Object's parameter is not a member of Object(UNITY EDITOR) - unity3d

Question

I've got errors
Assets/TextPierwszy.js(22,28): BCE0019: 'id' is not a member of 'Object'.
Assets/TextPierwszy.js(24,38): BCE0019: 'id' is not a member of 'Object'.
when trying to compile that script in UnityScript.
#pragma strict
private var pole : UI.Text;
public var Started = false;
public var Ludnosc = new Array();
public class Human {
public var id : byte;
public var gender : byte; // 0=k 1=m
public var age : byte;
public var pregnant : byte;
function Breed(partner) {
// Tu będzie logika rozmnażania
}
public var parents : int[]; //Najpierw podajemy ID matki, potem ID ojca.
}
function Test1() {
if(!Started) {
Started = true;
Ludnosc.push(new Human());
Ludnosc[0].id = 1; //Line number 22
Debug.Log(Ludnosc.length);
Debug.Log(Ludnosc[0].id); //Line number 24
}
}
How can I tell compiler to track Ludnosc[0] as instance of Human instead of tracking it at plain Object?
Or is there problem in other place? Also tried
public var Ludnosc : Human = new Array();
but this don't work too. :(

Answer 1

This is because when you initialize Ludnosc using:
public var Ludnosc = new Array();
you're creating an array of Object elements. As a result, when you try to access Ludnosc[0].id, Ludnosc[0] is treated an an Object and hence does not have id available to it.
To address this, either initialize Ludnosc as a built-in array like so:
public var Ludnosc : Human[];
Ludnosc = new Human[1]; // When you're initializing it
Ludnosc[0] = new Human(); // When you're populating it
Or, if you really want to use a JavaScript array, you can cast the Object to a Human when you access the value in Test1(), modify the typecasted version, then place it back into the array (haven't tested this code):
function Test1() {
if(!Started) {
Started = true;
Ludnosc.push(new Human());
var tempHuman = Ludnosc[0] as Human;
tempHuman.id = 1;
Ludnosc[0] = tempHuman; // Overwriting with the updated Human
Debug.Log(Ludnosc.length);
Debug.Log(tempHuman.id);
}
}
Hope this helps! Let me know if you have any questions.