The origional problem I am attempting to solve is that I need to show all rows from a specific "joined" table. However these are sometimes blank with no totals and normally would not show (think categories and counts for each).
So what I am attempting to do is union to a "0 value" data set to show all categories. However when I do the union it shows a 0 value row, as well as the normal data. Here is an example..
SELECT category_name, COUNT(files_number)
FROM files
LEFT JOIN categories ON categories.category_id = files.category_id
UNION
SELECT category_name, 0
FROM categories
This will give me a result set that looks similar to this:
category_name | value
----------------------
open file | 0
open file | 23
closed file | 0
Is there any way to remove duplicate zero value entries? Please not there is also a complex WHERE clause in the actual query, so avoiding duplication on it is preferred.
I don't get why you are doing left join and union..
You can do below to remove duplicates,wrap your query and do group by
;with cte
as
(
SELECT category_name, COUNT(files_number)
FROM files
LEFT JOIN categories ON categories.category_id = files.category_id
UNION
SELECT category_name, 0
FROM categories
)
select categoryname,sum(aggcol)
from cte
group by
category
One way is to select all categories from the categories table, and LEFT JOIN onto the file counts (grouped by category_id).
SELECT c.category_name, ISNULL(fc.FileCount, 0) AS FileCount
FROM categories c
LEFT JOIN (
SELECT category_id, COUNT(files_number) AS FileCount
FROM files
GROUP BY category_id
) fc ON c.category_id = fc.category_id
Edit
If you want to reverse the query, you could do it something like this, using a RIGHT OUTER JOIN - so every category from categories table is returned, regardless of if there are any files for it:
SELECT c.category_name, COUNT(f.category_id) AS FileCount
FROM files f
RIGHT JOIN categories c ON c.category_id = f.category_id
GROUP BY c.name
Related
Input data
I have the following association table:
AssociationTable
- Item ID: Integer
- Tag ID: Integer
Referring to the following example data
Item Tag
1 1
1 2
1 3
2 1
and some input list of tags T (e.g. [1, 2])
What I want
For each item, I would like to know which tags were not provided in the input list T.
With our sample data, we'd get:
Item Num missing
1 1
2 0
My thoughts
The best I've done so far is: select "ItemId", count("TagId") as "Num missing" from "AssociationTab" where "TagId" not in (1) group by "ItemId";
The problem here is that items where all tags match will not be included in the output.
You could use a calendar table with anti-join approach:
WITH cte AS (
SELECT t1.Item, t2.Tag
FROM (SELECT DISTINCT Item FROM AssociationTable) t1
CROSS JOIN (SELECT 1 AS Tag UNION ALL SELECT 2) t2
)
SELECT
t1.Item,
COUNT(*) FILTER (WHERE t2.Item IS NULL) AS num_missing
FROM cte t1
LEFT JOIN AssociationTable t2
ON t1.Item = t2.Item AND
t1.Tag = t2.Tag AND
t2.Tag IN (1, 2)
GROUP BY
t1.Item;
Demo
The strategy here is to build a calendar/reference table in the first CTE which contains all combinations of items and tags. Then, we left join this CTE to your association table, aggregate by item, and then detect how many tags are missing for each item.
Simplest solution is
SELECT
ItemId,
count(*) FILTER (WHERE TagId NOT IN (1,2))
FROM AssociationTab
GROUP BY ItemId
Alternatively, if you already have an Items table with the item list, you could do this:
SELECT
i.ItemId,
count(a.TagId)
FROM Items i
LEFT JOIN AssociationTab a ON a.ItemId = i.ItemId AND a.TagId NOT IN (1,2)
GROUP BY i.ItemId
The key is that LEFT JOIN does not remove the Items row if no tags match.
I have a temp table with multiple rows in it and each row has a column called Categories; which contains a very simple json array of ids for categories in a different table.
A few example rows of the temp table:
Id Name Categories
---------------------------------------------------------------------------------------------
'539f7e28-143e-41bb-8814-a7b93b846007' Test 1 ["category1Id", "category2Id", "category3Id"]
'f29e2ecf-6e37-4aa9-aa56-4a351d298bfc' Test 2 ["category1Id", "category2Id"]
'34e41a0a-ad92-4cd7-bf5c-8df6bfd6ed5c' Test 3 NULL
Now what I would like to do is to select all of the category ids from all of the rows in the temp table.
What I have is the following and it's not working as it's giving me the error of :
Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression.
SELECT
c.Id
,c.[Name]
,c.Color
FROM
dbo.Category as c
WHERE
c.Id in (SELECT [value] FROM OPENJSON((SELECT Categories FROM #TempTable)))
and c.IsDeleted = 0
Which I guess it makes sense that's failing on that because I'm selecting multiple rows and needing to parse each row's respective category ids json. I'm just not sure what to do/change to give me the results that I want. Thank you in advance for any help.
You'd need to use CROSS APPLY like so:
SELECT id ,
name ,
t.Value AS category_id
FROM #temp
CROSS APPLY OPENJSON(categories, '$') t;
And then, you can JOIN to your Categories table using the category_id column, something like this:
SELECT id ,
name ,
t.Value AS category_id,
c.*
FROM #temp
CROSS APPLY OPENJSON(categories, '$') t
LEFT JOIN Categories c ON c.Id = t.Value
I have two tables: contracts and contract_descriptions.
On contract_descriptions there is a column named contract_id which is equal on contracts table records.
I am trying to join the latest record on contract_descriptions:
SELECT *
FROM contracts c
LEFT JOIN contract_descriptions d ON d.contract_id = c.contract_id
AND d.date_description =
(SELECT MAX(date_description)
FROM contract_descriptions t
WHERE t.contract_id = c.contract_id)
It works, but is it the performant way to do it? Is there a way to avoid the second SELECT?
You could also alternatively use DISTINCT ON:
SELECT * FROM contracts c LEFT JOIN (
SELECT DISTINCT ON (cd.contract_id) cd.* FROM contract_descriptions cd
ORDER BY cd.contract_id, cd.date_description DESC
) d ON d.contract_id = c.contract_id
DISTINCT ON selects only one row per contract_id while the sort clause cd.date_description DESC ensures that it is always the last description.
Performance depends on many values (for example, table size). In any case, you should compare both approaches with EXPLAIN.
Your query looks okay to me. One typical way to join only n rows by some order from the other table is a lateral join:
SELECT *
FROM contracts c
CROSS JOIN LATERAL
(
SELECT *
FROM contract_descriptions cd
WHERE cd.contract_id = c.contract_id
ORDER BY cd.date_description DESC
FETCH FIRST 1 ROW ONLY
) cdlast;
I'm trying to find all IDs in TableA that are mentioned by a set of records in TableB and that set if defined in Table C. I've come so far to the point where a set of INNER JOIN provide me with the following result:
TableA.ID | TableB.Code
-----------------------
1 | A
1 | B
2 | A
3 | B
I want to select only the ID where in this case there is an entry for both A and B, but where the values A and B are based on another Query.
I figured this should be possible with a GROUP BY TableA.ID and HAVING = ALL(Subquery on table C).
But that is returning no values.
Since you did not post your original query, I will assume it is inside a CTE. Assuming this, the query you want is something along these lines:
SELECT ID
FROM cte
WHERE Code IN ('A', 'B')
GROUP BY ID
HAVING COUNT(DISTINCT Code) = 2;
It's an extremely poor question, but you you probably need to compare distinct counts against table C
SELECT a.ID
FROM TableA a
GROUP BY a.ID
HAVING COUNT(DISTINCT a.Code) = (SELECT COUNT(*) FROM TableC)
We're guessing though.
I am trying to removing duplicate values which, for some reason, was imported in a specific Table.
There is no Primary Key in this table.
There is 27797 unique records.
Select distinct txdate, plunumber from itemaudit
Give me the correct records, but only displays the txdate, plunumber of course.
If it was possible to select all the fields but only select the distinct of txdate,plunumber I could export the values, delete the duplicated ones and re-import.
Or if its possible to delete the distinct values from the entire table.
If you select the distinct of all fields the value is incorrect.
To get all information on the duplicates, you simply need to query all information for the duplicate rows using a JOIN:
SELECT b.*
FROM (SELECT COUNT(*) as cnt, txdate, plunumber
FROM itemaudit
GROUP BY txdate, plunumber
HAVING COUNT(*) > 1) a
INNER JOIN itemaudit b ON a.txdate = b.txdate AND a.plunumber = b.plunumber
DELETE FROM itemaudit t1
WHERE EXISTS (
SELECT 1 FROM itemaudit t2
WHERE t1.txdate = t2.txdate and t1.plunumber = t2.plunumber
AND t1.RDB$DB_KEY < t2.RDB$DB_KEY
);