I have following question. When I use this Helper:
echo $this->Form->input('start_date', array('required'=>false, 'class'=>'form-control date'));
I get following output:
Where can I change this output type? I tried it in
/lib/Cake/View/Helper/FormHelper.php
I found in this lib file, that the Helper gets the function __getInput() and in the date case, following sub function:
case 'date':
$options['value'] = $selected;
return $this->dateTime($fieldName, $dateFormat, null, $options);
But in the function dateTime() I got lost. Is there any updated Helper out or is there a simple trick to change the HTML-output format?
Thanks & regards
Set input type as text
echo $this->Form->input('start_date', array('type'=>'text','required'=>false, 'class'=>'form-control date'));
Related
In Magento my website 's current version is magento 2.2.5 . Now i have updated it to latest version magento 2.3.0 .
But there i am getting error when i run
php bin/magento setup:upgrade
I got this error
Cannot process definition to array for type tinytext
Please suggest me solution.
Thank You
You are getting this error because "data type" of any third party extension's table's column is tinytext.
So you need to find out column name using debug in following file.
Open this file /vendor/magento/framework/Setup/Declaration/Schema/Db/DefinitionAggregator.php and check this fromDefinition() method and then add debug code to find column name.
public function fromDefinition(array $data)
{
$type = $data['type'];
if (!isset($this->definitionProcessors[$type])) {
/* Add Code for Debug */
echo "<pre>";
print_r($data); exit();
/* Code End */
throw new \InvalidArgumentException(
sprintf("Cannot process definition to array for type %s", $type)
);
}
$definitionProcessor = $this->definitionProcessors[$type];
return $definitionProcessor->fromDefinition($data);
}
After that please run setup:upgrade command and you will get array of column data in console. so from this array you will get name of column from your third party extension table.
Now from that table please change column's data type "tinytext" to "text" and issue will be fixed.
Note : You might also get issues from ENUM and MEDIUMINT data type as well, so do the same steps if get any other data type issue.
Open file
/vendor/magento/framework/Setup/Declaration/Schema/Db/DefinitionAggregator.php
Replace function fromDefinition:
With:
public function fromDefinition(array $data)
{
$type = $data['type'];
if(in_array($type, ["tinytext", "enum"])){
$data['type'] = 'text';
$type = 'text';
}
if(in_array($type, ['time', 'mediumint'])){
$data['type'] = 'datetime';
$type = 'datetime';
}
if(in_array($type, ['mediumint'])){
$data['type'] = 'int';
$type = 'int';
}
if (!isset($this->definitionProcessors[$type])) {
throw new \InvalidArgumentException(
sprintf("Cannot process definition to array for type %s", $type)
);
}
$definitionProcessor = $this->definitionProcessors[$type];
return $definitionProcessor->fromDefinition($data);
}
Yes it is because of some extensions.I just exported the database and search for keywords tinytext , found a table which use this format, I changed it to TEXT and the problem solved.
You might want to check your extensions. I debugged this error for myself and it originated from an extension which was included with a theme purchased, but not updated.
I'm using the Aixeena Easy CCK-plugin in my Joomla 3.3-website. It's a plugin that allows me to add custom fields in my Article Edit-page. The content I fill out there (should) show up on my website. The plugin stores his information in the #_content table in the attribs column.
On their website, Aixeena says that I have to use the following code to make the filled out text visible on my website:
$attrb = json_decode($this->item->attribs);
echo $attrb->fieldname;
This code drops the following error:
Notice: Undefined property: JDocumentHTML::$item in /Applications/MAMP/htdocs/buutpot/templates/buutpot.nl-standaardtemplate/index.php on line 123
Notice: Trying to get property of non-object in /Applications/MAMP/htdocs/buutpot/templates/buutpot.nl-standaardtemplate/index.php on line 123
Fatal error: Call to a member function get() on a non-object in /Applications/MAMP/htdocs/buutpot/templates/buutpot.nl-standaardtemplate/index.php on line 124
I think it is written for an older version of Joomla. Then I searched around and found this code:
$params = $this->item->params;
echo $params->get('fieldname');
When I use this code on my site, it gives me the following error's:
Notice: Undefined property: JDocumentHTML::$item in /Applications/MAMP/htdocs/buutpot/templates/buutpot.nl-standaardtemplate/index.php on line 123
Notice: Trying to get property of non-object in /Applications/MAMP/htdocs/buutpot/templates/buutpot.nl-standaardtemplate/index.php on line 123
Notice: Trying to get property of non-object in /Applications/MAMP/htdocs/buutpot/templates/buutpot.nl-standaardtemplate/index.php on line 124
That's without a fatal error. I'm not sure why it is without.
Could anybody help me out getting the right code to get my variable out of the table? Thanks in advance!
EDIT 1: Link to the plugin: http://www.aixeena.org/aixeena-lab/aixeena-easy-cck
EDIT 2: Edited my question in reply on the comment of Elin.
So like the notices say, the problem is that $this->item does not exist. You need to figure out what the actual name of the object is and use that rather than $this->item. You will probably do that by looking in the layout of whereever it is that you are trying to display. Can you please check your template to see if it has a layout override for the article view (assuming that is the view you are trying to access the form from)?
I used this code to do a query on the database:
$db = JFactory::getDbo();
$query = $db->getQuery(true);
$query->select('attribs');
$query->from($db->quoteName('#__content'));
$query->where($db->quoteName('id')." = ".JRequest::getInt('id'));
$db->setQuery($query);
$attribs = $db->loadResult();
$attribs = json_decode($attribs, 'true');
$firstattr = $attribs['firstattr'];
$secondattr = $attribs['secondattr'];
$thirdattr = $attribs['thirdattr'];
$fourthattr = $attribs['fourthattr'];
But I'm sure this can be done simpler.
$attribs = new JRegistry($article->attribs);
echo $fieldname = $attribs['fieldname'];
For example, I use this code in on ContentPrepare like this
function onContentPrepare($context, &$article, &$params, $page) {
$attribs = new JRegistry($article->attribs);
//url is my custom field for the content
$url = $attribs['url'];
......
I have to copy the data from one collection to another collection based on a date. Here date is calculated as yesterday date dynamically and working properly.
If i pass the dynamic date value as /$yesterday/ to mongo find method, Its getting failed.
Assume data_timestamp format is 2013-08-20 17:04:40.633 and trying to get the result by like query.
Sample JS Code:
db=db.getSiblingDB('masterdb')
$today = new Date();
$yesterday = new Date($today);
$yesterday.setDate($today.getDate() - 1);
var $dd = $yesterday.getDate();
var $mm = $yesterday.getMonth()+1;
var $yyyy = $yesterday.getFullYear();
if($dd<10){$dd='0'+dd} if($mm<10){$mm='0'+$mm} $yesterday = $yyyy+'-'+$mm+'-'+$dd;
db.mastercollection.find( { "data_timestamp": /$yesterday/ } ).forEach( function(x){db.newcollection.insert(x)} );
Is any other way to pass dynamic value without using '$' symbol?
Please share your valuable comments
Thanks in advance...
Ramesh Kasi
The way you're doing your query now, I'm pretty sure that /$yesterday/ is being interpreted as a regular expression matching strings starting with "yesterday". A better approach would be to use the $regex operator so that you can pass in a javascript variable that holds the regular expression you hope to match.
What should i do ?
$edit_end_date = '2011-02-31';
$validator_date = new Zend_Validate_Date(array('format' => 'yyyy-mm-dd'));
$isval = $validator_date->isValid($edit_end_date);
if((!$isval) || empty($edit_end_date))
{
echo "Please Enter Valid End Date. !";
}else{
echo "Entered Is Valid End Date. !";
}
how come it returns true date ?
According to the Zend API Docs, it appears that Zend_Validate_Date will only validate whether the argument passed to it, is a valid date construct (also considers locale), it will not validate if the date actually exists.
Zend_Validate_Date allows you to validate if a given value contains a date. This validator validates also localized input.
-- Edit --
Looks like you can use PHP's built in checkdate() function to determine if a date is valid or not.
There are bugs in data validation (ZF-7583 at issue tracker). Look at Zend_Validate_Date just doesn't work properly
You can use regex validation like in answer to linked question, but it will only check for syntax, not if date exists for real. For this you can use checkdate() - as Mike Purcell suggested - combined with Zend_Validate_Callback:
$validator1 = new Zend_Validate_Regex(
array('pattern' => '/^[0-9]{4}-[0-9]{2}-[0-9]{2}$/')
);
$validator1->setMessage(
"Date does not match the format 'yyyy-mm-dd'",
Zend_Validate_Regex::NOT_MATCH
);
$validator2 = new Zend_Validate_Callback(function($value)) {
// using checkdate() or other function
});
After doing an insert I want to pass the object to the client using json_encode(). The problem is, the _id value is not included.
$widget = array('text' => 'Some text');
$this->mongo->db->insert($widget);
If I echo $widget['_id'] the string value gets displays on the screen, but I want to do something like this:
$widget['widgetId'] = $widget['_id']->id;
So I can do json_encode() and include the widget id:
echo json_encode($widget);
Believe this is what you're after.
$widget['_id']->{'$id'};
Something like this.
$widget = array('text' => 'Some text');
$this->mongo->db->insert($widget);
$widget['widgetId'] = $widget['_id']->{'$id'};
echo json_encode($widget);
You can also use:
(string)$widget['_id']
correct way is use ObjectId from MongoDB:
function getMongodbIDString($objectId){
$objectId = new \MongoDB\BSON\ObjectId($objectId);
return $objectId->jsonSerialize()['$oid'];
}
and do not cast the objectId like (string) $row['_id'] or $row->_id->{'$oid'}
I used something similar:
(string)$widget->_id
I used something similar if object:
$widget->_id->{'$oid'}
or
(string)$widget->_id
or array :
$widget['id']->{'$oid'}
(string)$widget['_id']