ID THINGS QTY PRICE
123 bag 1 25
123 shoes 1 10
123 pen 1 40
123 dress 1 20
The result in my report:
I put all the fields in sub_reports under group footer
bag 25x1 25
shoes 10x1 10
pen 40x1 40
dress 20x1 20
How can I merge them resulting to:
Materials 95x4 95
Can you help me.
As Siva suggested, you should probably have a Group created using your ID field, then Insert summary fields for sum(price) and sum(quantity) at the ID group. This will insert totals for both at the group footer
Related
I'm getting errors with PostgreSQL when am writing a group by query,
am sure someone will tell me to put all the columns I've selected in group by, but that will not give me the correct results.
Am writing a query that will select all the vehicles in the database and group the results by vehicles, giving me the total distance and cost for a given period.
Here is how am doing the query.
SELECT i.vehicle AS vehicle,
i.costcenter AS costCenter,
i.department AS department,
SUM(i.quantity) AS liters,
SUM(i.totalcost) AS Totalcost,
v.model AS model,
v.vtype AS vtype
FROM fuelissuances AS i
LEFT JOIN vehicles AS v ON i.vehicle = v.id
WHERE i.dates::text LIKE '%2019-03%' AND i.deleted_at IS NULL
GROUP BY i.vehicle;
If I put all the columns that are in the select in the group bt, the results will not be correct.
How do i go about this without putting all the columns in group by and creating sub-queries?
The fuel table looks like:
vehicle dates department quantity totalcost
1 2019-01-01 102 12 1200
1 2019-01-05 102 15 1500
1 2019-01-13 102 18 1800
1 2019-01-22 102 10 1000
2 2019-01-01 102 12 1260
2 2019-01-05 102 19 1995
2 2019-01-13 102 28 2940
Vehicle Table
id model vtype
1 1 2
2 4 6
2 5 7
This is the results i expect from the query
vehicle dates department quantity totalcost model vtype
1 2019-01-01 102 12 1200 1 2
1 2019-01-05 102 15 1500 1 2
1 2019-01-13 102 18 1800 1 2
1 2019-01-22 102 10 1000 1 2
1 2019-01-18 102 10 1000 1 2
1 65 6500
2 2019-01-01 102 12 1260 5 7
2 2019-01-05 102 19 1995 5 7
2 2019-01-13 102 28 2940 5 7
1 45 6195
Your query doesn't really make sense. Apparently there can be multiple departments and costcenters per vehicle in the fuelissuances table - which of those should be returned?
One way to deal with that, is to return all of them, e.g. as an array:
SELECT i.vehicle,
array_agg(i.costcenter) as costcenters,
array_agg(i.department) as departments,
SUM(i.quantity) AS liters,
SUM(i.totalcost) AS Totalcost,
v.model,
v.vtype
FROM fuelissuances AS i
LEFT JOIN vehicles AS v ON i.vehicle = v.id
WHERE i.dates >= date '2019-03-01'
and i.date < date '2019-04-01'
AND i.deleted_at IS NULL
group by i.vehicle, v.model, v.vtype;
Instead of an array, you could also return a comma separated lists of those values, e.g. string_agg(i.costcenter, ',') as costcenters.
Adding the columns v.model and v.vtype won't (shouldn't) change anything as the group by i.vehicle will only return a single vehicle anyway and thus the model and vtype won't change for that in the group.
Note that I removed the useless aliases and replaced the condition on the date with a proper range condition that can make use of an index on the dates column.
Edit
Based on your new sample data, you want a running total, rather than a "regular" aggregation. This can easily be done using window functions
SELECT i.vehicle,
i.costcenter,
i.department,
SUM(i.quantity) over (w) AS liters,
SUM(i.totalcost) over (w) AS Totalcost,
v.model,
v.vtype
FROM fuelissuances AS i
LEFT JOIN vehicles AS v ON i.vehicle = v.id
WHERE i.dates >= date '2019-01-01'
and i.dates < date '2019-02-01'
AND i.deleted_at IS NULL
window w as (partition by i.vehicle order by i.dates)
order by i.vehicle, i.dates;
I would not create those "total" lines using SQL, but rather in your front end that display the data.
Online example: https://rextester.com/CRJZ27446
You need to use a nested query to get those SUM you want inside that query.
SELECT i.vehicle AS vehicle,
i.costcenter AS costCenter,
i.department AS department,
(SELECT SUM(i.quantity) FROM TABLES WHERE CONDITIONS GROUP BY vehicle) AS liters,
(SELECT SUM(i.totalcost) FROM TABLES WHERE CONDITIONS GROUP BY vehicle) AS Totalcost,
v.model AS model,
v.vtype AS vtype
FROM fuelissuances AS i
LEFT JOIN vehicles AS v ON i.vehicle = v.id
WHERE i.dates::text LIKE '%2019-03%' AND i.deleted_at IS NULL;
I have a table with the following data for sales and inventory (oh):
category sales oh item_num
Clothes 12 10 1
Clothes 11 10 1
Clothes 10 10 1
Clothes 5 10 1
Clothes 8 10 1
Clothes 4 10 1
Clothes 23 10 2
Clothes 5 10 2
Clothes 20 10 2
Clothes 5 10 2
Clothes 13 10 2
Clothes 9 10 2
Food 6 25 3
Food 8 25 3
Food 7 25 3
Food 14 25 3
I am trying to query this table to get a sum of both the sales and oh columns by category:
SELECT category, SUM(sales) AS sales, SUM(oh) AS oh
FROM data
GROUP BY category
However, the problem is I need the SUM(oh) to only sum distinct items but the SUM(sales) to sum all the values. So the result should be:
category sales oh
Clothes 125 20
Food 35 25
I tried SUM(DISTINCT oh), but that only works for distinct oh values not distinct items. I really need something like SUM(DISTINCT(item_num) oh).
I experimented with various window functions, but could not come up with a solution. Does anyone know how to return this kind of sum on a unique key?
Here's how I'd do it:
SELECT category, SUM(sales) AS sales, SUM(oh) AS oh
FROM (
SELECT category, SUM(sales) AS sales, oh
FROM data
GROUP BY category, item_num, oh
) ttl
GROUP BY category;
Basically tackle the problem in stages. First group up the items by category and item number to get the sum of sales then group and sum by category to get the sum of oh.
Result:
category | sales | oh
----------+-------+----
Food | 35 | 25
Clothes | 125 | 20
(2 rows)
Edit: Included simplified query.
Consider the code below:
q)tab:flip `items`sales`prices!(`nut`bolt`cam`cog;6 8 0 3;10 20 15 20)
q)tab
items sales prices
------------------
nut 6 10
bolt 8 20
cam 0 15
cog 3 20
I would like to duplicate the prices column. I can write a query like this:
q)update prices_copy: prices from tab
I also can write a query like this:
q)select items, sales, prices, prices_copy: first prices by items from tab
Both would work. I would like to know how the "by" version would work and the motivation for writing each version. I cannot help but think the "by" version is more thinking in rows.
Your initial query would be ideally what you want for your duplicate column requirement.
The by creates groups of the column items in your example and collapses every other column in the select query according to the indices calculated from grouping items. More info on by here - http://code.kx.com/wiki/Reference/select and http://code.kx.com/wiki/JB:QforMortals2/queries_q_sql#The_by_Phrase
In your example, the column items is already unique and so no collapsing into groups is actually performed, however, the by will create nested lists from the other columns (i.e. lists of lists). The use of first will just un-nest the items column, thus collapsing it to a normal (long-typed) vector.
When the grouping is finished the by columns are used as the key column[s] of the result and you will see this by the use of a vertical line to the right hand side of the key column[s]. All other columns within the select query are placed to the right hand side of the key.
The logic of the by version coincidentally creates a copy of prices. But by changes the order:
q)ungroup select sales, prices by items from tab
items sales prices
------------------
bolt 8 20
cam 0 15
cog 3 20
nut 6 10
q)tab
items sales prices
------------------
nut 6 10
bolt 8 20
cam 0 15
cog 3 20
The by version works only because items is unique. For a tab with multiple values for item eg. 8#tab, the query only produces 4 values for prices_copy.
q)select items, sales, prices, prices_copy: first prices by items from 8#tab
items| items sales prices prices_copy
-----| ----------------------------------
bolt | bolt bolt 8 8 20 20 20
cam | cam cam 0 0 15 15 15
cog | cog cog 3 3 20 20 20
nut | nut nut 6 6 10 10 10
There is a fundamental difference between a simple update and update by queries.
Let's explore it by adding an extra column brand to the table
tab2:flip `items`sales`prices`brand!(`nut`bolt`cam`cog`nut`bolt`cam`cog;6 8 0 3 1 2 3 4;10 20 15 20 30 40 50 60;`b1`b1`b1`b1`b2`b2`b2`b2)
The following will now simply copy the column :
asc update prices_copy: prices from tab2
However, the following query is copying the first item price regardless of the brand and updating it for all other brands of same item.
asc ungroup select sales, prices,brand, prices_copy: first prices by items from tab2
items sales prices brand prices_copy
------------------------------------
bolt 2 40 b2 20
bolt 8 20 b1 20 //b2 price
cam 0 15 b1 15 //b2 price
cam 3 50 b2 15
cog 3 20 b1 20
cog 4 60 b2 20 //b2 price
nut 1 30 b2 10 //b2 price
nut 6 10 b1 10
update by might be useful in the case where you want to copy the max price of the items regardless of the brand or some other aggregation query.
asc ungroup select sales, prices,brand, prices_copy: max prices by items from tab2
items sales prices brand prices_copy
------------------------------------
bolt 2 40 b2 40
bolt 8 20 b1 40 //max price in bolts regardless of the brand
cam 0 15 b1 50
cam 3 50 b2 50
cog 3 20 b1 60
cog 4 60 b2 60
nut 1 30 b2 30
nut 6 10 b1 30
I have one table
id employee leave_days leave_type type
1 ABC 10 sick remove
2 ABC 20 sick add
3 ABC 15 Annual remove
4 ABC 50 Annual add
5 XYZ 10 sick remove
6 XYZ 20 sick add
7 XYZ 15 Annual remove
8 XYZ 50 Annual add
From the above table I will group by the column name called leave_type and then I will merge rows and the output should be as follows.
I have to group by column name leave_type and add new column called leave_allocated . In the leave_allocated column, the column type with value add only will come.
id employee leave_days leave_type leave_allocated
1 ABC 10 sick 20
2 ABC 15 Annual 50
3 XYZ 10 sick 20
4 XYZ 15 Annual 50
I tried with sub query I could not match the inner query with outer query .
This should help
SELECT id,
employee,
leave_dates,
leave type,
(SELECT leave_days
FROM TABLE t2
WHERE t2.id = t1.id
AND t2.type = 'add'
) leave_allocated
FROM TABLE t1
WHERE t1.type = 'remove'
Is there a formula for this:
mainId productId groupId product price qty
456 123 555 book 10 2
456 789 555 book 10 2
222 125 888 pencil 20 5
222 125 859 pencil 20 1
it shows (from sub report to main report):
product: book
Computation: 10x2 20
product: book
Computation: 10x2 20
Total 40
I want the result to be like this if data produce are the same like the one above:
product: book
Computation: 10x4 40
Total 40
if not the same data like with the mainId 222 the result should be like this:
product: pencil
Computation: 20x5 100
product: pencil
Computation: 20x1 20
Total 120
In sub report I group it by productId
Group Header: [Group#1 Name]
Details:
Group Footer: [product]
Computation: [computation (10x2)] [total (20)]
In main report I group it by productId too. I group the Subreport in Group Header. In the Page Footer is the Grand Total which is 20.
looks like you should group on GroupID rather than productid?