Generate non-decimal unique id in asterisk - centos

I want a unique id for a particular call in asterisk currently I am using ${CDR(uniqueid)} which gives me a decimal value like 12344.4321 .
My problem is that I want a non-decimal value cause I am using this id on various places its causing some issue.
Is there a variable from which I can get a non-decimal unique id for each calls in asterisk dialplan?

You can use MD5 or HEX function and convert decimal to hex string.
You also can just add some pre-defined string to decimal value
NONDEC${CDR(uniqueid)}

Related

Azure Data Factory - Dynamic Skip Lines Expression

I am attempting to import a CSV into ADF however the file header is not the first line of the file. It is dynamic therefore I need to match it based on the first column (e.g "TestID,") which is a string.
Example Data (Header is on Line 4)
Date:,01/05/2022
Time:,00:30:25
Test Temperature:,25C
TestID,StartTime,EndTime,Result
TID12345-01,00:45:30,00:47:12,Pass
TID12345-02,00:46:50,00:49:12,Fail
TID12345-03,00:48:20,00:52:17,Pass
TID12345-04,00:49:12,00:49:45,Pass
TID12345-05,00:50:22,00:51:55,Fail
I found this article which addresses this issue however I am struggling to rewrite the expression from using an integer to using a string.
https://kromerbigdata.com/2019/09/28/adf-dynamic-skip-lines-find-data-with-variable-headers
First Expression
iif(!isNull(toInteger(left(toString(byPosition(1)),1))),toInteger(rownum),toInteger(0))
As the article states, this expression looks at the first character of each row and if it is an integer it will return the row number (rownum)
How do I perform this action for a string (e.g "TestID,")
Many Thanks
Jonny
I think you want to consider first line that starts with string as your header and preceding lines that starts with numbers should not be considered as header. You can use isNan function to check if the first character is Not a number(i.e. string) as seen in the below modified expression:
iif(isNan(left(toString(byPosition(1)),1))
,toInteger(rownum)
,toInteger(0)
)
Following is a breakdown of the above expression:
left(toString(byPosition(1)),1): gets first character fron left side of the first column.
isNan: checks if the character is "not a number".
iif: not a number, true then return rownum, false then return 0.
Or you can also use functions like isInteger() to check if the first character is an integer or not and perform actions accordingly.
Later on as explained in the cited article you need to find minimum rownum to skip.
Hope it helps.

how to remove # character from national data type in cobol

i am facing issue while converting unicode data into national characters.
When i convert the Unicode data into national using national-of function, some junk character like # is appended after the string.
E.g
Ws-unicode pic X(200)
Ws-national pic N(600)
--let the value in Ws-Unicode is これらの変更は. getting from java end.
move function national-of ( Ws-unicode ,1208 ) to Ws-national.
--after converting value is like これらの変更は #.
i do not want the extra # character added after conversion.
please help me to find out the possible solution, i have tried to replace N'#' with space using inspect clause.
it worked well but failed in some specific scenario like if we have # in input from user end. in that case genuine # also converted to space.
Below is a snippet of code I used to convert EBCDIC to UTF. Before I was capturing string lengths, I was also getting # symbols:
STRING
FUNCTION DISPLAY-OF (
FUNCTION NATIONAL-OF (
WS-EBCDIC-STRING(1:WS-XML-EBCDIC-LENGTH)
WS-EBCDIC-CCSID
)
WS-UTF8-CCSID
)
DELIMITED BY SIZE
INTO WS-UTF8-STRING
WITH POINTER WS-XML-UTF8-LENGTH
END-STRING
SUBTRACT 1 FROM WS-XML-UTF8-LENGTH
What this code does is string the UTF8 representation of the EBCIDIC string into another variable. The WITH POINTER clause will capture the new length of the string + 1 (+ 1 because the pointer is positioned to the next position after the string ended).
Using this method, you should be able to know exactly how long second string is and use that string with the exact length.
That should remove the unwanted #s.
EDIT:
One thing I forgot to mention, in my case, the # signs were actually EBCDIC low values when viewing the actual hex on the mainframe
Use inspect with reverse and stop after first occurence of #

How to parse and format an integer with zero decimal places in GWT?

Using GWT NumberFormat, I need to have a decimal format that basically accepts no decimal point character and zero decimal places. For example, 123 should be valid but 123.4 and 123.9 should be rejected. Also, rounding of decimal values into nearest integer is not an option.
I thought the following would work, but it does not:
double val = NumberFormat.getFormat("#0").parse(str);
I definitely need it to support GWT i18n formatting, such as "," separators for large numbers. The input "str" is for example the argument coming to a Parser.parse(text) method, similar to the one in IntegerParser. IntegerParser does not validate zero decimal places properly and only rounds the value rather than rejecting numbers with decimal point.
Any ideas?
Use IntegerParser.
It uses the following method under the covers:
(int) Math.rint(NumberFormat.getDecimalFormat().parse(object.toString()));
UPDATE:
Also, you can use LongBox instead of TextBox.
The way I finally solved my problem was by explicitly looking for decimal separator in the input string before trying to parse it using NumberFormat. Here is the code:
final String DECIMAL_SEPARATOR =
LocaleInfo.getCurrentLocale().getNumberConstants().decimalSeparator();
if (str.contains(DECIMAL_SEPARATOR))
throw new ParseException("Invalid integer value (" + str + ")", 0);
return (int) Math.rint(NumberFormat.getDecimalFormat().parse(str));
I am still interested in finding a better way to do it using NumberFormat.

Crystal report issue with int to string conversion

I want to convert int to string and then concatenate dot with it. Here is the formula
totext({#SrNo})+ "."
It works perfectly but not what i want. I want to show at as
1.
but it shows me in this way
1.00.
it means that when i try to convert int to string it convert it into number with precision of two decimal zeros. Can someone tell me how can i show it in proper format. For information i want to tell you that SrNo is running total.
ToText(x, y, z, w) Function can use
x=The number to convert to text
y=The number of decimal places to include in result (optional). The value will be rounded to that decimal place.
z=The character to use as the thousands separator. If you don’t specify one, it will use your application default. (Optional.)
w=The character to use as the decimal separator. If you don’t specify one, it will use your application default. (Optional.)
Examples
ToText(12345.678) = > “12345.678″
ToText(12345.678,2) = > “12345.67″
ToText(12345.678,0) = > “12345″
You can try this :
totext({fieldname},0)
Ohhh I got the answer it was so simple.
totext takes 4 parameters
First parameter is value which is going to be converted
Second parameter is number of decimal previsions.
Third parameter is decimal separator. like (1,432.123) here dot(.) is third parameter.
Forth parameter is thousand separator. like (1,432) here comma(,) is forth parameter.
Example{
totext("1,432.1234",2) results 1,432.12
totext("1,432.1234",2,' " ') results 1,432"1234
totext("1,432.1234",2,' " ', ' : ') results 1:432,1234
}
Although i think this example may be not so good but i just want to give you an idea. This is for int conversion for date it has 2 parameters.
value to be converted and format of date.

How to get number digit from the varchar 2 in oracle?

I have variable l_string varchar 2(100).
The value of string is l_string='L000EW45UY678IOP'.
I want to get number from this string like
00045678
Please tell me how to get the above string result.
Google the TRANSLATE function.
It will let you replace the alphabetic characters by nothing, leaving the digits behind.
try this:
regexp_replace('L000EW45UY678IOP', '[^0-9]', '')