I have an object structure as shown below
{
"_id" : ObjectId("55d164f1c8f2c53a82535b9a"),
"plant_name" : "TOTAL",
"installed_capacity" : 3473,
"wind_data" : [
{
"date" : "16-08-15",
"timestamp" : " 16:27:15",
"generated_capacity" : 617.24,
"frequency" : 50.01
},
{
"date" : "16-08-15",
"timestamp" : " 21:21:15",
"generated_capacity" : 670.25,
"frequency" : 49.94
}, ....]
}
I need to sum up (at least retrieve) "generated_capacity" of all the objects under "wind_data" having "date" equal to "16-08-15" of "TOTAL" object. I have tried this query
db.collectionName.aggregate(
{"$unwind":"$wind_data"},
{"$match":{"plant_name":"TOTAL","wind_data.date":"16-08-15"}}
)
But, this query is not working. Please suggest some way to figure this out.
The following query would do the job
db.collectionName.aggregate([
{"$unwind":"$wind_data"},
{"$match":{"plant_name":"TOTAL","wind_data.date":"16-08-15"}},
{"$group":{"_id":"$wind_data.date","generated_capacity_sum":{"$sum":"$wind_data.generated_capacity"}}}
])
Related
I am trying to fetch total replies where read values for a replies is true. But I am getting count value as 3 but expected value is 2 (since only two read value is true) through Aggregation function available in Spring Data Mongo. Below is the code which I wrote:
Aggregation sumOfRepliesAgg = newAggregation(match(new Criteria().andOperator(Criteria.where("replies.repliedUserId").is(userProfileId),Criteria.where("replies.read").is(true))),
unwind("replies"), group("replies").count().as("repliesCount"),project("repliesCount"));
AggregationResults<Comments> totalRepliesCount = mongoOps.aggregate(sumOfRepliesAgg, "COMMENTS",Comments.class);
return totalRepliesCount.getMappedResults().size();
Using AND Operator inside Criteria Query and passed two criteria condition but not working as expected. Below is the sample data set:
{
"_id" : ObjectId("5c4ca7c94807e220ac5f7ec2"),
"_class" : "com.forum.api.domain.Comments",
"comment_data" : "logged by karthe99",
"totalReplies" : 2,
"replies" : [
{
"_id" : "b33a429f-b201-449b-962b-d589b7979cf0",
"content" : "dasdsa",
"createdDate" : ISODate("2019-01-26T18:33:10.674Z"),
"repliedToUser" : "#karthe99",
"repliedUserId" : "5bbc305950a1051dac1b1c96",
"read" : false
},
{
"_id" : "b886f8da-2643-4eca-9d8a-53f90777f492",
"content" : "dasda",
"createdDate" : ISODate("2019-01-26T18:33:15.461Z"),
"repliedToUser" : "#karthe50",
"repliedUserId" : "5c4bd8914807e208b8a4212b",
"read" : true
},
{
"_id" : "b56hy4rt-2343-8tgr-988a-c4f90598h492",
"content" : "dasda",
"createdDate" : ISODate("2019-01-26T18:33:15.461Z"),
"repliedToUser" : "#karthe50",
"repliedUserId" : "5c4bd8914807e208b8a4212b",
"read" : true
}
],
"last_modified_by" : "karthe99",
"last_modified_date" : ISODate("2019-01-26T18:32:41.394Z")
}
What is the mistake in the query that I wrote?
I am trying to write a query in mongo that will create a new table, loop through my data set, and insert the TopExecutiveTitle into the new table. I also would like it to keep count of each position and only insert a position into the table when it is new.
This is what I have so far. This code loops through my table and inserts the TopExectuiveTitle into a new table. However, it does not group them together and keep count. How do I write my query so that it will?
db.car.find().forEach( function (x) {
db.TopExecutiveTable.insert({Topexecutivetitle: x.Topexecutivetitle})
});
Here is a sample of a document in my database.
{
"_id" : ObjectId("5a22c8e562c2e489c5df70fa"),
"2016rank" : 1,
"Dealershipgroupname" : "AutoNation Inc.?",
"Address" : "200 S.W. 1st Ave.",
"City/State/Zip" : "Fort Lauderdale, FL 33301",
"Phone" : "(954) 769-7000",
"Companywebsite" : "www.autonation.com",
"Topexecutive" : "Mike Jackson",
"Topexecutivetitle" : "chairman & CEO",
"Totalnewretailunits" : "337,622",
"Totalusedunits" : "225,713",
"Totalfleetunits" : 3,
"Totalwholesaleunits" : "82,342",
"Total_units" : "649,415",
"Total_number_of _dealerships" : 260,
"Grouprevenuealldepartments*" : "$21,609,000,000",
"2015rank" : 1
}
The result I would like is something like this
"Topexecutivetitle" : "chairman & CEO"
"Count" : 3
"Topexecutivetitle" : "president"
"Count" : 7
}
To do this you need to use the aggregate function of mongo, something like this:
db.car.aggregate([
{
$group:{
_id:"$Topexecutivetitle",
count:{$sum:1}
}
},
{
$project:{
Topexecutivetitle:"$_id",
count:1,
_id:0
}
},
{
$out:"result"
}])
This will give you your desired output and store it into a new collection "result":
{
"_id" : "president",
"count" : 1.0
},
{
"_id" : "chairman & CEO",
"count" : 3.0
}
I have this array of documents, I would like to put "table" on the same level like mastil_antenas and other variables. how Can I do that with aggregate?
I'm trying with the aggregate $project but I can't get the result.
Example of Data
[ {
"mastil_antena" : "1",
"nro_platf" : "1",
"antmarcmast" : "ANDREW",
"antmodelmast" : "HWXXX6516DSA3M",
"retmarcmast" : "Ericsson",
"retmodelmast" : "ATM200-A20",
"distmast" : "1.50",
"altncramast" : "41.30",
"ORIENTMAG" : "73.00",
"incelecmast" : "RET",
"incmecmast" : "1.00",
"Feedertypemast" : "Fibra Optica",
"longjumpmast" : "5.00",
"longfo" : "100",
"calibrecablefuerza" : "10 mm",
"longcablefuerza" : "65.00",
"modelorruantena" : "32B66A",
"tiltmecfoto" : "https://secure.appenate.com/Files/FormEntry/47929-92cdf219-3128-4903-8324-a81000602b9d171017114934746000.jpg",
"tiltmecfoto_fh" : "2017-10-18T05:51:22Z",
"az0foto" : "https://secure.appenate.com/Files/FormEntry/47929-92cdf219-3128-4903-8324-a81000602b9d171017115012727000.jpg",
"az0foto_fh" : "2017-10-18T05:55:21Z",
"azneg60foto" : "https://secure.appenate.com/Files/FormEntry/47929-92cdf219-3128-4903-8324-a81000602b9d171017115016199000.jpg",
"azneg60foto_fh" : "2017-10-18T05:55:36Z",
"azpos60foto" : "https://secure.appenate.com/Files/FormEntry/47929-92cdf219-3128-4903-8324-a81000602b9d171017115020147000.jpg",
"azpos60foto_fh" : "2017-10-18T05:55:49Z",
"etiqantenafoto" : "https://secure.appenate.com/Files/FormEntry/47929-92cdf219-3128-4903-8324-a81000602b9d171017114920853000.jpg",
"etiqantenafoto_fh" : "2017-10-18T05:56:01Z",
"tiltelectfoto" : "https://secure.appenate.com/Files/FormEntry/47929-92cdf219-3128-4903-8324-a81000602b9d171017114914236000.jpg",
"tiltelectfoto_fh" : "2017-10-18T05:56:13Z",
"idcablefoto" : "https://secure.appenate.com/Files/FormEntry/47929-92cdf219-3128-4903-8324-a81000602b9d171017114900279000.jpg",
"idcablefoto_fh" : "2017-10-18T05:56:38Z",
"rrutmafoto" : "https://secure.appenate.com/Files/FormEntry/47929-92cdf219-3128-4903-8324-a81000602b9d171017114947279000.jpg",
"rrutmafoto_fh" : "2017-10-18T05:56:49Z",
"etiquetarrufoto" : "https://secure.appenate.com/Files/FormEntry/47929-92cdf219-3128-4903-8324-a81000602b9d171017114954648000.jpg",
"etiquetarrufoto_fh" : "2017-10-18T05:57:02Z",
"rrutmafoto1" : "https://secure.appenate.com/Files/FormEntry/47929-92cdf219-3128-4903-8324-a81000602b9d171017114959738000.jpg",
"rrutmafoto1_fh" : "2017-10-18T05:57:12Z",
"etiquetarrufoto1" : "https://secure.appenate.com/Files/FormEntry/47929-92cdf219-3128-4903-8324-a81000602b9d171017115005545000.jpg",
"etiquetarrufoto1_fh" : "2017-10-18T05:57:27Z",
"botontorre4" : "sstelcel3",
"table" : { /* put all varibles one level up*/
"tecmast" : "LTE",
"frecmast" : "2100",
"secmast" : "1",
"untitled440" : "Salir"
},
"comentmast" : "",
"longfeedmast" : "",
"numtmasmast" : "",
"otra_marca_antena" : "",
"otro_modelo_antena" : ""
}]
Starting from MongoDB version 3.4 you could use $addFields to do this.
//replace products with what makes sense in your database
db.getCollection('products').aggregate(
[
{ //1 add the properties from subdocument table to documents
$addFields: {
"documents.tecmast" : "documents.0.table.tecmast",
"documents.frecmast" : "documents.0.table.frecmast",
"documents.secmast" : "documents.0.table.secmast",
"documents.untitled440" : "documents.0.table.untitled440"
}
},
{
//(optional) 2 remove the table property from the documents
$project: {"documents.table" : 0}
}
]
)
Step 1: use $addFields to grab properties from table inside documents.table and put them on documents
Step 2: (optional) remove property "table" from documents.
I hope this helps!!!
Hello I'm a MongoDb beginner. I have a database of a IRC chatlog. The document structure is very simple
{
"_id" : ObjectId("000"),
"user" : "username",
"message" : "foobar foobar potato idontknow",
"time" : NumberLong(1451775601469)
}
I have thousands of these and I want to count the number of occurrences of the string "foobar". I have googled this issue and found something about aggregations. I looks very complicated and I haven't really found any issue this "simple". I'd be glad if someone pointed me in the right direction what to research and I wouldn't mind an example command that does exactly this what I want. Thank you.
There is no any built-in operator to solve your request.
You can try this query, but it has very poor performance:
db.chat.find().forEach(function(doc){
print(doc["user"] + " > " + ((doc["message"].match(/foobar/g) || []).length))
})
If you could change your message field to array, then we could apply aggregation...
EDIT:
If you add array of splitted words into your entry, we can apply aggregation
Sample:
{
"_id" : ObjectId("569bb7040586bcb40f7d2539"),
"user" : "username",
"fullmessage" : "foobar foobar potato idontknow",
"message" : [
"foobar",
"foobar",
"potato",
"idontknow"
],
"time" : NumberLong(1451775601469)
}
Aggregation. We create new entry for each array element, match given word (foobar, in this case) and then count matched result.
db.chat.aggregate([
{"$unwind" : "$message"},
{"$match" : {"message" : {"$regex" : "foobar", "$options" : "i"}}},
{"$group" : {_id:{"_id" : "$_id", "user" : "$user", "time" : "$time", "fullmessage" : "$fullmessage"}, "count" : {$sum:1}}},
{"$project" : {_id:"$_id._id", "user" : "$_id.user", "time" : "$_id.time", "fullmessage" : "$_id.fullmessage", "count" : "$count"}}
])
Result:
[
{
"_id" : ObjectId("569bb7040586bcb40f7d2539"),
"count" : 2,
"user" : "username",
"time" : NumberLong(1451775601469),
"fullmessage" : "foobar foobar potato idontknow"
}
]
Does this makes any sense when trying to add a sub-sub-item? (I'm new to mongo - be merciful :-))
question = db.questions.findOne({_id: ObjectId("529c5d44211c9a8c11000006")})
question.answers[0].votes.insert(...)
When I run this from the mongo console the result is an error saying [object object] does not have the method insert.
I have the following mongoDB Question Schema.
{
"__v" : 2,
"_creator" : ObjectId("529c5d2d211c9a8c11000005"),
"_id" : ObjectId("529c5d44211c9a8c11000006"),
"answers" : [
{
"postDate" : ISODate("2013-12-02T10:14:19.060Z"),
"postDateText" : "15min ago",
"authorEmail" : "guys#pix.com",
"authorName" : "guys#pix.com",
"body" : "You need magic powder",
"isWinner" : false,
"_creator" : ObjectId("529c5d2d211c9a8c11000005"),
"_id" : ObjectId("529c5d7b211c9a8c11000008"),
"votes" : [
{
"voteType" : "up",
"_creator" : ObjectId("529c5d2d211c9a8c11000005"),
"_id" : ObjectId("529c5d5b211c9a8c11000007")
}
]
}
],
"authorEmail" : "guys#wix.com",
"authorName" : "guys#wix.com",
"body" : "I'm trying to fly...\n\n<pre class=\"brush: js;\">\nfunction logName(name) {\n console.log(name);\n}\n</pre>",
"isResolved" : false,
"postDate" : ISODate("2013-12-02T10:13:24.235Z"),
"tags" : [
"fly"
],
"title" : "How do I fly?",
"views" : [],
"votes" : [
{
"voteType" : "up",
"_creator" : ObjectId("529c5d2d211c9a8c11000005"),
"_id" : ObjectId("529c5d5b211c9a8c11000007")
}
]
}
I'm trying, given a questionId and an answerId to add a vote to the votes array (which is inside the answer). I can't seem to do it. Help?
insert is for adding whole new documents; when you just want to add a new element to an array field of an existing document, you can use update along with an operator like $push.
So, in the shell you would use something like this:
db.questions.update(
{_id: ObjectId("529c5d44211c9a8c11000006")},
{'answers.0.votes': {$push: voteToPush}})