Swift: Clearing .sharedApplication().shortcutItems on application quit - swift

I'm having a very simple problem with my implemented 3D Touch dynamic quick action shortcuts.
I want the shortcuts to be cleared whenever the app is terminated (by double clicking the Home button and swiping up).
I am calling UIApplication.sharedApplication().shortcutItems.removeAll() as follows:
func applicationWillTerminate(application: UIApplication) {
// Called when the application is about to terminate. Save data if appropriate. See also applicationDidEnterBackground:.
// Saves changes in the application's managed object context before the application terminates.
UIApplication .sharedApplication().shortcutItems?.removeAll()
self.saveContext()
}
However it has no effect, and the quick actions still show when 3D touch is used.
If I place UIApplication.sharedApplication().shortcutItems?.removeAll() inside
func applicationDidEnterBackground(application: UIApplication), this works exactly as intended...
I read something about applicationDidEnterBackground being the function used in most cases due to background processing or something...but there has to be a way to achieve what I want when the user terminates the app using the app monitor swipe up.
Thanks

Didn't tried this. But this tweak should work.
Start a background task on applicationWillTerminate and end it after some small delay. In the mean time, you can call 'UIApplication .sharedApplication().shortcutItems?.removeAll()'.
This will hopefully clear the shortcut items.

There are dynamic and static quick actions. The first kind you define through the shortcutItems property of the UIApplication instance (like in your example). The second kind you register in the plist file.
From the documentation:
Your code creates dynamic quick actions, and registers them with your app object, at runtime.
The system registers your static quick actions when your app is installed.
If a user installs an update for your app but has not yet launched the update, pressing your Home screen icon shows the dynamic quick actions for the previously-installed version.
This means that even when the app is closed the system remembers about both kinds of quick actions. While your app is in memory, such as when going into background, the system can still query the UIApplication for the dynamic actions but it must keep some other sort of persistence of quick actions when the app is closed.
I think there is just no guarantee about the point at which the system synchronizes with the dynamic quick actions. My guess is that the system does not necessarily synchronize when closing the app, yours might be an unsupported use case.

Related

How to close System dialogs that appears on app crash?

I'm using xcuitest framework to automate mac application. I get system dialogs when the app is opened again after it crashes. I want to handle the dialog programmatically. But the dialog appears under the process `UserNotificationCenter' instead of the application under test. How can I handle the alert in such case?
You have two options:
Use InterruptionMonitor (documentation, use-case). This
approach is however kinda old and I found, that it does not work for
all dialogs and situations.
Create a method, which will wait for some regular app's button. If the app's button (or tab bar or other such XCUIElement) is visible and hittable after your app started, you can proceed with your test and if it's not, you can wait for the UserNotificationCenter dialog's button and identify&tap it by its string/position.
I'm using the second approach and its working much better, than the InterruptionMonitor. But it really depends on your app layout and use-case.
You should be able to revent it from appearing in the first place. Something like:
defaults write com.apple.CrashReporter DialogType none

NSPopover to start in a detached state

Is there a way to force the NSPopover to start in the detached state? I only see isDetached which is a read-only property for the state of the popover and an NSPopoverDelegate method detachableWindow(forPopover:) which lets me override the window that gets created. I'd like to essentially click a button and have the NSPopover start in the state in this photo.
The style of this window is exactly what a product requirement is and I can't seem to find any NSWindow style settings that would make a window do something like this (nor an NSPanel)
This detached popover functionality seems special in that it:
non-modal, but stays above main app. Able to still interact with the main app just like in Messages how you can still click around and type a new message.
Clicking another app, AppFoo, puts both the main app and the helper window behind AppFoo.
The helper window can be moved around and isn't hidden on app deactivation (another app gets selected).
Has the little, native, grey X in the top left.
If you don't mind calling private API, it's actually pretty simple:
let detach = NSSelectorFromString("detach")
if popover.responds(to: detach) {
popover.perform(detach)
}
No need to even add a delegate. I don't know when this private method was added but it's available at least since macOS 10.13. I suspect it's available since the introduction of NSPopover, though.
Here is the trick.
Use the required delegate method detachableWindowForPopover: to do the work for you, like:
- (void) showPopoverDetached
{
NSWindow* detachedWindow = [self detachableWindowForPopover:nil];
[detachedWindow.windowController showWindow:nil];
}
Seems that the Apple engineers implemented detachableWindowForPopover: on a pretty smart way, I guess it uses the content view controller class, and will always create a singleton like instance of the detached window.
Once detachableWindowForPopover: has called the presented window instance will be re-used no matter when and why it is called, called it directly (from a func like my sample above) or indirectly (e.g. when you drag out, detach, the popover from its original position)
This way they can prevent a popover from being detached 'twice' and we can also implement the detached way programmatically, nice job from them!
Here is a tiny demo of how it works in a real life (tested on macOS 10.13 - 13.0)
https://imgur.com/a/sfc7e6d

Implement swipe gestures in apple watch using watchOS2.0

Hi I need to implement a functionality in my apple watch where when user swipes down will move from one module(InterfaceController1) to another module(InterfaceController2).And when user force touch menu should pop up and tapping on any button in the menu should present a model.
I am able to implement forceTouch menu option. But where as with swipe down to move to second module, i am not able to get any doc about this.
Please let me know if someone is aware of it.
Short Answer:
No, You can't.
Long Answer:
All WKInterface objects are proxy objects(aka Remote UI) that allows you to send queries to real UI Objects.
Reminds that the bundle that contains storyboard is separated with extension bundle. In sand-box concept, Your code that running on extension bundle can't access real UI Objects directly.
So there is no way to react against of user actions except that are available with interface builder(aka sentAction).

Finish activity onPause but still be in backstack?

I'm trying to minimize memory usage in my app, and one of the things I'm doing is calling finish() in the onPause method (which I know is not the best way to do things). For the most part, it seems to be working well, but when the user clicks the back button from the next activity, it logically skips over the finished activity and goes back further. Is it possible to have that activity in the back stack and just get recreated if the user presses back?
No. This conclusion comes from the task and backstack documentation as well as the activity documentation and a general understanding of how a stack data structure works.
A stack data strucure only has 2 possible operations push/put, which adds something to the collection, and pop, which removes it. Stacks folow a last in first out model, or LIFO, where by last thing added - in your case an activity - is the first thing removed when pop is called.
Within the android lifecycle activities are generally popped from the stack when the back button is pressed. At that point onDestroy() is called and the activity is removed (you can verify this by overriding the onDestroy() method and logging the results if you want to check). Alternativly you can force onDestroy() to be called by calling finish() as you are. Finishing an activity effectivly does the same thing as pressing back. The activity is destroyed and must be recreated before it can be added to the stack.
For what you're trying to do the stack would have to incorporate some intermediate state in which an activity does not exist but rather something akin to a reference is held that, when moved to the top, would indicate that the corresponding activity should be recreated. Since this is not how the sack works - it only holds activities - that state cannont exist and so the result you are talking about is not possible.
Your Goal is to minimize memory usage,Just make use of activity life cycle, You can do this alternative(if you need)
-Just leave onCreate() method blank.(only do setContentView(layout))
-Override onResume();
-whatever you were doing in onCreate just copy paste to onResume().
-and In onPause(), Recycle your all bitmaps and set them to null(I think you are using Bitmaps thats why you are very cautious about it ). and remove your views.
Now what will happen, when you launch your new activity, onPause() would be called. that will remove your all bitmap and views. and when you come back, onResume() will be call.(onCreate will not be called). and that will again initialize your view and bitmaps.
No, i don't think that is possible. Once you finish the Activity it's gone. You could, however, implement and handle your own stack. On back pressed, you would just start the closed Activity again.

iOS: Making an App terminate when leave screen

I've build a simple app activating something in hardware, not important.
Now I just want the app to terminate completely if the user leaves the screen, switches apps, gets a call, press the home button, etc.
I'm all mixed up by all the application states, I couldn't find the right place to handle it.
I guess I need to listen to an "going to sleep" event and put a termination command (exit!)
or something like that.
This is easier than what one might think.
In your app's plist file define (check) the option "Application does not run in background" (UIApplicationExitsOnSuspend), and you are done.