I am trying to swap two words in a string. I currently have a txt file with a column of users formatted last.first. How can I swap that to first.last?
-split the string and concatenate:
$Last,$First = "Lastname.Firstname" -split '\.'
$newString = "$First.$Last"
or use -replace to reorder the two:
"Lastname.Firstname" -replace '(\w+)\.(\w+)','$2.$1'
gc .\names.txt |% { "{1}.{0}" -f $_.split('.') }
Get the lines out of the file with gc which is an alias for Get-Content
Loop over them with % which is an alias for ForEach-Object
Split() each line around the full stop, into an array of two items
Use the "" -f string formatting operator to build a string taking array items in the order 1, 0 which swaps the order of the parts.
Quick and dirty - minimal error checking...
Get-Content .\test.txt |
ForEach-Object {
if ( $_.Contains('.') ) {
$_.Split('.')[1] + '.' + $_.Split('.')[0] }
else { $_ }
}
Related
I want to be able to split some text out of a txtfile:
For example:
Brackets#Release 1.11.6#Path-to-Brackets
Atom#v1.4#Path-to-Atom
I just want to have the "Release 1.11.6" part. I am doing a where-object starts with Brackets but I don't know the full syntax. Here is my code:
"Get-Content -Path thisfile.txt | Where-Object{$_ < IM STUCK HERE > !
You could do this:
((Get-Content thisfile.txt | Where-Object { $_ -match '^Brackets' }) -Split '#')[1]
This uses the -match operator to filter out any lines that don't start with Brackets (the ^ special regex character indicates that what follows must be at the beginning of the line). Then it uses the -Split operator to split those lines on # and then it uses the array index [1] to get the second element of the split (arrays start at 0).
Note that this will throw an error if the split on # doesn't return at least two elements and it assumes that the text you want is always the second of those elements.
$bracketsRelease = Get-Content -path thisfile.txt | foreach-object {
if ( $_ -match 'Brackets#(Release [^#]+)#' )
{
$Matches[1]
}
}
or
(select-string -Path file.txt -Pattern 'Brackets#(Release [^#]+)#').Matches[0].Groups[1].value
I used the below steps to retrieve a string from file
$variable = 'abc#yahoo.com'
$test = $variable.split('#')[0];
$file = Get-Content C:\Temp\file1.txt | Where-Object { $_.Contains($test) }
$postPipePortion = $file | Foreach-Object {$_.Substring($_.IndexOf("|") + 1)}
This results in all lines that contain $test as a substring. I just want the result to contain only the lines that exactly matches $test.
For example, If a file contains
abc_def|hf#23$
abc|ohgvtre
I just want the text ohgvtre
If I understand the question correctly you probably want to use Import-Csv instead of Get-Content:
Import-Csv 'C:\Temp\file1.txt' -Delimiter '|' -Header 'foo', 'bar' |
Where-Object { $_.foo -eq $test } |
Select-Object -Expand bar
To address the exact matching, you should be testing for equality (-eq) rather than substring (.Contains()). Also, there is no need to parse the data multiple times. Here is your code, rewritten to to operate in one pass over the data using the -split operator.
$variable = 'abc#yahoo.com'
$test = $variable.split('#')[0];
$postPipePortion = (
# Iterate once over the lines in file1.txt
Get-Content C:\Temp\file1.txt | foreach {
# Split the string, keeping both parts in separate variables.
# Note the backslash - the argument to the -split operator is a regex
$first, $second = ($_ -split '\|')
# When the first half matches, output the second half.
if ($first -eq $test) {
$second
}
}
)
I have following Input lines in my notepad file.
example 1 :
//UNION TEXT=firststring,FRIEND='ABC,Secondstring,ABAER'
example 2 :
//UNION TEXT=firststring,
// FRIEND='ABC,SecondString,ABAER'
Basically, one line can span over two or three lines. If last character is , then it is treated as continuation character.
In example 1 - Text is in one line.
In example 2 - same Text is in two lines.
In example 1, I can probably write below code. However, I do not know how to do this if 'Input text' spans over two or three lines based on continuation character ,
$result = Get-Content $file.fullName | ? { ($_ -match firststring) -and ($_ -match 'secondstring')}
I think I need a way so that I can search text in multipl lines with '-and' condition. something like that...
Thanks!
You could read the entire content of the file, join the continued lines, and then split the text line-wise:
$text = [System.IO.File]::ReadAllText("C:\path\to\your.txt")
$text -replace ",`r`n", "," -split "`r`n" | ...
# get the full content as one String
$content = Get-Content -Path $file.fullName -Raw
# join continued lines, split content and filter
$content -replace '(?<=,)\s*' -split '\r\n' -match 'firststring.+secondstring'
If file is large and you want to avoid loading entire file into memory you might want to use good old .NET ReadLine:
$reader = [System.IO.File]::OpenText("test.txt")
try {
$sb = New-Object -TypeName "System.Text.StringBuilder";
for(;;) {
$line = $reader.ReadLine()
if ($line -eq $null) { break }
if ($line.EndsWith(','))
{
[void]$sb.Append($line)
}
else
{
[void]$sb.Append($line)
# You have full line at this point.
# Call string match or whatever you find appropriate.
$fullLine = $sb.ToString()
Write-Host $fullLine
[void]$sb.Clear()
}
}
}
finally {
$reader.Close()
}
If file is not large (let's say < 1G) Ansgar Wiechers answer should do the trick.
So I have a text file that looks something like this:
Members : {USER\member1, USER\member2, US
ER\member3, USER\member4, USER
\member5, USER\member6}
and I would like to remove USER\. The following code removes it but not when it's split by a newline, for example when US on one line and ER\ on another line.
Foreach-Object { %{$_.Replace('USER\', '') }
Putting `n or `r in there doesn't work. Any help is appreciated.
Try this:
PS > ((Get-Content .\t.txt) | % { $_.Trim() }) -join "" -replace "USER\\"
Members : {member1, member2, member3, member4, member5, member6}
If the text is in a string-array, switch out (Get-Content .\t.txt) with your variable. If you have the text in a string(not array) variable, use:
($MYSTRINGVAR.Split("`r`n") | % { $_.Trim() }) -join "" -replace "USER\\"
EDIT Just modify the "Members" part:
$text = (Get-Content .\input.txt) -join "`r`n"
($text | Select-String '(?s)(?<=Members : \{)(.+?)(?=\})' -AllMatches).Matches | % {
$text = $text.Replace($_.Value, ($_.Value -split "`r`n" | % { $_.Trim() }) -join "" -replace "USER\\")
}
$text | Set-Content output.txt
There are probably easier ways to get there, but you can give this one a try:
$Text = #'
Members : {USER\member1, USER\member2, US
ER\member3, USER\member4, USER
\member5, USER\member6}
'#
# First - USER\ with newline inside..
foreach ($index in 1..4) {
$Text = $Text -replace ('USER\\'.Insert($index,'(\r\n\s+)')), '$1'
}
# Than - pure USER\
$Text = $Text -replace 'USER\\'
$Text
As you can see I create few patterns that contain and keep that element in results (, '$1'). For simple ones - I just remove USER\
I've used herestring to create text to work with, it's possible that \r may not be needed for actual file.
This is actually just a comment to Graimer's solution, but it would've been too long and also not readable enough as a comment, so I'm making it a (supplementary) answer instead.
To re-wrap the string after removing USER\ you could do something like this:
$s = "Members : {member1, member2, member3, member4, member5, member6}"
$s -match '^(.*?{)(.*)(})$'
$pad = " " * $matches[1].Length
$matches[1] + ($matches[2] -replace '(.{1,20},) ', "`$1`r`n$pad") + $matches[3]
The first regular expression splits the string into 3 parts that can be accessed via the $matches collection:
Name Value
---- -----
3 }
2 member1, member2, member3, member4, member5, member6
1 Members : {
0 Members : {member1, member2, member3, member4, member5, member6}
$matches[1] is the prologue including the opening curly bracket, $matches[2] is the member list, and $matches[3] is the closing curly bracket. Now you only need to wrap $matches[2] at whatever length you want:
'(.*{1,20},) '
The above means "longest match of at most 20 characters followed by a comma and a space". Replace that with the 1st group ($1) followed by a line-break (```rn``) and a number of spaces that matches the length of the prologue ($pad`) and glue it back together with prologue and trailing curly bracket.
Iam trying to replace following string with PowerShell:
...
("
Intel(R) Network Connections 14.2.100.0
","
14.2.100.0
")
...
The code that I use is:
Get-Content $logfilepath |
Foreach-Object { $_ -replace '`r`n`r`n', 'xx'} |
Set-Content $logfilepath_new
But I have no success, can someone say me, where the error is?
First, you are using single quotes in the replace string -
'`r`n`r`n'
that means they are treated verbatim and not as newline characters, so you have to use -
"`r`n`r`n"
To replace, read the file as string and use the Replace() method
$content=[string] $template= [System.IO.File]::ReadAllText("test.txt")
$content.Replace("`r`n`r`n","xx")
Get-content returns an array of lines, so CRLF is essentially your delimiter. Two CRLF sequences back to back would be interpreted as the end of the currrent line, followed by a null line, so no line (object) should contain '`r`n`r`n'. A multi-line regex replace would probably be a better choice.
as alternate method using PS cmdlets:
Get-Content $logfilepath |
Foreach-Object -Begin { $content="" } -Process { $content += $_ ; $content += "xx" } -End { $content } |
Set-Content $logfilepath_new
I used the following code to replace somestring with newline:
$nl = [System.Environment]::NewLine
$content = $content.Replace( somestring, $nl )