I want to query data for last 30 days including today from redshift table. below is my query.
my date_column's type is 'timestamp without timezone'
select *
from mytable
WHERE date_column BETWEEN current_date - INTERVAL '30 day' AND current_date
order by date_column desc;
It gives the result for 30 days. But it doesn't include today's result.
I want to query for 30 days result including today's result also.
If it's a timestamp don't use between as it also compares the time part. Use a range query:
where date_column >= current_date - interval '30 day'
and date_column < current_date + interval '1 day'
Note that the upper bound is using < together with "tomorrow"
With Postgres this could be simplified to
where date_column >= current_date - 30
and date_column < current_date + 1
but Redshift isn't Postgres and I don't know if that would work there.
Related
I required a custom solution to a problem in which users can choose a number of different intervals for data comparisons.
Example:
CURRENT_DATE - interval '1 day'
CURRENT_DATE - interval '4 day'
CURRENT_DATE - interval '7 day'
AND so on
So I am looking for a solution in which I can pass the array of integers in intervals like
select CURRENT_DATE - interval '1day' * any(ARRAY[1,4,7])
But it is not possible because
op ANY/ALL (array) requires an operator to yield boolean
demos:db<>fiddle
You can use unnest() to extract the array elements into one record per element and then return the CURRENT_DATE minus each of these elements:
SELECT
CURRENT_DATE - array_element
FROM unnest(ARRAY[1,4,7]) as array_element
Naturally, you can put the unnest() into the SELECT list:
SELECT CURRENT_DATE - unnest(ARRAY[1,4,7])
Edit:
If you need another date range than days you can use intervals for that:
SELECT CURRENT_DATE - unnest(ARRAY[1,4,7]) * interval '1 week'
I'm using this to try and get all events with a timestamp of today
SELECT systemuserid,ondate from auditlog
WHERE ondate::date = NOW()::date
Performance seems really bad, over 2 minutes. I have a index on ondate.
Is there a more efficient way to do it?
Thanks
Use a range condition:
select *
from auditlog
where ondate >= current_date
and ondate < current_date + 1;
current_date will be converted to a timestamp at midnight, so ondate => current_date will include everything from "today".
And the condition ondate < current_date + 1 will exclude rows with a timestamp of tomorrow (midnight) or later.
I'm trying to make a SELECT query which will compare current time with time at database. For example in database there is a record '2018-02-07 12:00:00' and I wanna compare it to current time. If current time is '2018-02-07 11:00:00', record '2018-02-07 12:00:00' should be visible in results. It should compare two dates and shows only those who are 1h before or after current time.'
Tried something like this:
SELECT * FROM events WHERE age(current_date, event_date) < '1 hour';
or
SELECT * FROM events WHERE event_date > (now() - INTERVAL '1 hour');
those that are 1h before or after current time
Wouldn't the logic look like this?
SELECT e.*
FROM events e
WHERE e.event_date > now() - INTERVAL '1 hour' AND
e.event_date < now() + INTERVAL '1 hour'
I am using postgressql i wish to get the data for currentdate, i want filter the data based on the date
in data base my plandate filed is define as Time stamp with time zone so its showing like this format 2013-09-01 03:22:01.438348+05:30 my query is like this
select ttodoid ,date,details from ttodo where date=currentdate():
but currentdate function giving me just date '2013-10-06' based on this result is no rows how can i manage it for today date detail
UPDATED: One way to do it
SELECT *
FROM ttodo
WHERE date BETWEEN DATE_TRUNC('day', CURRENT_TIMESTAMP)
AND DATE_TRUNC('day', CURRENT_TIMESTAMP)
+ INTERVAL '1 DAY'
- INTERVAL '1 MICROSECOND';
or
SELECT *
FROM ttodo
WHERE date >= DATE_TRUNC('day', CURRENT_TIMESTAMP)
AND date < DATE_TRUNC('day', CURRENT_TIMESTAMP)
+ INTERVAL '1 DAY';
Here is SQLFiddle demo
select * from ttodo where (ttodo.todoplandate::date = current_date) or
(ttodo.todoplandate::date < current_date
I think the easier approach would be just to convert your field to date:
SELECT ttodoid ,date,details FROM ttodo
WHERE CAST(date AS DATE) = current_date;
Notice that, ff you want this query to be indexed, you have to create the index with the cast:
CREATE INDEX idx_ttodo_date ON ttodo ((CAST(date AS DATE)));
Another approach, is instead of casting the field, is checking the intervals, something similar of what petern proposed, but with correct intervals:
SELECT ttodoid ,date,details FROM ttodo
WHERE date >= date_trunc('day', current_timestamp)
AND date < (date_trunc('day', current_timestamp) + interval '1day');
This approach has the advantage that it can use an index on the date field only, which is good if you already have it.
How to get last 3 months records from the table.
SELECT *
from table
where month > CURRENT_DATE-120
and month < CURRENT_DATE
order by month;
I have used the above query is it correct? shall I use this for get last 3 month record from the table.
You can use built-in INTERVAL instruction
Check how this works:
SELECT CURRENT_DATE - INTERVAL '3 months'
and you can rewrite your SQL to:
SELECT * from table where date > CURRENT_DATE - INTERVAL '3 months'
(not checked but this should give you an idea how to use INTERVAL instruction)
Try that:
SELECT *
FROM table
WHERE month BETWEEN EXTRACT(MONTH FROM NOW() - INTERVAL '3 months')
AND EXTRACT(MONTH FROM NOW())
ORDER BY month
;
This filters the last 3 calendar months
SELECT * from table where date >= to_char(CURRENT_DATE - INTERVAL '3 months', 'YYYY-MM-01')::date
select date::date
from generate_series((current_date - INTERVAL '1 Month')::date, (current_date - INTERVAL '1 DAY')::date,'1
day'::interval) date
WHERE date >= date_trunc('month', current_date - interval '3' month)
and date < date_trunc('month', current_date)
This will give last three months date list, excluding current months date. Example if current month is November. This list will give use all dates of August, Septemeber and October.