I want to change a date format in SAS to another date informat using the query builder.
I thought it should be as simple as:
INPUT(t1.In_date, MMDDYY10.)
But this returns the following error:
ERROR: INPUT function requires a character argument.
So I played about with it & tried a few things for example:
INPUT("t1.In_date", MMDDYY10.)
This doesn't create an error message but only produces blanks.
I've googled the error message but I can't see a way to solve this problem using the query builder.
The informat of t1.In_date is DATETIME18.
If anyone has any suggestion I would be grateful.
You've got a few problems here.
First, informat is the wrong terminology. Your date variables are dates (numbers) with formats; so, you want to change their format. informat is converting a text string to a number; format is changing how a number (or text string) is displayed.
Second, you have a datetime. Datetimes are stored as the number of seconds from 1/1/1960, while Dates are the number of days. That means that they will be not compatible format-wise. You have to use datepart to convert a datetime to a date (basically, this means dividing by 86400).
So, what you want to do:
put(datepart(t1.in_date),mmddyy10.)
Related
I am trying to change the date format for one of my field to dd/MM/yyyy but every time I used the below expression I get dd/MM/yyyy as the value in the cell instead of changing the format.
The data source that I am using is Teradata.
Expression used: =Format(FormatDateTime(Fields!DATE.Value, DateFormat.ShortDate),"dd/MM/yyyy")
Can some one help me with where am I going wrong.
Any help would be appreciated.
The FormatDateTime function returns a string instead of a date. When the FORMAT function tries to format it, it doesn't find a date field so it returns the characters in the format.
If your field is a date, you should be able to format the field without conversion:
=Format(Fields!DATE.Value,"dd/MM/yyyy")
If it does need to be converted first, try using the CDATE function:
=Format(CDATE(Fields!DATE.Value),"dd/MM/yyyy")
I've looked everywhere and can't find this answer. It's a pretty simple query, but I can't for the life of me figure out how to change the date.
I have a date coming in as a string, but it's not being picked up. The date is being brought in as 20170601 but I need it to be in a date format to be picked up in Tableau. I'm using Standard SQL and have tried to PARSE_DATE("%x", date) as parsed, cast(date as date), etc. and I keep getting Error: Failed to parse input string "20170918" or some variation of that error.
#standardSQL
SELECT
visitorid,
parse_DATE("%x", date) AS parse
FROM google.com:analytics-bigquery.LondonCycleHelmet.ga_sessions_20130910
The table is within `
Please advise!!
You could try doing a regex replacement to build the date string which you require:
SELECT
REGEXP_REPLACE('20170601', r"^([0-9]{4})([0-9]{2})([0-9]{2})", "\\1/\\2/\\3")
This would output 2017/06/01, which perhaps is the format you require. Actually, I don't know what format Tableau is expecting, but YYYYMMDD is usually the correct order for a date, because it will sort correctly as text. You may use any replacement you want, using the above query as an example.
I am trying to see if a variable falls into a boundary of dates.
I hate a DATE1 already in MMDDYY10.
I use the following code
DATA GIANT;
SET GIANT;
UPPER_BOUND= intnx('week', DATE1, 2);
run;
it gives me back something in Num 8.
I want to restore it to MMDDYY10. so that I can compare it to my other dates.
Two Questions:
How can I convert a NUMERIC of length 8 into a date?
Why does intnx ... designed to work with dates return a numeric and not something in the same format?
I tried to convert it like this:
DATA GIANT;
SET GIANT;
UP_DATE=INPUT(PUT(UPPER_BOUND, 8.), MMDDYY10.);
FORMAT UP_DOS MMDDYY10.;
run;
but now it all comes up as null.
SAS Dates are always numeric (# of days since 1/1/1960). Date formats are simply a way of making that numeric readable. INTNX returns a numeric because that's all a date is; it's up to you to apply a date format to the new variable.
In your case it's very simple. You almost got it right in your attempt, but you don't need the input/put business.
data giant;
set giant;
upper_bound=intnx('week',Date1,2);
format upper_bound MMDDYY10.;
run;
INPUT converts human readable text into a value (usually a number). PUT converts a value into human readable text. PUT(INPUT(...)) is commonly used to convert a formatted value into a different kind of formatted value (for example, to convert the string "1/1/1960" to "01JAN1960"); INPUT(PUT(...)) is not very commonly used unless you are parsing the string that PUT created (such as, to read just a particular date element or something like that). Both change the type (from numeric to character in PUT or other way in INPUT) in most cases and certainly change the actual stored value.
Applying a format to a numeric column leaves the column as a numeric (which is usually good) but tells SAS how to display that numeric so you can understand it (also usually good). So underneath the value is 19857 but what is displayed is 05/14/2014.
I have imported some data into SAS from some Excel spreadsheets sent to me. When I view the output from the imported table, the date appears as "01APR2014" and maintains chronological order. When I view the column properties the type is "Date" and the length is 8. Both the format and informat are DATE9.
I need to be able to convert this date to week-year and month-year, but no matter what I try I always get Jan, 1960.
Using proc sql, I used the below to get the week-year,
"(put(datepart(a.fnlz_date),weeku3.))|| "-" ||(put(datepart(a.fnlz_date),year.)) as FNLZD_WK_YR,"
but all I got was "W00-1960". I've used the formula above successfully many times before with SAS datetime values.
For month-yr, using proc sql, I tried
"datepart(a.fnlz_date) as DT_FNLZD format=monyy.,"
but the only value returned is "JAN60".
I also tried using SUBSTR, but got an error saying it requires a character argument, so SAS must see it as a number at least.
My question; does anyone know a way to get the week-yr and/or month-yr from this format? If so, how? I'm not opposed to using a data step, but I haven't been able to get that to work either.
Thanks in advance for any help or insight provided.
datepart converts datetimes to dates. Not helpful here.
If you're just displaying this, then you have a few options, particularly for month. You can just change the format of the variable (This changes what's displayed, but not the underlying value; consider this a value label).
When you use this like this (again, it looks like you got most of the way there):
proc sql;
select datevar format=monyy5. from table;
quit;
Just don't include that datepart function call as that's not appropriate unless you have a datetime. (Date=# of days since 1/1/1960, Datetime = # of seconds since 1/1/1960:00:00:00).
That will display it with MONYY5. format, which would be MAY10 for May, 2010. You have some other format options, see the documentation on formats by category for more details.
I can't think of a Week format that matches what you want (there are week formats, like WEEKW., as you clearly found, but I don't know that they do exactly what you want. So, if you want to build one yourself, you can either build a custom picture format, or you can make a string.
Building a custom picture format isn't too hard; see the documentation on Picture formats or google SAS Date Picture Format.
proc format;
picture weekyear (default=8)
low-high = 'W%0U-%Y' (datatype=date) ;
quit;
Now you can use that as a normal format.
To get at the week/etc. to build values, you can also use functions week(), month(), etc., if that's easier.
Since the data was already in a date format, I only needed to drop the DATEPART function that only works with datetime values. So, for month-yr,
"a.fnlz_date as fnlz_mnth format=monyy.,"
gives me the results I'm looking for.
Cheers!
I've found several questions regarding SAS dates in this forum, but i haven't been able to find the answer to this one. I think it is rather simple, but i can't get it right.
I have a data set with a date (DD-MM-YYYY) which for some reason has a Character format. I would like it to be translated into a date format (YYYY-MM-DD). I can get it to 'look' right by by separating and concatenating the parts, but, then i can't get the format right.
Use the input() function with an appropriate informat:
datevariable=input(textvariable,ddmmyy10.);