I have a table that when i run this query over it
SELECT m.Id, m.DateOne, m.DateTwo, (SELECT IIF
(c.ClubId = 1095 , x.CaptainOne , x.CaptainTwo)
FROM Match x
JOIN Player c on c.Id = x.CaptainOne
JOIN Player d on d.Id = x.CaptainTwo
WHERE x.Id = m.Id ) AS Captain
FROM Match m
order by DateOne
give me an output that looks like this..
ID | DateOne | DateTwo | Captain
1 | 01/12/2015 | | 1658
2 | 08/12/2015 | | 1658
3 | 15/12/2015 | 22/12/2015 | 1658
4 | 02/01/2016 | | 1703
5 | 09/01/2016 | | 1703
6 | 16/01/2016 | 23/01/2016 | 1658
7 | 30/01/2016 | | 1658
8 | 06/02/2016 | | 1658
9 | 13/02/2016 | | 1658
10 | 20/02/2016 | | 1703
i then want to use these results to further narrow the output to look like this
Captain | Date(Min) | Date(Max) | Count
1658 | 01/12/2015 | 22/12/2015 | 3
1703 | 02/01/2016 | 09/01/2016 | 2
1658 | 16/01/2016 | 13/02/2016 | 4
1703 | 20/02/2016 | 20/02/2016 | 1
where it is creating a count of consecutive captain while getting the DateOne of the first occurrence and either DateTwo or DateOne if DateTwo is null of the last occurrence.
I hope this makes sense..
Thanks
Related
I have executed below query in sphinx,
select MVA_FIELD from mySphinxIndex facet MVA_FIELD order by count(*) desc;
What I got is like,
+----------------------------+----------+
| MVA_FIELD | count(*) |
+----------------------------+----------+
| | 664 |
| 0 | 536 |
| 13 | 439 |
| 4,13 | 8 |
| 19,13 | 8 |
| 18,13,20 | 8 |
| 8,17,18 | 8 |
| 8,18,13 | 8 |
| 8,15,18 | 8 |
| 8,13,20 | 7 |
| 17,13 | 7 |
| 18,19,20 | 7 |
| 8,17 | 7 |
| 13,17,19 | 7 |
| 11,6 | 7 |
| 6,11,13 | 7 |
| 15,18 | 7 |
| 11,13,20 | 7 |
| 11,13,17 | 7 |
| 6,18,19 | 6 |
| 7,20 | 6 |
| 8,11,13 | 6 |
| 13,17,20 | 6 |
I want to get the count of each ids in MVA_FIELD. For example, I just want the count of 0, 4, 13,... each id separately. How to achieve this ?
Honestly dont how how to do it with FACET suger, but with a normal GROUP BY query, would just use the GROUPBY() function when grouping by a MVA attribute
SELECT GROUPBY() AS value,COUNT(*) FROM mySphinxIndex GROUP BY MVA_FIELD ORDER BY COUNT(*) DESC;
From the docs
A special GROUPBY() function is also supported. It returns the GROUP BY key. That is particularly useful when grouping by an MVA value, in order to pick the specific value that was used to create the current group.
I have two objects within a SQl Server 2008 R2 database, which I am trying to join together with a left join but I am unable to get the left join to return all records from the table.
1 table - tt_activityoccurrence
1 view - vw_academicweeks
The vw_academicweeks, is a view that contains for each academic year a week number, and the first day and last day of the week and contains 52 records for each academic year.
tt_activityoccurrence is a table which contains occurrences of lessons within a year, lessons will not occur in all 52 weeks of the year.
With my query I am trying to return all instances from the vw_academicweeks view to return the following information
+------------+------------+------------+------------+---------+
| ActivityID | WeekStart | StartTime | EndTime | week_no |
+------------+------------+------------+------------+---------+
| 59936 | 04/09/2017 | 05/09/2017 | 05/09/2017 | 6 |
| 59936 | 11/09/2017 | 12/09/2017 | 12/09/2017 | 7 |
| 59936 | 18/09/2017 | 19/09/2017 | 19/09/2017 | 8 |
| 59936 | 25/09/2017 | 26/09/2017 | 26/09/2017 | 9 |
| 59936 | 02/10/2017 | 03/10/2017 | 03/10/2017 | 10 |
| 59936 | 09/10/2017 | 10/10/2017 | 10/10/2017 | 11 |
| 59936 | 16/10/2017 | 17/10/2017 | 17/10/2017 | 12 |
| 59936 | Null | Null | Null | 13 |
| 59936 | 30/10/2017 | 31/10/2017 | 31/10/2017 | 14 |
| 59936 | 06/11/2017 | 07/11/2017 | 07/11/2017 | 15 |
| 59936 | 13/11/2017 | 14/11/2017 | 14/11/2017 | 16 |
| 59936 | 20/11/2017 | 21/11/2017 | 21/11/2017 | 17 |
| 59936 | 27/11/2017 | 28/11/2017 | 28/11/2017 | 18 |
| 59936 | 04/12/2017 | 05/12/2017 | 05/12/2017 | 19 |
| 59936 | 11/12/2017 | 12/12/2017 | 12/12/2017 | 20 |
| 59936 | 18/12/2017 | 19/12/2017 | 19/12/2017 | 21 |
| 59936 | Null | Null | Null | 22 |
| 59936 | Null | Null | Null | 23 |
+------------+------------+------------+------------+---------+
With the left join I can return all values except the nulls, so that the week_no column is missing rows, 13,22 and 23. I have also tried this with an outer join but receive the same information.
I feel I am missing something obvious but it is escaping me at the moment.
select
ttao.ActivityID
,dateadd(dd,datediff(dd,0,DATEADD(dd, -(DATEPART(dw, ttao.StartTime)-1), ttao.StartTime)),0) WeekStart
,ttao.StartTime
,ttao.EndTime
,aw.week_no
from
vw_AcademicWeeks AW
left join TT_ActivityOccurrence TTAO on
(dateadd(dd,datediff(dd,0,DATEADD(dd, -(DATEPART(dw, ttao.StartTime)-1), ttao.StartTime)),0))=aw.ay_start
where
ay_code='1718' and
TTAO.ActivityID='59936'
order by aw.week_no asc
Your where clause makes it an inner join by eliminating rows outside of the scope of your join. You need to move this logic up to your join statement. Note, I didn't validate your join condiditon (the dateadd...datediff logic)
select
ttao.ActivityID
,dateadd(dd,datediff(dd,0,DATEADD(dd, -(DATEPART(dw, ttao.StartTime)-1), ttao.StartTime)),0) WeekStart
,ttao.StartTime
,ttao.EndTime
,aw.week_no
from
vw_AcademicWeeks AW
left join TT_ActivityOccurrence TTAO on
(dateadd(dd,datediff(dd,0,DATEADD(dd, -(DATEPART(dw, ttao.StartTime)-1), ttao.StartTime)),0)) = aw.ay_start
and ay_code='1718'
and TTAO.ActivityID='59936'
order by aw.week_no asc
I have two subqueries. Here is the output of subquery A....
id | date_lat_lng | stat_total | rnum
-------+--------------------+------------+------
16820 | 2016_10_05_10_3802 | 9 | 2
15701 | 2016_10_05_10_3802 | 9 | 3
16821 | 2016_10_05_11_3802 | 16 | 2
17861 | 2016_10_05_11_3802 | 16 | 3
16840 | 2016_10_05_12_3683 | 42 | 2
17831 | 2016_10_05_12_3767 | 0 | 2
17862 | 2016_10_05_12_3802 | 11 | 2
17888 | 2016_10_05_13_3683 | 35 | 2
17833 | 2016_10_05_13_3767 | 24 | 2
16823 | 2016_10_05_13_3802 | 24 | 2
and subquery B, in which date_lat_lng and stat_total has commonality with subquery A, but id does not.
id | date_lat_lng | stat_total | rnum
-------+--------------------+------------+------
17860 | 2016_10_05_10_3802 | 9 | 1
15702 | 2016_10_05_11_3802 | 16 | 1
17887 | 2016_10_05_12_3683 | 42 | 1
15630 | 2016_10_05_12_3767 | 20 | 1
16822 | 2016_10_05_12_3802 | 20 | 1
16841 | 2016_10_05_13_3683 | 35 | 1
15632 | 2016_10_05_13_3767 | 23 | 1
17863 | 2016_10_05_13_3802 | 3 | 1
16842 | 2016_10_05_14_3683 | 32 | 1
15633 | 2016_10_05_14_3767 | 12 | 1
Both subquery A and B pull data from the same table. I want to delete the rows in that table that share the same ID as subquery A but only where date_lat_lng and stat_total have a shared match in subquery B.
Effectively I need:
DELETE FROM table WHERE
id IN
(SELECT id FROM (subqueryA) WHERE
subqueryA.date_lat_lng=subqueryB.date_lat_lng
AND subqueryA.stat_total=subqueryB.stat_total)
Except I'm not sure where to place subquery B, or if I need an entirely different structure.
Something like this,
DELETE FROM table WHERE
id IN (
SELECT DISTINCT id
FROM subqueryA
JOIN subqueryB
USING (id,date_lat_lng,stat_total)
)
I have 2 tables:
Table1: 'op_ats'
| ID1 | numero |id_cofre | id_chave | estadoAT
| 1 | 111 | 1 | 3 | 1
| 2 | 222 | 3 | 3 | 2
| 3 | 333 | 1 | 4 | 2
| 4 | 444 | 1 | 2 | 3
Table_2: 'op_ats_cofres_chaves'
| ID2 | num_chave |
| 1 | A |
| 2 | B |
| 3 | C |
| 4 | D |
| 5 | E |
I have this SQL:
SELECT chaves.*, ats.numero numAT, ats.estadoAT
FROM op_ats_cofres_chaves chaves
LEFT JOIN op_ats ats ON ats.id_chave_cofre = chaves.id AND ats.id_cofre = 1
With this I get the following result:
| ID2 | num_chave | numAT | estadoAT |
| 1 | A | 444 | 3 |
| 2 | B | NULL | NULL |
| 3 | C | 111 | 1 |
| 4 | D | 333 | 2 |
| 5 | E | NULL | NULL |
Now the problem is that I want to filter the rows that are in Table1 but only that have the column 'estadoAT' with values 1 and 2. I've tried to add the line
WHERE op_ats.estadoAT = 1 OR op_ats.estadoAT = 2
But this makes the following result:
| ID2 | num_chave | numAT | estadoAT |
| 1 | A | 444 | 3 |
| 3 | C | 111 | 1 |
| 4 | D | 333 | 2 |
Resuming...
My intention is to get ALL rows in the Table2 and join the Table1 rows that have the 'id_cofre = 1' and '(estadoAT = 1 OR estadoAT = 2)'.
Any help is appreciated.
You have to move condition to JOIN clause instead of WHERE.
SELECT chaves.*, ats.numero numAT, ats.estadoAT
FROM op_ats_cofres_chaves chaves
LEFT JOIN op_ats ats ON ats.id_chave_cofre = chaves.id AND ats.id_cofre = 1
AND op_ats.estadoAT = 1 OR op_ats.estadoAT = 2;
I'd like to know if there is a way to include row numbers (basically telling me how many records I'm getting back from a database query).
I have the following SQL query
SELECT w.widget_id, w.class_id, wg.name classname, wg.label AS classgroup, c.label, c.seq,
g.name AS group, p.name, p.type, CASE WHEN v.value IS NOT NULL THEN v.value WHEN g2p.value IS NOT NULL THEN g2p.value ELSE p.value END AS value
FROM widgets_to_categories w
INNER JOIN widget_classes c ON w.class_id = c.class_id
JOIN classes_to_param_groups t2g ON c.class_id = t2g.class_id
JOIN widget_groups g ON t2g.group_id = g.group_id
JOIN param_groups_to_params g2p ON t2g.group_id = g2p.group_id
JOIN provisioning_params p ON g2p.param_id = p.param_id
INNER JOIN widget_cat_groups wg ON c.class_group_id = wg.class_group_id
LEFT JOIN widget_values v ON(w.widget_id=v.device_id AND p.param_id=v.param_id AND g.name=v.group_name )
WHERE w.widget_id=8 ORDER BY c.class_id ASC
And it returns data like:
widget_id | class_id | classname | classgroup | label | seq | group | name | type | value
8 | 1 | toy | group A | test label | 1 | toy | reg | text | af
8 | 1 | toy | group A | test label | 1 | reg2 | fall | text | 25327
8 | 1 | toy | group A | test label | 1 | reg2 | pd | text | dvaa
8 | 1 | toy | group A | test label | 1 | reg2 | ext | text | 28235
8 | 1 | toy | group A | test label | 1 | reg1 | ext | text | 28230
8 | 1 | toy | group A | test label | 1 | toy | meec | text | 094F22DE501
8 | 1 | toy | group A | test label | 1 | toy | mmap | text | 0|
8 | 1 | toy | group A | test label | 1 | reg1 | fna | text | 26014
8 | 1 | toy | group A | test label | 1 | reg1 | fall | text | t-123
8 | 1 | toy | group A | test label | 1 | toy | uen | boolean | false
8 | 1 | toy | group A | test label | 1 | toy | adminpd |
I'd like to know if there's a way to have the database auto generate and return another column that is just an identifier for the row, like so:
id |widget_id | class_id | classname | classgroup | label | seq | group | name | type | value
1 | 8 | 1 | toy | group A | test label | 1 | toy | reg | text | af
2 | 8 | 1 | toy | group A | test label | 1 | reg2 | fall | text | 25327
3 | 8 | 1 | toy | group A | test label | 1 | reg2 | pd | text | dvaa
4 | 8 | 1 | toy | group A | test label | 1 | reg2 | ext | text | 28235
5 | 8 | 1 | toy | group A | test label | 1 | reg1 | ext | text | 28230
6 | 8 | 1 | toy | group A | test label | 1 | toy | meec | text | 094F22DE501
7 | 8 | 1 | toy | group A | test label | 1 | toy | mmap | text | 0|
8 | 8 | 1 | toy | group A | test label | 1 | reg1 | fna | text | 26014
9 | 8 | 1 | toy | group A | test label | 1 | reg1 | fall | text | t-123
10 | 8 | 1 | toy | group A | test label | 1 | toy | uen | boolean | false
11 | 8 | 1 | toy | group A | test label | 1 | toy | adminpd | boolean | false
I think I can do this by selecting into a temporary table.. I haven't figured out the syntax on how to do it yet... But I'm also wondering if there's another simpler way.
Once I get the data back from the database, having this ID field makes it eaiser to manipulate.
Thanks.
You can use the row_number window function to keep track of each row number.
Like so:
create table foo
(
id serial,
val text
);
INSERT INTO foo (val)
VALUES ('One'), ('Two'), ('Three');
SELECT f.*, row_number() OVER(ORDER BY val)
FROM foo AS f
ORDER BY val;
Here's an SQL Fiddle which shows this:
http://sqlfiddle.com/#!15/0c434/2
Additional options:
You could count the result with a query of the form:
SELECT count(*)
FROM
(
SELECT *
FROM foo
);
Or you may be able to get the row count back as part of the Postgres library you're using. For example, psycopg2 (Python) and DBI (Perl) allow for this (with some caveats). The library you're using may offer something similar.