I have class User with embedded class Social. Social has properties vk,fb, so my structure something like:
User {
#class: User
social: {
#class : Social
"vk":"123",
"fb":"456"
}
}
How to create index, that i can use it on select: select from User where social.vk = '123'
Indexes are created for properties of class, not for embedded ones, so it's not possible.
We can create two separate class User and Social and indexes:
create class User
create class Social
create property Social.vk string
create property User.social LINK Social
create index User.social unique
create index Social.vk unique
Now select from User where social.vk = '123' uses index
Let me know, if I'm wrong.
Related
I use Hasura and I have a social-network like situation.
In which I have a "User" object and a "Feed" object.
Every user has a feed.
I have a relationship from user.id to feed.id.
The relevant mutation is UpsertUserDetails as follows:
mutation UserDetailsUpsert(
$email: String!
$picture: String
) {
insert_users_one(
object: {
email: $email
feed: { data: {} }
picture: $picture
}
on_conflict: { constraint: users_tid_email_key, update_columns: [picture] }
) {
id
}
}
So when I create a new user it also creates a feed for it.
But when I only update user details I don't want it to create a new feed.
I would like to stop the upsert from going through to relationships instead of the above default behavior.
and according to this manual I don't see if its even possible: https://hasura.io/docs/latest/graphql/core/databases/postgres/mutations/upsert.html#upsert-in-nested-mutations
To allow upserting in nested cases, set update_columns: []. By doing this, in case of a conflict, the conflicted column/s will be updated with the new value (which is the same values as they had before and hence will effectively leave them unchanged) and will allow the upsert to go through.
Thanks!
I'd recommend that you design your schema such that bad data cannot be entered in the first place. You can put partial unique indices on the feed table in order to prevent duplicate feeds from ever being created. Since you have both users and groups you can implement it with 2 partial indices.
CREATE UNIQUE INDEX unique_feed_per_user ON feed (user_id)
WHERE user_id IS NOT NULL;
CREATE UNIQUE INDEX unique_feed_per_group ON feed (group_id)
WHERE group_id IS NOT NULL;
I am creating a collection of judges and courthouses. Every judge will be assigned to one courthouse. I have set up my relation to be that courthouse has many judges
I am attempting to do this programmatically when the app loads. I have a function that is able to populate all the fields in judge except the relation to courthouse. My function uses the Strapi API like this
const judge = await strapi.query('judge').create({
name: data[i].name,
},
{
courthouse: data[i].courthouse_name // here is where I think the relation is created
}
)
I am passing in a string that has the name of courthouse, because I don't know the ID of the courthouse in the Courthouse collection.
My question is it possible to create a relation to another collection by anything other than an ID? How can I create a relation to a courthouse by its name?
I couldn't find a way around building a relationship between two models without the ID, so I created a custom solution using the Strapi lifecycle hooks
Essentially what I did I utilized the beforeCreate lifecycle hook to query and find the courthouse that matches the name like this:
// judges.js
async beforeCreate(result, data) {
const courthouse = await strapi.query('courthouse').find(
{courthouse_name:data.courthouse}
); // returns the courthouse that matches the name
result['courthouse'] = courthouse[0].id; // populates the relational field with the
// ID of the courthouse
}
The response object contained the courthouse's ID and I manipulated the data that is being sent to the create command like this:
const judge = await strapi.query('judge').create({
name: data[i].name,
courthouse: data[i].courthouse_name
})
The result is an object that looks like this:
{name: 'Garfield Lucas, courthouse: 7463987}
I am trying to get one query work since morning and not able to get it working I have two tables photographers and reviews please have a look at structure and then I will ask the question at the bottom :
Reviews table :
id int(10) unsigned -> primary key
review text
user_id int(10) unsigned foreign key to users table
user_name varchar(64)
photographer_id int(10) unsigned foreign key to photographers table
Photographers table :
id int(10) unsigned -> primary key
name text
brand text
description text
photo text
logo text
featured varchar(255)
Photographers model :
class Photographer extends Model
{
public function reviews()
{
return $this->hasMany('\App\Review');
}
}
Reviews Model :
class Review extends Model
{
public function photographers()
{
return $this->belongsTo('\App\Photographer');
}
}
My logic to query the records
$response = Photographer::with(['reviews' => function($q)
{
$q->selectRaw('max(id) as id, review, user_id, user_name, photographer_id');
}])
->where('featured', '=', 'Yes')
->get();
The question is : I want to fetch all the photographers who have at least one review in the review table, also I want to fetch only one review which is the most latest, I may have more than one review for a photographer but I want only one.
I would add another relationship method to your Photogrpaher class:
public function latestReview()
{
return $this->hasOne('App\Review')->latest();
}
Then you can call:
Photographer::has('latestReview')->with('latestReview')->get();
Notes:
The latest() method on the query builder is a shortcut for orderBy('created_at', 'desc'). You can override the column it uses by passing an argument - ->latest('updated_at')
The with method loads in the latest review.
The has method only queries photographers that have at least one item of the specified relationship
Have a look at Has Queries in Eloquent. If you want to customise the has query further, the whereHas method would be very useful
If you're interested
You can add query methods to the result of a relationship method. The relationship objects have a query builder object that they pass any methods that do not exist on themselves to, so you can use the relationships as a query builder for that relationship.
The advantage of adding query scopes / parameters within a relationship method on an Eloquent ORM model is that they are :
cacheable (see dynamic properties)
eager/lazy-loadable
has-queryable
What you need is best accomplished by a scoped query on your reviews relation.
Add this to your Review model:
use Illuminate\Database\Query\Builder;
use Illuminate\Database\Eloquent\Model;
class Review extends Model {
public function scopeLatest(Builder $query) {
// note: you can use the timestamp date for the last edited review,
// or use "id" instead. Both should work, but have different uses.
return $query->orderBy("updated_at", "desc")->first();
}
}
Then just query as such:
$photographers = Photographer::has("reviews");
foreach ($photographers as $photographer) {
var_dump($photographer->reviews()->latest());
}
Is there any way to make two domain classes' values unique.
Example:
Class A { String username }
Class B { int roll_no }
I want the combination of username and roll_no to be unique in the database.
I am using MongoDB in the backend.
Thanks in advance.
When creating objects in my domain class, id is automatically created - and in my sql database, it is created a column called id as well.
I want that column to be named, for example, "book_id" in class book and "movie_id" in class movie. My question is, how can i change the name?
You can explicitly declare the name of the identifier column using mapping like this:
class Book {
..
static mapping = {
id column:'book_id'
}
}