Protocol extensions on Structs causes compile error 'Self' constrained to non-protocol type - swift

Question

I'm attempting to apply a constrained protocol extension to a struct (Swift 2.0) and receiving the following compiler error:
type 'Self' constrained to non-protocol type 'Foo'
struct Foo: MyProtocol {
let myVar: String
init(myVar: String) {
self.myVar = myVar
}
}
protocol MyProtocol {
func bar()
}
extension MyProtocol where Self: Foo {
func bar() {
print(myVar)
}
}
let foo = Foo(myVar: "Hello, Protocol")
foo.bar()
I can fix this error by changing struct Foo to class Foo but I don't understand why this works. Why can't I do a where Self: constrained protocol a struct?

Answer 1

This is an expected behaviour considering struct are not meant to be inherited which : notation stands for.
The correct way to achieve what you described would be something like equality sign like:
extension MyProtocol where Self == Foo {
func bar() {
print(myVar)
}
}
But this doesn't compile for some stupid reason like:
Same-type requirement makes generic parameter Self non-generic
For what it's worth, you can achieve the same result with the following:
protocol FooProtocol {
var myVar: String { get }
}
struct Foo: FooProtocol, MyProtocol {
let myVar: String
}
protocol MyProtocol {}
extension MyProtocol where Self: FooProtocol {
func bar() {
print(myVar)
}
}
where FooProtocol is fake protocol which only Foo should extend.
Many third-party libraries that try to extend standard library's struct types (eg. Optional) makes use of workaround like the above.

Answer 2

I just ran into this problem too. Although I too would like a better understanding of why this is so, the Swift language reference (the guide says nothing about this) has the following from the Generic Parameters section:
Where Clauses
You can specify additional requirements on type parameters and their
associated types by including a where clause after the generic
parameter list. A where clause consists of the where keyword, followed
by a comma-separated list of one or more requirements.
The requirements in a where clause specify that a type parameter
inherits from a class or conforms to a protocol or protocol
composition. Although the where clause provides syntactic sugar for
expressing simple constraints on type parameters (for instance, T:
Comparable is equivalent to T where T: Comparable and so on), you can
use it to provide more complex constraints on type parameters and
their associated types. For instance, you can express the constraints
that a generic type T inherits from a class C and conforms to a
protocol P as <T where T: C, T: P>.
So 'Self' cannot be a struct or emum it seems, which is a shame. Presumably there is a language design reason for this. The compiler error message could certainly be clearer though.

Answer 3

As Foo is an existing type, you could simply extend it this way:
struct Foo { // <== remove MyProtocol
let myVar: String
init(myVar: String) {
self.myVar = myVar
}
}
// extending the type
extension Foo: MyProtocol {
func bar() {
print(myVar)
}
}
From The Swift Programming Language (Swift 2.2):
If you define an extension to add new functionality to an existing type, the new functionality will be available on all existing instances of that type, even if they were created before the extension was defined.