after looking on other topics i haven't resolved my problem, i'm looking to add the field user_id to the form (as the user won't choose it) but symfony return me "Call to a member function addEventListener() on string"
here is my code :
if ($form->isSubmitted() && $form->isValid()) {
$builder->addEventListener(FormEvents::PRE_SUBMIT, function(FormEvent $event) {
$data = $event->getData();
$form = $event->getForm();
$data['user_id'] = '2';
$event->setData($data);
});
$em = $this->getDoctrine()->getManager();
$em->persist($deplacement);
$em->flush($deplacement);
return $this->redirectToRoute('deplacement_show', array('id' => $deplacement->getId()));
}
Sure this is the good aproach? Maybe is better for you to write a method to update or create $deplacement, and pass 2 argoument: the $data variable from the form and the user_id, like this:
if ($form->isSubmitted() && $form->isValid()) {
$em = $this->getDoctrine()->getManager();
$userId = 2;
$formData->userId = $userId;
$deplacement->update($formData);
$em->persist($deplacement);
$em->flush($deplacement);
return $this->redirectToRoute('deplacement_show', array('id' => $deplacement->getId()));
}
Also I think you dont need the event listener. Why are you using it?
Related
This is my registration form code:
public function register(Request $request, UserPasswordEncoderInterface $passwordEncoder)
{
$user = new User();
$form = $this->createForm(RegisterType::class, $user);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
$password = $passwordEncoder->encodePassword($user, $user->getPlainPassword());
$user->setPassword($password);
$user->setPlan('1');
$datetime = new \DateTime();
$datetime->modify('+30 day');
$user->setExpiration($datetime);
$user->setActive('0');
$entityManager = $this->getDoctrine()->getManager();
$entityManager->persist($user);
$entityManager->flush();
$this->addFlash('success', 'Your account has been created. Check your inbox for verification e-mail.');
}
return $this->render('home/register.html.twig', array(
'form' => $form->createView(),
));
}
At the end of saving user into database there's set Flash message. Is there any way of showing that message through form error field?
No you cannot add a flash message to a form's errors. The only way to manipulate the errors of a form through it's class API is the public function addError(FormError $error) but as you can see it's only accepts arguments of type FormError not strings.
I have a form to add a new prescriber in my database. The first step consists in informing the various informations about the prescriber.
Then, I check if there are similar prescribers before adding it (2nd step with a 2nd form) and if there are, I ask the user to confirm.
In short, I have a 1-step form or a 2-steps form, depending on duplicates.
I tried with CraueFormFlowBundle but I don't know how to implement my conditional second step. My tests were inconclusive. So I decided to use forward method in my controller, and I like it !
But, I can't manage to flush my prescriber at the end of the 2nd step (after forwarding), I have this error : Unable to guess how to get a Doctrine instance from the request information for parameter "prescriber".
addAction (= step 1)
/**
* Add a new prescriber
*
* #Route("/prescribers/add", name="prescriber_add")
*/
public function addAction(Request $request) {
$em = $this->getDoctrine()->getManager();
$rp = $em->getRepository('AppBundle:Prescriber');
$p = new Prescriber();
// build the form
$form = $this->createForm(AddPrescriberType::class, $p);
// handle the submit
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
# search if a prescriber already exists
$qb = $rp->createQueryBuilder('p');
$qb->where($qb->expr()->eq('p.rpps', ':rpps'))
->orWhere($qb->expr()->andX(
$qb->expr()->like('p.lastname', ':name'),
$qb->expr()->like('p.firstname', ':firstname')
))
->setParameter('rpps', $p->getRpps())
->setParameter('name', '%'.$p->getLastname().'%')
->setParameter('firstname', '%'.$p->getFirstname().'%');
$duplicates = $qb->getQuery()->getArrayResult();
# there are duplicates
if (!empty($duplicates)) {
$em->persist($p);
// confirm the addition of the new prescriber
$params = array('prescriber' => $p, 'duplicates' => $duplicates);
$query = $request->query->all();
return $this->forward('AppBundle:Prescriber:addConfirm', $params, $query);
} else {
$em->persist($p); # save the prescriber
$em->flush(); # update database
$this->addFlash('p_success', 'The prescriber has been created successfully');
return $this->redirectToRoute('prescriber');
}
}
// show form
return $this->render('prescribers/form-step1.html.twig', array(
'form' => $form->createView()
));
}
addConfirmAction (= step 2)
/**
* Confirm addition of a new prescriber
*
* #Route("/prescribers/add/confirm", name="prescriber_add_confirm")
*/
public function addConfirmAction(Prescriber $prescriber, $duplicates, Request $request) {
$em = $this->getDoctrine()->getManager();
$form = $this->createFormBuilder()->getForm();
if ($form->handleRequest($request)->isValid()) {
$em->persist($prescriber);
$em->flush();
$this->addFlash('p_success', 'Prescriber has been created successfully');
return $this->redirectToRoute('prescriber');
}
// show confirm page
return $this->render('prescribers/form-step2.html.twig', array(
'h1_title' => 'Ajouter un nouveau prescripteur',
'form' => $form->createView(),
'p' => $prescriber,
'duplicates'=> $duplicates
));
}
I think the problem comes from the fact that I have 2 forms submissions...
I found a solution by using the session.
(I know it's not a perfect way but I didn't find other one)
For Symfony 3.3.*
use Symfony\Component\HttpFoundation\Session\SessionInterface;
public function addAction(Request $request, SessionInterface $session) {
// [...]
# there are duplicates
if (!empty($duplicates)) {
$data = $form->getData();
$session->set('prescriber', $data);
$session->set('duplicates', $duplicates);
return $this->forward('AppBundle:Prescriber:addConfirm');
// [...]
}
public function addConfirmAction(Request $request, SessionInterface $session) {
$em = $this->getDoctrine()->getManager();
$p = $session->get('prescriber');
$duplicates = $session->get('duplicates');
// empty form with only a CSRF field
$form = $this->createFormBuilder()->getForm();
if ($form->handleRequest($request)->isValid()) {
$em->persist($p);
$em->flush();
$this->addFlash('p_success', 'The prescriber has been created successfully');
return $this->redirectToRoute('prescriber');
}
// show confirm page
return $this->render('prescribers/form-step2.html.twig', array(
'form' => $form->createView(),
'prescriber'=> $p,
'duplicates'=> $duplicates
));
}
When I persist an entity I would like to add a button to the form. Is that possible. I read a lot about modifying the entity but this is not what I want to do, I just want to add a button.
if($form->isSubmitted() && $form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($entity);
.... what do I write here to add my button ? is it even here or the type ?
Thank you
}
I found a solution which is what it is but it is possible in fact. The formView has to be created before checking if the form has been submitted or is valid
$form_builder->add('button', 'boutons', array('attr' => array('boutons' => $buttons))); //boutons is a type field I created and I have to give an array of buttons I want to add)
$form = $form_builder->getForm();
$form->handleRequest($request);
$form_view = $form->createView();
if($form->isSubmitted() && $form->isValid()) {
$em = $this->getDoctrine()->getManager();
$entity = $form->getData();
$em->persist($entity);
if($form_view->offsetExists('button')) {
$form_view->children['button']->vars['attr']['boutons'][] = $button_send_validation; (// I add my new button to the array of buttons)
}
}
Hope it can help someone..
I Have a problem rendering a form in symfony.
I use a comercial template (SmartAdmin) and this template use AJAX to capture all the urls loaded, keep the menus and configuration when the url provide '#'
Normally i can work ok, but in this controller i have a problem when the validation fails
public function createAction(Request $request)
{
$entity = new Clientes();
$form = $this->createCreateForm($entity);
$form->handleRequest($request);
if ($form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($entity);
$em->flush();
$url=$this->generateUrl('ec_main_cliente', array('idcliente' => $entity->getId()));
$url = str_replace('cliente', '#cliente', $url);
return $this->redirect($url);
}
return $this->render('ECMainBundle:Clientes:nuevo_cliente.html.twig', array(
'entity' => $entity,
'form' => $form->createView(),
));
}
When Form is Invalid , load "ECMainBundle:Clientes:nuevo_cliente.html.twig" without the "#" and lost all the menus and configurations.
Any suggestion please?
Thanks in Advance and sorry for my english
Image work Ok:
Image of the problem:
I still don't have the feeling to fully understand what you're trying to achieve, but I think that you want the redirect always take place. In this case you should restructure your code a bit:
$id = 0;
if ($form->isValid()) {
$em = $this->getDoctrine()->getManager();
$em->persist($entity);
$em->flush();
$id = $entity->getId();
}
$url = $this->generateUrl('ec_main_cliente', array('idcliente' => $id));
$url = str_replace('cliente', '#cliente', $url);
return $this->redirect($url);
Then, of course, the last part with the template rendering would be never exectuted.
Can anyone please show me a specific example of a Symfony2 form entity update? The book only shows how to create a new entity. I need an example of how to update an existing entity where I initially pass the id of the entity on the query string.
I'm having trouble understanding how to access the form again in the code that checks for a post without re-creating the form.
And if I do recreate the form, it means I have to also query for the entity again, which doesn't seem to make much sense.
Here is what I currently have but it doesn't work because it overwrites the entity when the form gets posted.
public function updateAction($id)
{
$em = $this->getDoctrine()->getEntityManager();
$testimonial = $em->getRepository('MyBundle:Testimonial')->find($id);
$form = $this->createForm(new TestimonialType(), $testimonial);
$request = $this->get('request');
if ($request->getMethod() == 'POST') {
$form->bindRequest($request);
echo $testimonial->getName();
if ($form->isValid()) {
// perform some action, such as save the object to the database
//$testimonial = $form->getData();
echo 'testimonial: ';
echo var_dump($testimonial);
$em->persist($testimonial);
$em->flush();
return $this->redirect($this->generateUrl('MyBundle_list_testimonials'));
}
}
return $this->render('MyBundle:Testimonial:update.html.twig', array(
'form' => $form->createView()
));
}
Working now. Had to tweak a few things:
public function updateAction($id)
{
$request = $this->get('request');
if (is_null($id)) {
$postData = $request->get('testimonial');
$id = $postData['id'];
}
$em = $this->getDoctrine()->getEntityManager();
$testimonial = $em->getRepository('MyBundle:Testimonial')->find($id);
$form = $this->createForm(new TestimonialType(), $testimonial);
if ($request->getMethod() == 'POST') {
$form->bindRequest($request);
if ($form->isValid()) {
// perform some action, such as save the object to the database
$em->flush();
return $this->redirect($this->generateUrl('MyBundle_list_testimonials'));
}
}
return $this->render('MyBundle:Testimonial:update.html.twig', array(
'form' => $form->createView()
));
}
This is actually a native function of Symfony 2 :
You can generate automatically a CRUD controller from the command line (via doctrine:generate:crud) and the reuse the generated code.
Documentation here :
http://symfony.com/doc/current/bundles/SensioGeneratorBundle/commands/generate_doctrine_crud.html
A quick look at the auto-generated CRUD code by the Symfony's command generate:doctrine:crudshows the following source code for the edit action
/**
* Displays a form to edit an existing product entity.
*
* #Route("/{id}/edit", name="product_edit")
* #Method({"GET", "POST"})
*/
public function editAction(Request $request, Product $product)
{
$editForm = $this->createForm('AppBundle\Form\ProductType', $product);
$editForm->handleRequest($request);
if ($editForm->isSubmitted() && $editForm->isValid()) {
$this->getDoctrine()->getManager()->flush();
return $this->redirectToRoute('product_edit', array('id' => $product->getId()));
}
return $this->render('product/edit.html.twig', array(
'product' => $product,
'edit_form' => $editForm->createView(),
));
}
Note that a Doctrine entity is passed to the action instead of an id (string or integer). This will make an implicit parameter conversion and saves you from manually fetching the corresponding entity with the given id.
It is mentioned as best practice in the Symfony's documentation