Scala - Automatic Iterator inside pattern match - scala

Question

I have Array Data like this : [("Bob",5),("Andy",10),("Jim",7),...(x,y)].
How to do pattern matching in Scala? so they will match automatically based on Array Data that i have provided (instead of define "Case" one by one)
i mean dont like this, pseudocode :
val x = y.match {
case "Bob" => get and print Bob's Score
case "Andy" => get and print Andy's Score
..
}
but
val x = y.match {
case automatically defined by given Array => print each'score
}
Any Idea ? thanks in advance

Answer 1

If printing and storing results in an array is your main concern than the following will work well:
val ls = Array(("Bob",5),("Andy",10),("Jim",7))
ls.map({case (x,y) => println(y); y}) // print and store the score in an array

Answer 2

A bit confused about the question however if you just wish to print all the data in the array i would go about it doing this:
val list = Array(("Foo",3),("Tom",3))
list.foreach{
case (name,score) =>
println(s"$name scored $score")
}
//output:
//Foo scored 3
//Tom scored 3

Answer 3

Consider
val xs = Array( ("Bob",5),("Andy",10),("Jim",7) )
for ( (name,n) <- xs ) println(s"$name scores $n")
and also
xs.foreach { t => println(s"{t._1} scores ${t._2}") }
xs.foreach { t => println(t._1 + " scores " + t._2) }
xs.foreach(println)
A simple way to print the contents of xs,
println( xs.mkString(",") )
where mkString creates a string out of xs and separates each item by a comma.
Miscellany notes
To illustrate pattern matching on Scala Array, consider
val x = xs match {
case Array( t # ("Bob", _), _*) => println("xs starts with " + t._1)
case Array() => println("xs is empty")
case _ => println("xs does not start with Bob")
}
In the first case we extract the first tuple, and neglect the rest. In the first tuple we match against string "Bob" and neglect the second item. Moreover, we bind the first tuple to tag t, which is used in the printing where we refer to its first item.
The second case means every other case not covered.