Input boxes in while loop - forms

Question

I am wondering how I can differentiate the name on the input box in a while loop so when I post I get 2 separate values. Here is my code:
<form method="post" action="rewarded.php">
<?php
$nameqry="SELECT name FROM kids";
$names=mysqli_query($conn, $nameqry) or die ("Error could not execute name query: " . mysqli_error());
echo "<table>";
while($namerow=mysqli_fetch_array($names)) {
$name=$namerow["name"];
echo "<tr><td>$name will use <input type='text' name='points'> points.</td></tr>";
}
echo "</table>";
echo "<input type='submit' value='Submit'>";
?>
</form>

Answer 1

while($namerow=mysqli_fetch_array($names)) {
$name=$namerow["name"];
echo "<tr><td>$name will use <input type='text' name='points-<?php echo $name; ?>'> points.</td></tr>";
}
each time the code repeated in loop it gives you a different input name.
also you can use name="points[]"
it will return all names in a array

Answer 2

You could make the name a variable and change the variable on each loop.
$input_name_count = 1;
while($namerow=mysqli_fetch_array($names)) {
$name=$namerow["name"];
echo "<tr><td>$name will use <input type='text' name='".$input_name_count."'> points.</td></tr>";
}
Alternatively, if you don't want to use numbers (i.e. points1, points2, etc.or 1,2,3 etc.) make a list of names that you want.
$names_list = ['name', 'name 2', 'hippos'];
Then simply select the item you want from the list using a counter.
$counter = 0;
while($namerow=mysqli_fetch_array($names)) {
$name=$namerow["name"];
echo "<tr><td>$name will use <input type='text' name='".$names_list[$counter]."'> points.</td></tr>";
$counter++;
}