I have a Grid in my google form, where I want to add a script or an add-on that prevents both rows from having a same answer
In the above box Restless cannot be MOST and Least both
I want to disable option for LEAST for Restless when MOST is selected
If MOST has one column, LEAST can have any column other than the column taken by MOST
For Example
Solution:
Use GridValidationBuilder to limit multiple choice items to one response per column, with the method requireLimitOneResponsePerColumn().
Code snippet:
For example, to create your item:
function createItem() {
var form = FormApp.getActiveForm();
var gridItem = form.addGridItem();
gridItem.setTitle('Fill the options below')
.setRows(['MOST', 'LEAST'])
.setColumns(['Restless', 'Neighborly', 'Appealing', 'Careful']);
var gridValidation = FormApp.createGridValidation()
.setHelpText("Select one item per column.")
.requireLimitOneResponsePerColumn()
.build();
gridItem.setValidation(gridValidation);
}
Then, in your form, if you try to select the same column in the two rows:
I have a google form and a sheet that collects the responses which of course always appear at the bottom. I have been using the following script to copy the last response (which is always on the last row) from the Response sheet (Form Responses 2) to row two of another sheet (All Responses). When run by a trigger on Form Submit the script inserts a blank row into All Responses, then the copied values into another row above the blank row. Please can you help and tell me why and how I might change the script so the blank row is not added:
function CopyLastrowformresponse () {
var ss = SpreadsheetApp.getActive();
var AR = ss.getSheetByName("All Responses");
var FR = ss.getSheetByName("Form responses 2");
var FRlastrow = FR.getLastRow();
AR.insertRowBefore(2);
FR.getRange(FRlastrow, 1, FRlastrow, 22).copyTo(AR.getRange("A2"), SpreadsheetApp.CopyPasteType.PASTE_VALUES, false);
}
A few things could be going on here.
You're getting a number of rows equal to FRlastrow, when I think you only want to be getting 1 row.
Apps Script has buggy behavior with onFormSubmit() triggers, so you may to check duplicate triggers (see this answer).
The script isn't fully exploiting the event object provided by onFormSubmit(). Specifically, rather than getting the last row from one sheet, you could use e.values, which is the same data.
I would change the script to be something like this:
function CopyLastrowformresponse (e) {
if (e.values && e.values[1] != "") { // assuming e.values[1] (the first question) is required
SpreadsheetApp.getActive()
.getSheetByName("All Responses")
.insertRowBefore(2)
.getRange(2, 1, 1, e.values.length)
.setValues([e.values]);
}
}
But, ultimately, if all you want to do is simply reverse the order of the results, then I'd ditch Apps Script altogether and just use the =SORT() function.
=SORT('Form responses 2'!A:V, 'Form responses 2'!A:A, FALSE)
I'm super new to Maxscript and want to automate a process, I've been looking at some tutorials, but I'm running into a issue with selection. What I'm trying to do, is I have a list of strings (that I might have to add to) that represent objects in the max file that I want to select (if they exist in that file) and then add to a new layer.
for instance:
/* I have a big long list of objects I want to mass select, this has to be hardcoded because its a similar list that exists in a ton of max files */
rObj1 = "testObj1"
rObj2 = "sampleObj2"
""
rObj99 = "newObj90"
/*I want to then add it to an array
removeList = #(rObj***)
/* Then run through each entry in the array to make sure it exists and then add it to my selection
for i in removeList do
(
if i != undefined then select (i)
)
/*Then Add what I have selected to a new layer
newLayer = LayerManager.newLayerFromName "removed_list"
for obj in selection do newLayer.addNode obj
I keep getting an error when it comes to selection, being new to Max I'm not sure what to do.
You are trying to select string where you should be selecting (or adding to the layer) an object:
newLayer = LayerManager.newLayerFromName "removed_list"
for objName in removeList where isValidNode (getNodeByName objName) do
newLayer.addNode (getNodeByName objName)
I'm trying to test out Firebase to allow users to post comments using push. I want to display the data I retrieve with the following;
fbl.child('sell').limit(20).on("value", function(fbdata) {
// handle data display here
}
The problem is the data is returned in order of oldest to newest - I want it in reversed order. Can Firebase do this?
Since this answer was written, Firebase has added a feature that allows ordering by any child or by value. So there are now four ways to order data: by key, by value, by priority, or by the value of any named child. See this blog post that introduces the new ordering capabilities.
The basic approaches remain the same though:
1. Add a child property with the inverted timestamp and then order on that.
2. Read the children in ascending order and then invert them on the client.
Firebase supports retrieving child nodes of a collection in two ways:
by name
by priority
What you're getting now is by name, which happens to be chronological. That's no coincidence btw: when you push an item into a collection, the name is generated to ensure the children are ordered in this way. To quote the Firebase documentation for push:
The unique name generated by push() is prefixed with a client-generated timestamp so that the resulting list will be chronologically-sorted.
The Firebase guide on ordered data has this to say on the topic:
How Data is Ordered
By default, children at a Firebase node are sorted lexicographically by name. Using push() can generate child names that naturally sort chronologically, but many applications require their data to be sorted in other ways. Firebase lets developers specify the ordering of items in a list by specifying a custom priority for each item.
The simplest way to get the behavior you want is to also specify an always-decreasing priority when you add the item:
var ref = new Firebase('https://your.firebaseio.com/sell');
var item = ref.push();
item.setWithPriority(yourObject, 0 - Date.now());
Update
You'll also have to retrieve the children differently:
fbl.child('sell').startAt().limitToLast(20).on('child_added', function(fbdata) {
console.log(fbdata.exportVal());
})
In my test using on('child_added' ensures that the last few children added are returned in reverse chronological order. Using on('value' on the other hand, returns them in the order of their name.
Be sure to read the section "Reading ordered data", which explains the usage of the child_* events to retrieve (ordered) children.
A bin to demonstrate this: http://jsbin.com/nonawe/3/watch?js,console
Since firebase 2.0.x you can use limitLast() to achieve that:
fbl.child('sell').orderByValue().limitLast(20).on("value", function(fbdataSnapshot) {
// fbdataSnapshot is returned in the ascending order
// you will still need to order these 20 items in
// in a descending order
}
Here's a link to the announcement: More querying capabilities in Firebase
To augment Frank's answer, it's also possible to grab the most recent records--even if you haven't bothered to order them using priorities--by simply using endAt().limit(x) like this demo:
var fb = new Firebase(URL);
// listen for all changes and update
fb.endAt().limit(100).on('value', update);
// print the output of our array
function update(snap) {
var list = [];
snap.forEach(function(ss) {
var data = ss.val();
data['.priority'] = ss.getPriority();
data['.name'] = ss.name();
list.unshift(data);
});
// print/process the results...
}
Note that this is quite performant even up to perhaps a thousand records (assuming the payloads are small). For more robust usages, Frank's answer is authoritative and much more scalable.
This brute force can also be optimized to work with bigger data or more records by doing things like monitoring child_added/child_removed/child_moved events in lieu of value, and using a debounce to apply DOM updates in bulk instead of individually.
DOM updates, naturally, are a stinker regardless of the approach, once you get into the hundreds of elements, so the debounce approach (or a React.js solution, which is essentially an uber debounce) is a great tool to have.
There is really no way but seems we have the recyclerview we can have this
query=mCommentsReference.orderByChild("date_added");
query.keepSynced(true);
// Initialize Views
mRecyclerView = (RecyclerView) view.findViewById(R.id.recyclerView);
mManager = new LinearLayoutManager(getContext());
// mManager.setReverseLayout(false);
mManager.setReverseLayout(true);
mManager.setStackFromEnd(true);
mRecyclerView.setHasFixedSize(true);
mRecyclerView.setLayoutManager(mManager);
I have a date variable (long) and wanted to keep the newest items on top of the list. So what I did was:
Add a new long field 'dateInverse'
Add a new method called 'getDateInverse', which just returns: Long.MAX_VALUE - date;
Create my query with: .orderByChild("dateInverse")
Presto! :p
You are searching limitTolast(Int x) .This will give you the last "x" higher elements of your database (they are in ascending order) but they are the "x" higher elements
if you got in your database {10,300,150,240,2,24,220}
this method:
myFirebaseRef.orderByChild("highScore").limitToLast(4)
will retrive you : {150,220,240,300}
In Android there is a way to actually reverse the data in an Arraylist of objects through the Adapter. In my case I could not use the LayoutManager to reverse the results in descending order since I was using a horizontal Recyclerview to display the data. Setting the following parameters to the recyclerview messed up my UI experience:
llManager.setReverseLayout(true);
llManager.setStackFromEnd(true);
The only working way I found around this was through the BindViewHolder method of the RecyclerView adapter:
#Override
public void onBindViewHolder(final RecyclerView.ViewHolder holder, int position) {
final SuperPost superPost = superList.get(getItemCount() - position - 1);
}
Hope this answer will help all the devs out there who are struggling with this issue in Firebase.
Firebase: How to display a thread of items in reverse order with a limit for each request and an indicator for a "load more" button.
This will get the last 10 items of the list
FBRef.child("childName")
.limitToLast(loadMoreLimit) // loadMoreLimit = 10 for example
This will get the last 10 items. Grab the id of the last record in the list and save for the load more functionality. Next, convert the collection of objects into and an array and do a list.reverse().
LOAD MORE Functionality: The next call will do two things, it will get the next sequence of list items based on the reference id from the first request and give you an indicator if you need to display the "load more" button.
this.FBRef
.child("childName")
.endAt(null, lastThreadId) // Get this from the previous step
.limitToLast(loadMoreLimit+2)
You will need to strip the first and last item of this object collection. The first item is the reference to get this list. The last item is an indicator for the show more button.
I have a bunch of other logic that will keep everything clean. You will need to add this code only for the load more functionality.
list = snapObjectAsArray; // The list is an array from snapObject
lastItemId = key; // get the first key of the list
if (list.length < loadMoreLimit+1) {
lastItemId = false;
}
if (list.length > loadMoreLimit+1) {
list.pop();
}
if (list.length > loadMoreLimit) {
list.shift();
}
// Return the list.reverse() and lastItemId
// If lastItemId is an ID, it will be used for the next reference and a flag to show the "load more" button.
}
I'm using ReactFire for easy Firebase integration.
Basically, it helps me storing the datas into the component state, as an array. Then, all I have to use is the reverse() function (read more)
Here is how I achieve this :
import React, { Component, PropTypes } from 'react';
import ReactMixin from 'react-mixin';
import ReactFireMixin from 'reactfire';
import Firebase from '../../../utils/firebaseUtils'; // Firebase.initializeApp(config);
#ReactMixin.decorate(ReactFireMixin)
export default class Add extends Component {
constructor(args) {
super(args);
this.state = {
articles: []
};
}
componentWillMount() {
let ref = Firebase.database().ref('articles').orderByChild('insertDate').limitToLast(10);
this.bindAsArray(ref, 'articles'); // bind retrieved data to this.state.articles
}
render() {
return (
<div>
{
this.state.articles.reverse().map(function(article) {
return <div>{article.title}</div>
})
}
</div>
);
}
}
There is a better way. You should order by negative server timestamp. How to get negative server timestamp even offline? There is an hidden field which helps. Related snippet from documentation:
var offsetRef = new Firebase("https://<YOUR-FIREBASE-APP>.firebaseio.com/.info/serverTimeOffset");
offsetRef.on("value", function(snap) {
var offset = snap.val();
var estimatedServerTimeMs = new Date().getTime() + offset;
});
To add to Dave Vávra's answer, I use a negative timestamp as my sort_key like so
Setting
const timestamp = new Date().getTime();
const data = {
name: 'John Doe',
city: 'New York',
sort_key: timestamp * -1 // Gets the negative value of the timestamp
}
Getting
const ref = firebase.database().ref('business-images').child(id);
const query = ref.orderByChild('sort_key');
return $firebaseArray(query); // AngularFire function
This fetches all objects from newest to oldest. You can also $indexOn the sortKey to make it run even faster
I had this problem too, I found a very simple solution to this that doesn't involved manipulating the data in anyway. If you are rending the result to the DOM, in a list of some sort. You can use flexbox and setup a class to reverse the elements in their container.
.reverse {
display: flex;
flex-direction: column-reverse;
}
myarray.reverse(); or this.myitems = items.map(item => item).reverse();
I did this by prepend.
query.orderByChild('sell').limitToLast(4).on("value", function(snapshot){
snapshot.forEach(function (childSnapshot) {
// PREPEND
});
});
Someone has pointed out that there are 2 ways to do this:
Manipulate the data client-side
Make a query that will order the data
The easiest way that I have found to do this is to use option 1, but through a LinkedList. I just append each of the objects to the front of the stack. It is flexible enough to still allow the list to be used in a ListView or RecyclerView. This way even though they come in order oldest to newest, you can still view, or retrieve, newest to oldest.
You can add a column named orderColumn where you save time as
Long refrenceTime = "large future time";
Long currentTime = "currentTime";
Long order = refrenceTime - currentTime;
now save Long order in column named orderColumn and when you retrieve data
as orderBy(orderColumn) you will get what you need.
just use reverse() on the array , suppose if you are storing the values to an array items[] then do a this.items.reverse()
ref.subscribe(snapshots => {
this.loading.dismiss();
this.items = [];
snapshots.forEach(snapshot => {
this.items.push(snapshot);
});
**this.items.reverse();**
},
For me it was limitToLast that worked. I also found out that limitLast is NOT a function:)
const query = messagesRef.orderBy('createdAt', 'asc').limitToLast(25);
The above is what worked for me.
PRINT in reverse order
Let's think outside the box... If your information will be printed directly into user's screen (without any content that needs to be modified in a consecutive order, like a sum or something), simply print from bottom to top.
So, instead of inserting each new block of content to the end of the print space (A += B), add that block to the beginning (A = B+A).
If you'll include the elements as a consecutive ordered list, the DOM can put the numbers for you if you insert each element as a List Item (<li>) inside an Ordered Lists (<ol>).
This way you save space from your database, avoiding unnecesary reversed data.
I am using sessions to populate a multi select box with options in my Zend application.
The user selects one or more options and fills in other fields on the form and then submits. If the user didn't select all of the options in the multi select then the form is displayed again but the multi select only has the options that the user did not select the last time. This process goes on until there are no more options from the multi select left to process.
Here is the code I use to get rid of the options that have already been processed so that they are not used to populate the multi select box:
if($form_successful){
// TODO remove $post['keyword_names'] (i.e. already processed) from $keyword_names (that come from $_SESSION)
$keyword_names = array_diff($keyword_names, $post['keyword_names']);
print_r($keyword_names);
if(is_array($keyword_names) && !empty($keyword_names)){
// save updated $keyword_names into $_SESSION['workflow1']
$session = new Zend_Session_Namespace('workflow1');
$session->keyword_names = $keyword_names;
// set flag to false so that we display form again
$form_successful = false;
}else{ // all keywords have been assigned
// go to next step
$this->_redirect('/workflow-1/step-'.($step+1).'/');
}
}
print_r($keyword_names); displays the correct options, however when the form is loaded when the user submits, the multi select displays the options that were there from the begining ie the options the user has just selected and submitted are not being taken out of the multi select, it is only when the user submits the form again then the multi select box updates.
Appreciate the help.
Solved the issue by making use of URL parameters. Here is the code (might differ a lot from what I posted first because some big changes were made):
// after successful form submission
if($form_successful){
// remove $post['keyword_names'] (i.e. already processed) from $keyword_names (that come from $_SESSION)
$keyword_names = array_diff($keyword_names, $post['keyword_names']);
// save remaining $keyword_names into $_SESSION['workflow1']
$session = new Zend_Session_Namespace('workflow1');
$session->keyword_names = $keyword_names;
if(is_array($keyword_names) && !empty($keyword_names)){
// redirect to the same step again - to ensure that the form will reflect (in select lists) newly created AdGroup and/or Campaign
// GET parameteres ($params_array) provide a way to remember user's choice
$params_array = array();
if(!empty($post['match_type_id'])){
$params_array['match_type_id'] = $post['match_type_id'];
}
if(!empty($post['with_permutations'])){
$params_array['with_permutations'] = $post['with_permutations'];
}
if(!empty($ad_group_id)){
$params_array['ad_group_id'] = $ad_group_id;
}
$this_step_url = UrlUtils::assemble('', $this->getRequest()->getActionName(), $this->getRequest()->getControllerName(), $this->getRequest()->getModuleName(), $params_array);
$this->_redirect($this_step_url);
}else{ // all keywords have been assigned
// go to next step
$this->_redirect('/workflow-1/step-'.($step+1).'/');
}
}
So you don't have any code about Zend_Form object here. How do you populate the form element? If you post your class code which extends Zend_Form (or any other code dials with your form) then I may help. But in any case you can populate your multiselectbox with setMultiOptions() method or addMultiOption() for each item in multiselectbox.