I have been trying to overload a static method for a public class in Swift 2.
How is that possible? This is similar to what I want to achieve:
static func test(message: String) -> Void)?) { ### }
static func test(message: String, number: Int) -> Void)?) { ### }
It's unclear what you're trying to do exactly, but there are two extra closing parenthesis. It looks like maybe you're trying to take a closure argument?
If the intent is to take a String argument in the first method (and a String & Int in the second) and return Void, then your syntax should look like this:
static func test(message: String) { /* implementation */ }
static func test(message: String, number: Int) { /* implementation */ }
However, if the intent is to take an optional closure which takes a String and returns nothing, then the syntax looks like this:
static func test(closure: ((String) -> Void)?) {
// implementation
}
And then if the closure also takes an Int:
static func test(closure: ((String, Int) -> Void)?) {
// implementation
}
Related
Here a function b calls a and passes a completion block:
func a(completion: (_ succeeded: Bool)) {
completion(true)
}
func b() {
a() { succeeded in
...
}
}
Can I use a protocol function definition to define the block?
Something like this (which does not work):
protocol P {
func c(succeeded: Bool)
}
func a(completion: P) {
completion.c(succeeded: true)
}
func b() {
a() { c(succeeded) in
...
}
}
Note: I am not looking for the protocol/delegate concept.
The issue with using a protocol here is that functions cannot conform to a protocol, only classes, enums and structs can conform to a protocol. So you either need one of these types or an instance of one of these types, but then the instance seems superfluous. If you really want to do it the protocol way here is an example with static conformance on an enum:
import UIKit
protocol Callable {
static func call(someString: String, someInt: Int)
}
enum MyCallable: Callable {
static func call(someString: String, someInt: Int) {
print(someString, someInt)
}
}
func someFunction<T: Callable>(callable: T.Type) {
callable.call(someString: "a",someInt: 1)
}
someFunction(callable: MyCallable.self)
You can use a labeled tuple to give yourself argument labels if that is what you are after. Here is a playground example:
import UIKit
typealias MyArguements = (someInt: Int, someString: String)
func someFunction( completion: #escaping (MyArguements) -> Void) {
completion((someInt: 1, someString: "a"))
}
someFunction { tuple in
let (someInt, someString) = tuple
print(someInt, someString)
}
Example:
struct Wrapper<T> {
var key: Int = 0
var listeners: [Int: (T) -> Void] = Dictionary()
mutating func add(_ handler:#escaping (T) -> Void) {
self.key += 1
self.listeners[self.key] = handler
}
func get(key: Int) -> (T) -> Void {
return self.listeners[key]!
}
}
Test protocol:
protocol CommonProtocol {
}
Class that create Wrapper of test class
class C {
var wrapper: Wrapper = Wrapper<CommonProtocol>()
func add<T: CommonProtocol>(_ handler: #escaping (T) -> Void) {
self.wrapper.add(handler) //Cannot convert value of type '(T) -> Void' to expected argument type '(CommonProtocol) -> Void'
}
}
Image with error
I get error:
Cannot convert value of type '(T) -> Void' to expected argument type '(CommonProtocol) -> Void'
Question:
Why (T) -> Void can't be casted to (CommonProtocol) -> Void ? The T
is explicitly declared as <T: CommonProtocol>
This is my first question, if you have some suggestions please don't hesitate to contact me
You don't need to make func add generic.
When you specify in func add<T: CommonProtocol>... you explicitly telling the compiler that your function accepts all Types that inherit CommonProtocol but your Wrapper specifies that accepts CommonProtocol not inherited types.
Solution
Either type-erase class C:
Class C<T: CommonProtocol> {
var wrapper: Wrapper<T>
....
}
or if type T doesn't actually matter to you then:
func add(_ handler: #escaping (CommonProtocol) -> Void)
but second one doesn't make sense at all. You have to downcast it every-time you'll use this method (and downcasts are very bad :D)
Note: It's actually not related to this question, but one of your options is to type-erase the CommonProtocol too.
I have this closure as variable:
public var cellClicked: (name: String, number: Int)?
How can I make it a trailing closure, so I can do something like:
cell.cellClicked!{
(str: String, n: Int) in
}
What you have declared is tuple not the closure, If you want to make closure declared it like this.
public var cellClicked: ((String,Int) -> ())?
And make call like this
cell.cellClicked = { (name, value) in
}
SWIFT 3.0
Try this.
public var cellClicked = (String, Int) -> Void
cell.cellClicked = {(str,n) in
}
You can use as below :
func myMethod(completionHandler: #escaping (_ param : type, _ param2 : type) -> Void)
Description of #escaping -> https://cocoacasts.com/what-do-escaping-and-noescaping-mean-in-swift-3/
I have these two swift classes:
class A {
static func list(completion: (_ result:[A]?) -> Void) {
completion (nil)
}
static func get(completion: (_ result:A?) -> Void) {
completion (nil)
}
}
class B: A {
static func list(completion: (_ result:[B]?) -> Void) {
completion (nil)
}
static func get(completion: (_ result:B?) -> Void) {
completion (nil)
}
}
Trying to compile this raise the error "overriding declaration requires an 'override' keyword" but just for the 'get' method of class B. 'list' method compiles fine. What is the difference between [B]? and B? for the compiler in this case?
Edit: Also notice that adding 'override' is not possible. I get the error 'Cannot override static method'.
In class B, the method list is a separate method from list in class A. They just share the same name, that's all.
The parameters of the two list methods are actually different:
// A.list
static func list(completion: (_ result:[A]?) -> Void) {
// B.list
static func list(completion: (_ result:[B]?) -> Void) {
A.list takes an argument of type (_ result: [A]?) -> Void while B.list takes a (_ result: [B]?) -> Void. The array type in the closure type's parameter list is different!
So you're not overridding anything, you're just overloading.
Note:
static methods can never be overridden! If you want to override a method, use class instead of static.
class A {
class func get(completion: (_ result:A?) -> Void) {
completion (nil)
}
}
class B: A {
override class func get(completion: (_ result:B?) -> Void) {
completion (nil)
}
}
In short, as per rule, static methods can't be overridden.
Initializer of class A takes an optional closure as argument:
class A {
var closure: ()?
init(closure: closure()?) {
self.closure = closure
self.closure()
}
}
I want to pass a function with an argument as the closure:
class B {
let a = A(closure: action(1)) // This throws the error: Cannot convert value of type '()' to expected argument type '(() -> Void)?'
func action(_ i: Int) {
//...
}
}
Class A should execute the closure action with argument i.
I am not sure about how to write this correctly, see error in code comment above. What has to be changed?
Please make your "what-you-have-now" code error free.
Assuming your class A like this:
class A {
typealias ClosureType = ()->Void
var closure: ClosureType?
init(closure: ClosureType?) {
self.closure = closure
//`closure` would be used later.
}
//To use the closure in class A
func someMethod() {
//call the closure
self.closure?()
}
}
With A given above, you need to rewrite your class B as:
class B {
private(set) var a: A!
init() {
//initialize all instance properties till here
a = A(closure: {[weak self] in self?.action(1)})
}
func action(i: Int) {
//...
}
}
The problem is that closure()? is not a type. And ()? is a type, but it is probably not the type you want.
If you want var closure to have as its value a certain kind of function, you need to use the type of that function in the declaration, e.g.
var closure: (Int) -> Void
Similarly, if you want init(closure:) to take as its parameter a certain kind of function, you need to use the type of that function in the declaration, e.g.
init(closure: (Int) -> Void) {
Types as Parameters
In Swift, every object has a type. For example, Int, String, etc. are likely all types you are extremely familiar with.
So when you declare a function, the explicit type (or sometimes protocols) of any parameters should be specified.
func swallowInt(number: Int) {}
Compound Types
Swift also has a concept of compound types. One example of this is Tuples. A Tuple is just a collection of other types.
let httpStatusCode: (Int, String) = (404, "Not Found")
A function could easily take a tuple as its argument:
func swallowStatusCode(statusCode: (Int, String)) {}
Another compound type is the function type. A function type consists of a tuple of parameters and a return type. So the swallowInt function from above would have the following function type: (Int) -> Void. Similarly, a function taking in an Int and a String and returning a Bool would have the following type: (Int, String) -> Bool.
Function Types As Parameters
So we can use these concepts to re-write function A:
class A {
var closure: (() -> Void)?
init(closure: (() -> Void)?) {
self.closure = closure
self.closure()
}
}
Passing an argument would then just be:
func foo(closure: (Int) -> Void) {
// Execute the closure
closure(1)
}
One way to do what I think you're attempting is with the following code:
class ViewController: UIViewController {
override func viewDidLoad() {
let _ = A.init(){Void in self.action(2)}
}
func action(i: Int) {
print(i)
}
}
class A: NSObject {
var closure : ()?
init(closure: (()->Void)? = nil) {
// Notice how this is executed before the closure
print("1")
// Make sure closure isn't nil
self.closure = closure?()
}
}