When I persist an entity I would like to add a button to the form. Is that possible. I read a lot about modifying the entity but this is not what I want to do, I just want to add a button.
if($form->isSubmitted() && $form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($entity);
.... what do I write here to add my button ? is it even here or the type ?
Thank you
}
I found a solution which is what it is but it is possible in fact. The formView has to be created before checking if the form has been submitted or is valid
$form_builder->add('button', 'boutons', array('attr' => array('boutons' => $buttons))); //boutons is a type field I created and I have to give an array of buttons I want to add)
$form = $form_builder->getForm();
$form->handleRequest($request);
$form_view = $form->createView();
if($form->isSubmitted() && $form->isValid()) {
$em = $this->getDoctrine()->getManager();
$entity = $form->getData();
$em->persist($entity);
if($form_view->offsetExists('button')) {
$form_view->children['button']->vars['attr']['boutons'][] = $button_send_validation; (// I add my new button to the array of buttons)
}
}
Hope it can help someone..
Related
after looking on other topics i haven't resolved my problem, i'm looking to add the field user_id to the form (as the user won't choose it) but symfony return me "Call to a member function addEventListener() on string"
here is my code :
if ($form->isSubmitted() && $form->isValid()) {
$builder->addEventListener(FormEvents::PRE_SUBMIT, function(FormEvent $event) {
$data = $event->getData();
$form = $event->getForm();
$data['user_id'] = '2';
$event->setData($data);
});
$em = $this->getDoctrine()->getManager();
$em->persist($deplacement);
$em->flush($deplacement);
return $this->redirectToRoute('deplacement_show', array('id' => $deplacement->getId()));
}
Sure this is the good aproach? Maybe is better for you to write a method to update or create $deplacement, and pass 2 argoument: the $data variable from the form and the user_id, like this:
if ($form->isSubmitted() && $form->isValid()) {
$em = $this->getDoctrine()->getManager();
$userId = 2;
$formData->userId = $userId;
$deplacement->update($formData);
$em->persist($deplacement);
$em->flush($deplacement);
return $this->redirectToRoute('deplacement_show', array('id' => $deplacement->getId()));
}
Also I think you dont need the event listener. Why are you using it?
I'm using symfony4 and In my project I have and entity Bill and it offer two packs:
1) First pack, user can generate just one bill in PDF after filling out a form and saving data in database and it has its own price.
2) Second pack, user can generate Three bills in PDF after filling out a form and saving data in database and this has its own price also.
The first pack is simple and it works fine , I have created BillType and an action in the controller and everything is well.
public function newBillFirstPack(Request $request)
{
$entity = new Bill();
$em = $this->getDoctrine()->getManager();
$form = $this->createForm(BillType::class, $entity);
$form->handleRequest($request);
if ($form->isSubmitted()) {
if ($form->isValid()) {
$em->persist($entity);
$em->flush();
//...............
}
}
return $this->render('frontOffice/bill/new_first_pack.html.twig', array(
'form' => $form->createView()
));
}
The problem is with the second pack , I'd like to know how can I create three bills from one form. I tried to create 3 FormType
- FirstBillType and a twig to render its view.
- SecondtBillType and a twig to render its view.
- ThirdBillType and a twig to render its view also.
And in the controller I created three forms.
I didn't test it yet but even it works I don't like it , I fell it's not a clean solution. Imagine if a day I want to edit an attribute in the formType, so I must edit it in three formsType and three html.twig views, same thing if I want to remove or add an attribute in the forms.
I have see in the documentation "How to Embed a Collection of Forms", but that example is how to embed one attribute many times.
Any good solution ?
If I understand what you need. New action can handle this and depending on your needs form can run different action.
public function newBillThirdPack(Request $request)
{
$entity = new Bill();
$em = $this->getDoctrine()->getManager();
$form = $this->createForm(BillType::class, $entity);
$form->handleRequest($request);
if ($form->isSubmitted()) {
if ($form->isValid()) {
$em->persist($entity);
$em->persist(clone $entity);
$em->persist(clone $entity);
$em->flush();
//...............
}
}
return $this->render('frontOffice/bill/new_third_pack.html.twig', array(
'form' => $form->createView()
));
}
This is my registration form code:
public function register(Request $request, UserPasswordEncoderInterface $passwordEncoder)
{
$user = new User();
$form = $this->createForm(RegisterType::class, $user);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$password = $passwordEncoder->encodePassword($user, $user->getPlainPassword());
$user->setPassword($password);
$user->setPlan('1');
$datetime = new \DateTime();
$datetime->modify('+30 day');
$user->setExpiration($datetime);
$user->setActive('0');
$entityManager = $this->getDoctrine()->getManager();
$entityManager->persist($user);
$entityManager->flush();
$this->addFlash('success', 'Your account has been created. Check your inbox for verification e-mail.');
}
return $this->render('home/register.html.twig', array(
'form' => $form->createView(),
));
}
At the end of saving user into database there's set Flash message. Is there any way of showing that message through form error field?
No you cannot add a flash message to a form's errors. The only way to manipulate the errors of a form through it's class API is the public function addError(FormError $error) but as you can see it's only accepts arguments of type FormError not strings.
I Have a problem rendering a form in symfony.
I use a comercial template (SmartAdmin) and this template use AJAX to capture all the urls loaded, keep the menus and configuration when the url provide '#'
Normally i can work ok, but in this controller i have a problem when the validation fails
public function createAction(Request $request)
{
$entity = new Clientes();
$form = $this->createCreateForm($entity);
$form->handleRequest($request);
if ($form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($entity);
$em->flush();
$url=$this->generateUrl('ec_main_cliente', array('idcliente' => $entity->getId()));
$url = str_replace('cliente', '#cliente', $url);
return $this->redirect($url);
}
return $this->render('ECMainBundle:Clientes:nuevo_cliente.html.twig', array(
'entity' => $entity,
'form' => $form->createView(),
));
}
When Form is Invalid , load "ECMainBundle:Clientes:nuevo_cliente.html.twig" without the "#" and lost all the menus and configurations.
Any suggestion please?
Thanks in Advance and sorry for my english
Image work Ok:
Image of the problem:
I still don't have the feeling to fully understand what you're trying to achieve, but I think that you want the redirect always take place. In this case you should restructure your code a bit:
$id = 0;
if ($form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($entity);
$em->flush();
$id = $entity->getId();
}
$url = $this->generateUrl('ec_main_cliente', array('idcliente' => $id));
$url = str_replace('cliente', '#cliente', $url);
return $this->redirect($url);
Then, of course, the last part with the template rendering would be never exectuted.
Can anyone please show me a specific example of a Symfony2 form entity update? The book only shows how to create a new entity. I need an example of how to update an existing entity where I initially pass the id of the entity on the query string.
I'm having trouble understanding how to access the form again in the code that checks for a post without re-creating the form.
And if I do recreate the form, it means I have to also query for the entity again, which doesn't seem to make much sense.
Here is what I currently have but it doesn't work because it overwrites the entity when the form gets posted.
public function updateAction($id)
{
$em = $this->getDoctrine()->getEntityManager();
$testimonial = $em->getRepository('MyBundle:Testimonial')->find($id);
$form = $this->createForm(new TestimonialType(), $testimonial);
$request = $this->get('request');
if ($request->getMethod() == 'POST') {
$form->bindRequest($request);
echo $testimonial->getName();
if ($form->isValid()) {
// perform some action, such as save the object to the database
//$testimonial = $form->getData();
echo 'testimonial: ';
echo var_dump($testimonial);
$em->persist($testimonial);
$em->flush();
return $this->redirect($this->generateUrl('MyBundle_list_testimonials'));
}
}
return $this->render('MyBundle:Testimonial:update.html.twig', array(
'form' => $form->createView()
));
}
Working now. Had to tweak a few things:
public function updateAction($id)
{
$request = $this->get('request');
if (is_null($id)) {
$postData = $request->get('testimonial');
$id = $postData['id'];
}
$em = $this->getDoctrine()->getEntityManager();
$testimonial = $em->getRepository('MyBundle:Testimonial')->find($id);
$form = $this->createForm(new TestimonialType(), $testimonial);
if ($request->getMethod() == 'POST') {
$form->bindRequest($request);
if ($form->isValid()) {
// perform some action, such as save the object to the database
$em->flush();
return $this->redirect($this->generateUrl('MyBundle_list_testimonials'));
}
}
return $this->render('MyBundle:Testimonial:update.html.twig', array(
'form' => $form->createView()
));
}
This is actually a native function of Symfony 2 :
You can generate automatically a CRUD controller from the command line (via doctrine:generate:crud) and the reuse the generated code.
Documentation here :
http://symfony.com/doc/current/bundles/SensioGeneratorBundle/commands/generate_doctrine_crud.html
A quick look at the auto-generated CRUD code by the Symfony's command generate:doctrine:crudshows the following source code for the edit action
/**
* Displays a form to edit an existing product entity.
*
* #Route("/{id}/edit", name="product_edit")
* #Method({"GET", "POST"})
*/
public function editAction(Request $request, Product $product)
{
$editForm = $this->createForm('AppBundle\Form\ProductType', $product);
$editForm->handleRequest($request);
if ($editForm->isSubmitted() && $editForm->isValid()) {
$this->getDoctrine()->getManager()->flush();
return $this->redirectToRoute('product_edit', array('id' => $product->getId()));
}
return $this->render('product/edit.html.twig', array(
'product' => $product,
'edit_form' => $editForm->createView(),
));
}
Note that a Doctrine entity is passed to the action instead of an id (string or integer). This will make an implicit parameter conversion and saves you from manually fetching the corresponding entity with the given id.
It is mentioned as best practice in the Symfony's documentation