I am having problems attempting to return elements of a String array line by line within a textView. I have indeed used the special carriage return character in my code sequence to return elements of the array on separate lines. However, I have not been able to succeed thus far. Here is a code snippet of what I typed:
txtViewQuestionStatus.text = "\(numCorrect) correct Answers, However these are the questions answered INCORRECTLY: \(model.incorrectItems())\n" //Have text view present number of correct answers and list incorrect Questions line by line.
What could I be doing wrong in my source code? Thanks!
What is model.incorrectItems() returning? Can you post that part of your code? If it returns an array of strings you can join them like so:
"... INCORRECTLY: \(model.incorrectItems().joinWithSeparator("\n"))\n"
Related
I'm trying to change the value of nulls to something else that can be used to filter. This data comes from a QVD file. The field that contains nulls, contains nulls due to no action taken on those items ( they will eventually change to something else once an action has been taken). I found this link which was very informative but i tried multiple solutions from the document to no avail.
What i don't quite understand is that whenever i make a new field (in the script or as an expression) the formula does not propagate in the records that are null, it shows " - ". For instance, the expression isNull(ActionTaken) will return false in a field that that not null, but only " - " in fields that are null. If i export the table to Excel, the " - " is exported, i copy this cell to a text analyzer i the UTF-8 encoded is \x2D\x0A\x0A, i'm not sure if that's an artifact of the export process.
I also tried using the NullAsValue statement but no luck. Using a combination of Len & Trim = 0 will return the same result as above. This is only one table, no other tables are involved.
Thanks in advance.
I had a similar case few years ago where the field looked empty but actually it was filled with a character which just looked empty. Trimming the field also didnt worked as expected in this case, because the character code was different
What I can suggest you is to check if the character number, returned for the empty value, is actually an empty string. You can use the ord to check the character number for the empty values. Once you have the number then you can use this number to replace it with whatever you want (for example empty string)
As stated in the title, I have two tables I'm attempting to link. Both Strings appear to be a match, however Crystal Reports is not picking it up. The only thing I can think is that that length of the field is different, even though the strings are the same. could that cause a discrepancy? If so how can I correct for it? Thank you
Length of the string will prevent a match. If you are using the Trim(string) function, that only removes spaces found at the beginning or end of your string, so the two strings could still be of different lengths after using this function. You will need to use another function to capture a substring of the original string. To do this you can use the Left(string, length) function to ensure both strings are the same length.
If they still do not match then you may have non-printable characters in one or both of your strings. Carriage Return and Line Feed tend to be the most commonly found non-printable characters. A Carriage Return is represented as Chr(10), while a Line Feed is represented as Chr(13). These are Built In Constants similar to those found in VBA and Visual Basic.
You can use a find and replace to remove them with the following formula. Its not a bad idea to also include the trim and left functions in this as well to ensure you get the best match possible.
Replace(Replace(Left(Trim({YourStringField}), 10),Chr(10), ""),Chr(13), "")
There are a few additional Built In Constants you may need to check for if this doesn't work. A Tab is represented as Chr(9) for example. Its very rare for strings to contain the other Built In Constants though. In most cases Carriage Return and Line Feed are the only ones that are typically found in Plain Text. Tabs and the other constants should only be found in Rich Text and are very rare in string data.
Hey i have a string which printed gives the following: BBBKKKKJJJJJJGGGâG
If I use this code:
for (index,character) in vin.characters.enumerated(){
print(character)
vinTextFields[index].text = String(character)
}
to split it into some textFields the index is out of range. This is because the for loop inserts an empty character.
This is what the print(character) gives me back.
I really not get why this empty line appears.
I tested it, it seems there is a character that is not printable between the last two 'G'.
I think you copied and pasted it from somewhere. That's how that character made it there.
Remove the last two 'G' and type them again and you will be good to go. I tested that too.
I asked a question earlier today and got a really quick answer from llbrink. I really should have asked that question before I spent several hours trying to find an answer.
So - here's another question that I have never found an answer for (although I have created a work-around which seems very cludgy).
My AHK program asks the user for a login name. The program then compares the login name with an existing list of names in a file.
The login name in the file may contain spaces, but there are never spaces at the beginning of the name. When the user enters the name, he may include spaces at the beginning. This means that when my program compares the name with those in the file, it can not find a match (because of the extra spaces).
I want to find a way of stripping the spaces from the beginning of the input.
My work-round has been to split the input string into an array (which does ignore leading spaces) and then use the first element of the array. This is my code :
name := DoStrip(name)
DoStrip(xyz) ; strip leading and trailing spaces from string
{
StringSplit, out, xyz, `,, %A_Space%
Return out1
}
This seems to be a very laboured way to do it - is there a better way ?
I don't see a problem with your example if it works on all cases.
There is a much simpler way; just use Autotrim which works like this.
AutoTrim, On ; not required it is on by default
my_variable = %my_variable%
There are also many other different ways to trim string in autohotkey,
which you can combine into something useful.
You can also use #LTrim and #RTrim to remove white spaces at the beginning and at the end of the string.
I've developed a workaround since crystal reports doesn't seem to have a substring function with the following formula:
right({_v_hardware.groupname},
truncate(instr(replace({_v_hardware.groupname},".",
","), ","))
What I'm trying to do is search for the period (".") in a string and replace it with a comma. Then find the comma position in the string and print all characters following after the comma. This is assuming the string will only have 1 period in the entire string.
Now when I attempt to do this, I get some weird characters which look like wingdings. Any ideas?
thanks in advance.
I don't know the entire issue that you are attempting to accomplish, but for this question alone, the step of replacing the period with a comma seems to be unnecessary. If you know that there is only one period in the string and you only want the characters right of the period then you should be able to do something like the following (this is #first_formula):
right({_v_hardware.groupname}, len({_v_hardware.groupname}) - instr({_v_hardware.groupname},"."))
If for some reason you want to show the comma then I'd do that in a separate formula. If you need the entire screen with the comma replaced then just do:
replace({_v_hardware.groupname},".",",")
And if you need the comma plus included in the string then it might just be easier to do something like:
"," + {#first_formula}
Hope this helps.