in my main program i receive inputs like -
key1=value1 key2=value2
Now what I want is to create a map out of it. I know the imperative way of doing this where I would get Array[String] that can be foreach and then split by "=" and then key and value can be used to form a Map.
is there a good functional and readable way to achieve this?
Also It will be great if I can avoid mutable Map and I want to avoid initial Dummy value initialization.
def initialize(strings: Array[String]): Unit = {
val m = collection.mutable.Map("dummy" -> "dummyval")
strings.foreach(
s => {
val keyVal:Array[String] = s.split("=")
m += keyVal(0) -> keyVal(1)
})
println(m)
}
you can just use toMap().
However, converting from array to tuple is not quite trivial:
How to convert an Array to a Tuple?
scala> val ar = Array("key1=value1","key2=value2")
ar: Array[String] = Array(key1=value1, key2=value2)
scala> ar.collect(_.split("=") match { case Array(x,y) => (x,y)}).toMap
res10: scala.collection.immutable.Map[String,String] = Map(key1 -> value1, key2 -> value2)
Maybe you have to call Function.unlift for intellij
val r = ar.collect(Function.unlift(_.split("=") match { case Array(x, y) => Some(x, y)})).toMap
similar to above but using only 'map'
ar.map(_.split("=")).map(a=>(a(0), a(1))).toMap
You can use Scopt to do the command line argument parsing in a neat way.
Related
I have a situation here
I have two strins
val keyMap = "anrodiApp,key1;iosApp,key2;xyz,key3"
val tentMap = "androidApp,tenant1; iosApp,tenant1; xyz,tenant2"
So what I want to add is to create a nested immutable nested map like this
tenant1 -> (andoidiApp -> key1, iosApp -> key2),
tenant2 -> (xyz -> key3)
So basically want to group by tenant and create a map of keyMap
Here is what I tried but is done using mutable map which I do want, is there a way to create this using immmutable map
case class TenantSetting() {
val requesterKeyMapping = new mutable.HashMap[String, String]()
}
val requesterKeyMapping = keyMap.split(";")
.map { keyValueList => keyValueList.split(',')
.filter(_.size==2)
.map(keyValuePair => (keyValuePair[0],keyValuePair[1]))
.toMap
}.flatten.toMap
val config = new mutable.HashMap[String, TenantSetting]
tentMap.split(";")
.map { keyValueList => keyValueList.split(',')
.filter(_.size==2)
.map { keyValuePair =>
val requester = keyValuePair[0]
val tenant = keyValuePair[1]
if (!config.contains(tenant)) config.put(tenant, new TenantSetting)
config.get(tenant).get.requesterKeyMapping.put(requester, requesterKeyMapping.get(requester).get)
}
}
The logic to break the strings into a map can be the same for both as it's the same syntax.
What you had for the first string was not quite right as the filter you were applying to each string from the split result and not on the array result itself. Which also showed in that you were using [] on keyValuePair which was of type String and not Array[String] as I think you were expecting. Also you needed a trim in there to cope with the spaces in the second string. You might want to also trim the key and value to avoid other whitespace issues.
Additionally in this case the combination of map and filter can be more succinctly done with collect as shown here:
How to convert an Array to a Tuple?
The use of the pattern with 2 elements ensures you filter out anything with length other than 2 as you wanted.
The iterator is to make the combination of map and collect more efficient by only requiring one iteration of the collection returned from the first split (see comments below).
With both strings turned into a map it just needs the right use of groupByto group the first map by the value of the second based on the same key to get what you wanted. Obviously this only works if the same key is always in the second map.
def toMap(str: String): Map[String, String] =
str
.split(";")
.iterator
.map(_.trim.split(','))
.collect { case Array(key, value) => (key.trim, value.trim) }
.toMap
val keyMap = toMap("androidApp,key1;iosApp,key2;xyz,key3")
val tentMap = toMap("androidApp,tenant1; iosApp,tenant1; xyz,tenant2")
val finalMap = keyMap.groupBy { case (k, _) => tentMap(k) }
Printing out finalMap gives:
Map(tenant2 -> Map(xyz -> key3), tenant1 -> Map(androidApp -> key1, iosApp -> key2))
Which is what you wanted.
I am reading a file composed of lines in the format a=b.
Using Source.fromFile("file").getLines I get an Iterator[String]. I figure I need to split the strings into tuples and then form the map from the tuples - that is easy. I am not being able to go from the Iterator[String] to an Iterator[(String,String)].
How can I do this? I am a beginner to scala and not experienced with functional programming, so I am receptive to alternatives :)
You can do so by splitting the string and then creating the tuples from the first and second elements using Iterator.map:
val strings = List("a=b", "c=d", "e=f").iterator
val result: Iterator[(String, String)] = strings.map { s =>
val split = s.split("=")
(split(0), split(1))
}
If you don't mind the extra iteration and intermediate collection you can make this a little prettier:
val result: Iterator[(String, String)] =
strings
.map(_.split("="))
.map(arr => (arr(0), arr(1)))
You can transform the values returned by an Iterator using the map method:
def map[B](f: (A) ⇒ B): Iterator[B]
Maybe like this?
Source.fromFile("file").getLines.map(_.split("=").map( x => (x.head,x.tail) ) )
You might want to wrap this into Try.
This is my try:
val strings = List("a=b", "c=d", "e=f")
val map = strings.map(_.split("=")).map { case Array(f1,f2) => (f1,f2) }
I have Some() type Map[String, String], such as
Array[Option[Any]] = Array(Some(Map(String, String)
I want to return it as
Array(Map(String, String))
I've tried few different ways of extracting it-
Let's say if
val x = Array(Some(Map(String, String)
val x1 = for (i <- 0 until x.length) yield { x.apply(i) }
but this returns IndexedSeq(Some(Map)), which is not what I want.
I tried pattern matching,
x.foreach { i =>
i match {
case Some(value) => value
case _ => println("nothing") }}
another thing I tried that was somewhat successful was that
x.apply(0).get.asInstanceOf[Map[String, String]]
will do something what I want, but it only gets 0th index of the entire array and I'd want all the maps in the array.
How can I extract Map type out of Some?
If you want an Array[Any] from your Array[Option[Any]], you can use this for expression:
for {
opt <- x
value <- opt
} yield value
This will put the values of all the non-empty Options inside a new array.
It is equivalent to this:
x.flatMap(_.toArray[Any])
Here, all options will be converted to an array of either 0 or 1 element. All these arrays will then be flattened back to one single array containing all the values.
Generally, the pattern is either to use transformations on the Option[T], like map, flatMap, filter, etc.
The problem is, we'll need to add a type cast to retrieve the underlying Map[String, String] from Any. So we'll use flatten to remove any potentially None types and unwrap the Option, and asInstanceOf to retreive the type:
scala> val y = Array(Some(Map("1" -> "1")), Some(Map("2" -> "2")), None)
y: Array[Option[scala.collection.immutable.Map[String,String]]] = Array(Some(Map(1 -> 1)), Some(Map(2 -> 2)), None)
scala> y.flatten.map(_.asInstanceOf[Map[String, String]])
res7: Array[Map[String,String]] = Array(Map(1 -> 1), Map(2 -> 2))
Also when you talk just about single value you can try Some("test").head and for null simply Some(null).flatten
I wish to apply a sequence of functions to an object (each of the functions may return the same or modified object) and get the ultimate result returned by the last function.
Is there an idiomatic Scala way to turn this (pseudocode):
val pipeline = ListMap(("a" -> obj1), ("b" -> obj2), ("c" -> obj3))
into this?
val initial_value = Something("foo", "bar")
val result = obj3.func(obj2.func(obj1.func(initial_value)))
The pipeline is initialized at runtime and contains an undetermined number of "manglers".
I tried with foreach but it requires an intermediate var to store the result, and foldLeft only works on types of ListMap, while the initial value and the result are of type Something.
Thanks
This should do it:
pipeline.foldLeft(initial_value){case (acc, (k,obj)) => obj.func(acc)}
No idea why pipeline contains pairs, though.
Assuming input and output types are the same, I'd go with a reduceLeft and composition by andThen:
def pipe[A](a: A, funcs: List[A => A]): A = funcs.reduceLeft(_ andThen _)(a)
I think foldLeft is the right choice:
val pipeline = List("a"-> func1, "b"-> func2, "c"-> func3)
...
val result = pipeline.foldLeft(initial_value) {case (acc,(key,func)) => func(acc)}
Get rid of your keys, first:
pipeline.values.foldLeft(initial_value)((a, f) => f.func(a))
I am trying to create a map after getting result for each items in the list. Here is what I tried so far:
val sourceList: List[(Int, Int)] = ....
val resultMap: Map[Int, Int] = for(srcItem <- sourceList) {
val result: Int = someFunction(srcItem._1)
Map(srcItem._1 -> result)
}
But I am getting type mismatch error in IntelliJ and I am definitely not writing proper syntax here. I don't think I can use yield as I don't want List of Map. What is correct way to create Map using for loop. Any suggestion?
The simplest way is to create the map out of a list of tuples:
val resultMap = sourceList.map(item => (item._1, someFunction(item._1))).toMap
Or, in the monadic way:
val listOfTuples = for {
(value, _) <- sourceList
} yield (value, someFunction(value))
val resultMap = listOfTuples.toMap
Alternatively, if you want to avoid the creation of listOfTuples you can make the transformation a lazy one by calling .view on sourceList and then call toMap:
val resultMap = sourceList.view
.map(item => (item._1, someFunction(item._1)))
.toMap
Finally, if you really want to avoid generating extra objects you can use a mutable Map instead and append the keys and values to it using += or .put