I want to list the trigger no system ending with "_BI" in firebird database,
but no result with this
select * from rdb$triggers
where
rdb$trigger_source is not null
and (coalesce(rdb$system_flag,0) = 0)
and (rdb$trigger_source not starting with 'CHECK' )
and (rdb$trigger_name like '%BI')
but with this syntaxs it gives me a "_bi" and "_BI0U" and "_BI0U" ending result
and (rdb$trigger_name like '%BI%')
but with this syntaxs it gives me null result
and (rdb$trigger_name like '%#_BI')
thank you beforehand
The problem is that the Firebird system tables use CHAR(31) for object names, this means that they are padded with spaces up to the declared length. As a result, use of like '%BI') will not yield results, unless BI are the 30th and 31st character.
There are several solutions
For example you can trim the name before checking
trim(rdb$trigger_name) like '%BI'
or you can require that the name is followed by at least one space
rdb$trigger_name || ' ' like '%BI %'
On a related note, if you want to check if your trigger name ends in _BI, then you should also include the underscore in your condition. And as an underscore in like is a single character matcher, you need to escape it:
trim(rdb$trigger_name) like '%\_BI' escape '\'
Alternatively you could also try to use a regular expressions, as you won't need to trim or otherwise mangle the lefthand side of the expression:
rdb$trigger_name similar to '%\_BI[[:SPACE:]]*' escape '\'
Related
I inserted a bunch of rows with a text field like content='...\n...\n...'.
I didn't use e in front, like conent=e'...\n...\n..., so now \n is not actually displayed as a newline - it's printed as text.
How do I fix this, i.e. how to change every row's content field from '...' to e'...'?
The syntax variant E'string' makes Postgres interpret the given string as Posix escape string. \n encoding a newline is only one of many interpreted escape sequences (even if the most common one). See:
Insert text with single quotes in PostgreSQL
To "re-evaluate" your Posix escape string, you could use a simple function with dynamic SQL like this:
CREATE OR REPLACE FUNCTION f_eval_posix_escapes(INOUT _string text)
LANGUAGE plpgsql AS
$func$
BEGIN
EXECUTE 'SELECT E''' || _string || '''' INTO _string;
END
$func$;
WARNING 1: This is inherently unsafe! We have to evaluate input strings dynamically without quoting and escaping, which allows SQL injection. Only use this in a safe environment.
WARNING 2: Don't apply repeatedly. Or it will misinterpret your actual string with genuine \ characters, etc.
WARNING 3: This simple function is imperfect as it cannot cope with nested single quotes properly. If you have some of those, consider instead:
Unescape a string with escaped newlines and carriage returns
Apply:
UPDATE tbl
SET content = f_eval_posix_escapes(content)
WHERE content IS DISTINCT FROM f_eval_posix_escapes(content);
db<>fiddle here
Note the added WHERE clause to skip updates that would not change anything. See:
How do I (or can I) SELECT DISTINCT on multiple columns?
Use REPLACE in an update query. Something like this: (I'm on mobile so please ignore any typo or syntax erro)
UPDATE table
SET
column = REPLACE(column, '\n', e'\n')
This may sound like a duplicate, but existing solutions does not work.
I need to remove all non-alphanumerics from a varchar field. I'm using the following but it doesn't work in all cases (it works with diamond questionmark characters):
select TRANSLATE(FIELDNAME, '?',
TRANSLATE(FIELDNAME , '', 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789'))
from TABLENAME
What it's doing is the inner translate parse all non-alphanumeric characters, then the outer translate replace them all with a '?'. This seems to work for replacement character�. However, it throws The second, third or fourth argument of the TRANSLATE scalar function is incorrect. which is expected according to IBM:
The TRANSLATE scalar function does not allow replacement of a character by another character which is encoded using a different number of bytes. The second and third arguments of the TRANSLATE scalar function must end with correctly formed characters.
Is there anyway to get around this?
Edit: #Paul Vernon's solution seems to be working:
· 6005308 ??6005308
–6009908 ?6009908
–6011177 ?6011177
��6011183�� ??6011183??
Try regexp_replace(c,'[^\w\d]','') or regexp_replace(c,'[^a-zA-Z\d]','')
E.g.
select regexp_replace(c,'[^a-zA-Z\d]','') from table(values('AB_- C$£abc�$123£')) t(c)
which returns
1
---------
ABCabc123
BTW Note that the allowed regular expression patterns are listed on this page Regular expression control characters
Outside of a set, the following must be preceded with a backslash to be treated as a literal
* ? + [ ( ) { } ^ $ | \ . /
Inside a set, the follow must be preceded with a backslash to be treated as a literal
Characters that must be quoted to be treated as literals are [ ] \
Characters that might need to be quoted, depending on the context are - &
I have registration codes in my PostgreSQL table which are written messy, like MU-321-AB, MU/321/AB, MU 321-AB and so forth...
I would need to clear all of this to get MU321AB.
For this I uses following expression:
SELECT DISTINCT regexp_replace(ccode, '([^A-Za-z0-9])', ''), ...
This expression work as expected in 'NET' but not in PostgreSQL where it 'clears' only first occurrence of unwanted character.
How would I modify regular expression which will replace all unwanted chars in string to get clear code with only letters and numbers?
Use the global flag, but without any capture groups:
SELECT DISTINCT regexp_replace(ccode, '[^A-Za-z0-9]', '', 'g'), ...
Note that the global flag is part of the standard regular expression parser, so .NET is not following the standard in this case. Also, since you do not want anything extracted from the string - you just want to replace some characters - you should not use capture groups ().
I need to update a record, which contains literal percent signs, using PostgreSQL in Railo. The query looks like
<cfquery>
update foo set bar = 'string with % in it %'
</cfQuery>
It throws error as ColdFusion normally interprets it as a wildcard character. I can escape it using the following query.
<cfquery>
update foo set bar = 'string with escaped \% in it \%'
</cfQuery>
However, the record now contains "\%" in the database and will be displayed on the page as "\%".
I found a documentation with an example of escaping percent sign in a SELECT. But it does not work for me: syntax error at or near "ESCAPE".
SELECT emp_discount
FROM Benefits
WHERE emp_discount LIKE '10\%'
ESCAPE '\';
Is there a better to achieve the same goal? The underlining database is PostgreSQL. Thanks!
Queryparameters escape special characters. Yet another reason to use them.
What is wrong with this statement that it is still giving me spaces after the field. This makes me think that the syntax combining the WHEN statements is off. My boss wants them combined in one statement. What am I doing wrong?
Case WHEN LTRIM(RTRIM(cSHortName))= '' Then NULL
WHEN cShortname is NOT NULL THEN
REPLACE (cShortName,SUBSTRING,(cShortName,PATINDEX('%A-Za-z0-9""},1,) ''_
end AS SHORT_NAME
Judging from the code, it seems that you may be trying to strip spaces and non-alphanumeric characters from the beginning and ending of the string.
If so, would this work for you?
I think it provides the substring from the first alphanumeric occurrence to the last.
SELECT
SUBSTRING(
cShortName,
PATINDEX('%A-Za-z0-9',cShortName),
( LEN(cShortName)
-PATINDEX('%A-Za-z0-9',REVERSE(cShortName))
-PATINDEX('%A-Za-z0-9',cShortName)
)
) AS SHORTNAME
Replace TRIM with LTRIM.
You can also test LEN(cShortName) = 0
Ummm there seems to be some problems in this script, but try this.
Case
WHEN LTRIM(RTRIM(cSHortName))= '' Then NULL
WHEN cShortname is NOT NULL THEN REPLACE(cShortName, SUBSTRING(cShortName, PATINDEX('%A-Za-z0-9', 1) , ''), '')
end AS SHORT_NAME
Why do you think it is supposed not to give you spaces after the field?
Edit:
As far as I understand you are trying to remove any characters from the string that do not match this regular expression range [a-zA-Z0-9] (add any other characters that you want to preserve).
I see no clean way to do that in Microsoft SQL Server (you are using Microsoft SQL Server it seems) using the built-in functions. There are some examples on the web that use a temporary table and a while loop, but this is ugly. I would either return the strings as is and process them on the caller side, or write a function that does that using the CLR and invoke it from the select statement.
I hope this helps.