Swift static property initilizers are lazy why I could declared it as a constant - swift

As far as I known (see reference A), Static property initilizers are lazy, and I found the following description by the office documents
You must always declare a lazy property as a variable (with the var
keyword) because its initial value might not be retrieved until after
instance initialization completes. Constant properties must always
have a value before initialization completes, and therefore cannot be
declared as lazy.
From the above information, I think I couldn't define the static property as a constant variable and I made a tryout, it turns out I can do that without triggering any error from the compiler.
Example:
class Person {
static let firstNaID = "First Name"
static let lastNaID = "Last Name"
}
Question: Is this a bug of the Swift 3.0.1 or I was wrong.
Reference A: Neuburg. M.2016. IOS 10 Programming Fundamental with Swift. P127
Thanks for your time and help

Neuburg M. is drawing a distinction between static properties and instance properties. You are pretending to ignore that distinction. But you cannot ignore it; they are totally different things, used for different purposes.
In this code:
class Person { // let's declare a static property
static let firstNaID = "First Name"
}
... firstNaID is already lazy. But now try to do this:
class Person { // let's declare an instance property
lazy let firstNaID : String = "First Name" // error
}
You can't; as things stand (up thru Swift 3.1), you have to say lazy var instead — and when you do, you get a lazy instance property.
Your static let declaration thus doesn't accomplish what lazy let wanted to accomplish, because a static property is not an instance property.

You are talking about type properties
Form the same chapter of the documentation
Type Properties
... Type properties are useful for defining values that are universal to all instances of a particular type, such as a constant property that all instances can use ...
Stored type properties can be variables or constants. Computed type properties are always declared as variable properties, in the same way as computed instance properties.
NOTE
...
Stored type properties are lazily initialized on their first access. They are guaranteed to be initialized only once, even when accessed by multiple threads simultaneously, and they do not need to be marked with the lazy modifier.

Related

initialize Swift Class variables in declaration or with init?

In Swift you can initialize a variable in a class when you declare the variable:
var name: String = "John"
or you can initialize with init:
var name: String
init(name: String) {
self.name = name
}
Which version do you use and when?
Unless you are providing the initial value as an initializer parameter, for which you have for obvious reasons do that in the initializer, you can use any of the 2 ways.
My rules are:
if there are several initializers, and the property is initialized with the same value in all cases, I prefer inline initialization
if the property is (or should be) immutable, I prefer inline initialization
if the property can change during the instance lifetime, I prefer constructor initialization
but besides the first one, the other 2 are just based on personal preference.

Using "let" inside Struct - Swift

I'm currently practicing examples from Swift Language iBook. My understanding of "let" is that we use "let" to make a constant. Once we assign a value to it, we cannot assign another value to it again. Like the codes below:
let city="NY"
city="LA" <--error (Cannot assign 'let' value city)
But I saw this example on iBook which really confused me:
struct Color{
let red=0.0, green=0.0, blue=0.0 //<---declare variables using "let" and assign value
init(red:Double,green:Double,blue:Double){
self.red=red //<---assign value to variable again?
self.green=green
self.blue=blue
}
}
In this example, it has already assigned values to red, green and blue which use "let".
Why can we assign values to these three variables again in init?
The initialization in the let provides default values if you don't initialize them yourself in the constructor.
Constructors (init) are special. Inside them, you can assign to a constant instance variable. In fact, if you don't have a default value for them, you have to assign to them. (This applies to classes too.)
Thanks to Qwerty Bob for finding this in the docs
Modifying Constant Properties During Initialization
You can modify the value of a constant property at any point during initialization, as long as it is set to a definite value by the time initialization finishes.
Excerpt From: Apple Inc. “The Swift Programming Language.” iBooks. https://itun.es/us/jEUH0.l
You may set constant variables during the init process, before the self keyword is used. After this they are then truly 'constant'.
You must do it before the self keyword is used, as if you pass it to another object it could in turn call a method of yours which relies on that constant property
And also: structs get passed by value and not by reference, so you cannot modify the variables in a struct at all after their set. So the let keyword really makes sense.
If you continue reading a few paragraphs after the example you gave from the book (unless they use it in multiple locations), it actually talks about this behavior:
You can modify the value of a constant property at any point during
initialization, as long as it is set to a definite value by the time
initialization finishes.
So basically you can modify constants and upon ending the initialization all constants must have a definitive value. It also goes on to talk about how this works with subclasses too:
For class instances, a constant property can only be modified during
initialization by the class that introduces it. It cannot be modified
by a subclass.
Here is the doc reference for it (same as the book), the quoted sections is under the "Modifying Constant Properties During Initialization" subheading.
Apart from the initialization part, which was answered by Kevin, you're still missing the constant part of let. So to clarify let is not exactly a constant.
According to „The Swift Programming Language.” Apple Inc., 2014-05-27T07:00:00Z. iBooks:
Like C, Swift uses variables to store and refer to values by an
identifying name. Swift also makes extensive use of variables whose
values cannot be changed. These are known as constants, and are much
more powerful than constants in C.
Both var and let are references, therefore let is a const reference.
Using fundamental types doesn't really show how let is different than const.
The difference comes when using it with class instances (reference types):
class CTest
{
var str : String = ""
}
let letTest = CTest()
letTest.str = "test" // OK
letTest.str = "another test" // Still OK
//letTest = CTest() // Error
var varTest1 = CTest()
var varTest2 = CTest()
var varTest3 = CTest()
varTest1.str = "var 1"
varTest2.str = "var 2"
varTest3 = varTest1
varTest1.str = "var 3"
varTest3.str // "var 3"

Why Choose Struct Over Class?

Playing around with Swift, coming from a Java background, why would you want to choose a Struct instead of a Class? Seems like they are the same thing, with a Struct offering less functionality. Why choose it then?
According to the very popular WWDC 2015 talk Protocol Oriented Programming in Swift (video, transcript), Swift provides a number of features that make structs better than classes in many circumstances.
Structs are preferable if they are relatively small and copiable because copying is way safer than having multiple references to the same instance as happens with classes. This is especially important when passing around a variable to many classes and/or in a multithreaded environment. If you can always send a copy of your variable to other places, you never have to worry about that other place changing the value of your variable underneath you.
With Structs, there is much less need to worry about memory leaks or multiple threads racing to access/modify a single instance of a variable. (For the more technically minded, the exception to that is when capturing a struct inside a closure because then it is actually capturing a reference to the instance unless you explicitly mark it to be copied).
Classes can also become bloated because a class can only inherit from a single superclass. That encourages us to create huge superclasses that encompass many different abilities that are only loosely related. Using protocols, especially with protocol extensions where you can provide implementations to protocols, allows you to eliminate the need for classes to achieve this sort of behavior.
The talk lays out these scenarios where classes are preferred:
Copying or comparing instances doesn't make sense (e.g., Window)
Instance lifetime is tied to external effects (e.g., TemporaryFile)
Instances are just "sinks"--write-only conduits to external state (e.g.CGContext)
It implies that structs should be the default and classes should be a fallback.
On the other hand, The Swift Programming Language documentation is somewhat contradictory:
Structure instances are always passed by value, and class
instances are always passed by reference. This means that they are
suited to different kinds of tasks. As you consider the data
constructs and functionality that you need for a project, decide
whether each data construct should be defined as a class or as a
structure.
As a general guideline, consider creating a structure when one or more
of these conditions apply:
The structure’s primary purpose is to encapsulate a few relatively simple data values.
It is reasonable to expect that the encapsulated values will be copied rather than referenced when you assign or pass around an
instance of that structure.
Any properties stored by the structure are themselves value types, which would also be expected to be copied rather than referenced.
The structure does not need to inherit properties or behavior from another existing type.
Examples of good candidates for structures include:
The size of a geometric shape, perhaps encapsulating a width property and a height property, both of type Double.
A way to refer to ranges within a series, perhaps encapsulating a start property and a length property, both of type Int.
A point in a 3D coordinate system, perhaps encapsulating x, y and z properties, each of type Double.
In all other cases, define a class, and create instances of that class
to be managed and passed by reference. In practice, this means that
most custom data constructs should be classes, not structures.
Here it is claiming that we should default to using classes and use structures only in specific circumstances. Ultimately, you need to understand the real world implication of value types vs. reference types and then you can make an informed decision about when to use structs or classes. Also, keep in mind that these concepts are always evolving and The Swift Programming Language documentation was written before the Protocol Oriented Programming talk was given.
This answer was originally about difference in performance between struct and class. Unfortunately there are too much controversy around the method I used for measuring. I left it below, but please don't read too much into it. I think after all these years, it has become clear in Swift community that struct (along with enum) is always preferred due to its simplicity and safety.
If performance is important to your app, do measure it yourself. I still think most of the time struct performance is superior, but the best answer is just as someone said in the comments: it depends.
=== OLD ANSWER ===
Since struct instances are allocated on stack, and class instances are allocated on heap, structs can sometimes be drastically faster.
However, you should always measure it yourself and decide based on your unique use case.
Consider the following example, which demonstrates 2 strategies of wrapping Int data type using struct and class. I am using 10 repeated values are to better reflect real world, where you have multiple fields.
class Int10Class {
let value1, value2, value3, value4, value5, value6, value7, value8, value9, value10: Int
init(_ val: Int) {
self.value1 = val
self.value2 = val
self.value3 = val
self.value4 = val
self.value5 = val
self.value6 = val
self.value7 = val
self.value8 = val
self.value9 = val
self.value10 = val
}
}
struct Int10Struct {
let value1, value2, value3, value4, value5, value6, value7, value8, value9, value10: Int
init(_ val: Int) {
self.value1 = val
self.value2 = val
self.value3 = val
self.value4 = val
self.value5 = val
self.value6 = val
self.value7 = val
self.value8 = val
self.value9 = val
self.value10 = val
}
}
func + (x: Int10Class, y: Int10Class) -> Int10Class {
return IntClass(x.value + y.value)
}
func + (x: Int10Struct, y: Int10Struct) -> Int10Struct {
return IntStruct(x.value + y.value)
}
Performance is measured using
// Measure Int10Class
measure("class (10 fields)") {
var x = Int10Class(0)
for _ in 1...10000000 {
x = x + Int10Class(1)
}
}
// Measure Int10Struct
measure("struct (10 fields)") {
var y = Int10Struct(0)
for _ in 1...10000000 {
y = y + Int10Struct(1)
}
}
func measure(name: String, #noescape block: () -> ()) {
let t0 = CACurrentMediaTime()
block()
let dt = CACurrentMediaTime() - t0
print("\(name) -> \(dt)")
}
Code can be found at https://github.com/knguyen2708/StructVsClassPerformance
UPDATE (27 Mar 2018):
As of Swift 4.0, Xcode 9.2, running Release build on iPhone 6S, iOS 11.2.6, Swift Compiler setting is -O -whole-module-optimization:
class version took 2.06 seconds
struct version took 4.17e-08 seconds (50,000,000 times faster)
(I no longer average multiple runs, as variances are very small, under 5%)
Note: the difference is a lot less dramatic without whole module optimization. I'd be glad if someone can point out what the flag actually does.
UPDATE (7 May 2016):
As of Swift 2.2.1, Xcode 7.3, running Release build on iPhone 6S, iOS 9.3.1, averaged over 5 runs, Swift Compiler setting is -O -whole-module-optimization:
class version took 2.159942142s
struct version took 5.83E-08s (37,000,000 times faster)
Note: as someone mentioned that in real-world scenarios, there will be likely more than 1 field in a struct, I have added tests for structs/classes with 10 fields instead of 1. Surprisingly, results don't vary much.
ORIGINAL RESULTS (1 June 2014):
(Ran on struct/class with 1 field, not 10)
As of Swift 1.2, Xcode 6.3.2, running Release build on iPhone 5S, iOS 8.3, averaged over 5 runs
class version took 9.788332333s
struct version took 0.010532942s (900 times faster)
OLD RESULTS (from unknown time)
(Ran on struct/class with 1 field, not 10)
With release build on my MacBook Pro:
The class version took 1.10082 sec
The struct version took 0.02324 sec (50 times faster)
Similarities between structs and classes.
I created gist for this with simple examples.
https://github.com/objc-swift/swift-classes-vs-structures
And differences
1. Inheritance.
structures can't inherit in swift. If you want
class Vehicle{
}
class Car : Vehicle{
}
Go for an class.
2. Pass By
Swift structures pass by value and class instances pass by reference.
Contextual Differences
Struct constant and variables
Example (Used at WWDC 2014)
struct Point{
var x = 0.0;
var y = 0.0;
}
Defines a struct called Point.
var point = Point(x:0.0,y:2.0)
Now if I try to change the x. Its a valid expression.
point.x = 5
But if I defined a point as constant.
let point = Point(x:0.0,y:2.0)
point.x = 5 //This will give compile time error.
In this case entire point is immutable constant.
If I used a class Point instead this is a valid expression. Because in a class immutable constant is the reference to the class itself not its instance variables (Unless those variables defined as constants)
Assuming that we know Struct is a value type and Class is a reference type.
If you don't know what a value type and a reference type are then see What's the difference between passing by reference vs. passing by value?
Based on mikeash's post:
... Let's look at some extreme, obvious examples first. Integers are
obviously copyable. They should be value types. Network sockets can't
be sensibly copied. They should be reference types. Points, as in x, y
pairs, are copyable. They should be value types. A controller that
represents a disk can't be sensibly copied. That should be a reference
type.
Some types can be copied but it may not be something you want to
happen all the time. This suggests that they should be reference
types. For example, a button on the screen can conceptually be copied.
The copy will not be quite identical to the original. A click on the
copy will not activate the original. The copy will not occupy the same
location on the screen. If you pass the button around or put it into a
new variable you'll probably want to refer to the original button, and
you'd only want to make a copy when it's explicitly requested. That
means that your button type should be a reference type.
View and window controllers are a similar example. They might be
copyable, conceivably, but it's almost never what you'd want to do.
They should be reference types.
What about model types? You might have a User type representing a user
on your system, or a Crime type representing an action taken by a
User. These are pretty copyable, so they should probably be value
types. However, you probably want updates to a User's Crime made in
one place in your program to be visible to other parts of the program.
This suggests that your Users should be managed by some sort of user
controller which would be a reference type. e.g
struct User {}
class UserController {
var users: [User]
func add(user: User) { ... }
func remove(userNamed: String) { ... }
func ...
}
Collections are an interesting case. These include things like arrays
and dictionaries, as well as strings. Are they copyable? Obviously. Is
copying something you want to happen easily and often? That's less
clear.
Most languages say "no" to this and make their collections reference
types. This is true in Objective-C and Java and Python and JavaScript
and almost every other language I can think of. (One major exception
is C++ with STL collection types, but C++ is the raving lunatic of the
language world which does everything strangely.)
Swift said "yes," which means that types like Array and Dictionary and
String are structs rather than classes. They get copied on assignment,
and on passing them as parameters. This is an entirely sensible choice
as long as the copy is cheap, which Swift tries very hard to
accomplish.
...
I personally don't name my classes like that. I usually name mine UserManager instead of UserController but the idea is the same
In addition don't use class when you have to override each and every instance of a function ie them not having any shared functionality.
So instead of having several subclasses of a class. Use several structs that conform to a protocol.
Another reasonable case for structs is when you want to do a delta/diff of your old and new model. With references types you can't do that out of the box. With value types the mutations are not shared.
Here are some other reasons to consider:
structs get an automatic initializer that you don't have to maintain in code at all.
struct MorphProperty {
var type : MorphPropertyValueType
var key : String
var value : AnyObject
enum MorphPropertyValueType {
case String, Int, Double
}
}
var m = MorphProperty(type: .Int, key: "what", value: "blah")
To get this in a class, you would have to add the initializer, and maintain the intializer...
Basic collection types like Array are structs. The more you use them in your own code, the more you will get used to passing by value as opposed to reference. For instance:
func removeLast(var array:[String]) {
array.removeLast()
println(array) // [one, two]
}
var someArray = ["one", "two", "three"]
removeLast(someArray)
println(someArray) // [one, two, three]
Apparently immutability vs. mutability is a huge topic, but a lot of smart folks think immutability -- structs in this case -- is preferable. Mutable vs immutable objects
Some advantages:
automatically threadsafe due to not being shareable
uses less memory due to no isa and refcount (and in fact is stack allocated generally)
methods are always statically dispatched, so can be inlined (though #final can do this for classes)
easier to reason about (no need to "defensively copy" as is typical with NSArray, NSString, etc...) for the same reason as thread safety
Structs are value type and Classes are reference type
Value types are faster than Reference types
Value type instances are safe in a multi-threaded environment as
multiple threads can mutate the instance without having to worry
about the race conditions or deadlocks
Value type has no references unlike reference type; therefore there
is no memory leaks.
Use a value type when:
You want copies to have independent state, the data will be used in
code across multiple threads
Use a reference type when:
You want to create shared, mutable state.
Further information could be also found in the Apple documentation
https://docs.swift.org/swift-book/LanguageGuide/ClassesAndStructures.html
Additional Information
Swift value types are kept in the stack. In a process, each thread has its own stack space, so no other thread will be able to access your value type directly. Hence no race conditions, locks, deadlocks or any related thread synchronization complexity.
Value types do not need dynamic memory allocation or reference counting, both of which are expensive operations. At the same time methods on value types are dispatched statically. These create a huge advantage in favor of value types in terms of performance.
As a reminder here is a list of Swift
Value types:
Struct
Enum
Tuple
Primitives (Int, Double, Bool etc.)
Collections (Array, String, Dictionary, Set)
Reference types:
Class
Anything coming from NSObject
Function
Closure
Structure is much more faster than Class. Also, if you need inheritance then you must use Class. Most important point is that Class is reference type whereas Structure is value type. for example,
class Flight {
var id:Int?
var description:String?
var destination:String?
var airlines:String?
init(){
id = 100
description = "first ever flight of Virgin Airlines"
destination = "london"
airlines = "Virgin Airlines"
}
}
struct Flight2 {
var id:Int
var description:String
var destination:String
var airlines:String
}
now lets create instance of both.
var flightA = Flight()
var flightB = Flight2.init(id: 100, description:"first ever flight of Virgin Airlines", destination:"london" , airlines:"Virgin Airlines" )
now lets pass these instance to two functions which modify the id, description, destination etc..
func modifyFlight(flight:Flight) -> Void {
flight.id = 200
flight.description = "second flight of Virgin Airlines"
flight.destination = "new york"
flight.airlines = "Virgin Airlines"
}
also,
func modifyFlight2(flight2: Flight2) -> Void {
var passedFlight = flight2
passedFlight.id = 200
passedFlight.description = "second flight from virgin airlines"
}
so,
modifyFlight(flight: flightA)
modifyFlight2(flight2: flightB)
now if we print the flightA's id and description, we get
id = 200
description = "second flight of Virgin Airlines"
Here, we can see the id and description of FlightA is changed because the parameter passed to the modify method actually points to the memory address of flightA object(reference type).
now if we print the id and description of FLightB instance we get,
id = 100
description = "first ever flight of Virgin Airlines"
Here we can see that the FlightB instance is not changed because in modifyFlight2 method, actual instance of Flight2 is passes rather than reference ( value type).
Answering the question from the perspective of value types vs reference types, from this Apple blog post it would appear very simple:
Use a value type [e.g. struct, enum] when:
Comparing instance data with == makes sense
You want copies to have independent state
The data will be used in code across multiple threads
Use a reference type [e.g. class] when:
Comparing instance identity with === makes sense
You want to create shared, mutable state
As mentioned in that article, a class with no writeable properties will behave identically with a struct, with (I will add) one caveat: structs are best for thread-safe models -- an increasingly imminent requirement in modern app architecture.
Struct vs Class
[Stack vs Heap]
[Value vs Reference type]
Struct is more preferable. But Struct does not solve all issues by default. Usually you can hear that value type is allocated on stack, but it is not always true. Only local variables are allocated on stack
//simple blocks
struct ValueType {}
class ReferenceType {}
struct StructWithRef {
let ref1 = ReferenceType()
}
class ClassWithRef {
let ref1 = ReferenceType()
}
func foo() {
//simple blocks
let valueType1 = ValueType()
let refType1 = ReferenceType()
//RetainCount
//StructWithRef
let structWithRef1 = StructWithRef()
let structWithRef1Copy = structWithRef1
print("original:", CFGetRetainCount(structWithRef1 as CFTypeRef)) //1
print("ref1:", CFGetRetainCount(structWithRef1.ref1)) //2 (originally 3)
//ClassWithRef
let classWithRef1 = ClassWithRef()
let classWithRef1Copy = classWithRef1
print("original:", CFGetRetainCount(classWithRef1)) //2 (originally 3)
print("ref1:", CFGetRetainCount(classWithRef1.ref1)) //1 (originally 2)
}
*You should not use/rely on retainCount, because it does not say useful information
To check stack or heap
During compiling SIL(Swift Intermediate Language) can optimize you code
swiftc -emit-silgen -<optimization> <file_name>.swift
//e.g.
swiftc -emit-silgen -Onone file.swift
//emit-silgen -> emit-sil(is used in any case)
//-emit-silgen Emit raw SIL file(s)
//-emit-sil Emit canonical SIL file(s)
//optimization: O, Osize, Onone. It is the same as Swift Compiler - Code Generation -> Optimization Level
There you can find alloc_stack(allocation on stack) and alloc_box(allocation on heap)
[Optimization Level(SWIFT_OPTIMIZATION_LEVEL)]
With classes you get inheritance and are passed by reference, structs do not have inheritance and are passed by value.
There are great WWDC sessions on Swift, this specific question is answered in close detail in one of them. Make sure you watch those, as it will get you up to speed much more quickly then the Language guide or the iBook.
I wouldn't say that structs offer less functionality.
Sure, self is immutable except in a mutating function, but that's about it.
Inheritance works fine as long as you stick to the good old idea that every class should be either abstract or final.
Implement abstract classes as protocols and final classes as structs.
The nice thing about structs is that you can make your fields mutable without creating shared mutable state because copy on write takes care of that :)
That's why the properties / fields in the following example are all mutable, which I would not do in Java or C# or swift classes.
Example inheritance structure with a bit of dirty and straightforward usage at the bottom in the function named "example":
protocol EventVisitor
{
func visit(event: TimeEvent)
func visit(event: StatusEvent)
}
protocol Event
{
var ts: Int64 { get set }
func accept(visitor: EventVisitor)
}
struct TimeEvent : Event
{
var ts: Int64
var time: Int64
func accept(visitor: EventVisitor)
{
visitor.visit(self)
}
}
protocol StatusEventVisitor
{
func visit(event: StatusLostStatusEvent)
func visit(event: StatusChangedStatusEvent)
}
protocol StatusEvent : Event
{
var deviceId: Int64 { get set }
func accept(visitor: StatusEventVisitor)
}
struct StatusLostStatusEvent : StatusEvent
{
var ts: Int64
var deviceId: Int64
var reason: String
func accept(visitor: EventVisitor)
{
visitor.visit(self)
}
func accept(visitor: StatusEventVisitor)
{
visitor.visit(self)
}
}
struct StatusChangedStatusEvent : StatusEvent
{
var ts: Int64
var deviceId: Int64
var newStatus: UInt32
var oldStatus: UInt32
func accept(visitor: EventVisitor)
{
visitor.visit(self)
}
func accept(visitor: StatusEventVisitor)
{
visitor.visit(self)
}
}
func readEvent(fd: Int) -> Event
{
return TimeEvent(ts: 123, time: 56789)
}
func example()
{
class Visitor : EventVisitor
{
var status: UInt32 = 3;
func visit(event: TimeEvent)
{
print("A time event: \(event)")
}
func visit(event: StatusEvent)
{
print("A status event: \(event)")
if let change = event as? StatusChangedStatusEvent
{
status = change.newStatus
}
}
}
let visitor = Visitor()
readEvent(1).accept(visitor)
print("status: \(visitor.status)")
}
In Swift, a new programming pattern has been introduced known as Protocol Oriented Programming.
Creational Pattern:
In swift, Struct is a value types which are automatically cloned. Therefore we get the required behavior to implement the prototype pattern for free.
Whereas classes are the reference type, which is not automatically cloned during the assignment. To implement the prototype pattern, classes must adopt the NSCopying protocol.
Shallow copy duplicates only the reference, that points to those objects whereas deep copy duplicates object’s reference.
Implementing deep copy for each reference type has become a tedious task. If classes include further reference type, we have to implement prototype pattern for each of the references properties. And then we have to actually copy the entire object graph by implementing the NSCopying protocol.
class Contact{
var firstName:String
var lastName:String
var workAddress:Address // Reference type
}
class Address{
var street:String
...
}
By using structs and enums, we made our code simpler since we don’t have to implement the copy logic.
Many Cocoa APIs require NSObject subclasses, which forces you into using class. But other than that, you can use the following cases from Apple’s Swift blog to decide whether to use a struct / enum value type or a class reference type.
https://developer.apple.com/swift/blog/?id=10
One point not getting attention in these answers is that a variable holding a class vs a struct can be a let while still allowing changes on the object's properties, while you cannot do this with a struct.
This is useful if you don't want the variable to ever point to another object, but still need to modify the object, i.e. in the case of having many instance variables that you wish to update one after another. If it is a struct, you must allow the variable to be reset to another object altogether using var in order to do this, since a constant value type in Swift properly allows zero mutation, while reference types (classes) don't behave this way.
As struct are value types and you can create the memory very easily which stores into stack.Struct can be easily accessible and after the scope of the work it's easily deallocated from the stack memory through pop from the top of the stack.
On the other hand class is a reference type which stores in heap and changes made in one class object will impact to other object as they are tightly coupled and reference type.All members of a structure are public whereas all the members of a class are private.
The disadvantages of struct is that it can't be inherited .
Structure and class are user defied data types
By default, structure is a public whereas class is private
Class implements the principal of encapsulation
Objects of a class are created on the heap memory
Class is used for re usability whereas structure is used for grouping
the data in the same structure
Structure data members cannot be initialized directly but they can be
assigned by the outside the structure
Class data members can be initialized directly by the parameter less
constructor and assigned by the parameterized constructor

Why do I need to declare an optional value as nil explicitly in Struct - Swift

Here's a quote from the docs:
If your custom type has a stored property that is logically allowed to have “no value”—perhaps because its value cannot be set during initialization, or because it is allowed to have “no value” at some later point—declare the property with an optional type. Properties of optional type are automatically initialized with a value of nil, indicating that the property is deliberately intended to have “no value yet” during initialization.
If I do this with a class it works fine:
class MyClass {
var someProperty: String?
}
var myClass = MyClass()
myClass.someProperty // Shows nil
However, if I do this with a struct type, I get an error on initialization:
struct MyStruct {
var someProperty: String?
}
// ERROR
var myStruct = MyStruct()
Error:
Missing argument for parameter 'someProperty'
I can remedy this by declaring it nil explicitly like so:
struct MyStruct {
var someProperty: String? = nil
}
// Valid
var myStruct = MyStruct()
Question
Given the documentation, I would expect properties on any type that are set as optionals to be defaulted to nil. Is there a reason I have to declare it explicitly on a struct?
Why?
No good reason, like many of you, I'm just experimenting.
Both Classes and Structs need to have all property values set when they are initialized. This can be done either through explicit default values or by setting a value in the designated initializer.
However, Structs differ in the fact that they have an automatically generated memberwise initializer.
When you don't define a value for someProperty explicitly, your struct has one initializer only: the automatically generated memberwise one.
If you do provide a default value, you get two: one that takes no arguments, and one that takes a value for someProperty as an argument
From the docs:
All structures have an automatically-generated memberwise initializer,
which you can use to initialize the member properties of new structure
instances. Initial values for the properties of the new instance can
be passed to the memberwise initializer by name:
let vga = Resolution(width: 640, height: 480)
Unlike structures, class instances do not receive a default memberwise
initializer. Initializers are described in more detail in
Initialization.
I agree this is rather quirky (unless I'm also missing something). For structures with only optionals, it might be worth suggesting (via Apple bugreport) that in such cases, a default parameterless initialiser is also added by default?
Another remedy is
var myStruct = MyStruct(someProperty:nil)
However, if you had a lot of optional members, this becomes clumbsy.
I think this is an deliberate difference between structs and classes, which makes a bit of sense. For example when you have a struct, say a 3d point with three floats for XYZ. It doesn't make much sense to have a nil value for x or y or z. With a class on the other hand this is a very important feature. If you think about a downloader class, for example, that goes and downloads a text file and stores it in a property. It makes more sense for that property to be nil when the class is first initialized. Since apple has changed structs to be much more closely related to classes I think this is an important distinction. It's my opinion that setting the optional explicitly to nil is a bug.
My reasoning for this:
In the optional documentation all of the example are on classes.

Class instance variable initialization order?

Currently, I am seeing something strange behavior.
class DataManager1
{
let THE_ID = "SOME_ID_STRING"
let _con1 = CKContainer(identifier: THE_ID) // error
// error: 'DataManager1.Type' does not have a member named 'THE_ID'
}
class DataManager2
{
let THE_ID = "SOME_ID_STRING"
let _con1:CKContainer?
init()
{
_con1 = CKContainer(identifier: THE_ID) // no error.
}
}
In C++ we have a defined initialization order between instance member variables. I expected something similar, but actually I couldn't find a mention for that form the manual.
Does Swift has a defined initialization order of properties? If it does, what is the rule, and where can I find the rule?
This is due to the fact that you're using a Closure (a Function is just a special case of Closure that is unnamed) to initialize the _con1 property with a default value.
From the Apple provided iBook:
If you use a closure to initialize a property, remember that the rest
of the instance has not yet been initialized at the point that the
closure is executed. This means that you cannot access any other
property values from within your closure, even if those properties
have default values. You also cannot use the implicit self property,
or call any of the instance’s methods.
Even though the note above refers specifically to closures, it seems that trying to set the default value for a property to be that of another property directly also does not work.