I have executed below query in sphinx,
select MVA_FIELD from mySphinxIndex facet MVA_FIELD order by count(*) desc;
What I got is like,
+----------------------------+----------+
| MVA_FIELD | count(*) |
+----------------------------+----------+
| | 664 |
| 0 | 536 |
| 13 | 439 |
| 4,13 | 8 |
| 19,13 | 8 |
| 18,13,20 | 8 |
| 8,17,18 | 8 |
| 8,18,13 | 8 |
| 8,15,18 | 8 |
| 8,13,20 | 7 |
| 17,13 | 7 |
| 18,19,20 | 7 |
| 8,17 | 7 |
| 13,17,19 | 7 |
| 11,6 | 7 |
| 6,11,13 | 7 |
| 15,18 | 7 |
| 11,13,20 | 7 |
| 11,13,17 | 7 |
| 6,18,19 | 6 |
| 7,20 | 6 |
| 8,11,13 | 6 |
| 13,17,20 | 6 |
I want to get the count of each ids in MVA_FIELD. For example, I just want the count of 0, 4, 13,... each id separately. How to achieve this ?
Honestly dont how how to do it with FACET suger, but with a normal GROUP BY query, would just use the GROUPBY() function when grouping by a MVA attribute
SELECT GROUPBY() AS value,COUNT(*) FROM mySphinxIndex GROUP BY MVA_FIELD ORDER BY COUNT(*) DESC;
From the docs
A special GROUPBY() function is also supported. It returns the GROUP BY key. That is particularly useful when grouping by an MVA value, in order to pick the specific value that was used to create the current group.
Related
I have a table where field with multiple value by comma:
+------+---------------+
| id | education_ids |
+------+---------------+
| 3 | 7,5 |
| 4 | 7,3 |
| 5 | 1,5 |
| 8 | 3 |
| 9 | 5,7 |
| 11 | 9 |
...
+------+---------------+
when I trying use faceted search:
select id,education_ids from jobResume facet education_ids;
I'm getting this response:
+---------------+----------+
| education_ids | count(*) |
+---------------+----------+
| 7,5 | 3558 |
| 7,3 | 3655 |
| 1,5 | 3686 |
| 3 | 31909 |
| 5,7 | 3490 |
| 9 | 31743 |
| 9,6 | 3535 |
| 8,2 | 3547 |
| 6,2,7 | 291 |
| 7,8,1 | 291 |
| 1,2 | 3637 |
| 7 | 31986 |
| 5,9,7 | 408 |
| 1,1,5 | 365 |
| 5 | 31768 |
| 3,8,3,7 | 32 |
| 3,7,6 | 431 |
| 2 | 31617 |
| 5,5 | 3614 |
| 9,9,2,2 | 6 |
+---------------+----------+
but that's not what I wanted to see. I would like to where each value had its own count, for example like here:
+---------------+----------+
| education_ids | count(*) |
+---------------+----------+
| 10 | 961 |
| 11 | 1653 |
| 12 | 1998 |
| 13 | 2090 |
| 14 | 1058 |
| 15 | 347 |
...
+---------------+----------+
can I get such a result with sphinx?
Make sure you use an MVA, not a string attribute:
index rt
{
type = rt
rt_field = f
rt_attr_multi = education_ids
path = rt
}
snikolaev#dev:$ mysql -P9306 -h0
Welcome to the MySQL monitor. Commands end with ; or \g.
Your MySQL connection id is 1
Server version: 3.2.2 62ea5ff#191220 release
Copyright (c) 2000, 2019, Oracle and/or its affiliates. All rights reserved.
Oracle is a registered trademark of Oracle Corporation and/or its
affiliates. Other names may be trademarks of their respective
owners.
Type 'help;' or '\h' for help. Type '\c' to clear the current input statement.
mysql> insert into rt(education_ids) values((7,5)), ((7,3)), ((7,1)), ((5,1)), ((5,3));
Query OK, 5 rows affected (0.00 sec)
mysql> select * from rt facet education_ids;
+---------------------+---------------+
| id | education_ids |
+---------------------+---------------+
| 2810610458032078849 | 5,7 |
| 2810610458032078850 | 3,7 |
| 2810610458032078851 | 1,7 |
| 2810610458032078852 | 1,5 |
| 2810610458032078853 | 3,5 |
+---------------------+---------------+
5 rows in set (0.00 sec)
+---------------+----------+
| education_ids | count(*) |
+---------------+----------+
| 7 | 3 |
| 5 | 3 |
| 3 | 2 |
| 1 | 2 |
+---------------+----------+
4 rows in set (0.00 sec)
BTW here's an interactive course about faceting in Sphinx / Manticore in case you want to learn more about that - https://play.manticoresearch.com/faceting/
I am a novice self-teaching Microsoft Access.
I have an MS Access database with a table of students (Table1).
Table1
+----+-----------+----------+------------+------------+
| id | firstname | lastname | Year_Group | Form_Group |
+----+-----------+----------+------------+------------+
| 2 | mnb | nbgfv | 7 | 1 |
| 3 | jhg | uhgf | 8 | 2 |
| 4 | poi | ijuy | 9 | 2 |
| 5 | tgf | tgfd | 10 | 2 |
| 6 | wer | qwes | 11 | 2 |
+----+-----------+----------+------------+------------+
Every day students days are recorded sort of like Table2.
Table2
+----------+----+-----------+----------+------------+--------+-----------+----------+
| Date | id | firstname | lastname | Year_Group | Effort | Behaviour | Homework |
+----------+----+-----------+----------+------------+--------+-----------+----------+
| 28/02/19 | 2 | mnb | nbgfv | 7 | Good | Good | Y |
| 28/02/19 | 3 | jhg | uhgf | 8 | OK | OK | Y |
| 28/02/19 | 4 | poi | ijuy | 9 | Bad | Bad | N |
| 01/03/19 | 5 | tgf | tgfd | 10 | Good | OK | Y |
| 01/03/19 | 6 | wer | qwes | 11 | Good | Good | Y |
+----------+----+-----------+----------+------------+--------+-----------+----------+
Is there a way (when using a list box or combo box) to select a student from Table1 so that their information is used for the corresponding columns in Table2?
Or is there a more efficient way to do this?
Firstly, you should normalise your data.
Currently, you are repeating the firstname, lastname, and Year_Group data in two separate tables, which not only bloats your database, but also means that such data must be maintained in two separate places, potentially leading to inconsistencies and then uncertainty as to which is the master.
Instead, I would suggest that your Students table should contain all information pertaining to the characteristics of a student:
Students
+----+-----------+----------+------------+------------+
| id | firstname | lastname | Year_Group | Form_Group |
+----+-----------+----------+------------+------------+
| 2 | mnb | nbgfv | 7 | 1 |
| 3 | jhg | uhgf | 8 | 2 |
| 4 | poi | ijuy | 9 | 2 |
| 5 | tgf | tgfd | 10 | 2 |
| 6 | wer | qwes | 11 | 2 |
+----+-----------+----------+------------+------------+
And the information pertaining to each school day should only reference the student ID in the Students table:
SchoolDays
+----------+----+--------+-----------+----------+
| Date | id | Effort | Behaviour | Homework |
+----------+----+--------+-----------+----------+
| 28/02/19 | 2 | Good | Good | Y |
| 28/02/19 | 3 | OK | OK | Y |
| 28/02/19 | 4 | Bad | Bad | N |
| 01/03/19 | 5 | Good | OK | Y |
| 01/03/19 | 6 | Good | Good | Y |
+----------+----+--------+-----------+----------+
Then, if you want to display the data in its entirety, you would use a query which joins the two tables, e.g.:
select
t2.date,
t1.firstname,
t1.lastname,
t1.year_group,
t2.effort,
t2.behaviour,
t2.homework
from
students t1 inner join schooldays t2 on t1.id = t2.id
I have two objects within a SQl Server 2008 R2 database, which I am trying to join together with a left join but I am unable to get the left join to return all records from the table.
1 table - tt_activityoccurrence
1 view - vw_academicweeks
The vw_academicweeks, is a view that contains for each academic year a week number, and the first day and last day of the week and contains 52 records for each academic year.
tt_activityoccurrence is a table which contains occurrences of lessons within a year, lessons will not occur in all 52 weeks of the year.
With my query I am trying to return all instances from the vw_academicweeks view to return the following information
+------------+------------+------------+------------+---------+
| ActivityID | WeekStart | StartTime | EndTime | week_no |
+------------+------------+------------+------------+---------+
| 59936 | 04/09/2017 | 05/09/2017 | 05/09/2017 | 6 |
| 59936 | 11/09/2017 | 12/09/2017 | 12/09/2017 | 7 |
| 59936 | 18/09/2017 | 19/09/2017 | 19/09/2017 | 8 |
| 59936 | 25/09/2017 | 26/09/2017 | 26/09/2017 | 9 |
| 59936 | 02/10/2017 | 03/10/2017 | 03/10/2017 | 10 |
| 59936 | 09/10/2017 | 10/10/2017 | 10/10/2017 | 11 |
| 59936 | 16/10/2017 | 17/10/2017 | 17/10/2017 | 12 |
| 59936 | Null | Null | Null | 13 |
| 59936 | 30/10/2017 | 31/10/2017 | 31/10/2017 | 14 |
| 59936 | 06/11/2017 | 07/11/2017 | 07/11/2017 | 15 |
| 59936 | 13/11/2017 | 14/11/2017 | 14/11/2017 | 16 |
| 59936 | 20/11/2017 | 21/11/2017 | 21/11/2017 | 17 |
| 59936 | 27/11/2017 | 28/11/2017 | 28/11/2017 | 18 |
| 59936 | 04/12/2017 | 05/12/2017 | 05/12/2017 | 19 |
| 59936 | 11/12/2017 | 12/12/2017 | 12/12/2017 | 20 |
| 59936 | 18/12/2017 | 19/12/2017 | 19/12/2017 | 21 |
| 59936 | Null | Null | Null | 22 |
| 59936 | Null | Null | Null | 23 |
+------------+------------+------------+------------+---------+
With the left join I can return all values except the nulls, so that the week_no column is missing rows, 13,22 and 23. I have also tried this with an outer join but receive the same information.
I feel I am missing something obvious but it is escaping me at the moment.
select
ttao.ActivityID
,dateadd(dd,datediff(dd,0,DATEADD(dd, -(DATEPART(dw, ttao.StartTime)-1), ttao.StartTime)),0) WeekStart
,ttao.StartTime
,ttao.EndTime
,aw.week_no
from
vw_AcademicWeeks AW
left join TT_ActivityOccurrence TTAO on
(dateadd(dd,datediff(dd,0,DATEADD(dd, -(DATEPART(dw, ttao.StartTime)-1), ttao.StartTime)),0))=aw.ay_start
where
ay_code='1718' and
TTAO.ActivityID='59936'
order by aw.week_no asc
Your where clause makes it an inner join by eliminating rows outside of the scope of your join. You need to move this logic up to your join statement. Note, I didn't validate your join condiditon (the dateadd...datediff logic)
select
ttao.ActivityID
,dateadd(dd,datediff(dd,0,DATEADD(dd, -(DATEPART(dw, ttao.StartTime)-1), ttao.StartTime)),0) WeekStart
,ttao.StartTime
,ttao.EndTime
,aw.week_no
from
vw_AcademicWeeks AW
left join TT_ActivityOccurrence TTAO on
(dateadd(dd,datediff(dd,0,DATEADD(dd, -(DATEPART(dw, ttao.StartTime)-1), ttao.StartTime)),0)) = aw.ay_start
and ay_code='1718'
and TTAO.ActivityID='59936'
order by aw.week_no asc
I want to create a cross table in Spotfire where in which Average is calculated only when there are at least 3 values. If there are no values or less than 3 values the average should be blank.
+-------+-----+---------+
| Month | Age | Average |
+-------+-----+---------+
| 1 | 10 | |
| 2 | 11 | |
| 3 | 2 | 7.7 |
| 4 | | |
| 5 | 13 | |
| 6 | 14 | |
| 7 | | |
| 8 | 19 | |
| 9 | 20 | |
| 10 | 21 | 20 |
+-------+-----+---------+
If I'm understanding you correctly, you want to group by Month, and then have something like this as your aggregation:
If(Count()>2,Avg([Age]),null) as [AverageAge_3Min]
I have two subqueries. Here is the output of subquery A....
id | date_lat_lng | stat_total | rnum
-------+--------------------+------------+------
16820 | 2016_10_05_10_3802 | 9 | 2
15701 | 2016_10_05_10_3802 | 9 | 3
16821 | 2016_10_05_11_3802 | 16 | 2
17861 | 2016_10_05_11_3802 | 16 | 3
16840 | 2016_10_05_12_3683 | 42 | 2
17831 | 2016_10_05_12_3767 | 0 | 2
17862 | 2016_10_05_12_3802 | 11 | 2
17888 | 2016_10_05_13_3683 | 35 | 2
17833 | 2016_10_05_13_3767 | 24 | 2
16823 | 2016_10_05_13_3802 | 24 | 2
and subquery B, in which date_lat_lng and stat_total has commonality with subquery A, but id does not.
id | date_lat_lng | stat_total | rnum
-------+--------------------+------------+------
17860 | 2016_10_05_10_3802 | 9 | 1
15702 | 2016_10_05_11_3802 | 16 | 1
17887 | 2016_10_05_12_3683 | 42 | 1
15630 | 2016_10_05_12_3767 | 20 | 1
16822 | 2016_10_05_12_3802 | 20 | 1
16841 | 2016_10_05_13_3683 | 35 | 1
15632 | 2016_10_05_13_3767 | 23 | 1
17863 | 2016_10_05_13_3802 | 3 | 1
16842 | 2016_10_05_14_3683 | 32 | 1
15633 | 2016_10_05_14_3767 | 12 | 1
Both subquery A and B pull data from the same table. I want to delete the rows in that table that share the same ID as subquery A but only where date_lat_lng and stat_total have a shared match in subquery B.
Effectively I need:
DELETE FROM table WHERE
id IN
(SELECT id FROM (subqueryA) WHERE
subqueryA.date_lat_lng=subqueryB.date_lat_lng
AND subqueryA.stat_total=subqueryB.stat_total)
Except I'm not sure where to place subquery B, or if I need an entirely different structure.
Something like this,
DELETE FROM table WHERE
id IN (
SELECT DISTINCT id
FROM subqueryA
JOIN subqueryB
USING (id,date_lat_lng,stat_total)
)