Why Is Matlab Ignoring My If Statements? - matlab

Question

So I have to write program that solves for these rules:
Find a six digit number in which the first digit is one more than the third, the second digit is one less than the fourth, the fifth digit is one less than the third, and the sixth digit is one more than the fourth. The sum of the second and third digits equals the first. The sum of all digits is thirty.
I am only allowed to use nested for and if statements and this is what I came up with:
for I = inf
for n4 = (1:9)
n6 = n4 + 1;
n2 = n4 -1;
for n3 = (1:9)
n1 = n3 + 1;
n5 = n3 - 1;
if (n1 - n2 == n3)
if (n1 + n2 + n3 + n4 + n5 + n6 == 30)
break
end
end
end
end
end
The issue I am having is that Matlab ignores all my if statements because at the end of the program, n1 - n2 = 0, n3 = 9, and the sum n1+n2+...+n6 = 22 not 30. This is my first project in Matlab so I hope I gave enough information for this question,
Thank you!

Answer 1

Code works perfectly and give right result, the only problem:
as already told break interrupts only 1 inner for loop.
If this is the whole code of your program you can use return instead of break.
Another way:
use some logical index.
For example:
flag = 0;
for I = inf
for n4 = (1:9)
n6 = n4 + 1;
n2 = n4 -1;
for n3 = (1:9)
n1 = n3 + 1;
n5 = n3 - 1;
if (n1 - n2 == n3)
if (n1 + n2 + n3 + n4 + n5 + n6 == 30)
flag = 1;
break
end
end
end
if flag==1
break
end
end
end
By the way. The answer is 918273.