Spring data and mongoDB - aggregation with java list - mongodb

Question

I have the following document (#Document):
#Id
private String id;
private String fileName;
private String projectId;
private List<DocumentFileVersion> documentFileVersions;
private List<String> userIdBlackList; // here userIds are included
and this is my current aggregation:
final String userId = "5589929b887dc1fdb501cdbb";
final Aggregation aggregate = newAggregation(match(Criteria.where("projectId").in(projectId)),
group("fileName").count().as("amountOfDocumentFiles"));
final AggregationResults<DocumentFileAmount> groupDocumentFiles = mongoTemplate.aggregate(aggregate, DocumentFile.class,
DocumentFileAmount.class);
final List<DocumentFileAmount> documentFileAmounts = groupDocumentFiles.getMappedResults();
final int amountOfDocumentFiles = documentFileAmounts.size();
Now I will extend the aggreagation in that way that I only will have the DocumentFiles where userId (in this case "1234") is not in userIdBlackList.
Is there a possibility to do that, like in pseudocode:
final Aggregation aggregate = newAggregation(match(Criteria.where("projectId").in(projectId).and(userId).notInList("userIdBlackList")),
group("fileName").count().as("amountOfDocumentFiles"));
I would need something like this: ... .and(userId).notInList("userIdBlackList") ...
[EDIT]
I have tried this query:
final Aggregation aggregate = newAggregation(
match(Criteria.where("projectId").in(projectId).and(userId).and("‌​userIdBlackList").ne(userId)),
group("fileName").count().as("amountOfDocumentFiles"));
A Database entry can look like this:
{
"_id" : ObjectId("587e7cabafdaff28743f3034"),
"_class" : "com.smartinnotec.legalprojectmanagement.dao.domain.DocumentFile",
"fileName" : "Hydrangeas.jpg",
"projectId" : "587e7c95afdaff28743f302e",
"userIdBlackList" : [
"5589929b887dc1fdb501cdbb"
]
}
but .and(userId).and("‌​userIdBlackList").ne(userId) has no effect.
[EDIT2]
I have tried to simulate it in the mongo console too.
I have listed all documentfiles with the command db.DocumentFile.find().pretty():
db.DocumentFile.find().pretty()
{
"_id" : ObjectId("587f0d61473c92b933a68efa"),
"_class" : "com.smartinnotec.legalprojectmanagement.dao.domain.DocumentFile",
"fileName" : "DocumentFile1",
"ending" : "jpg",
"projectId" : "587f0d61473c92b933a68ef9",
"active" : true,
"userIdBlackList" : [
"587f0d61473c92b933a68ef8"
]}
and my query looks like this:
db.DocumentFile.aggregate({ "$match" : { "projectId" : { "$in" : [ "587f0d61473c92b933a68ef9"]} , "‌​userIdBlackList" : { "$ne" : "587f0d61473c92b933a68ef8"}}}).pretty();
{
"_id" : ObjectId("587f0d61473c92b933a68efa"),
"_class" : "com.smartinnotec.legalprojectmanagement.dao.domain.DocumentFile",
"fileName" : "DocumentFile1",
"ending" : "jpg",
"projectId" : "587f0d61473c92b933a68ef9",
"active" : true,
"userIdBlackList" : [
"587f0d61473c92b933a68ef8"
]}
I have expected that I do not get a documentfile because of this expression "‌​userIdBlackList" : { "$ne" : "587f0d61473c92b933a68ef8"}
Does anyone know what I am doing wrong?
[EDIT3]
I have this two documents and with the aggegate:
final Aggregation aggregate = newAggregation(
match(Criteria.where("projectId").in(projectId).and("‌​userIdBlackList").nin(userId)),
group("fileName").count().as("amountOfDocumentFiles"));
I get the amount of 2 but it should 1. I don't know what I am doing wrong?
db.DocumentFile.find().pretty()
{
"_id" : ObjectId("587f2228e232342f74b166f9"),
"_class" : "com.smartinnotec.legalprojectmanagement.dao.domain.DocumentFile",
"fileName" : "DocumentFile1",
"ending" : "jpg",
"projectId" : "587f2228e232342f74b166f8",
"active" : true,
"userIdBlackList" : [
"587f2228e232342f74b166f7"
]}
{
"_id" : ObjectId("587f2228e232342f74b166fa"),
"_class" : "com.smartinnotec.legalprojectmanagement.dao.domain.DocumentFile",
"fileName" : "DocumentFile2",
"ending" : "jpg",
"projectId" : "587f2228e232342f74b166f8",
"active" : true,
"userIdBlackList" : [ ]
}

Answer 1

Have you tried using .nin
final Aggregation aggregate = newAggregation(
match(Criteria.where("projectId").in(projectId).and("‌​userIdBlackList").nin(userId)),
group("fileName").count().as("amountOfDocumentFiles"));