Adding one year to a date field in postgresql - postgresql

I have a table in postgresql with a field_date using the syntax 'YYYY-MM-DD', I want to add a year to the field with the the sentence:
UPDATE table SET date_field = DATEADD(YEAR, 1, date_field);
but postgres return:
ERROR: column "year" does not exist
I can't see what's wrong with the sentence


Try this:
UPDATE table SET date_field = date_field + interval '1 year'
It appears that you were trying to use SQL Server's DATEADD() function, which does not exist in Postgres.


select CURRENT_DATE, CURRENT_DATE + interval '1 year'
In your case you trying to do it in Transact SQL not in Postgres.
Try to use:
DATEADD-> "DATE + interval '1 year'"

Related

current_date in redshift exclude today's date when i am using with between command

I want to query data for last 30 days including today from redshift table. below is my query.
my date_column's type is 'timestamp without timezone'
select *
from mytable
WHERE date_column BETWEEN current_date - INTERVAL '30 day' AND current_date
order by date_column desc;
It gives the result for 30 days. But it doesn't include today's result.
I want to query for 30 days result including today's result also.

If it's a timestamp don't use between as it also compares the time part. Use a range query:
where date_column >= current_date - interval '30 day'
and date_column < current_date + interval '1 day'
Note that the upper bound is using < together with "tomorrow"
With Postgres this could be simplified to
where date_column >= current_date - 30
and date_column < current_date + 1
but Redshift isn't Postgres and I don't know if that would work there.

Oracle to PostgreSQL round and trunc on date columns

Can you please help me to convert the below Oracle query to PostgreSQL query?. Looks like "round" and "trunc" functions are not there in postgreSQL.
Here "intime" is the date and time column i.e date datatype.
select round(((intime - trunc(CURRENT_DATE-1, 'DDD')) * 24),2) from tpe
Below is the posgreSQL format and o/p -2496 days -132:00:00
SELECT (('2021-02-19 08:00:00'::timestamp AT time zone 'EST' - CURRENT_DATE - (interval '1 day'))*24)
Below is ORACLE format and o/p -2464
select ((to_date('02/19/2021 8:00:00','MM/DD/YYYY HH24:MI:SS') - trunc(CURRENT_DATE-1, 'DDD')) * 24) from dual;
And When apply round function in postgreSQL it's throwing error
SELECT round((('2021-02-19 08:00:00'::timestamp AT time zone 'EST' - CURRENT_DATE - (interval '1 day'))*24),2)
"ERROR: function round(interval, integer) does not exist.
Idea is to get same output of oracle's one.

PostgresSQL: interval field value out of range

I am new to PostgresSQL where I am running one query where I am looking for activities within last week but it is throwing out of range error
Postgres SQL:
select *
from myTable
where order_time > '2018-12-04 18:22:26' - INTERVAL '7 day'
Error:
IntervalFieldOverflow: ERROR: interval field value out of range: "2018-12-04 18:22:26"
Version: PostgresSQL 9.6
I have tried to resolve my issue by searching online but did not get much help.

Try casting the timestamp literal string:
select *
from myTable
where order_time > '2018-12-04 18:22:26'::timestamp - interval '7 day';

How to select data in 2 month(from now) use postgresql?

I'm new to sql and database work . Now I want select data in 2 month from now . the key is xxdate lookslike 2019-4-11
like:
select * from table where date > now() - 2 month
but I don't know the correct way to express it. can someone help?

You can use this query:
SELECT * FROM table WHERE date > (current_date - interval '2 month')::date;

How define today date with Default timestmp

I am using postgressql i wish to get the data for currentdate, i want filter the data based on the date
in data base my plandate filed is define as Time stamp with time zone so its showing like this format 2013-09-01 03:22:01.438348+05:30 my query is like this
select ttodoid ,date,details from ttodo where date=currentdate():
but currentdate function giving me just date '2013-10-06' based on this result is no rows how can i manage it for today date detail

UPDATED: One way to do it
SELECT *
FROM ttodo
WHERE date BETWEEN DATE_TRUNC('day', CURRENT_TIMESTAMP)
AND DATE_TRUNC('day', CURRENT_TIMESTAMP)
+ INTERVAL '1 DAY'
- INTERVAL '1 MICROSECOND';
or
SELECT *
FROM ttodo
WHERE date >= DATE_TRUNC('day', CURRENT_TIMESTAMP)
AND date < DATE_TRUNC('day', CURRENT_TIMESTAMP)
+ INTERVAL '1 DAY';
Here is SQLFiddle demo

select * from ttodo where (ttodo.todoplandate::date = current_date) or
(ttodo.todoplandate::date < current_date

I think the easier approach would be just to convert your field to date:
SELECT ttodoid ,date,details FROM ttodo
WHERE CAST(date AS DATE) = current_date;
Notice that, ff you want this query to be indexed, you have to create the index with the cast:
CREATE INDEX idx_ttodo_date ON ttodo ((CAST(date AS DATE)));
Another approach, is instead of casting the field, is checking the intervals, something similar of what petern proposed, but with correct intervals:
SELECT ttodoid ,date,details FROM ttodo
WHERE date >= date_trunc('day', current_timestamp)
AND date < (date_trunc('day', current_timestamp) + interval '1day');
This approach has the advantage that it can use an index on the date field only, which is good if you already have it.