash at end makes this difference.
In other words: On using switch -ep1 everything up to last backslash in file/directory specification is not added to the archive.
For more information about available switches see the text file Rar.txt in the program files directory of WinRAR.
I'm trying to automate the install of my platform. I've made a script for compressing the build of the deployables to a 7zip file.
Now i need to uncompress partially some folders to a specific destination.
Package
-app1
--folder11
---folder111
--folder12
-app2
--folder21
--folder22
...
I need to create a powershell script to extract the content of 'app1' to a destination folder.
I've been trying to use the following command but the result is not the as i expected.
I've been receiving the full path and not the content from folder11 recursivelly.
Set-Alias zip $ZipCommand
zip x $FilePath app1\folder11 -oc:DeployableFolder -r
Any ideas? Suggestions?
Thanks.
I tried and had no issue.
set-alias zip "c:\Program Files\outils\7-Zip\7z.exe"
zip x program.7z python-core-2.6.1\lib -oc:\data
I eventually got a c:\data\python-core-2.6.1 which only contains the lib folder with all its subfolders & files.
The only difference I see is the backslash \ in the output path.
HTH
I'm developing a simple launchdaemon that copies files from one directory to another. I've gotten the files to transfer over fine.
I just want the files in the directory to be .mp3's instead of .dat's
Some of the files look like this:
6546785.8786.dat
3678685.9834.dat
4658679.4375.dat
I want them to look like this:
6546785.8786.mp3
3678685.9834.mp3
4658679.4375.mp3
This is what I have at the end of the bash script to rename the file extensions.
cd $mp3_dir
mv *.dat *.mp3
exit 0
Problem is the file comes out as *.mp3 instead of 6546785.8786.mp3
and when another 6546785.8786.dat file is imported to $mp3_dir, the *.mp3 is overwritten with the new .mp3
I need to rename just the .dat file extensions to .mp3 and keep the filename.
Ideas? Suggestions?
Try:
for file in *.dat; do mv "$file" "${file%dat}mp3"; done
Or, if your shell has it:
rename .dat .mp3 *.dat
Now, why your command didn't work: first of all, it is more than certain that you only had one file in your directory when it was renamed to *.mp3, otherwise mv would have failed with *.mp3: not a directory.
And mv does NOT do any magic with file globs, it is the shell which expands globs. Which means, if you had this file in the directory:
t.dat
and you typed:
mv *.dat *.mp3
the shell would have expanded *.dat to t.dat. However, as nothing would match *.mp3, the shell would have left it as is, meaning the fully expanded command is:
mv t.dat *.mp3
Which will create a file named, literally, *.mp3.
If, on the other hand, you had several files named *.dat, as in:
t1.dat t2.dat
the command would have expanded to:
mv t1.dat t2.dat *.mp3
But this will fail: if there are more than two arguments to mv, it expects the last argument (ie, *.mp3) to be a directory.
For anyone on a mac, this is quite easy if you have BREW, if you don't have brew then my advice is get it. then when installed just simply do this
$ brew install rename
then once rename is installed just type (in the directory where the files are)
$ rename -s dat mp3 *
I need to write a batch file that copies a file to a new folder and renames it.
At the moment, my batch file consists of only this command:
COPY ABC.PDF \\Documents
As you can see, it only copies the file ABC.pdf to the network folder Documents.
However I need to change this so it renames the file ABCxxx.pdf, where xxx is a text variable that I would like to set somewhere in the batch file.
For example, if xxx = _Draft, then file would be renamed ABC_Draft.pdf after it is copied.
Make a bat file with the following in it:
copy /y C:\temp\log1k.txt C:\temp\log1k_copied.txt
However, I think there are issues if there are spaces in your directory names. Notice this was copied to the same directory, but that doesn't matter. If you want to see how it runs, make another bat file that calls the first and outputs to a log:
C:\temp\test.bat > C:\temp\test.log
(assuming the first bat file was called test.bat and was located in that directory)
type C:\temp\test.bat>C:\temp\test.log