MongoDB find subdocument - mongodb

Question

I am starting a collection for aggregated results.
So I am following MO 'Pre aggegrated reports'
I am inserting docs with this schema:
{
"_id" : "20160526/78220/59",
"metadata" : {
"date" : "2016-05-26",
"offer" : "78220",
"adv" : NumberLong(59),
"update" : ISODate("2016-05-26T10:49:25.597Z")
},
"daily" : NumberLong(6),
"hourly" : {
"12" : NumberLong(6)
},
"publisher" : {
"43" : {
"daily" : NumberLong(3),
"hourly" : {
"12" : NumberLong(3)
}
},
"738" : {
"daily" : NumberLong(3),
"hourly" : {
"12" : NumberLong(3)
}
}
}
The idea is to have aggregated info from every hour from every publisher. _id is date/offer/code, and every publisher can give some offers.
But now I need to get, for example, a sum of the daily or hourly data for all publisher's offers.
My main question is how can I access a report on specific publisher, for example, 738, or 43?
If I query:
db.getCollection('daily_aggregate').find({'publisher.738':{$exists:true}})
I get all documents that has publisher 738, but I get other publishers data too. I want to retrieve data just from 738.
I am trying different approaches here, but probably I have to include pub_id inside the publisher schema in some way.
Any clue?
Thanks in advance.

Answer 1

Probably, what I need to query is just this:
db.getCollection('daily_aggregate').find({'publisher.738':{$exists: true}}, {_id: 0, 'publisher' : 1})
It gives me:
1
{
"publisher" : {
"738" : {
"daily" : NumberLong(4),
"hourly" : {
"18" : NumberLong(4)
}
}
}
}
2
{
"publisher" : {
"738" : {
"daily" : NumberLong(6),
"hourly" : {
"18" : NumberLong(6)
}
}
}
}
3
{
"publisher" : {
"43" : {
"daily" : NumberLong(9),
"hourly" : {
"12" : NumberLong(3),
"19" : NumberLong(6)
}
},
"738" : {
"daily" : NumberLong(3),
"hourly" : {
"12" : NumberLong(3)
}
}
}
}
4
{
"publisher" : {
"43" : {
"daily" : NumberLong(1),
"hourly" : {
"12" : NumberLong(1)
}
},
"738" : {
"daily" : NumberLong(2),
"hourly" : {
"12" : NumberLong(2)
}
}
}
}
But I am wondering if this is the best scenario.