I am quite new to OrientDB and have some trouble that keeps me for days now:
I have two classes. "PAGES" is holding information about pages, "CHECKS" contains information about checks on these pages.
They are connected by a 1 > n linkset called page2chck
It looks like this
Class PAGES
+----+---------+---------------------------------+
| Id | Title | Url |
+----+-------------------------------------------+
| 30 | Blahbla | http://www.test.com/test.html |
+----+-------------------------------------------+
| 40 | sometxt | http://www.foo.org/dummy.html |
+----+-------------------------------------------+
Class CHECKS
+---------------------+---------+
| Lastcheck | Status |
+-------------------------------+
| 2016-02-01 23:58:12 | OK |
+-------------------------------+
| 2016-02-02 22:04:24 | OK |
+-------------------------------+
| 2016-02-02 23:57:55 | ERR |
+-------------------------------+
| 2016-02-01 23:59:01 | OK |
+-------------------------------+
I created a linkset like this
CREATE LINK page2chck TYPE LINKSET FROM CHECKS.CH_PID to PAGES.Id INVERSE
Now I want to retrieve all Pages that do not have a check after 2016-02-03, and I want to show the last date they were checked and the status
What I tried was:
select Title, page2chck.Lastcheck, page2chck.Status from PAGES
where date.asLong(page2chck.Lastcheck) < 1454540400
But it returns an empty result
However, to test the integrity of the relation I ran
select Title from PAGES where page2chck.CH_PID=30
which correctly returns "BlahBlah"
So I tried
page2chck.Lastcheck, page2chck.Status, Title from PAGES
where page2chck.CH_PID=30
which returned
# |#CLASS|page2chck|page2chck|Title
----+------+---------+---------+---------------------------------
0 |null |[441] |[441] |BlahBlah
So basically I have two problems here:
How can I run comparison on the date of a linked class and
how can I show the fields of this class?
CREATE LINK page2chck TYPE LINKSET FROM CHECKS.CH_PID to PAGES.Id INVERSE
Now From console
From Studio
You can use this query
SELECT Title, $checks[0].Lastcheck as Lastcheck , $checks[0].Status as Status FROM PAGES
let $a = (select EXPAND(page2chck) from $parent.$current),
$checks= ( select Lastcheck, Status from $a where Lastcheck in
( select max(Lastcheck) from $a where Lastcheck < DATE("2016-02-03 00:00:00")))
From console
From Studio
If you want to retrieve all Pages that do not have a check after 2016-02-03
you can use this query
select from (SELECT Title, $checks[0].Lastcheck as Lastcheck , $checks[0].Status as Status FROM PAGES
let $a = ( select EXPAND(page2chck) from $parent.$current),
$checks= ( select Lastcheck, Status from $a where Lastcheck in ( select max(Lastcheck) from $a))
) where Lastcheck < DATE("2016-02-03 00:00:00")
Hope it helps.
I think I've found one of the problems in your query
select Title, page2chck.Lastcheck, page2chck.Status from PAGES where date.asLong(page2chck.Lastcheck) < 1454540400
1454540400 means 1970-01-17 21:02:20, verifiable by
select DATE(1454540400)
----+------+-------------------
# |#CLASS|DATE
----+------+-------------------
0 |null |1970-01-17 21:02:20
----+------+-------------------
BTW, you could create the linklist without the INVERSE
CREATE LINK chck2page TYPE LINKSET FROM CHECKS.CH_PID to PAGES.Id
and querying like this:
orientdb {db=pages_checks}> select chck2page.title, lastcheck, status from CHECKS where lastcheck < DATE("2016-02-01 23:59:10")
----+------+---------+-------------------+------
# |#CLASS|chck2page|lastcheck |status
----+------+---------+-------------------+------
0 |null |blablabla|2016-02-01 23:58:12|OK
1 |null |foo |2016-02-01 23:59:01|OK
----+------+---------+-------------------+------
Related
I have the following sample data (items) with some kind of recursion. For the sake of simplicity I limited the sample to 2 level. Matter of fact - they could grow quite deep.
+----+--------------------------+----------+------------------+-------+
| ID | Item - Name | ParentID | MaterializedPath | Color |
+----+--------------------------+----------+------------------+-------+
| 1 | Parent 1 | null | 1 | green |
| 2 | Parent 2 | null | 2 | green |
| 4 | Parent 2 Child 1 | 2 | 2.4 | orange|
| 6 | Parent 2 Child 1 Child 1 | 4 | 2.4.6 | red |
| 7 | Parent 2 Child 1 Child 2 | 4 | 2.4.7 | orange|
| 3 | Parent 1 Child 1 | 1 | 1.3 | orange|
| 5 | Parent 1 Child 1 Child | 3 | 1.3.5 | red |
+----+--------------------------+----------+------------------+-------+
I need to get via SQL all children
which are not orange
for a given starting ID
with either starting ID=1. The result should be 1, 1.3.5. When start with ID=4 the should be 2.4.6.
I read little bit and found the CTE should be used. I tried the following simplified definition
WITH w1( id, parent_item_id) AS
( SELECT
i.id,
i.parent_item_id
FROM
item i
WHERE
id = 4
UNION ALL
SELECT
i.id,
i.parent_item_id
FROM
item, JOIN w1 ON i.parent_item_id = w1.id
);
However, this won't even be executed as SQL-statement. I have several question to this:
CTE could be used with Hibernate?
Is there a way have the result via SQL queries? (more or less as recursive pattern)
I'm somehow lost with the recursive pattern combined with selection of color for the end result.
Your query is invalid for the following reasons:
As documented in the manual a recursive CTE requires the RECURSIVE keyword
Your JOIN syntax is wrong. You need to remove the , and give the items table an alias.
If you need the color column, just add it to both SELECTs inside the CTE and filter the rows in the final SELECT.
If that is changed, the following works fine:
WITH recursive w1 (id, parent_item_id, color) AS
(
SELECT i.id,
i.parent_item_id,
i.color
FROM item i
WHERE id = 4
UNION ALL
SELECT i.id,
i.parent_item_id,
i.color
FROM item i --<< missing alias
JOIN w1 ON i.parent_item_id = w1.id
)
select *
from w1
where color <> 'orange'
Note that the column list for the CTE definition is optional, so you can just write with recursive w1 as ....
Table A contains student names, table B and C contain classes and the presence of students.
I would like to display all students and attend their presence. The problem is that I can not display all students who did not have a checked presence.
Where I checked the presence of students it is ok, but if there is no checked presence in a given class, on a given day and in a given subject- nothing is displayed.
My query:
SELECT student.id_student, CONCAT(student.name,' ' ,student.surname) as 'name_surname',pres_student_present, pres_student_absent, pres_student_justified, pres_student_late, pres_student_rel, pres_student_course, pres_student_delegation, pres_student_note FROM student
LEFT JOIN class ON student.no_classes = class.no_classes
LEFT JOIN pres_student ON student.id_student = pres_student.id_student
WHERE (class.no_classes = '$class' OR NULL AND pres_student_data = '$data' AND pres_student_id_subject = $id_subject OR NULL)
GROUP BY student.surname
ORDER BY student.surname ASC
I want to display name_surname always and any other column should have NULL or 1
like:
Name | present | absent | just | late | rel | delegation | note |
Donald Trump | 1 | | | | | | |
Bush | | | | | | | |
Someone | 1 | | | | | | |
etc...
You should move restrictions on class and pres_studenttables from the WHERE clause to the ON (LEFT join).
In your case when you perform a restriction in the WHERE clause on a table with an outer join, the sql engine consider you are performing an INNER join
SELECT student.id_student
, CONCAT(student.name, ' ', student.surname) AS 'name_surname'
, pres_student_present
, pres_student_absent
, pres_student_justified
, pres_student_late
, pres_student_rel
, pres_student_course
, pres_student_delegation
, pres_student_note
FROM student
LEFT JOIN class
ON student.no_classes = class.no_classes
AND class.no_classes = '$class'
LEFT JOIN pres_student
ON student.id_student = pres_student.id_student
AND pres_student_data = '$data'
AND pres_student_id_subject = $id_subject
GROUP BY student.surname
ORDER BY student.surname ASC
I'm working on a problem, involving these two tables.
books
isbn | title | author
------------+-----------------------------------------+------------------
1840918626 | Hogwarts: A History | Bathilda Bagshot
3458400871 | Fantastic Beasts and Where to Find Them | Newt Scamander
9136884926 | Advanced Potion-Making | Libatius Borage
transactions
id | patron_id | isbn | checked_out_date | checked_in_date
----+-----------+------------+------------------+-----------------
1 | 1 | 1840918626 | 2012-05-05 | 2012-05-06
2 | 4 | 9136884926 | 2012-05-05 | 2012-05-06
3 | 2 | 3458400871 | 2012-05-05 | 2012-05-06
4 | 3 | 3458400871 | 2018-04-29 | 2018-05-02
5 | 2 | 9136884926 | 2018-05-03 | NULL
6 | 1 | 3458400871 | 2018-05-03 | 2018-05-05
7 | 5 | 3458400871 | 2018-05-05 | NULL
the query "Make a list of all book titles and denote whether or not a copy of that book is checked out." so pretty much just the first table with a checked out column.
im trying to SELECT DISTINCT on a sub query with the checkout books first, but that doesn't work. I've researched and others say to accomplish this use a GROUP BY clause instead of DISTINCT but the examples they provide are one column queries and when more columns are added it doesn't work.
this is my closest attempt
SELECT DISTINCT ON (title)
title, checked_out
FROM(
SELECT b.title, t.checked_in_date IS NULL AS checked_out
FROM transactions t
natural join books b
ORDER BY checked_out DESC
) t;
or you can join only transactions where books are not checked in:
SELECT b.title, t.isbn IS NOT NULL AS checked_out
, t.checked_out_date
FROM books b
LEFT JOIN transactions t ON t.isbn = b.isbn AND t.checked_in_date IS NULL
ORDER BY checked_out DESC
I adjusted your attempt a little bit. Basically I changed the way your data is joined
SELECT DISTINCT ON (title)
title, checked_out
FROM(
SELECT b.title, t.checked_in_date IS NULL AS checked_out
FROM books b
LEFT OUTER JOIN transactions t USING (isbn)
ORDER BY checked_out DESC
) t;
Situation
Using Python 3, Django 1.9, Cubes 1.1, and Postgres 9.5.
These are my datatables in pictorial form:
The same in text format:
Store table
------------------------------
| id | code | address |
|-----|------|---------------|
| 1 | S1 | Kings Row |
| 2 | S2 | Queens Street |
| 3 | S3 | Jacks Place |
| 4 | S4 | Diamonds Alley|
| 5 | S5 | Hearts Road |
------------------------------
Product table
------------------------------
| id | code | name |
|-----|------|---------------|
| 1 | P1 | Saucer 12 |
| 2 | P2 | Plate 15 |
| 3 | P3 | Saucer 13 |
| 4 | P4 | Saucer 14 |
| 5 | P5 | Plate 16 |
| and many more .... |
|1000 |P1000 | Bowl 25 |
|----------------------------|
Sales table
----------------------------------------
| id | product_id | store_id | amount |
|-----|------------|----------|--------|
| 1 | 1 | 1 |7.05 |
| 2 | 1 | 2 |9.00 |
| 3 | 2 | 3 |1.00 |
| 4 | 2 | 3 |1.00 |
| 5 | 2 | 5 |1.00 |
| and many more .... |
| 1000| 20 | 4 |1.00 |
|--------------------------------------|
The relationships are:
Sales belongs to Store
Sales belongs to Product
Store has many Sales
Product has many Sales
What I want to achieve
I want to use cubes to be able to do a display by pagination in the following manner:
Given the stores S1-S3:
-------------------------
| product | S1 | S2 | S3 |
|---------|----|----|----|
|Saucer 12|7.05|9 | 0 |
|Plate 15 |0 |0 | 2 |
| and many more .... |
|------------------------|
Note the following:
Even though there were no records in sales for Saucer 12 under Store S3, I displayed 0 instead of null or none.
I want to be able to do sort by store, say descending order for, S3.
The cells indicate the SUM total of that particular product spent in that particular store.
I also want to have pagination.
What I tried
This is the configuration I used:
"cubes": [
{
"name": "sales",
"dimensions": ["product", "store"],
"joins": [
{"master":"product_id", "detail":"product.id"},
{"master":"store_id", "detail":"store.id"}
]
}
],
"dimensions": [
{ "name": "product", "attributes": ["code", "name"] },
{ "name": "store", "attributes": ["code", "address"] }
]
This is the code I used:
result = browser.aggregate(drilldown=['Store','Product'],
order=[("Product.name","asc"), ("Store.name","desc"), ("total_products_sale", "desc")])
I didn't get what I want.
I got it like this:
----------------------------------------------
| product_id | store_id | total_products_sale |
|------------|----------|---------------------|
| 1 | 1 | 7.05 |
| 1 | 2 | 9 |
| 2 | 3 | 2.00 |
| and many more .... |
|---------------------------------------------|
which is the whole table with no pagination and if the products not sold in that store it won't show up as zero.
My question
How do I get what I want?
Do I need to create another data table that aggregates everything by store and product before I use cubes to run the query?
Update
I have read more. I realised that what I want is called dicing as I needed to go across 2 dimensions. See: https://en.wikipedia.org/wiki/OLAP_cube#Operations
Cross-posted at Cubes GitHub issues to get more attention.
This is a pure SQL solution using crosstab() from the additional tablefunc module to pivot the aggregated data. It typically performs better than any client-side alternative. If you are not familiar with crosstab(), read this first:
PostgreSQL Crosstab Query
And this about the "extra" column in the crosstab() output:
Pivot on Multiple Columns using Tablefunc
SELECT product_id, product
, COALESCE(s1, 0) AS s1 -- 1. ... displayed 0 instead of null
, COALESCE(s2, 0) AS s2
, COALESCE(s3, 0) AS s3
, COALESCE(s4, 0) AS s4
, COALESCE(s5, 0) AS s5
FROM crosstab(
'SELECT s.product_id, p.name, s.store_id, s.sum_amount
FROM product p
JOIN (
SELECT product_id, store_id
, sum(amount) AS sum_amount -- 3. SUM total of product spent in store
FROM sales
GROUP BY product_id, store_id
) s ON p.id = s.product_id
ORDER BY s.product_id, s.store_id;'
, 'VALUES (1),(2),(3),(4),(5)' -- desired store_id's
) AS ct (product_id int, product text -- "extra" column
, s1 numeric, s2 numeric, s3 numeric, s4 numeric, s5 numeric)
ORDER BY s3 DESC; -- 2. ... descending order for S3
Produces your desired result exactly (plus product_id).
To include products that have never been sold replace [INNER] JOIN with LEFT [OUTER] JOIN.
SQL Fiddle with base query.
The tablefunc module is not installed on sqlfiddle.
Major points
Read the basic explanation in the reference answer for crosstab().
I am including with product_id because product.name is hardly unique. This might otherwise lead to sneaky errors conflating two different products.
You don't need the store table in the query if referential integrity is guaranteed.
ORDER BY s3 DESC works, because s3 references the output column where NULL values have been replaced with COALESCE. Else we would need DESC NULLS LAST to sort NULL values last:
PostgreSQL sort by datetime asc, null first?
For building crosstab() queries dynamically consider:
Dynamic alternative to pivot with CASE and GROUP BY
I also want to have pagination.
That last item is fuzzy. Simple pagination can be had with LIMIT and OFFSET:
Displaying data in grid view page by page
I would consider a MATERIALIZED VIEW to materialize results before pagination. If you have a stable page size I would add page numbers to the MV for easy and fast results.
To optimize performance for big result sets, consider:
SQL syntax term for 'WHERE (col1, col2) < (val1, val2)'
Optimize query with OFFSET on large table
ALTER TABLE users ADD todo map;
UPDATE users SET todo = { '1':'1111', '2':'2222', '3':'3' ,.... } WHERE user_id = 'frodo';
now ,i want to run the follow cql ,but failed ,is here any other method ?
SELECT user_id, todo['1'] FROM users WHERE user_id = 'frodo';
ps:
the length my map can change. for example : { '1':'1111', '2':'2222', '3':'3' } or { '1':'1111', '2':'2222', '3':'3', '4':'4444'} or { '1':'1111', '2':'2222', '3':'3', '4':'4444' ...}
If you want to use a map collection, you'll have the limitation that you can only select the collection as a whole (docs).
I think you could use the suggestion from the referenced question, even if the length of your map changes. If you store those key/value pairs for each user_id in separate fields, and make your primary key based on user_id and todo_k, you'll have access to them in the select query.
For example:
CREATE TABLE users (
user_id text,
todo_k text,
todo_v text,
PRIMARY KEY (user_id, todo_k)
);
-----------------------------
| user_id | todo_k | todo_v |
-----------------------------
| frodo | 1 | 1111 |
| frodo | 2 | 2222 |
| sam | 1 | 11 |
| sam | 2 | 22 |
| sam | 3 | 33 |
-----------------------------
Then you can do queries like:
select user_id,todo_k,todo_v from users where user_id = 'frodo';
select user_id,todo_k,todo_v from users where user_id = 'sam' and todo_k = 2;