What happens if I reference a package but don't use/require it? - perl

Question

As much as I can (mostly for clarity/documentation), I've been trying to say
use Some::Module;
use Another::Module qw( some namespaces );
in my Perl modules that use other modules.
I've been cleaning up some old code and see some places where I reference modules in my code without ever having used them:
my $example = Yet::Another::Module->AFunction($data); # EXAMPLE 1
my $demo = Whats::The::Difference::Here($data); # EXAMPLE 2
So my questions are:
Is there a performance impact (I'm thinking compile time) by not stating use x and simply referencing it in the code?
I assume that I shouldn't use modules that aren't utilized in the code - I'm telling the compiler to compile code that is unnecessary.
What's the difference between calling functions in example 1's style versus example 2's style?

Answer 1

I would say that this falls firmly into the category of preemptive optimisation and if you're not sure, then leave it in. You would have to be including some vast unused libraries if removing them helped at all
It is typical of Perl to hide a complex issue behind a simple mechanism that will generally do what you mean without too much thought
The simple mechanisms are these
use My::Module 'function' is the same as writing
BEGIN {
require My::Module;
My::Module->import( 'function' );
}
The first time perl successfully executes a require statement, it adds an element to the global %INC hash which has the "pathified" module name (in this case, My/Module.pm) for a key and the absolute location where it found the source as a value
If another require for the same module is encountered (that is, it already exists in the %INC hash) then require does nothing
So your question
What happens if I reference a package but don't use/require it?
We're going to have a problem with use, utilise, include and reference here, so I'm code-quoting only use and require when I mean the Perl language words.
Keeping things simple, these are the three possibilities
As above, if require is seen more than once for the same module source, then it is ignored after the first time. The only overhead is checking to see whether there is a corresponding element in %INC
Clearly, if you use source files that aren't needed then you are doing unnecessary compilation. But Perl is damn fast, and you will be able to shave only fractions of a second from the build time unless you have a program that uses enormous libraries and looks like use Catalyst; print "Hello, world!\n";
We know what happens if you make method calls to a class library that has never been compiled. We get
Can't locate object method "new" via package "My::Class" (perhaps you forgot to load "My::Class"?)
If you're using a function library, then what matters is the part of use that says
My::Module->import( 'function' );
because the first part is require and we already know that require never does anything twice. Calling import is usually a simple function call, and you would be saving nothing significant by avoiding it
What is perhaps less obvious is that big modules that include multiple subsidiaries. For instance, if I write just
use LWP::UserAgent;
then it knows what it is likely to need, and these modules will also be compiled
Carp
Config
Exporter
Exporter::Heavy
Fcntl
HTTP::Date
HTTP::Headers
HTTP::Message
HTTP::Request
HTTP::Response
HTTP::Status
LWP
LWP::MemberMixin
LWP::Protocol
LWP::UserAgent
Storable
Time::Local
URI
URI::Escape
and that's ignoring the pragmas!
Did you ever feel like you were kicking your heels, waiting for an LWP program to compile?
I would say that, in the interests of keeping your Perl code clear and tidy, it may be an idea to remove unnecessary modules from the compilation phase. But don't agonise over it, and benchmark your build times before doing any pre-handover tidy. No one will thank you for reducing the build time by 20ms and then causing them hours of work because you removed a non-obvious requirement.

Answer 2

You actually have a bunch of questions.
Is there a performance impact (thinking compile time) by not stating use x and simply referencing it in the code?
No, there is no performance impact, because you can't do that. Every namespace you are using in a working program gets defined somewhere. Either you used or required it earlier to where it's called, or one of your dependencies did, or another way1 was used to make Perl aware of it
Perl keeps track of those things in symbol tables. They hold all the knowledge about namespaces and variable names. So if your Some::Module is not in the referenced symbol table, Perl will complain.
I assume that I shouldn't use modules that aren't utilized in the code - I'm telling the compiler to compile code that is unnecessary.
There is no question here. But yes, you should not do that.
It's hard to say if this is a performance impact. If you have a large Catalyst application that just runs and runs for months it doesn't really matter. Startup cost is usually not relevant in that case. But if this is a cronjob that runs every minute and processes a huge pile of data, then an additional module might well be a performance impact.
That's actually also a reason why all use and require statements should be at the top. So it's easy to find them if you need to add or remove some.
What's the difference between calling functions in example 1's style versus example 2's style?
Those are for different purposes mostly.
my $example = Yet::Another::Module->AFunction($data); # EXAMPLE 1
This syntax is very similar to the following:
my $e = Yet::Another::Module::AFunction('Yet::Another::Module', $data)
It's used for class methods in OOP. The most well-known one would be new, as in Foo->new. It passes the thing in front of the -> to the function named AFunction in the package of the thing on the left (either if it's blessed, or if it's an identifier) as the first argument. But it does more. Because it's a method call, it also takes inheritance into account.
package Yet::Another::Module;
use parent 'A::First::Module';
1;
package A::First::Module;
sub AFunction { ... }
In this case, your example would also call AFunction because it's inherited from A::First::Module. In addition to the symbol table referenced above, it uses #ISA to keep track of who inherits from whom. See perlobj for more details.
my $demo = Whats::The:Difference::Here($data); # EXAMPLE 2
This has a syntax error. There is a : missing after The.
my $demo = Whats::The::Difference::Here($data); # EXAMPLE 2
This is a function call. It calls the function Here in the package Whats::The::Difference and passes $data and nothing else.
Note that as Borodin points out in a comment, your function names are very atypical and confusing. Usually functions in Perl are written with all lowercase and with underscores _ instead of camel case. So AFunction should be a_function, and Here should be here.
1) for example, you can have multiple package definitions in one file, which you should not normally do, or you could assign stuff into a namespace directly with syntax like *Some::Namespace::frobnicate = sub {...}. There are other ways, but that's a bit out of scope for this answer.