Possible to change the package name when generating client code - scala

Question

I am generating the client scala code for an API using the Swagger Edtior. I pasted the json then did a Generate Client/Scala. It gives me a default root package of
io.swagger.client
I can't see any obvious way of specifying something different. Can this be done?

Answer 1

Step (1): Create a file config.json and add following lines and define package names:
{
"modelPackage" : "com.xyz.model",
"apiPackage" : "com.xyz.api"
}
Step (2): Now, pass the above file name along with codegen command with -c option:
$ java -jar swagger-codegen-cli.jar generate -i path/swagger.json -l java -o Code -c path/config.json
Now, it will generate your java packages like com.xyz… instead of default one io.swagger.client…

Answer 2

Run the following command to get information about the supported configuration options
java -jar swagger-codegen-cli.jar config-help -l scala
This will give you information about supported by this generator (Scala in this example):
CONFIG OPTIONS
sortParamsByRequiredFlag
Sort method arguments to place required parameters before optional parameters. (Default: true)
ensureUniqueParams
Whether to ensure parameter names are unique in an operation (rename parameters that are not). (Default: true)
modelPackage
package for generated models
apiPackage
package for generated api classes
Next, define a config.json file with the above parameters:
{
"modelPackage": "your package name",
"apiPackage": "your package name"
}
And supply config.json as input to swagger-codegen using the -c flag.