I used the answer on Plot vector (or arc) onto a rose plot. MATLAB to plot my rose diagram but my plot looks like this:
My code:
circ_plot(BB,'hist',[],20,true,true,'linewidth',2,'color','r')
hold on
plot([0 cos(mean)*a], [0 sin(mean)*a], 'r')
%// Plot error as many shaded triangles that compose a circular wedge
t = linspace(-Var/2+mean,Var/2+mean,100); %// increase "100" if needed
for k = 1:numel(t)-1
h = patch([0 cos(t(k))*a cos(t(k+1))*a 0], ...
[0 sin(t(k))*a sin(t(k+1))*a 0], [.5 0 0], 'edgecolor', 'none');
%// change color [.5 0 0] to something else if desired. Note also alpha
set(h,'Facealpha',.3) %// make transparent
end
%// Place rose on top by rearranging order of axis children
ch = get(gca,'children');
set(gca,'children',[ch(2:end); ch(1)]);
Any ideas how I get my error shaded area do follow the circumference of the circle rather than being a triangle?
Thanks
I don't know why, but today its works fine. I didn't change anything. Thanks for your reply and offer of help. unfortunately due to the sensitive nature of my data I am unable to post.
thanks again.
Related
A = [239920.240412166 1.31193313030682;
243577.444235102 1.38185205485119;
241899.250050298 1.51264147493485;
244659.326936560 1.50845243215867;
239862.361809342 1.50810833389632;
238395.616682194 1.37125000688350;
244558.389789124 1.27212093329482;
244290.890880318 1.35116080948488;
240303.711239396 1.36064181572699;
237464.430450140 1.48857869573721;
244415.381196104 1.51252425335623;
239855.328594799 1.29178640586301;
239304.806448742 1.31075813783171;
244827.243024016 1.32080934043223;
241465.885648910 1.53667019314427;
241139.254464482 1.40424079027764;
242300.037630214 1.27160249886092;
243330.396959248 1.61411410292679;
237530.389940994 1.21846939260826];
B = [0.6 0.18; 0.15 0.46]; % green circles
for i=1:2
plot(A(:,1),A(:,2),'r*');
hold on
plot(B(i,1),B(i,2), '-ko',...
'LineWidth',1,...
'MarkerFaceColor',[.49 1 .63],...
'MarkerSize',9);
end
When I ploted A and B, I got this:
B(1,1) = 0.6, but it appears in 0 (X-axis). Same with B(2,1) = 0.15
How to correct this?
A logarithmic scale on the xaxis will help with the view
set(gca, 'XScale', 'log')
However, it will lead to the fact, that now the values of A appear to populate one vertical line.
If you cannot live with this, you may want to try a broken x-axis. MATLAB doesn't support this with build-in functions, but there is a solution in the MATLAB file exchange
https://de.mathworks.com/matlabcentral/fileexchange/3683-breakxaxis
Btw: There is no need for the loop in your code. In fact you plot A twice on top of each other. Just
% Plot A and B without loop
plot(A(:,1), A(:,2),'r*')
hold on
plot(B(:,1), B(:,2), '-ko', 'LineWidth', 1, ...
'MarkerFaceColor', [.49 1 .63], 'MarkerSize',9)
% Set x axis to logarithmic scale
set(gca, 'XScale', 'log')
is sufficient to display your plot
Your x-axis goes from 0 to 250000. On that range, 0.6 and 0.15 are practically 0.
If you want you can use logarithmic scale in x-axis using semilogx
I want to add something to make my phase portrait more understandable. Nevertheless, I can't find anything (I found this
https://se.mathworks.com/help/matlab/ref/colorspec.html
https://se.mathworks.com/matlabcentral/fileexchange/11611-linear-2d-plot-with-rainbow-color
https://se.mathworks.com/help/symbolic/mupad_ref/linecolortype.html
) but it is not what I need.
I would really like to see the color of the line of the phase portrait changing depending of if it is at the beginning or at the end of the simulation.
I found this idea which seems great :
I don't understand at all what he has done (the code is I suppose written here:
https://blogs.mathworks.com/pick/2008/08/15/colors-for-your-multi-line-plots/ )
but It would be great if I can plot a one line function which color varies depending of the time. If moreover, like on the picture, I can have have a scale on the right: it would be awesome.
So for now, I have that :
data = readtable('test.txt');
figure('Name','Phase' , 'units','normalized','outerposition',[(8/100) (0.3- 16/100) 0.5 0.7]);
hold on
plot(data{:,2},data{:,3}, 'k.', 'LineWidth',1.5 );
plot(data{:,4},data{:,5}, 'r.', 'LineWidth',1.5 );
xL = xlim;
yL = ylim;
line([0 0], yL); %x-axis
line(xL, [0 0]); %y-axis
title(['Phase portrait'])
xlabel('f')
ylabel('f '' ')
hold off
I read the values of the function in a .txt file, and then I plot the 2nd/3rd columns and 4/5th columns. The first column is the time evoluting.
Do you have any idea :)?
Thank you!
There are several ways to go about this to be honest.
However it makes a bit easier if you let us know what your time data is.
Do you plot your time data on the x (or y) axis or is it a different additional data set. Should it be an additional data set then you can consider it like z-data, plotted on the Z-axis or/and as a color.
Below is an example of what you can do by making a 3D plot but displaying it in 2D, this allows you to add the colorbar without too many problems.
x=0:5;
y=0:5;
z=rand(1,6); %random data to simulate your time
xx=[x' x']; %this allows you to plot the data using surf in 3d
yy=[y' y']; %same as for xx
z1=zeros(size(xx)); % we don't need z-data so we're making it a matrix of zeros
zc=[z' z']; %input here your time data values, if x/y then you can just use those instead of z
hs=surf(xx,yy,z1,zc,'EdgeColor','interp') %// color binded to "z" values, choose interp for interpolated/gradual color changes, flat makes it sudden
colormap('hsv') %choose your colormap or make it yourself
view(2) %// view(0,90)
hcb=colorbar; %add a colorbar
I found this, thanks to another user on stackoverflaw.
data = readtable('4ressorspendule.txt');
n = numel(data.Var1);
c = size(data,2);
figure('Name','Phase' , 'units','normalized','outerposition',[(8/100) (0.3 - 16/100) 0.5 0.7]);
for i=1:n
hold on
plot(data{i,2},data{i,3},'.','Color',[1 (1-i/n) 0] ,'MarkerSize',4);
plot(data{i,4},data{i,5},'.','Color',[0 (i/n) (1-i/n)],'MarkerSize',4);
end
xL = xlim;
yL = ylim;
line([0 0], yL); %x-axis
line(xL, [0 0]); %y-axis
title(['Phase portrait'])
xlabel('f')
ylabel('f '' ')
hold off
I have two datasets. One detailing a list of angles (which I am plotting onto a rose plot):
angles
-0.8481065519
0.0367932161
2.6273740453
...
n
The other, detailing directional statistics from this group of angles:
angle,error
-0.848106563,0.8452778824
Where angle essentially defines the directional mean, and error the circular variance, essentially an error bar either side of the angle
I have thus far plotted a rose histogram using the set of angles, as such:
h = rose(angles,36)
I would like to create a plot of the directional statistic angle (it does not need a length/magnitude - just to the edge of the circle plot) with the error around it.
As an example:
I added the lines by hand in Matlab. If possible it would be good to perhaps have shading within the arc too. Alternatively, (and possibly preferred) would be to have just a sliver above the rose plot bins (so it doesn't cover the data) with a centre line (showing the angle and shading surrounding for the error.
Thanks in advance.
How about this?
%// Data
angles = 2*pi*.8*randn(1,1e4);
angle = -0.848106563;
error = 0.8452778824;
%// Plot rose
rose(angles, 36);
axis image %// make axis square
hold on
%// Plot mean
a = axis;
a = a(2); %// size of axis
plot([0 cos(angle)*a], [0 sin(angle)*a], 'r')
%// Plot error as many shaded triangles that compose a circular wedge
t = linspace(-error/2+angle,error/2+angle,100); %// increase "100" if needed
for k = 1:numel(t)-1
h = patch([0 cos(t(k))*a cos(t(k+1))*a 0], ...
[0 sin(t(k))*a sin(t(k+1))*a 0], [.5 0 0], 'edgecolor', 'none');
%// change color [.5 0 0] to something else if desired. Note also alpha
set(h,'Facealpha',.3) %// make transparent
end
%// Place rose on top by rearranging order of axis children
ch = get(gca,'children');
set(gca,'children',[ch(2:end); ch(1)]);
For this to work, you need to use a figure renderer capable of transparency. So you may need to adjust the figure's renderer property.
I want to plot the overlapping area of 2 rectangles in a color. I know I can plot the rectangles by using the rectangle command. With rectint I can find out whether they overlap or not.
Is there a specific command for this or does anyone know how I can do this? As you have noticed, I do not have much experience with Matlab.
Code:
A = [0 0 3 3];
B = [2 2 2 2];
hold on;
rectangle('Position',A) %plot rectangle A
rectangle('Position',B) %plot rectangle B
if (rectint(A,B) > 0)
%plot overlapping
end
hold off;
Image:
Assuming the rectangles overlap, the part for the plotting could be done like this:
if (A(1)<=B(1))
intersection(1)=B(1);
intersection(3)=A(1)+A(3)-B(1);
else
intersection(1)=A(1);
intersection(3)=B(1)+B(3)-A(1);
end
if (A(2)<=B(2))
intersection(2)=B(2);
intersection(4)=A(2)+A(4)-B(2);
else
intersection(2)=A(2);
intersection(4)=B(2)+B(4)-A(2);
end
intersectionPlot=rectangle('Position', intersection);
set(intersectionPlot, 'FaceColor', 'r'); % r stands for red, you can choose any other color
So you only want to plot the little rectangle in the middle?
I don't think that there is a builtin function for that, and this is probably the way to go:
Determine the coordinates of the intersection (as long as it are just rectangles this should not be too hard)
Plot the result
I was trying use the code shown below to plot in such a way that each iso-surface will be different in color and there will be a color bar at the right. I made a ss(k) color matrix for different colors. Number of iso-surfaces is 10 but I have only 8 colors. That's why I wrote ss(9)='r' and ss(10)='r'.
I need a solution to plot the iso-surface with different color and bar at the right side.
ss=['y','m','c','r','g','b','w','k','r','r']
k=1;
for i=.1:.1:1
p=patch(isosurface(x,y,z,v,i));
isonormals(x,y,z,v,p)
hold on;
set(p,'FaceColor',ss(k),'EdgeColor','none');
daspect([1,1,1])
view(3); axis tight
camlight
lighting gouraud
k=k+1;
end
Another possibility is to draw the patches with direct color-mapping (by setting the property 'CDataMapping'='direct'), while assigning the 'CData' of each patch to an index in the colormap of your choice. This is in fact recommended for maximum graphics performance.
Consider the following example:
%# volumetric data, and iso-levels we want to visualize
[x,y,z,v] = flow(25);
isovalues = linspace(-2.5,1.5,6);
num = numel(isovalues);
%# plot isosurfaces at each level, using direct color mapping
figure('Renderer','opengl')
p = zeros(num,1);
for i=1:num
p(i) = patch( isosurface(x,y,z,v,isovalues(i)) );
isonormals(x,y,z,v,p(i))
set(p(i), 'CData',i);
end
set(p, 'CDataMapping','direct', 'FaceColor','flat', 'EdgeColor','none')
%# define the colormap
clr = hsv(num);
colormap(clr)
%# legend of the isolevels
%#legend(p, num2str(isovalues(:)), ...
%# 'Location','North', 'Orientation','horizontal')
%# fix the colorbar to show iso-levels and their corresponding color
caxis([0 num])
colorbar('YTick',(1:num)-0.5, 'YTickLabel',num2str(isovalues(:)))
%# tweak the plot and view
box on; grid on; axis tight; daspect([1 1 1])
view(3); camproj perspective
camlight; lighting gouraud; alpha(0.75);
rotate3d on
I also included (commented) code to display the legend, but I found it to be redundant, and a colorbar looks nicer.
Matlab usually plots different iso-surfaces in different colors automatically, so you don't need to care about that. What kind of bar do you need? A colorbar or a legend? Either way, it is just to use the colorbar or legend function..
%Create some nice data
[x y z] = meshgrid(1:5,1:5,1:5);
v = ones(5,5,5);
for i=1:5
v(:,:,i)=i;
end
v(1:5,3:5,2)=1
v(1:5,4:5,3)=2
%Plot data
for i=1:5
isosurface(x,y,z,v,i)
end
%Add legend and/or colorbar
legend('one','Two','Three','Four')
colorbar
Since the color bar encodes value->color, it is impossible to do what you ask for, unless there is no intersection in z-values between all pairs of surfaces. So the solution below assumes this is the case. If this is not the case, you can still achieve it by adding a constant value to each surface, so to separate the surfaces along the z axis, and eliminate any intersection.
The solution is based on constructing a colormap matrix of piecewise constant values, distributed similarly to the z values of your surfaces. So for example, if you have 3 surfaces, the first has z values between 1 and 10, the 2nd between 11 and 30, and the 3rd between 31 and 60, you should do something like this (I plot in 2D for simplicity)
r = [1 0 0];
g = [0 1 0];
b = [0 0 1];
cmap = [r(ones(10,1),:); g(ones(20,1),:); b(ones(30,1),:)];
z1 = 1:10;
z2 = 11:30;
z3 = 31:60;
figure; hold on
plot(z1,'color',r)
plot(z2,'color',g)
plot(z3,'color',b)
colorbar
colormap(cmap)
More complex colormaps (i.e, more colors) can be constructed with different mixtures of red, green, and blue (http://www.mathworks.com/help/techdoc/ref/colorspec.html)