I have variable l_string varchar 2(100).
The value of string is l_string='L000EW45UY678IOP'.
I want to get number from this string like
00045678
Please tell me how to get the above string result.
Google the TRANSLATE function.
It will let you replace the alphabetic characters by nothing, leaving the digits behind.
try this:
regexp_replace('L000EW45UY678IOP', '[^0-9]', '')
Related
Below is the value of a string in a text column.
select col1 from tt_d_tab;
'A:10000000,B:50000000,C:1000000,D:10000000,E:10000000'
I'm trying to convert it into json of below format.
'{"A": 10000000,"B": 50000000,"C": 1000000,"D": 10000000,"E": 10000000}'
Can someone help on this?
If you know that neither the keys nor values will have : or , characters in them, you can write
select json_object(regexp_split_to_array(col1,'[:,]')) from tt_d_tab;
This splits the string on every colon and comma, then interprets the result as key/value pairs.
If the string manipulation gets any more complicated, SQL may not be the ideal tool for the job, but it's still doable, either by this method or by converting the string into the form you need directly and then casting it to json with ::json.
If your key is a single capital letter as in your example
select concat('{',regexp_replace('A:10000000,B:50000000,C:1000000,D:10000000,E:10000000','([A-Z])','"\1"','g'),'}')::json json_field;
A more general case with any number of letters caps or not
select concat('{',regexp_replace('Ac:10000000,BT:50000000,Cs:1000000,D:10000000,E:10000000','([a-zA-Z]+)','"\1"','g'),'}')::json json_field;
I am trying to remove using REGEXP_REPLACE the following special characters: "[]{}
from the following text field: [{"x":"y","s":"G_1","cn":"C8"},{"cn":"M2","gn":"G_2","cn":"CA99"},{"c":"ME3","gn":"G_3","c":"CA00"}]
and replace them with nothing, not even a space.
*Needless to say, this is just an example string, and I need to find a consistent solution for similar but different strings.
I was trying to run the following: SELECT REGEXP_REPLACE('[{"x":"y","s":"G_1","cn":"C8"},{"cn":"M2","gn":"G_2","cn":"CA99"},{"c":"ME3","gn":"G_3","c":"CA00"}] ','[{[}]":]','')
But received pretty much the same string..
Thanks in advance!
You need to escape the special characters (\), and to specify that you want to repeat the operation for every characters ('g') else it will stop at the 1st match
SELECT REGEXP_REPLACE(
'[{"x":"y","s":"G_1","cn":"C8"},{"cn":"M2","gn":"G_2","cn":"CA99"},{"c":"ME3","gn":"G_3","c":"CA00"}] ',
'[{\[}\]":]',
'',
'g');
regexp_replace
--------------------------------------------------
xy,sG_1,cnC8,cnM2,gnG_2,cnCA99,cME3,gnG_3,cCA00
(1 row)
I had a quick question, how can I go about using SUBSTRING on an integer? I currently have field labeled "StoreID" that contains a 5 digit integer (60008). I am trying to use SUBSTRING to remove the 6 when I query out this information. When I use something like:
SUBSTRING('StoreID', 2, 6)
I get an error returning back saying that SUBSTRING(integer,integer,integer) does not exist.
Is there another function I can use in postgres to accomplish what I am trying to do?
You can cast the integer
SUBSTR(cast (StoreId as text), 2,6)
If you are interested in the number 8, use the modulo operator %
SELECT 60008%10000
If you want the string '0008', the function right() is right for you (added with Postgres 9.1):
SELECT right(60008::text, -1)
Or with modulo and to_char():
SELECT to_char(60008%10000, 'FM0000')
The FM modifier removes space padding.
I want to convert int to string and then concatenate dot with it. Here is the formula
totext({#SrNo})+ "."
It works perfectly but not what i want. I want to show at as
1.
but it shows me in this way
1.00.
it means that when i try to convert int to string it convert it into number with precision of two decimal zeros. Can someone tell me how can i show it in proper format. For information i want to tell you that SrNo is running total.
ToText(x, y, z, w) Function can use
x=The number to convert to text
y=The number of decimal places to include in result (optional). The value will be rounded to that decimal place.
z=The character to use as the thousands separator. If you don’t specify one, it will use your application default. (Optional.)
w=The character to use as the decimal separator. If you don’t specify one, it will use your application default. (Optional.)
Examples
ToText(12345.678) = > “12345.678″
ToText(12345.678,2) = > “12345.67″
ToText(12345.678,0) = > “12345″
You can try this :
totext({fieldname},0)
Ohhh I got the answer it was so simple.
totext takes 4 parameters
First parameter is value which is going to be converted
Second parameter is number of decimal previsions.
Third parameter is decimal separator. like (1,432.123) here dot(.) is third parameter.
Forth parameter is thousand separator. like (1,432) here comma(,) is forth parameter.
Example{
totext("1,432.1234",2) results 1,432.12
totext("1,432.1234",2,' " ') results 1,432"1234
totext("1,432.1234",2,' " ', ' : ') results 1:432,1234
}
Although i think this example may be not so good but i just want to give you an idea. This is for int conversion for date it has 2 parameters.
value to be converted and format of date.
I am trying to fix Microsoft word smart quotes (and other word smart characters) that were inserted into some content due to copy/paste. While we are working on a permanent solution to this I am trying to create a script so we can fix the data as it becomes an issue.
To test it out I"m running the following query: select title from DigArticleArticle where ArticleId = 8249. This correctly retrieves our title, complete with the question mark due to the invalid character. To replace this I tried the following query:
select REPLACE(title, CHAR(8216), char(39)), Title from DigArticleArticle where ArticleID = 8249
This returns null as the first column. Why would my replace return null? Even if the character code isn't found it should still return the original string.
Try:
select REPLACE(title, NCHAR(8216), char(39)), Title from DigArticleArticle where ArticleID = 8249
As mentioned above CHAR() deals with ASCII characters (0-255). In this case Unicode version is needed, NCHAR() can deal with range 0-65535
From the MSDN Docs on the argument for char
CHAR ( integer_expression )
Arguments
integer_expression
Is an integer from 0 through 255. NULL is returned if the integer expression is not in this range.
8216 is larger than 255 so its null
For replace
Return Types
Returns nvarchar if one of the input arguments is of the nvarchar data type; otherwise, REPLACE returns varchar.
Returns NULL if any one of the arguments is NULL.
So you'll always get back null if char(8216) is an argument in replace
As per trekstuff's answer you should use nchar instead