crystal report grouped by company and invoiced
company name invoiceNo which has max(dayslate)? (maxdaysLate)
------------- records -------------------------------
there is a chance of one invoice is assigned to multiple companies,
for example
company1 inv1 30 days late (max(dayslate) col below)
invoiceNo duedate dayslate (cal field today - duedate)
inv1 2016-01-01 30
inv2 2016-01-01 30
Company2 inv3 26 days late(inv1 below has max but already in comp1, so 2nd max)
invoiceNo duedate dayslate
inv1 2016-01-01 30
inv3 2016-01-04 26
need help how to write a formula for max days late record field in a group (ex: inv1)
how to calculate max days as already one is used find second so on...
edit
days late is column which is calculated column (today - due date)
on group want to display which has max days late of that group and its related invoice number
there is chance of one invoice has been assigned to multiple companies, in case any that invoice has max days in 2 groups it should be calculated to only one company group and on other group it should consider the second highest
Related
I have a dataset ab the donor of the organization. Each row starts with donor's ID and name, home address, donate_date_1, donate_amount_1, donate_date_2, donate_amount_2, keep going until 98. It looks similar to this
Donor_ID NAME donate_date_1 donate_amount_1 donate_date_2 donate_amount_2 Total_Amount
0 A Month/Day/Year 100 Month/Day/Year 200 300
1 B Month/Day/Year 200 Month/Day/Year 50 250
2 C Month/Day/Year 1000 Month/Day/Year 500 1500
The dataset has the donors' records from 1982. Every donor starts to donate on different date, ex: 2007 to donor1 is the first donation, but to donor 2 might be the 10th donation.
So here is my question: How can I combine all the dates to see which year the donors donate the most money and create the filter to see how much money was donated in total in the specific period?
I'm trying to get Weekly MTD and YTD values based of hourly data, but I'm having difficulties achieving this.
This is the data I'm working with:
max(Date) - Last day of the week
ISOWeek - Week in question
Value - The data I'm trying to sum
SELECT MAX(ISOWeek) AS [ISOWeek]
,MAX(Date) AS [Date]
,SUM(Value1) AS [MTD]
FROM Table1
GROUP BY ISOWeek, FORMAT(Date,'yyMM')
ORDER BY ISOWeek DESC
This is what that query returns:
ISOWeek Date MTD
29 2020-07-19 367529
28 2020-07-12 367138
27 2020-06-30 103290
27 2020-07-05 266755
26 2020-06-28 346588
25 2020-06-21 337168
This is what I would like to get:
ISOWeek Date MTD
29 2020-07-19 261515
28 2020-07-12 184104
27 2020-07-05 103414
26 2020-06-28 432114
25 2020-06-21 346588
The data has to be grouped by ISOWeek, if it's a week that dips into two months, I'm only interested in the MTD of the month in which the week ends. We have hundreds of values, so the plan is to create a MTD view and a YTD view. If I can get some help with the MTD one, I can get the other one done.
I'm nearly sure that what I'm after has to do with a WHERE clause and DATEADD but I'm not too sure what it should say.
Thank you for taking the time.
I don't really follow the rules you would like to apply, but per dates apply the formula to get weekstart/monthend or what you need. Place the date instead of the current date in the example.
Then group by the modified date.
You could build a date dimension where you have the required dates in some columns (first day of month, first day of week,etc.). This way you get a table with all the dates and the matching result for each.
It might be easier/faster to join it on the requried column.
declare #monthstart date,
#monthend date,
#weekstart date
;
select #monthstart=datefromparts(year(current_timestamp),month(current_timestamp),1);
select #monthend=EOMONTH(getdate(),0);
select #monthstart,#monthend,EOMONTH(getdate(),1) as next_month, EOMONTH(getdate(),-1) as previous_month;
select cast(DATEADD(d,1-DATEPART(WEEKDAY,current_timestamp),CURRENT_TIMESTAMP) as date) as Sunday,
cast(DATEADD(d,2-case when DATEPART(WEEKDAY,current_timestamp)=1 then 8 else DATEPART(WEEKDAY,current_timestamp) end,CURRENT_TIMESTAMP) as date) as Monday
;
I have a table containing courses run by teachers, I want to grab the number of taught days and split these by years and teachers' status.
The table contains the following fields:
id teacher_id course_name course_date course_duration teacher_status
--------------------------------------------------------------------------
1 Teacher_01 Course_AA 2012-02-01 2 volunteer
2 Teacher_02 Course_BB 2012-02-01 7 employee
3 Teacher_03 Course_BB 2013-02-01 7 contractor
4 Teacher_01 Course_AA 2014-02-01 2 paid volunteer
5 Teacher_04 Course_AA 2014-06-01 2 paid volunteer
Teachers may run a course under various statuses: volunteer, paid volunteer, contractor, employee, etc. The status of a given teacher can change through time. The duration of a course is expressed in days.
I can already gather the sum of taught days by teachers, split by status. This is done by
SELECT
teacher_status,
sum(course_duration) AS "Taught days"
FROM
my_table
GROUP BY
teacher_status
;
But data is not normalized and different families of statuses have been mixed. So I want to gather the same info (number of taught days) split:
by 3 statuses: volunteer, paid volunteer, all other statuses,
and by years.
What is expected is:
Year Teacher_status Taught_days
---------------------------------------
2012 volunteer 2
2012 employee 7
2013 contractor 7
2014 paid volunteer 4
I've tried various combinations of aggregate functions, GROUP BY / HAVING / ROLLUP statements but without success. How should I achieve this?
You'll want to select a complex expression and then GROUP BY that, not just by a raw column value. You could either repeat the expression or, in Postgres, also refer to the column alias:
SELECT
EXTRACT(year FROM course_date) as year,
(CASE teacher_status
WHEN 'volunteer' THEN 'volunteer'
WHEN 'paid volunteer' THEN 'paid'
ELSE 'other'
END) AS status,
SUM(course_duration) AS "Taught days"
FROM
my_table
GROUP BY
year,
status;
To get your example result, I have this query
SELECT extract (year from course_date),
teacher_status,
sum(course_duration) AS "Taught days"
FROM
my_table
GROUP BY
extract (year from course_date),
teacher_status;
I'm trying to find a way to obtain the amount of sales made from month to month but only comparing the aggregate total up to the current month's date.
In other words, I want to compare this month's sales up until now, against other months sales up until that month's same day.
Example using today's date as a reference (2016-06-18):
Total sales on January 2016 (*From 2016-01-01 to 2016-01-31*): 1000
Total sales on January 2016 (*From 2016-01-01 to 2016-01-17*): 650
Total sales on February 2016 (*From 2016-02-01 to 2016-01-17*): 670
Total sales on July 2016 (*From 2016-06-01 to current_date - 1*): 680
The structure of my data is as follows:
date sales
2016-01-01 5
2016-01-02 4
2016-01-03 5
2016-01-04 7
.
.
.
When I run the query I would like to have a monthly comparison of the totals mentioned above, so a result that looks like this:
month sales
2016-01 650
2016-02 670
.
.
2016-06 680
So comparing the month-to-date total of each month.
This is what I have tried so far and it seems to be fine, but somehow I always get a small difference whenever I make tests for limit days like the first of each month or the last.
select
order_month,
sum(sales) as sales
from table
where extract (day from order_date::date)
<=
extract (day from current_date::date)
- case when extract (day from current_date::date)=1 then 0 else 1 end
group by 1;
I'm new to Tableau. I have a customer-event table to show which customers attended which events (like webinars, etc). One of fields is sales - which is the sales for that customer 30 days from the date of the event.
custid eventid eventdt 30daysales
1 aa jan 1 $100
1 ab jan 1 $100
2 aa jan 2 $150
Note that customer 1 attended 2 events on the same day. So the sales number is duplicated. If I were building a report for a single event, it's no problem. But when I build a monthly report, I want sum(Sales) = $250 and not $350.
My report sample:
Month eventcount customercount 30daysales
Jan 2 2 $250
With tableau 9, I read that using an LOD formula would allow me to sum sales on a per customer basis. But I'm on Tableau 8.3 and I'm wondering what the manual workaround is.
How do I write the calculated field to compute the 30daysales without duplicating?