I would like to see if the letter inputted by the user matches any of the words in a dictionary.
Could someone please help me do this? Thank you!
words = {'apple', 'banana', 'bee', 'salad', 'corn', 'elephant', 'pterodactyl'};
user_letter_input = input('Please enter the first letter of a word: ');
for i = words
if (i starts with user_letter_input)
disp(['Your new word is: ' i]);
end
end
You can use:
if(i{1}(1) == user_letter_input)
Here's a different, admittedly more hackish approach:
w = char(words); %// convert to 2D char array, padding with spaces
result = find(w(:,1)==user_letter_input); %// test equality with first column
result will be a vector with the indices of all matching words. For example,
words = {'apple', 'banana', 'bee', 'salad', 'corn', 'elephant', 'pterodactyl'};
user_letter_input = 'b'
will give
result =
2
3
Related
How can I go about doing this? So far I've opened the file like this
fileID = fopen('hamlet.txt'.'r');
[A,count] = fscanf(fileID, '%s');
fclose(fileID);
Getting spaces from the file
First, if you want to capture spaces, you'll need to change your format specifier. %s reads only non-whitespace characters.
>> fileID = fopen('space.txt','r');
>> A = fscanf(fileID, '%s');
>> fclose(fileID);
>> A
A = Thistexthasspacesinit.
Instead, we can use %c:
>> fileID = fopen('space.txt','r');
>> A = fscanf(fileID, '%c');
>> fclose(fileID);
>> A
A = This text has spaces in it.
Mapping between characters and values (array indices)
We could create a character array that contains all of the target characters to look for:
search_chars = ['A':'Z', 'a':'z', ',', '.', ' '];
That would work, but to map the character to a position in the array you'd have to do something like:
>> char_pos = find(search_chars == 'q')
char_pos = 43
You could also use containters.Map, but that seems like overkill.
Instead, let's use the ASCII value of each character. For convenience, we'll use only values 1:126 (0 is NUL, and 127 is DEL. We should never encounter either of those.) Converting from characters to their ASCII code is easy:
>> c = 'q'
c = s
>> a = uint8(c) % MATLAB actually does this using double(). Seems wasteful to me.
a = 115
>> c2 = char(a)
c2 = s
Note that by doing this, you're counting characters that are not in your desired list like ! and *. If that's a problem, then use search_chars and figure out how you want to map from characters to indices.
Looping solution
The most intuitive way to count each character is a loop. For each character in A, find its ASCII code and increment the counter array at that index.
char_count = zeros(1, 126);
for current_char = A
c = uint8(current_char);
char_count(c) = char_count(c) + 1;
end
Now you've got an array of counts for each character with ASCII codes from 1 to 126. To find out how many instances of 's' there are, we can just use its ASCII code as an index:
>> char_count(115)
ans = 4
We can even use the character itself as an index:
>> char_count('s')
ans = 4
Vectorized solution
As you can see with that last example, MATLAB's weak typing makes characters and their ASCII codes pretty much equivalent. In fact:
>> 's' == 115
ans = 1
That means that we can use implicit broadcasting and == to create a logical 2D array where L(c,a) == 1 if character c in our string A has an ASCII code of a. Then we can get the count for each ASCII code by summing along the columns.
L = (A.' == [1:126]);
char_count = sum(L, 1);
A one-liner
Just for fun, I'll show one more way to do this: histcounts. This is meant to put values into bins, but as we said before, characters can be treated like values.
char_count = histcounts(uint8(A), 1:126);
There are dozens of other possibilities, for instance you could use the search_chars array and ismember(), but this should be a good starting point.
With [A,count] = fscanf(fileID, '%s'); you'll only count all string letters, doesn't matter which one. You can use regexp here which search for each letter you specify and will put it in a cell array. It consists of fields which contains the indices of your occuring letters. In the end you only sum the number of indices and you have the count for each letter:
fileID = fopen('hamlet.txt'.'r');
A = fscanf(fileID, '%s');
indexCellArray = regexp(A,{'A','B','C','D',... %I'm too lazy to add the other letters now^^
'a','b','c','d',...
','.' '};
letterCount = cellfun(#(x) numel(x),indexCellArray);
fclose(fileID);
Maybe you put the cell array in a struct where you can give fieldnames for the letters, otherwise you might loose track which count belongs to which number.
Maybe there's much easier solution, cause this one is kind of exhausting to put all the letters in the regexp but it works.
I am trying to capitalize the first and last letter of only the three letter words in a string. So far, I have tried
spaces = strfind(str, ' ');
spaces = [0 spaces];
lw = diff(spaces);
lw3 = find(lw ==4);
a3 = lw-1;
b3 = spaces(a3+1);
b4 = b3 + 2 ;
str(b3) = upper(str(b3));
str(b4) = upper(str(b4);
we had to find where the 3 letter words were first so that is what the first 4 lines of code are and then the others are trying to get it so that it will find where the first and last letters are and then capitalize them?
I would use regular expressions to identity the 3-letter words and then use regexprep combined with an anonymous function to perform the case-conversion.
str = 'abcd efg hijk lmn';
% Custom function to capitalize the first and last letter of a word
f = #(x)[upper(x(1)), x(2:end-1), upper(x(end))];
% This will match 3-letter words and apply function f to them
out = regexprep(str, '\<\w{3}\>', '${f($0)}')
% abcd EfG hijk LmN
Regular expressions are definitely the way to go. I am going to suggest a slightly different route, and that is to return the indices using the tokenExtents flag for regexpi:
str = 'abcd efg hijk lmn';
% Tokenize the words and return the first and last index of each
idx = regexpi(str, '(\<w{3}\>)', 'tokenExtents');
% Convert those indices to upper case
str([idx{:}]) = upper(str([idx{:}]));
Using the matlab ipusum function from the File Exchange, I generated a 1000 paragraph random text string with mean word length 4 +/- 2.
str = lower(matlab_ipsum('WordLength', 4, 'Paragraphs', 1000));
The result was a 177,575 character string with 5,531 3-letter words. I used timeit to check the execution time of using regexprep and regexpi with tokenExtents. Using regexpi is an order of magnitude faster:
regexpi = 0.013979s
regexprep = 0.14401s
In the following code, I check to see if the first letter is in the dictionary of words and if the length of the word matches. If it does, return the word. Otherwise, return an error statement.
words = {'apple', 'banana', 'bee', 'salad', 'corn', 'elephant', 'pterodactyl'};
user_letter_input = input('Please enter the first letter of a word: ', 's');
user_num_input = input('Please enter how long you would like the word to be: ');
for i = words
if ((i{1}(1) == user_letter_input) && (length(i{1}) == user_num_input))
result = i;
else
result = 0;
end
end
if (result == 0)
disp('There are no matching words');
else
disp(['Your new word is: ' result]);
end
The comparison returns i being 'apple' if I type a for the first input and 5 for the second input - as it should.
However, at the end when I try to see if (result == 0), it does not display the new word, even though result is not 0.
Could someone help me fix this please?
You are overwriting result each time through your for loop. The only time that result will be 0 after the loop, is if the last word in words matches your criteria.
I would recommend storing the matching words in a separate cell array, or have a boolean array to indicate which words match. In my opinion, using a boolean is better as it takes less memory and doesn't duplicate data.
words = {'apple', 'banana', 'bee', 'salad', 'corn', 'elephant', 'pterodactyl'};
user_letter_input = input('Please enter the first letter of a word: ', 's');
user_num_input = input('Please enter how long you would like the word to be: ');
isMatch = false(size(words));
for k = 1:numel(words)
word = words{k};
isMatch(k) = word(1) == lower(user_letter_input) && ...
numel(word) == user_num_input;
end
if ~any(isMatch)
disp('There are no matching words');
else
disp(['Your matching words are:', sprintf(' %s', words{isMatch})]);
end
Also, as a side note don't use the cell array in the for loop like that. That leads to a lot of confusion. Also avoid using i as a loop variable.
You're overwriting result each time the word in your dictionary doesn't match. The only time this will work is if the last word matches. You need to change both your initialization of result and your loop:
result = 0; %// assume that no words match
for i = words
if (....
result = 1; %// we found a match... record it
end
%// no else! If we get no match, result will already be 0
end
You can use a flag to detect whether a match was found:
breakflag = 0
for i = words
if ((i{1}(1) == user_letter_input) && (length(i{1}) == user_num_input))
breakflag = 1;
break;
end
end
if (breakflag == 0)
disp('There are no matching words');
else
disp(['Your new word is: ' i]);
end
I have a set of documents containing pre-processed texts from html pages. They are already given to me. I want to extract only the words from it. I do not want any numbers or common words or any single letters to be extracted. The first problem I am facing is this.
Suppose I have a cell array :
{'!' '!!' '!!!!)' '!!!!thanks' '!!dogsbreath' '!)' '!--[endif]--' '!--[if'}
I want to make the cell array having only the words - like this.
{'!!!!thanks' '!!dogsbreath' '!--[endif]--' '!--[if'}
And then convert this to this cell array
{'thanks' 'dogsbreath' 'endif' 'if'}
Is there any way to do this ?
Updated Requirement : Thanks to all of your answers. However I am facing a problem ! Let me illustrate this (Please note that the cell values are extracted text from HTML documents and hence may contain non ASCII values) -
{'!/bin/bash' '![endif]' '!take-a-long' '!–photo'}
This gives me the answer
{'bin' 'bash' 'endif' 'take' 'a' 'long' 'â' 'photo' }
My Questions:
Why is bin/bash and take-a-long being separated into three cells ? Its not a problem for me but still why? Can this be avoided. I mean all words coming from a single cell being combined into one.
Notice that in '!–photo' there exists an non-ascii character â which esentially means a. Can a step be incorporated such that this transformation is automatic?
I noticed that the text "it? __________ About the Author:" gives me "__________" as a word. Why is this so ?
Also the text "2. areoplane 3. cactus 4. a_rinny_boo... 5. trumpet 6. window 7. curtain ... 173. gypsy_wagon..." returns a word as 'areoplane' 'cactus' 'a_rinny_boo' 'trumpet' 'window' 'curtain' 'gypsy_wagon'. I want the words 'a_rinny_boo' and ''gypsy_wagon to be 'a' 'rinny' 'boo' 'gypsy' 'wagon'. Can this be done ?
Update 1 Following all the suggestions I have written down a function which does most of the things except the above two newly asked questions.
function [Text_Data] = raw_txt_gn(filename)
% This function will convert the text documnets into raw text
% It will remove all commas empty cells and other special characters
% It will also convert all the words of the text documents into lowercase
T = textread(filename, '%s');
% find all the important indices
ind1=find(ismember(T,':WebpageTitle:'));
T1 = T(ind1+1:end,1);
% Remove things which are not basically words
not_words = {'##','-',':ImageSurroundingText:',':WebpageDescription:',':WebpageKeywords:',' '};
T2 = []; count = 1;
for j=1:length(T1)
x = T1{j};
ind=find(ismember(not_words,x), 1);
if isempty(ind)
B = regexp(x, '\w*', 'match');
B(cellfun('isempty', B)) = []; % Clean out empty cells
B = [B{:}]; % Flatten cell array
% convert the string into lowecase
% so that while generating the features the case sensitivity is
% handled well
x = lower(B);
T2{count,1} = x;
count = count+1;
end
end
T2 = T2(~cellfun('isempty',T2));
% Getting the common words in the english language
% found from Wikipedia
not_words2 = {'the','be','to','of','and','a','in','that','have','i'};
not_words2 = [not_words2, 'it' 'for' 'not' 'on' 'with' 'he' 'as' 'you' 'do' 'at'];
not_words2 = [not_words2, 'this' 'but' 'his' 'by' 'from' 'they' 'we' 'say' 'her' 'she'];
not_words2 = [not_words2, 'or' 'an' 'will' 'my' 'one' 'all' 'would' 'there' 'their' 'what'];
not_words2 = [not_words2, 'so' 'up' 'out' 'if' 'about' 'who' 'get' 'which' 'go' 'me'];
not_words2 = [not_words2, 'when' 'make' 'can' 'like' 'time' 'no' 'just' 'him' 'know' 'take'];
not_words2 = [not_words2, 'people' 'into' 'year' 'your' 'good' 'some' 'could' 'them' 'see' 'other'];
not_words2 = [not_words2, 'than' 'then' 'now' 'look' 'only' 'come' 'its' 'over' 'think' 'also'];
not_words2 = [not_words2, 'back' 'after' 'use' 'two' 'how' 'our' 'work' 'first' 'well' 'way'];
not_words2 = [not_words2, 'even' 'new' 'want' 'because' 'any' 'these' 'give' 'day' 'most' 'us'];
for j=1:length(T2)
x = T2{j};
% if a particular cell contains only numbers then make it empty
if sum(isstrprop(x, 'digit'))~=0
T2{j} = [];
end
% also remove single character cells
if length(x)==1
T2{j} = [];
end
% also remove the most common words from the dictionary
% the common words are taken from the english dicitonary (source
% wikipedia)
ind=find(ismember(not_words2,x), 1);
if isempty(ind)==0
T2{j} = [];
end
end
Text_Data = T2(~cellfun('isempty',T2));
Update 2
I found this code in here which tells me how to check for non-ascii characters. Incorporating this code snippet in Matlab as
% remove the non-ascii characters
if all(x < 128)
else
T2{j} = [];
end
and then removing the empty cells it seems my second requirement is fulfilled though the text containing a part of non-ascii characters completely disappears.
Can my final requirements be completed ? Most of them concerns the character '_' and '-'.
A regexp approach to go directly to the final step:
A = {'!' '!!' '!!!!)' '!!!!thanks' '!!dogsbreath' '!)' '!--[endif]--' '!--[if'};
B = regexp(A, '\w*', 'match');
B(cellfun('isempty', B)) = []; % Clean out empty cells
B = [B{:}]; % Flatten cell array
Which matches any alphabetic, numeric, or underscore character. For the sample case we get a 1x4 cell array:
B =
'thanks' 'dogsbreath' 'endif' 'if'
Edit:
Why is bin/bash and take-a-long being separated into three cells ? Its not a problem for me but still why? Can this be avoided. I mean all words coming from a single cell being combined into one.
Because I'm flattening the cell arrays to remove nested cells. If you remove B = [B{:}]; each cell will have a nested cell inside containing all of the matches for the input cell array. You can combine these however you want after.
Notice that in '!–photo' there exists an non-ascii character â which esentially means a. Can a step be incorporated such that this transformation is automatic?
Yes, you'll have to make it based on the character codes.
I noticed that the text "it? __________ About the Author:" gives me "__________" as a word. Why is this so ?
As I said, the regex matches alphabetic, numeric, or underscore characters. You can change your filter to exclude _, which will also address the fourth bullet point: B = regexp(A, '[a-zA-Z0-9]*', 'match'); This will match a-z, A-Z, and 0-9 only. This will also exclude the non-ASCII characters, which it seems like the \w* flag matches.
I think #excaza's solution would be the go-to approach, but here's an alternative one with isstrprop using its optional input argument 'alpha' to look for alphabets -
A(cellfun(#(x) any(isstrprop(x, 'alpha')), A))
Sample run -
>> A
A =
'!' '!!' '!!!!)' '!!!!thanks' '!!dogsbreath' '!)' '!--[endif]--' '!--[if'
>> A(cellfun(#(x) any(isstrprop(x, 'alpha')), A))
ans =
'!!!!thanks' '!!dogsbreath' '!--[endif]--' '!--[if'
To get to the final destination, you can tweak this approach a bit, like so -
B = cellfun(#(x) x(isstrprop(x, 'alpha')), A,'Uni',0);
out = B(~cellfun('isempty',B))
Sample run -
A =
'!' '!!' '!!!!)' '!!!!thanks' '!!dogsbreath' '!)' '!--[endif]--' '!--[if'
out =
'thanks' 'dogsbreath' 'endif' 'if'
I am trying to extract bi-grams from a set of words and store them in a matrix. what I want is to insert the word in the first raw and all the bi-grams related to that word
for example: if I have the following string 'database file there' my output should be:
database file there
da fi th
at il he
ta le er
ab re
..
I have tried this but it gives me only the bigram without the original word
collection = fileread('e:\m.txt');
collection = regexprep(collection,'<.*?>','');
collection = lower(collection);
collection = regexprep(collection,'\W',' ');
collection = strtrim(regexprep(collection,'\s*',' '));
temp = regexprep(collection,' ',''',''');
eval(['words = {''',temp,'''};']);
word = char(words(1));
word2 = regexp(word, sprintf('\\w{1,%d}', 1), 'match');
bi = cellfun(#(x,y) [x '' y], word2(1:end-1)', word2(2:end)','un',0);
this is only for the first word however, i want to do that for every word in the "words" matrix 1X1000
is there an efficient way to accomplish this as I will deal with around 1 million words?
I am new to Matlab and if there any resource to explain how to deal with matrix (update elements, delete, ...) will be helpful
regards,
Ashraf
If you were looking to get a cell array as the output, this might work for you -
input_str = 'database file there' %// input
str1_split = regexp(input_str,'\s','Split'); %// split words into cells
NW = numel(str1_split); %// number of words
char_arr1 = char(str1_split'); %//' convert split cells into a char array
ind1 = bsxfun(#plus,[1:NW*2]',[0:size(char_arr1,2)-2]*NW); %//' get indices
%// to be used for indexing into char array
t1 = reshape(char_arr1(ind1),NW,2,[]);
t2 = reshape(permute(t1,[2 1 3]),2,[])'; %//' char array with rows for each pair
out = reshape(mat2cell(t2,ones(1,size(t2,1)),2),NW,[])'; %//'
out(reshape(any(t2==' ',2),NW,[])')={''}; %//' Use only paired-elements cells
out = [str1_split ; out] %// output
Code Output -
input_str =
database file there
out =
'database' 'file' 'there'
'da' 'fi' 'th'
'at' 'il' 'he'
'ta' 'le' 'er'
'ab' '' 're'
'ba' '' ''
'as' '' ''
'se' '' ''