I'm trying to get Weekly MTD and YTD values based of hourly data, but I'm having difficulties achieving this.
This is the data I'm working with:
max(Date) - Last day of the week
ISOWeek - Week in question
Value - The data I'm trying to sum
SELECT MAX(ISOWeek) AS [ISOWeek]
,MAX(Date) AS [Date]
,SUM(Value1) AS [MTD]
FROM Table1
GROUP BY ISOWeek, FORMAT(Date,'yyMM')
ORDER BY ISOWeek DESC
This is what that query returns:
ISOWeek Date MTD
29 2020-07-19 367529
28 2020-07-12 367138
27 2020-06-30 103290
27 2020-07-05 266755
26 2020-06-28 346588
25 2020-06-21 337168
This is what I would like to get:
ISOWeek Date MTD
29 2020-07-19 261515
28 2020-07-12 184104
27 2020-07-05 103414
26 2020-06-28 432114
25 2020-06-21 346588
The data has to be grouped by ISOWeek, if it's a week that dips into two months, I'm only interested in the MTD of the month in which the week ends. We have hundreds of values, so the plan is to create a MTD view and a YTD view. If I can get some help with the MTD one, I can get the other one done.
I'm nearly sure that what I'm after has to do with a WHERE clause and DATEADD but I'm not too sure what it should say.
Thank you for taking the time.
I don't really follow the rules you would like to apply, but per dates apply the formula to get weekstart/monthend or what you need. Place the date instead of the current date in the example.
Then group by the modified date.
You could build a date dimension where you have the required dates in some columns (first day of month, first day of week,etc.). This way you get a table with all the dates and the matching result for each.
It might be easier/faster to join it on the requried column.
declare #monthstart date,
#monthend date,
#weekstart date
;
select #monthstart=datefromparts(year(current_timestamp),month(current_timestamp),1);
select #monthend=EOMONTH(getdate(),0);
select #monthstart,#monthend,EOMONTH(getdate(),1) as next_month, EOMONTH(getdate(),-1) as previous_month;
select cast(DATEADD(d,1-DATEPART(WEEKDAY,current_timestamp),CURRENT_TIMESTAMP) as date) as Sunday,
cast(DATEADD(d,2-case when DATEPART(WEEKDAY,current_timestamp)=1 then 8 else DATEPART(WEEKDAY,current_timestamp) end,CURRENT_TIMESTAMP) as date) as Monday
;
Related
Here I'm with another unusual requirement.
Ok, so I have BO webi report (db2 database), and the report is supposed to run on 5th of every month and then it should have only data between a certain billing cycle (26th to 25th of last month)
So basically if I run the report on 5th of March, it should have data of billing cycle** 26th Jan - 25th Feb**.
I know I can manually put the dates in the query every month and run the report, but this report is going to be a schedule. So has to run automatically.
Any ideas ? Any date functions that can particularly tells a query to run between those dates ?
have not tried anything yet, but trying to come up a syntax. no clue :(
If you have whatever date of the same month as 2022-03-05, then you may get your date intervals as follows.
WITH PAR (DT) AS (VALUES '2022-03-05'::DATE)
SELECT
DT - (DAY (DT) - 1) - 2 MONTH + 25 AS DATE_FROM
, DT - (DAY (DT) - 1) - 1 MONTH + 24 AS DATE_TO
FROM PAR;
DATE_FROM
DATE_TO
2022-01-26
2022-02-25
I have 12 monthly tables, one for each month of the year 2019, records are order by an identifier (mmsi) and datetime (timestamp). I have calculated the interval (linetime2) between two consecutive rows. see below (August 2019):
Now I need to convert interval in hours in a new column. How can I do it? Can I run this:
SELECT EXTRACT(epoch FROM linetime2)/3600
or I have to take into account the number of days in a month and year?
I want to use Redshift to count the number of Mondays in a given time range. I've tried using date_part, which returns the day of the week. I can't use a simple count as there are multiple instances on the same day.
if you have dates table reference you can use the following code
select count(distinct my_table.date)
from my_table
where
date_part(dow,my_table.date)=1
and my_table.date between '2015-01-01' and '2016-01-01'
in this case the query will count all Mondays during 2015,
you can change the dates range the the day week .
date_part(dow,my_table.date)=1 -- Monday
date_part(dow,my_table.date)=2 -- Tuesday
and so on
if you don't have dates table , you should create Cartesian product
I have a condition here in which I will have total experience in terms of month and year. For example, two drop down will be there for asking total number of experience in month and year. So if I am working from 1 Jan 2012, then I will write total experience as 3 year and 11 months. Now I have to convert this 3 year and 11 months into date format so that I can save this into database
You could use java.util.Calendar:
Calendar calendar = Calendar.getInstance();
calendar.add(Calendar.MONTH, month);
calendar.add(Calendar.YEAR, year);
Date date = calendar.getTime();
As a word of caution, the day field would be set to today's date. Check the intended behaviour if the current day is outside of the bounds for the target month. For example, setting the month to February when calendar has a day field of 30. It might be wise to set the day to a known, valid value for every month (eg: 1) before setting the month and year.
Use DATE_SUB() function:
Try this:
SELECT DATE_SUB(DATE_SUB(CURRENT_DATE(), INTERVAL 3 YEAR), INTERVAL 11 MONTH);
You can use mysql's date_sub() function or <date> - interval <expression> unit syntax to subtract an interval from a date.
select date_sub(curdate(),interval '3-11' YEAR_MONTH) as start_date
UPDATE:
Following the conversation between the OP and #eggyal, the OP need to replace the period in the incoming data with - and construct an insert statement as follows:
insert into mytable (...,join_date,...) values (...,date_sub(curdate(),interval '3-11' YEAR_MONTH),...)
NEWBIE at work! I am trying to create a simple summary that counts the number of customer visits and groups by 1) date and 2) hour, BUT outputs this:
Date Day of Wk Hour #visits
8/12/2013 Monday 0 5
8/12/2013 Monday 1 7
8/12/2013 Monday 6 10
8/13/2013 Tuesday 14 25
8/13/2013 Tuesday 16 4
We are on military time, so 14 = 2:00 pm
Select
TPM300_PAT_VISIT.adm_ts as [Date]
,TPM300_PAT_VISIT.adm_ts as [Day of Week]
,TPM300_PAT_VISIT.adm_ts as [Hour]
,count(TPM300_PAT_VISIT.vst_ext_id) as [Total Visits]
From
TPM300_PAT_VISIT
Where
TPM300_PAT_VISIT.adm_srv_cd='22126'
and TPM300_PAT_VISIT.adm_ts between '07-01-2013' and '08-01-2013'
Group by
cast(TPM300_PAT_VISIT.adm_ts as DATE)
,datepart(weekday,TPM300_PAT_VISIT.adm_ts)
,datepart(hour,TPM300_PAT_VISIT.adm_ts)
Order by
CAST(TPM300_PAT_VISIT.adm_ts as DATE)
,DATEPART(hour,TPM300_PAT_VISIT.adm_ts)
This should solve the problem:
; With Streamlined as (
SELECT
DATEADD(hour,DATEDIFF(hour,'20010101',adm_ts),'20010101') as RoundedTime,
vst_ext_id
from
TPM300_PAT_VISIT
where
adm_srv_cd='22126' and
adm_ts >= '20130701' and
adm_ts < '20130801'
)
Select
CONVERT(date,RoundedTime) as [Date],
DATEPART(weekday,RoundedTime) as [Day of Week],
DATEPART(hour,RoundedTime) as [Hour],
count(vst_ext_id) as [Total Visits]
From
Streamlined
Group by
RoundedTime
Order by
CONVERT(date,RoundedTime),
DATEPART(hour,RoundedTime)
In the CTE (Streamlined)'s select list, we floor each adm_ts value down to the nearest hour using DATEADD/DATEDIFF. This makes the subsequent grouping easier to specify.
We also specify a semi-open interval for the datetime comparisons, which makes sure we include everything in July (including stuff that happened at 23:59:59.997) whilst excluding events that happened at midnight on 1st August. This is frequently the correct type of comparison to use when working with continuous data (floats, datetimes, etc), but means you have to abandon BETWEEN.
I'm also specifying the dates as YYYYMMDD which is a safe, unambiguous format. Your original query could have been interpreted as either January 7th - January 8th or 1st July - 1st August, depending on the settings of whatever account you use to connect to SQL Server. Better yet, if these dates are being supplied by some other (non-SQL) code, would be for them to be passed as datetimes in the first place, to avoid any formatting issues.