I wrote this peace of code that is supposed to check whether the device is a RPI and output the temperature.
import os
def CheckIfPi():
try:
res = os.popen('vcgencmd measure_temp').readline()
return float((res.replace("temp=","").replace("'C\n","")))
except:
return 0
def ReturnTemperature():
if CheckIfPi() > 0:
print("The temperature of the Pi is: ", CheckIfPi())
else:
print("This is not a Pi.")
ReturnTemperature()
The output I get:
/bin/sh: 1: vcgencmd: not found
This is not a Pi.
The output i didnt expect to get was /bin/sh: 1: vcgencmd: not found
Related
Hey i am runing the following piece of code:
import nipype.interfaces.spm as spm
realign = spm.Realign()
And getting the following error:
raise IOError("This docstring was not generated by Nipype!\n") from e
OSError: This docstring was not generated by Nipype!
After debugging:
My code:
spm.Realign()
When this runs it uses matlab to run the follwing (base.py lines 217):
mlab.inputs.script = """
if isempty(which('spm')),
throw(MException('SPMCheck:NotFound','SPM not in matlab path'));
end;
spm_path = spm('dir');
[name, version] = spm('ver');
fprintf(1, 'NIPYPE path:%s|name:%s|release:%s', spm_path, name, version);
exit;
"""
try:
out = mlab.run()
I run it in Matlab and got :
>> isempty(which('spm'))
ans =
logical
0
>> [name, version] = spm('ver');
fprintf(1, 'NIPYPE path:%s|name:%s|release:%s', spm_path, name, version);
NIPYPE path:C:\Program Files\MATLAB\R2022b\toolbox\spm12\spm12|name:SPM12|release:7771
so as you can see I have result from this script, but when checking the "out" variable here (line 239):
out = sd._strip_header(out.runtime.stdout)
Stdout is "" empty string
So I think the problem is Somehow related to the answer of the script from Matlab, how to fix it ??
Thanks!
I've written a couple production BPF agents, but my approach is very iterative until I please the verifier and can move on. I've reached my limit again.
Here's a program that works if I have one fewer && condition -- and breaks otherwise. The confusing part is that the warning implies that 103 insns is greater-than at most 4096 insns. There's obviously something I'm misunderstanding about how this is all strung together.
My ultimate goal is to do logging based on a process' environment -- so alternative approaches are welcome. :)
Error:
$ sudo python foo.py
bpf: Argument list too long. Program too large (103 insns), at most 4096 insns
Failed to load BPF program b'tracepoint__sched__sched_process_exec': Argument list too long
BPF Source:
#include <linux/mm_types.h>
#include <linux/sched.h>
#include <linux/version.h>
int tracepoint__sched__sched_process_exec(
struct tracepoint__sched__sched_process_exec* args
) {
struct task_struct* task = (typeof(task))bpf_get_current_task();
const struct mm_struct* mm = task->mm;
unsigned long env_start = mm->env_start;
unsigned long env_end = mm->env_end;
// Read up to 512 environment variables -- only way I could find to "limit"
// the loop to satisfy the verifier.
char var[12];
for (int n = 0; n < 512; n++) {
int result = bpf_probe_read_str(&var, sizeof var, (void*)env_start);
if (result <= 0) {
break;
}
env_start += result;
if (
var[0] == 'H' &&
var[1] == 'I' &&
var[2] == 'S' &&
var[3] == 'T' &&
var[4] == 'S' &&
var[5] == 'I' &&
var[6] == 'Z' &&
var[7] == 'E'
) {
bpf_trace_printk("Got it: %s\n", var);
break;
}
}
return 0;
}
Basic loader program for reproducing:
#!/usr/bin/env python3
import sys
from bcc import BPF
if __name__ == '__main__':
source = open("./foo.c").read()
try:
BPF(text=source.encode("utf-8")).trace_print()
except Exception as e:
error = str(e)
sys.exit(error)
bpf: Argument list too long. Program too large (103 insns), at most 4096 insns
Looking at the error message, my guess would be that your program has 103 instructions and it's rejected because it's too complex. That is, the verifier gave up before analyzing all instructions on all paths.
On Linux 5.15 with a privileged user, the verifier gives up after reading 1 million instructions (the complexity limit). Since it has to analyze all paths through the program, a program with a small number of instructions can have a very high complexity. That's particularly the case when you have loops and many conditions, as is your case.
Why is the error message confusing? This error message is coming from libbpf.c:
if (ret < 0 && errno == E2BIG) {
fprintf(stderr,
"bpf: %s. Program %s too large (%u insns), at most %d insns\n\n",
strerror(errno), attr->name, insns_cnt, BPF_MAXINSNS);
return -1;
}
Since the bpf(2) syscall returns E2BIG both when the program is too large and when its complexity is too high, libbpf prints the same error message for both cases, always with at most 4096 instructions. I'm confident upstream would accept a patch to improve that error message.
So I'm trying to learn some python3 with some simple code as stated below. The point of the code is to have a loop that runs until one of the files exists and contains data. For some reason i'm getting an error running this, saying that the variable has an invalid syntax just as if numbers in variables are illegal (which they arent?):
$ python3 test.py
File "test.py", line 14
While file1==False and file2==False and file3==False:
^
SyntaxError: invalid syntax
Code:
import os
filePath1 = '/some/path'
filePath2 = '/some/path'
filePath3 = '/some/path'
file1 = False
file2 = False
file3 = False
While file1==False and file2==False and file3==False:
if os.path.exists(filePath1):
with open(filePath1,'r') as f:
try:
file1 = f.read()
except:
print("No file data.")
if os.path.exists(filePath2):
with open(filePath2,'r') as f:
try:
file2 = f.read()
except:
print("No file data.")
if os.path.exists(filePath3):
with open(filePath3,'r') as f:
try:
file3 = f.read()
except:
print("No file data.")
I don't understand this because:
>>>file1=False
>>>file2=False
>>>file1==False and file2==False
True
I'd be grateful for any help
invalid syntax is caused by your capitalized While keyword, which python doesn't recognize. Use the reserved keyword while, small letters only.
Student trying to compare two .txt files of string "answers" from a multiple choice test a,c,d,b, etc. I've found some information on different parts of the problems I'm having and found a possible way to get the comparisons I want, but the guide was meant for in script strings and not pulling a list from a file.
For the import of the two files and comparing them, I'm basing my code on my textbook and this video here: Video example
I've got the code up and running, but for some reason I'm only getting 0.0% match when I want to a 100.0% match, at least for the two text files I'm using with identical answer lists.
import difflib
answer_sheet = "TestAnswerList.txt"
student_sheet = "StudentAnswerList.txt"
ans_list = open(answer_sheet).readlines()
stu_list = open(student_sheet).readlines()
sequence = difflib.SequenceMatcher(isjunk=None, a=ans_list, b=stu_list)
check_list = sequence.ratio()*100
check_list = round(check_list,1)
print(str(check_list) + "% match")
if check_list == 100:
print('This grade is Plus Ultra!')
elif check_list >= 75:
print('Good job, you pass!')
else:
print('Please study harder for your next test.')
# not the crux of my issue, but will accept advice all the same
answer_sheet.close
student_sheet.close
If I add in the close statement at the end for both of the text files, then I receive this error:
Traceback (most recent call last): File
"c:/Users/jaret/Documents/Ashford U/CPT 200/Python Code/Wk 5 Int Assg
- Tester code.py", line 18, in
answer_sheet.close AttributeError: 'str' object has no attribute 'close'
I had to re-look at how my files were being opened and realized that the syntax was for Python 2 not 3. I chose to go w/ basic open and later close to reduce any potential errors on my novice part.
import difflib
f1 = open('TestAnswerList.txt')
tst_ans = f1.readlines()
f2 = open('StudentAnswerList.txt')
stu_ans = f2.readlines()
sequence = difflib.SequenceMatcher(isjunk=None, a=stu_ans, b=tst_ans)
check_list = sequence.ratio()*100
check_list = round(check_list,1)
print(str(check_list) + "% match") # Percentage correct
if check_list == 100:
print('This grade is Plus Ultra!')
elif check_list >= 75:
print('Good job, you pass!')
else:
print('Please study harder for your next test.')
# Visual Answer match-up
print('Test Answers: ', tst_ans)
print('Student Answers:', stu_ans)
f1.close()
f2.close()
I am trying to send video from raspberry pi to my laptop via laptop
and save them as pictures so i found the below code online
but I get the following errors when I run them
so i run this client code on the pi using Thonny ide that comes preloaded
, I apologize for the way code is formatted below and would be very grateful if anybody can help me sort this out
Server on the laptop is run using python 3.6 idle
import sys
import numpy as np
import cv2
import socket
class VideoStreamingTest(object):
def __init__(self):
self.server_socket = socket.socket()
self.server_socket.bind(('0.0.0.0', 9006))
self.server_socket.listen(0)
self.connection, self.client_address = self.server_socket.accept()
self.connection = self.connection.makefile('rb')
self.streaming()
def streaming(self):
try:
print("Connection from: ", self.client_address)
print("Streaming...")
print("Press 'q' to exit")
stream_bytes = ' '
while True:
stream_bytes += self.connection.read(1024)
first = stream_bytes.find('\xff\xd8')
last = stream_bytes.find('\xff\xd9')
if first != -1 and last != -1:
jpg = stream_bytes[first:last + 2]
stream_bytes = stream_bytes[last + 2:]
#image = cv2.imdecode(np.fromstring(jpg, dtype=np.uint8), cv2.CV_LOAD_IMAGE_GRAYSCALE)
image = cv2.imdecode(np.fromstring(jpg, dtype=np.uint8), cv2.CV_LOAD_IMAGE_UNCHANGED)
cv2.imshow('image', image)
if cv2.waitKey(1) & 0xFF == ord('q'):
break
finally:
self.connection.close()
self.server_socket.close()
if __name__ == '__main__':
VideoStreamingTest()
I get the following error
Connection from: ('192.168.43.3', 47518)
Streaming...
Press 'q' to exit
Traceback (most recent call last):
File "C:\Users\John Doe\d-ff\Desktop\AutoRCCar-master
3\test\stream_server_test.py", line 46, in <module>
VideoStreamingTest()
File "C:\Users\John Doe\d-ff\Desktop\AutoRCCar-master
3\test\stream_server_test.py", line 16, in __init__
self.streaming()
File "C:\Users\John Doe\d-ff\Desktop\AutoRCCar-master
3\test\stream_server_test.py", line 28, in streaming
stream_bytes += self.connection.read(1024)
TypeError: must be str, not bytes
Client side on the pi
import io
import socket
import struct
import time
import picamera
# create socket and bind host
client_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
client_socket.connect(('ToM', 9006))
connection = client_socket.makefile('wb')
try:
with picamera.PiCamera() as camera:
camera.resolution = (320, 240) # pi camera resolution
camera.framerate = 5 # 10 frames/sec
time.sleep(2) # give 2 secs for camera to initilize
start = time.time()
stream = io.BytesIO()
# send jpeg format video stream
for foo in camera.capture_continuous(stream, 'jpeg', use_video_port = True):
connection.write(struct.pack('<L', stream.tell()))
connection.flush()
stream.seek(0)
connection.write(stream.read())
if time.time() - start > 600:
break
stream.seek(0)
stream.truncate()
connection.write(struct.pack('<L', 0))
finally:
connection.close()
client_socket.close()
I get the following error
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "/home/pi/Desktop/stream_client.py", line 40, in <module>
connection.close()
File "/usr/lib/python3.5/socket.py", line 594, in write
return self._sock.send(b)
BrokenPipeError: [Errno 32] Broken pipe
I first thought it might be because of the limited bandwidth since i was running vnc viewer (remote desktop) via wifi on the pi but I don't think it is
I also had same problem. After some searching I found solution.
In python 3 we have to specify whether string is regular string or binary.Thats why we use b'string' instead of just 'string'
Change
stream_bytes = ' '
to
stream_bytes = b' '
Also change
first = stream_bytes.find('\xff\xd8')
last = stream_bytes.find('\xff\xd9')
to
first = stream_bytes.find(b'\xff\xd8')
last = stream_bytes.find(b'\xff\xd9')
Note that you are using cv2.CV_LOAD_IMAGE_UNCHANGED which is not available in opencv3.0
Use cv2.IMREAD_COLOR to show image in color.
Edit these changes and your stream should run smoothly.
connection.write(struct.pack('<L', 0))
Check out by inserting the above within try