I'm trying to use d3.time.format on a date like this:
2016-02-10T12:40:16-05:00
Basically, a UTC date with a timezone offset.
The issue is, the %Z formatter in D3 looks for the timezone written as follows: -0500. In other words, the colon is missing.
Does anyone know a workaround?
Related
I want to do something relatively straightforward please help I'm stuck
Given today's date is 02 May, 2021 in my current timezone (Pacific Standard Time), build the string 20210502 (yyyymmdd format) dynamically.
What is the simplest way to do this in ADF? I tried following but returns error invalid expression:
#substring(formatString(getutcdate()),0,8)
I'm also not sure how to make it flexible so I can enter a different timezone if I want like Pacific Standard Time.
You can create a timezone variable and pass that value to convertFromUtc or convertTimeZone function. And you can choose format as you need. Here is the format specifiers list.
You can follow this:
expression:#replace(split(convertFromUtc(utcnow(),variables('timezone'),'u'),' ')[0],'-','')
Output:
I have a sensor log file with dates in the form Mon Nov 30 18:21:40 UTC 2020 that I'd like to convert to OpenRefine dates.
Per GREL Date Functions, I thought the correct transformation would be value.toDate('E M d H:m:s z y'), but I consistently get "Error: Unable to convert to a date".
I've tried simple things like replacing UTC with GMT, without success.
What clue am I missing?
That's a weird date format. I'm not sure why a sensor log wouldn't just use ISO 8601.
Try using value.toDate('EEE MMM d H:m:s Z y').
It's not super obvious from the docs that you need multiple characters, but if you look at the examples at the bottom of this page, you can see them used there.
https://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html
In TYPO3 I am using the News Extension to create an Event. In my List view I am using the following code snippet to show the End Time of the Event.
<f:format.date format=" - %H:%M Uhr">{newsItem.eventEnd}</f:format.date>
Which results in " - 20:00 Uhr" (German Language, hence the "Uhr").
I want a Format that switches that time to " - 08:00 PM" for the English translation, I am assuming that is not possible in Fluid since my searches have no result. Is there any workaround?
You can put your format into a locallang file. There it's possible to change the format related to the language.
<f:format.date format="{f:translate(key:'dateFormat')}">{newsItem.eventEnd}</f:format.date>
The date format viewhelper uses the same format as the default PHP date and strftime functions, so anything you can use %I:%M %p to get 08:00 PM. See http://php.net/manual/en/function.date.php and http://php.net/strftime for more about this.
I have this date and time format:
2010-05-19 07:53:30
and would like to change it to:
Wednesday # 7:53PM 5/19/2010
I'm doing this, which gets the current format:
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
formatter.dateFormat = #"yyyy-MM-dd HH:mm:ss";
but when I change the format, I end up with a null. For example:
formatter.dateFormat = #"hh:mm tt MM-dd-yyyy";
date = [formatter stringFromDate:formattedDate];
date will be null. I want to put the end result into an NSString. It would be nice if time and date could come out as separate properties so I can arrange them however I like. Any ideas on how I can change the formatting?
I think your formatting string is the problem. You should only use the characters you find in the table in UTS#35 Date Format Patterns. I tried your code and while the time hh:mm displays correctly, formatting stops at tt - not in the table!
If you really want characters in the format string that are not in the table you can escape them, like hh 'o''clock' a, zzzz - produces format like "12 o'clock PM, Pacific Daylight Time".
It would be nice if time and date could come out as separate properties so I can arrange them however I like. Any ideas on how I can change the formatting?
You have things backwards. If this is a date/time to be displayed to the user, you need to present it how the user wants it, not how you want it. For instance, most people outside the USA will be confused by MM-dd-yyyy particularly if the day is less than 13. Consider using -setDateStyle: and -setTimeStyle:. That way, the display string will come out as the user expects.
I know this sucks. Date stuff sucks hard. But: Imagine a date format like "dd-MM-yyyy h:mm" how would you tell for sure what time mode that is? AM / PM or 24 hour? I'd say: If there is no "a" in the date format, then that's no AM / PM stuff and therefore it's nice 24h stuff. What do you think?
If you are given a date, such as 11:15, you can't know whether it is AM or PM. Just as you don't know whether when I say Deer, I mean one or more than one. As a program designer, you have to remove ambiguities or make assumptions. You could either force the data to have AM/PM, or tell the provider of the time to give it to you in 24 hour format, or you can assume that they are smart enough to realize that without AM/PM you have no way of knowing. Not knowing your situation, I can't tell you how to proceed, but there are issues that transcend plain old programming. Like whether 1,000,000,000 is a billion or a milliard or a trillion or whether a ton is 1000 kilograms or ....
You should rather check for a M or m and not an a.
But "dd-MM-yyyy hh:mm" is surely an ambiguous format.
That is, parsing a date that just looks like dd-MM-yyyy hh:mm can't tell you about the 12/24 format.
You could assume it's 24h format, otherwise something is missing or it would look like "dd-MM-yyyy hh:mm X", where X is 'AM' or 'PM'.
The only truly unambiguous format is ISO 8601 'yyyy-MM-dd hh:mm' with 24h times.